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10:00 PM
@EmilioPisanty "Record"?
 
@SirCumference As in, it happened.
 
yeah, who flagged that?!
 
@EmilioPisanty You mean that one time I argued with you about PSE's logo?
 
@SirCumference That's the time.
 
Quite a short record, I'd say
 
10:01 PM
Given that the same pattern just recurred, maybe you can entertain the possibility that the problem is with parts of your attitude and not with other people?
Just a suggestion.
 
@EmilioPisanty I just don't really get the rationale for questions like "What real-world impact would your proposed change have?"
 
"this is not a useful conversation."
WWRS
 
@SirCumference I don't understand why you think those comments are anything other than people trying to help you improve your question.
but
 
what would rob say?
3
 
I agree with AFT
 
10:03 PM
Same
 
@AccidentalFourierTransform who's Rob-with-a-capital-R?
 
Just curious, what's the difference between 1 mol^2 (of dimension N^2) and N_A(1 mol^2) (of dimension N)? Is this the correct place to be asking?
 
@EmilioPisanty I'll gladly admit that your comments were less aggressive than the ones I received on the latter post
 
@AccidentalFourierTransform good
now I can star it
 
Someone teach me a physics.
Anything.
 
@DanielSank did you see the IBM "quantum volume" thing?
 
Oh also one more thing: if anyone here is interested in giving a technical talk/seminar at the quantum computing lab in Santa Barbara, email me.
5
 
@DanielSank Light moves fast
 
We just started doing that.
 
10:05 PM
Congrats, you passed my physics class
 
@CRDrost Hi there :) You recommended talking here, I think it's a good idea
 
@EmilioPisanty Briefly.
 
@doublefelix Physics, math and CS?
o_O
 
@DanielSank how worthwhile is this volume notion thing?
 
10:06 PM
@EmilioPisanty I haven't read it carefully.
 
@DanielSank fair enough
I'll quiz you later
no, serious question, though
can anyone make heads or tails of this?
 
Glancing over it, this is very much not a new idea at all.
 
oh, whoa that was a while ago. I ended up doing just physics and math
 
Abstract
Intuition from our everyday lives gives rise to the belief that information exchanged between remote parties is carried by physical particles. Surprisingly, in a recent theoretical study [Salih H, Li ZH, Al-Amri M, Zubairy MS (2013) Phys Rev Lett 110:170502], quantum mechanics was found to allow for communication, even without the actual transmission of physical particles. From the viewpoint of communication, this mystery stems from a (nonintuitive) fundamental concept in quantum mechanics—wave-particle duality. All particles can be described fully by wave functions. To determine w
 
@doublefelix Update that profile, sir.
 
10:07 PM
Significance

Recent theoretical studies have shown that quantum mechanics allows counterfactual communication, even without actual transmission of physical particles, which raised a heated debate on its interpretation. Although several papers have been published on the theoretical aspects of the subject, a faithful experimental demonstration is missing. Here, by using the quantum Zeno effect and a single-photon source, direct communication without carrier particle transmission is implemented successfully. We experimentally demonstrate the feasibility of direct counterfactual communication
 
i am ;)
 
> "direct communication without carrier particle transmission is implemented successfully"
does this ring huge red bells for other people as well?
I mean
ring huge flags
 
It's just entanglement stuff.
 
@DanielSank but you start off with shared entanglement, right?
 
10:09 PM
Saying there's no particle exchange is kinda... I dunno.
@EmilioPisanty Probably. I'd have to read it more carefully.
I doubt they've broken physics.
 
@DanielSank yeah, me too
I tried reading it but it got boring =|
 
or rather, I tried reading the PNAS, couldn't get access, looked for it on shady russian servers, didn't find it, switched to the Salih, Sih, Zubairy paper they reference in the abstract, didn't get any of it
 
What's the derivative (with respect to time) of the linear acceleration?
 
@DanielSank if you do get round to reading it I'd appreciate a ping
@nbro the jerk
 
10:14 PM
be nice.
 
