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8:01 PM
Sure, I like these rare occasions I find myself useful
 
Election's over
 
Congratulations indeed
 
Quelle surprise! Well, two of the guys I voted for were elected - not bad.
 
@JyrkiLahtonen Same for me.
 
8:08 PM
We need @Pedro to complete this convention
 
HARRO.
My plan to take over MSE is going swimmingly well.
 
Congratulations to @Pedro, @Daniel, and @Jyrki!
11
May you live to regret this not too much :) I plan to be misbehave, speaking personally :P
 
Does Asaf ever come to the chatroom anymore? I suppose not.
 
Yeah. Pedro will outlive me by about 30 years. With a bit of patience...
 
Well, @Pedro, now that you'll be so busy taking over, you won't need to talk math with me any more.
I haven't ever seen Asaf in chat.
 
8:11 PM
@Mike sadly not
 
The stars have been conferred.
Moderators, I invite you to delete this message to show off your newfound absolute power.
 
Aren't chat gurus different from moderators in main?
 
Their names are not yet blue
 
<click, click, click... > nothing happening, @Mike
 
LOL @Jyrki
 
8:13 PM
Maybe I'm just more powerful than you?
 
@Studentmath: Did you scare @A.E away? :D
 
A.E
@TedShifrin, no :P I am just still at a loss on how to count this probability of at least one element appearing in all the subsets.
 
@Ted I think your hint was all that hee needed
 
Let us see who remembers me.
 
Or maybe not
 
8:14 PM
@Lord_Farin Oh hey buddy.
 
Hello there @AlexanderGruber. It's been a while, hasn't it?
 
@A.E given a single subset, what's the probability of a specific element appearing in it?
 
Yah, where have you been?
 
Hi @Lord_Farin
 
Hi @Lord.
 
8:16 PM
I saw you at some point when I was just starting here before you left.
 
@Venus They are too nice to stop working on them :D.
 
Well, let me think. I was looking for employment, and I noted that MSE was eating away bigger and bigger parts of my day.
So I quit radically.
 
One of my colleagues in graduate school was named Farin, so I remember your name.
 
@Lord_Farin Ah, yes. That'll do it.
 
Hi @DonL
 
8:17 PM
Did you get employment?
 
gainful or not, you should add, @Mike.
 
Hi everyone!
 
And now, after a year and a bit, I have an awesome day job, and I'm back at MSE :D.
 
How is $\phi(27) = 18$? I have as my totatives $2,4,5,7,8,10,11,13,14,16,17,19,20,22,23,25,26$
 
@Lord_Farin That'll fix that problem quick. ;)
 
8:18 PM
You forgot 1.
 
Congratulations, @Lord.
 
Oh, the election is over.
 
@TedShifrin Thanks :).
 
Ok @Mik
 
A.E
Given a subset S of P, the probability of some e in P appearing in S is (P - 1 choose |S| - 1) / (|P| choose S)
*|S|
 
8:19 PM
@TedShifrin I think I vaguely remember your name, but that's about it. Sorry about that :(.
 
I prefer to be forgetable, @Lord, as far too many people remember me with pain. :D
forgettable, I guess
nah, neither looks right
 
Forgettable is right methinks.
 
Oh I did not know 2 mods were leaving.
 
How are you doing, @Ted?
 
I thought three were, @Jasper.
 
8:20 PM
2 3 mods are leaving, @Jasper? :0
 
ok, @Khallil, and you?
 
@MikeMiller From perusing meta, your name stood out as one of the new ones. It seems I had adequate replacement :).
@KhallilBenyattou I concur.
 
Ah, no, I don't do the fighting in meta. I just whine about it in here.
 
Who are the 3?
 
@Mike doesn't have enough work to do learning math in graduate school, @Lord.
 
8:21 PM
Alex, Willie and?
 
@TedShifrin Hm, that also sounds eerily familiar :P.
 
Yea, not bad thanks, @Ted. ^_^
I've started some really basic Analysis (sequences, series and completeness), so that's started to eat away at my days. =P
 
@JasperLoy 2 leaving, 3 new ones
 
@AlexanderGruber Ah, sometimes, I am right after all.
 
Good, good, @Khallil.
 
8:22 PM
I have the system $$2^a \equiv 7 \mod 27$$ and $$2^{18} \equiv 1 \mod 27$$
 
@Studentmath: Have you taken over with @A.E? He forgot to ping you.
 
What do you study, @Lord_Farin?
 
Does that symbol mean congruent to, @DonLarynx?
 
@PedroTamaroff @JyrkiLahtonen @DanielFischer Y'all got your superpowers yet?
 
Fixed @Khal
 
A.E
8:23 PM
Sorry, @stud
 
@AlexanderGruber Yes.
 
A.E
@Studentmath
Given a subset S of P, the probability of some e in P appearing in S is (P - 1 choose |S| - 1) / (|P| choose |S|)
 
Ah, what was the symbol before the edit, @Don?
 
