12:00 AM
someone
don't know if that really counts

@danielunderwood of course it doesn't

once
I can't really think of anything that isn't strongly related to one

of course that doesn't either
@danielunderwood but you'd kinda expect a basic word like that to be usable by beginners, no?

I expect it to be the first word they learn aside from hello

(no, of course you wouldn't. the basic words are the ones that get the most use and accumulate the most wear and tear so you expect them to be the most irregular.)

12:14 AM
@EmilioPisanty Lol

Yeah I guess that makes some sense

Probably my favorite question was this
Which was edited and became this

12:36 AM
What's up with the revisions, timeline, and clock (join date?) below the name?
In other words, wow
Sometimes I think I don't quite understand something, but wow
Did I say wow?
At least it isn't as bad as searching for cern on youtube
Only do that search if you want to lose more faith in humanity

@danielunderwood A userscript, Stack Overflow Extras

Oh neato. Looks like there's a whole site for them I didn't even know about stackapps.com
And apparently the nutters just have an issue with cern. I searched black holes and quantums without finding any in the top results

2 hours later…
2:55 AM
Is it possible to do anything with the power of an integral like $(\int f(x) dx)^n$. I was thinking about the earlier conversation about functionals and thought it may be interesting to try to extremize one, but this step seems problematic. I could differentiate $n$ times then go back and integrate $n$ times, but that gets something that I have no idea how to solve and seems a bit fishy anyway.

@danielunderwood There's a famous trick for computing the area under a Gaussian that involves squaring the integral and then converting to cylindrical coordinates.

@rob That's different than the way that's taught in a typical calc class of just changing to polar coordinates, right?
And I think I may have a partial answer since I somehow forgot that you can split an integral of a sum into a sum of integrals. From what I can tell, to extremize $(\int f(x) dx)^2$, you get the condition $\int f(x) dx = 0$...which seems obvious in retrospect
Ahh I think that is the change of coordinates way I was thinking of. I just forgot squaring the integral for some reason
Although $\int f(x) dx$ seems like it may be a trivial solution and there's somehow more structure like Euler-Lagrange. hmmm

3:44 AM
@EmilioPisanty Belousov–Zhabotinsky reactions are something all chemistry students will have seen, though it takes effort to get the patterns looking as good as they do in the videos - obviously the videos have been cherry picked.