(Just asking this in order to make this seem a serious chat about physics)
 
after which come snap crackle and pop
 
gotta leave
bye chaps
 
In physics, jerk, also known as jolt, surge, or lurch, is the rate of change of acceleration; that is, the derivative of acceleration with respect to time, and as such the second derivative of velocity, or the third derivative of position. Jerk is a vector, and there is no generally used term to describe its scalar magnitude (more precisely, its norm, e.g. "speed" as the norm of the velocity vector). According to the result of dimensional analysis of jerk, [length/time3], the SI units are m/s3 (or m·s−3); jerk can also be expressed in standard gravity per second (g/s). == Expressions == Jerk can...
 
to raise the levels in the same way that the glaciers do when they melt
nah mean?!
and I drop more metaphors than the bibble
 
10:18 PM
@EmilioPisanty
> It gets even worse when you consider that, unlike classical computers, you need a certain number of qubits to even carry out a calculation of a certain computational size
That's... wrong.
 
yeah
 
If I give you a classical computer with two bits, you can't use it to add 8-bit numbers.
 
@EmilioPisanty Thanks, anyway!
:D
 
@DanielSank yeah, well, when's the last time you saw a two-bit classical computer?
... that sounded unexpectedly demeaning w.r.t said perfectly-respectable classical computer possessing two bits
 
@DanielSank If you've got a memory as well, then it should be possible
(as in, a memory big enough to store the numbers, then some more)
 
10:21 PM
@Mithrandir24601 Mehhhhhhhh ok but in a quantum computer you're doing logic directly on the "memory".
There's no separation between memory and logic units in a quantum computer (yet).
This might change later, but for now we're going with a system where all the qubits are just there in a grid and the logic operations happen directly on them.
There's no separation between qubits storing data and qubits processing data.
 
@DanielSank ooh, have you heard of CRNs?
 
k.
so CRN stands for chemical reaction network
the basic idea is that you have a bunch of chemicals (the "states" of the system)
and the reactions between them are the "commands" of the programming language
i.e., you can use it to solve problems.
molecular computing =)
you can also store information using chemicals
for example, if you use DNA, you can store approximately a petabyte of data in a vial the size of your pinkie finger
 
That sounds extremely impractical. Has anyone done it?
Oh well, yes, living things have done this amazingly well.
That's a good point.
 
people have stored info on DNA and computed on chemicals, yes
 
10:24 PM
It's not programmable though... yet.
Is it?
 
for example, someone solved a version of the traveling salesman problem using molecular computing
 
@heather that sounds remarkably like a biological brain
 
@DanielSank - well, I guess I don't quite know.
 
(hence programmable)
 
I think yes? @DanielSank
 
10:25 PM
@DanielSank Weren't you one of the authors on a paper a few years ago entitled "Implementing the Quantum von Neumann Architecture with Superconducting Circuits" where you demonstrated "a quantum central processing unit that exchanges data with a quantum random-access memory integrated on a chip"?
 
but anyway, I was reading this paper recently
 
@EmilioPisanty Ehhhhh, programmable? Kiiiiind of.
 
well, currently.
 
@Mithrandir24601 Link?
 
called reachability problems for continuous chemical reaction networks
 
10:25 PM
Oh Matteo's paper?
 
@DanielSank you can tell people "follow this algorithm" and have them follow a pre-set run of operations
 
and the paper has come up with an algorithm that runs in polynomial time
 
(if you're nice enough and you pay them a salary for it, of course)
 
@EmilioPisanty Programmable to me means "No solve this problem".
 
10:26 PM
that checks if there is a path between a state c and a state d, and if there is one, produces one possible path
 
You can train a biological brain, but I wouldn't say you can "program" it.
 
(the path, of course, being in terms of reactions)
 
I mean, that's what "computer" meant before the late 1950s
 
so i'm reading and trying to understand that.
 
@DanielSank you can load programs on it
 
10:27 PM
@EmilioPisanty That's a cute point.
 
@DanielSank, well, couldn't you cause certain reactions to happen?
 
and have it execute them
 
@EmilioPisanty Not... really.
 
@DanielSank no, seriously
 
@EmilioPisanty ehhhhhhhhhh
 
10:27 PM
you haven't seen Hidden Figures?
 
I'm not comfortable calling that "programmable".
 
Hidden Figures is a great movie
 
@EmilioPisanty Yes I have, and I know that the word predate's electronic computers.
 
The term "computer", in use from the early 17th century (the first known written reference dates from 1613), meant "one who computes": a person performing mathematical calculations, before electronic computers became commercially available. "The human computer is supposed to be following fixed rules; he has no authority to deviate from them in any detail." Teams of people were frequently used to undertake long and often tedious calculations; the work was divided so that this could be done in parallel. Since the end of the 20th century, the term "human computer" has also been applied to individuals...
 
Yes yes I know.
I object to the term "programmable".
 