@PedroTamaroff Can you enter mod chat?
 
@MikeMiller I graduated last year; my primary focus was on logic.
 
8:23 PM
a congruent symbol
 
@AlexanderGruber Link?
 
@AlexanderGruber Let me first find my profile. An old man is not so fast.
 
It looks cool. What was it's $\LaTeX$ code, @DonLarynx?
^_^
 
Are you still doing it, @Lord_Farin?
 
\cong
 
8:24 PM
LOL @Pedro @DanielF
 
Ah, nice!
 
@MikeMiller Occasionally; I'm in the IT business nowadays, so not too much time to spare for maths unfortunately :(.
 
Now I feel like a very lesser person, @Alex @Pedro @DanielF @Jyrki
 
It looks cooler than \equiv, @DonLarynx. =P
 
Ah, I see. Are you enjoying it?
 
8:25 PM
Very different from your namesake when I was in grad school, @Lord
 
@A.E I think that looks right.
 
@MikeMiller Very much, my employer is aware of my abilities and gives me challenging tasks :).
 
@Studentmath, @A.E: I'm no longer paying attention, so you'll have to let me know if I am needed.
 
Great!
 
Challenging tasks is wonderful @Lord
 
8:25 PM
@TedShifrin Sorry?
 
I think $\leadsto$, short for \leadsto, is cooler
 
My classmate named Farin was in a field very far from logic.
 
@TedShifrin Ah :).
 
@DonL: I learned to write that for \mapsto because Mike Artin loves it so.
 
@TedShifrin That field is called delusion.
 
8:26 PM
@A.E that's considering the subset is chosen at random, i.e. uniformly - right?
 
$\bigodot$.$\bigodot$
 
A.E
@Studentmath Yes
 
logic? @Jasper
 
@TedShifrin I mean that delusion is far from logic, lol.
 
Oh, well, no, I don't think of complex geometry as delusion, thank you.
 
8:28 PM
I think people in this room are quite bad at getting my jokes.
In the Eng room, I am quite bad at getting their jokes.
 
I claim to get your jokes, and I also claim they're not very funny.
2
 
There's symmetry to it, @Jasper.
 
Can anyone tell me who user Behaviour is?
 
@AlexanderGruber
 
They apparently remember me, but have only joined 7 months ago.
 
8:29 PM
Where's the chat?
@Lord_Farin Hello there.
 
@PedroTamaroff Hello, Pedro.
 
@A.E then you are right, and wrote it elegantly - now we want to think of the probability of an element not appearing in a given subset
 
It's been a while :).
 
@Lord_Farin They've been around for a while. You might also know them under the past names of "Post No Bulls", "40 votes", and some other username I don't remember.
 
@PedroTamaroff Your mod powers are still gettin' beamed down
 
8:30 PM
@Alexander: I did click the mod agreement. When and where is the hazing ritual?
 
Now we're Star Trek, @Alex?
 
@PedroTamaroff How have you been doing? Quite fine, I presume, seeing that you have been elected as a moderator - for which I congratulate you.
 
An SE staff was concerned about me after reading the transcript, so decided to send me an email. I was surprised to get it.
 
A.E
@Studentmath The form I wrote simplifies to Q / P, so then the probability of a specific element not appearing in a given subset is just 1 - Q/P
 
@MikeMiller Ah, 40 votes rings a bell. That makes sense, thanks :).
 
8:30 PM
@AlexanderGruber I think I just misclicked. Dang this buttons are too close, eh.
 
@Pedro:
 
@AlexanderGruber I am making the silly assumption that you're not already, but you might look at the comments on the mod election page.
 
Are you going to misclick and eradicate me?
 
I hope so, @Ted
 
User X once ignored me accidentally. It took him long to figure out how to undo it.
 
8:32 PM
@A.E right, for some reason I forgot the original question - we want to work in the complement, so while that's true it's not exactly what we care about. So you have the probability of specific element apearing in a given subset. What's the probability the given element appears in 2 different subsets?
 
Concerned about you in what way, @Jasper? Not the recent comments, but some of your old ones?
 
@TedShifrin Well, I have been talking about my problems quite a lot the last few days in chat, so he got worried, I think.
 
@MikeMiller Asaf's post?
 
A.E
@Studentmath Well those are independent, so it should just be the product (Q/P)^2
 
Yes, @Alex
 
8:33 PM
Ah, yeah, we're on it
 
Ah, well, there's only so much (i.e., not much) we can do for you, @Jasper, but that makes me glad that he was concerned.
 
@TedShifrin Aha. I hope it was not someone who complained about me talking too much though.
 
Right, so for $N$ different subsets of $P$?
 
A.E
@Studentmath So this gives me the probability of a specific element appearing in all N subsets: (Q/P)^N.
 
Correct. But does it gives us the complement probability that we are looking for?
 
A.E
8:35 PM
No
 
@AlexanderGruber Alex.
Link me to the mod chat.
 
What do we need, then?
 