10:28 PM
@DanielSank science.sciencemag.org/content/334/6052/61 I get what you're saying that 'logic operations happen on the memory' (to paraphrase), but it's not like you're not able to have any separate memory, surely?
 
@DanielSank how is what a human computer does any different to loading a program on a general-purpose electronic computer?
 
@DanielSank to make this overly meta, wouldn't you call someone teaching me something "programming" me?
 
Humans computers are buggy af
 
(sort of)
 
Worse than those dreaded PDP-8's
 
10:28 PM
@Mithrandir24601 Yeah that was Matteo's paper. I do not necessarily agree with all decisions made with respect to title or tone of the discussion.
 
(it was 2 years ago since I read this, so I've actually forgotten most of it and might be completely misremembering things)
 
@BernardoMeurer especially this one =P
 
I stand behind the science, of course.
 
@DanielSank "do not necessarily agree" ftw?
 
there's a professor at Iowa State University that has a lab that researches molecular programming
which is kinda cool.
 
10:29 PM
@EmilioPisanty On an electronic computer, I can write a program to do a specific task, and it gets done. Humans can't do this in the same way. There's no input format I can give a human and be guaranteed that they do the required task immediately and without error.
You can train humans, like you can train neural nets. Not an accident.
 
@DanielSank Fair enough, I suppose. It was interesting to read about though
 
@DanielSank you can't exactly guarantee it always works for a computer either
 
oye veh
You guys... ;-)
 
hey, you're making these arguments, i'll argue right back =P
 
@DanielSank there's no input format you can give an electronic computer and be guaranteed that they do the required task immediately and without error.
 
10:30 PM
@heather In any reasonable architecture you can, for all practical meanings of the word, guarantee it will work
 
there's always some give and take on standards
 
The following question was marked as duplicate, but that isn't a real duplicated question, so I would foster a moderator to remove that (e.g. @DavidZ)
7
Q: Why don't we consider jerk in physics classes?

Devian DoverWhen i got more into physics, i started asking myself if just like acceleration represents the growth of speed, something else could also represent the growth of acceleration itself. And it came that is exists and is called "jerk". Before i thought about this, i thought that acceleration was the ...

 
but once those are agreed
 
not really - edge cases and such
 
@EmilioPisanty Input NULL :^)
 
10:31 PM
@BernardoMeurer I write C code. Computer does what I want.
 
or poor programming
or running out of memory or something
brb
 
Surely you see a difference between how a human learns and how a computer takes input?
 
@heather That's semantical faults, you're cheating
 
like they are for a professional human computer
 
@DanielSank She always leaves when things get interesting...
 
10:31 PM
you just agree on a standard, and use that as input format
 
@EmilioPisanty Humans don't take procedural program instructions!
 
@DanielSank they do if you pay them
 
You can't take any human and have them run your algorithm.
You have to train them.
@EmilioPisanty Are you being cute now?
 
@DanielSank so?
@DanielSank no, I'm being dead serious
I don't see the distinction
 
@DanielSank Speak for yourself
 
10:32 PM
with an EC you need to agree on standards
with a HC you need to agree on standards
same thing
 
What is this discussion even?
 
Standards... are beside the point, I think.
 
I just came in because I felt like fighting
 
@BernardoMeurer I claim that humans are programmable, finite-memory, (relatively buggy), Turing-complete machines
computationally speaking
 
Turing complete?! That's a helluva claim.
 
10:34 PM
@EmilioPisanty If the implementation is buggy then they're not Turing complete
I see your point though
 
@DanielSank not really
 
@EmilioPisanty I would not call humans programmable at all, not even computationally speaking
 
If required, you can dry run a Turing machine's workings on paper and tape
that's not an accident
 
The most accurate description of a human you gave was given in parenthesis
Humans learn, they are not programmed!
 
Most accurate description of humans: aspogijaspoaefjocjo2rc98984rnfqchasd f
 
10:37 PM
@nbro sigh
see above discussion
 
I crafted that with my elbows :^)
 
@EmilioPisanty Yours is a very risky claim, which I would bet that most of us don't really agree with without evidence.
 
I'm kinda starting to agree with you @EmilioPisanty, but I still think there's some qualitative difference.
 
hello
(again)
 
@BernardoMeurer Make sure you know about floating-pointing arithmetic and related problems...
 
10:43 PM
@DanielSank so... elaborate on what the qualitative difference?
 
consider also that computers are beginning to operate more and more like humans.
 
Rytsas @heather
 
@Mithrandir24601 rytsas
 
That's the first time anyone has actually said that back - thanks :)
 
@nbro What about it? The IEEE standard for floating point arithmetic works OK?
 
10:44 PM
@nbro I don't really see why this is controversial. Turing machines were modelled on humans. Of course humans can perform Turing-complete calculations.
with the only limitation being size and memory
same as any other physical implementation
 
@BernardoMeurer Take a course online or read a book about computational science... any serious programmer needs to know about roundoff errors, and things like that.
 
@nbro I do know about roundoff errors and the problems associated with floating point. Heck I implemented a floating point ALU in VHDL; my point was that it's an issue with how we implement floating point, not a fault inherent to computers
 
But it isn't the easiest subject as you delve into the details/advanced topics.
 
Well, not how we implement it, but the whole idea of a floating point
and perhaps not an issue but a quirk
 
@nbro It's not clear to me that it isn't a duplicate. Both questions are asking why we don't generally consider third and higher derivatives in physics. (Besides, five people voted to mark that question as a duplicate; even if I did think it wasn't, I would be somewhat hesitant to undo their decision on my own.) Maybe you could make a meta post arguing for its reopening, to get the community's eyes on it.
 
@DavidZ Two perspectives make them not duplicate, in my opinion.
 
This is how I learned floating point
 
@nbro Asking the same thing makes them duplicates, in my opinion.
 
Woah, a true clash of minds here
 
I mean, different perspectives isn't enough.
 
10:50 PM
@BernardoMeurer No, it's also inherent to computers, no matter how much memory you put into them.
@DavidZ How can you consider "Why is the Lagrangian a function of the position and velocity (possibly also of time) and why are dependences on higher order derivatives (acceleration, jerk,...) excluded?" a duplicate of "why isn't jerk widely used/taught in physics"?
 
@nbro How about you don't use floating point
Use GMP
or OpenMP
 
lol
 
@nbro I don't think this is a productive way to start a discussion about it. I really think it's better if you make a meta post, if you feel strongly about it.
 
No, I don't want to bring this further... I just thought I was helping, but, apparently, I'm seeing dead birds flying
(bring this further?) maybe not the best expression for the purpose, or is it?
 
Hello, I have only learnt high-school physics but would like to understand how Earnshaw's theorem makes passive magnetic bearings (bearings that use magnetic levitation from permanent, inactive, magnets) impractical? Any places I could do this or would anyone be kind enough the explain the gist?
 
11:03 PM
@Monad You could probably ask that on the main site. Some people may answer in a way that's above your level, but perhaps some others will explain in a way that makes sense to you.
 
Should I insist for a simplified answer?
 
"insist", no, but do state your level.
 
@doublefelix sorry I missed your message :(
 
okay, albeit, having narrowed down on statements such as "[It is] not possible, to stabilized all degrees of freedom of a body by passive magnetic levitation, alone", would the question not be too specific?
 
@CRDrost no prob :)
I still have time if you do
 
11:08 PM
Interesting project.
 
@doublefelix sure. so you're totally right to identify vectors and covectors; there's a bijection there between them.
But it is important to define what this \hat e_i and \hat e^i are, and how you're relating them to each other.
 
@DavidZ In any case, I will try asking and thank you.
 
@AccidentalFourierTransform Jeez, 11 downvotes, 13 upvotes
 
the bijection here is that given an inner product $\cdot$ then covectors are just linear maps from vectors to scalars, so each vector \vec v defines some covector as (\vec v \cdot), if that helps.
 
11:16 PM
In my mind, I have the following scheme for defining the vector and covector bases: define the \hat e_i as $\partial_\mu$, then define a metric using $g_{\mu \nu} = e_{\mu} \cdot e_{\nu}$. In euclidean space this was not an issue, as any basis vectors could be expanded in another orthonormal basis and then the regular dot product could be used. Then use that metric to "raise the index" of the e_mu. You'll need to find the inverse of the metric to get the version with upper components
I don't know enough to say whether the fact that you work on the tangent plane lets you work as if you're in euclidean space in this example
 
So I found Geroch's paper on the spacetime example that is geodesically complete but still has singularities
I think it's the worst spacetime I've ever seen
It is literally made if an infinite stack of spacetime
 
Are you assuming g_{\mu\nu} is given to you and using it to define \cdot in that expression? Because if so that makes some sense.
It probably falters a bit in that it now requires you to know what $\partial_\mu$ is which will suck when you try to transfer to general relativity, but if you're just in special relativity then you can use the fields w=ct, x, y, z as coordinates and they cover the whole space and you can use \partial_w, \partial_x, \partial_y, \partial_z as basis covectors.
 