I am going to click the mod chat link.
I'm going to do it.
 
A.E
I would think we need a factor of P, to account for the P choices of a specific element appearing in all N subsets
 
@PedroTamaroff I just pinged you from in there.
 
8:36 PM
@Alex I can't click the link if you don't link it.
 
I gather user26857 is going to be a pleasure to deal with ...
 
That's apparently YACP if you remember the name. I don't.
 
Right, and also we wouldn't mind if more than 1 element appears as @Ted said, so we need to account for the option they have 2, 3, ... P elements in common.
 
You shouldn't need to worry about that if you've done it right, @Studentmath :P
 
8:38 PM
@MikeMiller I recall that name as regularly sparking tensions.
 
@AlexanderGruber I didn't get the ping.
 
An uncompromising character.
 
@PedroTamaroff rob's workin on it
 
You'd better just link it, @Alexander
 
A.E
@TedShifrin mind giving your input? I have Pr{A specific element belongs to all N subsets}, and I want to calculate Pr{Any element belongs to all N subsets}
 
8:39 PM
I don't either, @Mike.
 
@A.E Are the probabilities independent?
 
A.E
Pr{A specific element belongs to all N subsets} = (Q/P)^n
Yes, each subset is of size Q drawn uniformly from P elements
 
Oh, I see ... Ugh, we are going to need inclusion/exclusion this way.
 
@Ted what way did you have in mind?
 
Another question on RH.
 
8:41 PM
I should go back to avoiding all probability questions, now that I'm done teaching :)
I guess we can alternatively add up terms for exactly one overlap, exactly two, etc., @Studentmath ...
 
@TedShifrin If you are very free, you can look at my article and tell me what you think, though I forgot what I had written ten years ago. I hope it will at least help me get into grad school.
 
@Ted ah yeah, that might be nicer
Probably will be
 
@Studentmath "Nice" is not the word that comes to my mind in this context...
It'll probably be a messy, messy expression.
 
@Lord_Farin I remember you. I think you are a girl, iirc.
 
@Jasper, thanks for reminding me. I will try to look at it over break. I have to read 15 teaching award nomination dossiers, each 25 pages long.
 
8:44 PM
@JasperLoy You recalled wrong.
 
Well, @Lord, inclusion/exclusion isn't exactly elegant :D
 
@Lord messier than the inclusion/exclusion we gonna need here otherwise?
 
@TedShifrin Wow, 25 pages is too long. Should be at most 2.5 pages.
 
LOL ... in some cases, yes, @Jasper, but in most cases not.
What is absurd is that someone would include a 12-page research CV for a teaching award nomination. Drove me nuts last year, too.
 
@Studentmath I'm not sure. I just want to make sure I'm not the one writing everything up in the end :P.
 
8:45 PM
@Lord oh yes, certainly. Though I don't think we are helping @A.E this way :P
 
A.E
:)
 
@Studentmath True, true. But there might be more virtue in thinking out a more elegant approach :).
 
@Lord true
 
A.E
I have to go, I will keep thinking about it. Thanks for the help, guys.
In case you feel like writing something down, I made a post here: math.stackexchange.com/questions/1078342/…
 
I thought I suggested doing the complement in the first place ? Of course, now I've forgotten. :)
 
8:47 PM
@A.E Thanks for handing me a nice problem to think about :).
 
@TedShifrin Wait, who submits these nominations? They nominate others and then include others' CV?
 
Well, the candidate helps in preparing the nomination, @Jasper. But someone is supposed to collect all the stuff, all the letters written by colleagues/students, and write a narrative for it.
 
@A.E same as Lord said, if I think of something elegant I will let you know.
@Ted we were working on the complement :P
 
No, we weren't. His question is for subsets with nontrivial overall intersection, @Studentmath. But the complement is likewise yucky. I forgot he changed the question after I started thinking.
 
@TedShifrin That is extremely weird. I think the candidate should not have any hand in it.
 
8:50 PM
Well, @Jasper, I tend to agree, but the candidate has to provide a CV and a list of students to contact. In some cases over the years, it has looked almost totally self-prepared, which I find disgusting. I have prepared a number of these dossiers, and I take it seriously.
 
Hi @Lord_Farin
 
@skullpatrol Hello skull.
Good to see you again.
 
Nice to see you my friend @Lord_Farin :-)
 
@skullpatrol :). How are you doing?
 
@Lord_Farin fine thank you. How are you?
 
8:55 PM
@skullpatrol I'm also fine, thanks. It's good to be back.
@Ted Would your inclusion/exclusion approach yield the following? $$\sum_{i=1}^n (-1)^{1+i} \binom{p}{i}\binom{p-i}{q-i}^n\binom{p}{q}^{-n}$$
(Summation to $q$ of course.)
 
I quit thinking about it when @Studentmath took over, @Lord :)
 
@Ted Ok :).
 
Interesting that there is a student and a lord in here.
 
Welcome back @Lord_Farin
 
8:59 PM
:)
 

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