I was wondering about that \cdot... in the embedded case where I can define the basis vectors as \frac{dr}{dx^\mu}, it can just be the usual dot product (sum of squares of the components, with a minus sign if working in SR). But here I'm not sure how to form a dot product out of just partial derivatives
 
@Monad if you're quoting from somewhere specific, always cite the source
 
Well yeah, that's basically the problem you're going to face. Really \partial_\mu is an operator which turns a scalar field into a covector, because it operates on a vector field to produce a scalar.
 
11:26 PM
@Monad Otherwise, your question is OK as is
 
The way that it operates on that vector field is by first obtaining that vector field's directional derivative \vec v \cdot \nabla, and then applying that on the scalar field to get a new scalar field.
 
@EmilioPisanty you mean the one I just posted?
 
@Monad yes
 
ok, thanks.
I just edited btw and cited.
 
So then, how does one construct the metric in the embedded case?
oops, in the non-embedded case
 
11:32 PM
well, you'll see geometry-minded people start with the scalar fields, define vector fields as derivations on those scalar fields, then define covector and tangent fields from the vector fields, and finally identify a [0, 2]-tensor as the metric tensor, where it serves also as a canonical way to raise and lower indices.
so the definition of the partial derivative operator literally is just what I said above, in Haskell you might write grad scalar = \vector -> vector(scalar) since a vector field maps scalar fields to scalar fields anyway.
Geometry-minded people don't like the fact that things have these components, you see, with their complicated transformation rules... so those come in later, you say "also in any neighborhood of a point you can define some scalar fields which work as coordinates; any other scalar field is a smooth function applied pointwise to these coordinate fields."
@doublefelix just in case I get torn away from the screen by other responsibilities, I gave sort of an overview of what this background looks like at physics.stackexchange.com/questions/312703/… .
 
thanks. I am going to work through the site and/or some book. I was thinking of using Nakahara, since I want to see somewhat from a physics perspective, but maybe something less "quick and dirty" would be better.
 
@doublefelix one thing that might help before you get into relativity too is to focus on the solid-state side of the picture.
Usually you've got tensors like a stress or conductivity tensor that in some crystal work out to be really simple along some principal axes.
You might think, "why don't I just choose my basis vectors to lie along those axes?" and the only thing that's stopping you is, those axes are not orthogonal.
So then you can think "well I will just define a dual basis to my normal $\hat e_i$ which is that the dual vector $\hat e^i$ satisfies $\hat e^a \cdot \hat e_b = \delta^a_b$ with the usual Kronecker $\delta$."
Then any vector has two sets of coordinates which describe it, the $v^i$ in the normal basis and the $v_i$ in the dual basis, and this restores your simple formula that $\vec u \cdot \vec v = \sum_i u_i v^i = \sum_i u^i v_i,$ but only if you pair the dual coordinates from one with the normal coordinates of the other, or vice versa.
 
I feel that I have a pretty good understanding of how things work in embedded geometry. I see how a dual basis arises, I know where the christoffel symbols come from, I can describe curvature and all that. It feels just like an extension of basic vector calculus. What's been baffling me is how much more I need to learn to speak in the language that people use in differential geometry
(of non-embedded manifolds)
 
11:48 PM
Cool.
I mean, I think there's a lot of that.
If you're embedded in a bigger space then you know that you can take for granted "hey, I've got these unit vectors." When you're not embedded in a bigger space there's much more of a push for "uh, ANY numbers that can be different in a neighborhood of points need to be 'good enough' because we don't necessarily know some nice choices up-front."
 
@doublefelix Yep, I felt exactly the same about the language used doing differential geometry
 
I think the definition of \partial_\mu is somewhat natural because it comes almost directly from the embedded basis vectors \frac{dr}{dx^\mu}. Having dx^\mu be a basis for the cotangent space as opposed to \partial^\mu is where I am stuck at the moment
of course I still have to get used to the operator properties of the vector basis but it seems like a very reasonable extension
Does the reason for not using \partial^\mu as a basis for the cotan space have to do with the difficulty of constructing a metric that you could use to "raise" the index of \partial_\mu?
(without first defining a basis for the cotan space)
 
No, I mean, people raise the index of $\partial_\mu$ all the time.
 

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