« first day (2329 days earlier)      last day (2603 days later) » 

4:00 PM
I'm not sure how the site decides who to ping. Maybe you've visited the Physics chat once too often and it now knows where you live :-)
 
@JohnRennie I think I came here once to test a bug that turned out not to be a bug
 
Welcome to the chat session everyone! If you are new to the site, new to chat, or have other questions about our site, now is the ideal time to ask.
 
$Doe$ thi$ $crew $LaTaX$?
 
@DownChristopher Oh no! You're now a marked man! :-)
 
@EmilioPisanty lame
 
4:01 PM
We don't have much of an agenda today, so if you don't have something you wish to bring up, I guess we'll just chatter along as usual
 
vzn
@ACuriousMind somebody said something about an agenda earlier? is there one today?
 
Today's agenda is cake recipes
Share your best cakes
 
@vzn no-one has raised any outstanding issues
 
@JohnRennie I guess so
Anyways bye!
 
If you have interesting physics news that developed in the recent past you'd like to discuss, now's also a good time to get more than the usual regulars' input for discussing them
 
4:02 PM
howdy
 
In that case, maybe it's a good idea for folks to go over their posts and make sure that there's no non-imgur http images?
 
@EmilioPisanty Ah, yes, that's a good point
 
jlab.org/conferences/3Dmodeling/index.html conference this week. Are there really lots of quark/anti-quark mesons in a proton or are they created the the energy of crashing protons together.
 
4:05 PM
@ACuriousMind Ahhhh. I forgot the definition of closure. The closure of the unit ball of $X$ is a closed set that contains the open unit ball of $X''$ (the esimate gives that much, just choose $\epsilon$ small enough!). So that has to contain the closed unit ball in $X''$ by definition of closure. However, the closure of the ball in $X$ $\subset$ closed unit ball in $X''$ since it's an isometric embedding. So they must be equal.
 
So anyway
 
This is my favorite cake recipe
it is fairly simple and good
 
@EmilioPisanty I get no results on physics, is there something to adjust in that query?
 
4:06 PM
@ACuriousMind I'm looking into it
Its behaviour has changed since I last used it
 
@AnimatedPhysics particles are a surprisingly elusive concept in quantum field theory. It can be very hard to point to anything specific and say look there's a particle.
 
@0celo7 Why are you telling me that? :P
 
@ACuriousMind Because you like functional analysis
 
@AnimatedPhysics So askign how many particles there are ina proton is a surprisingly ill defined question.
 
4:07 PM
that's because there's no such thing as a particle in QFT
that's why it's called a field theory
 
What I need to check is that the closed unit ball is actually closed in the wk* topology.
But since the norm topology is stronger, that might be immediate.
Or is it weaker?
 
Although I think you can find that roughly the sum of quarks and antiquarks average to 3 quarks
 
vzn
@ACuriousMind whats up with non-imgur links? missed that
 
OK, here goes
 
@vzn SE is switching to forcing https for linked images. Imgur links are updated automatically, the rest needs to be adjusted manually because they can't automatically repair arbitrary image links
 
4:09 PM
Can folks go to this query and make sure that their posts don't contain non-https images? They will stop displaying correctly.
Ideally all images should be on stack.imgur to avoid link rot
 
vzn
@ACuriousMind strange/ seems weird, wonder why, did they announce this somewhere?
 
At the conference they had a very nice history of the proton. In the 70's we had 3 quarks and some gluons, now we have 3 quarks and an indetermined (variable, unknown?) number of gluons and mesons.
 
@vzn This post is still featured and contains the roadmap. The thing about forcing https images is linked in one of the steps.
 
Oh you have way more than 3 quarks
It's just that you have $\sum q - \sum \bar q = 3$
 
4:12 PM
@Slereah what?
the number of quarks and antiquarks should be the same, no?
 
In a proton?
No
 
oh
 
@AnimatedPhysics I never really understood why people are so adamant about there being "sea quarks" or "sea gluons". They arise from the same faulty interpretation of Feynman diagrams as the silly idea of particle-antiparticle pairs "popping from the vacuum".
 
@slereah I think the number of quarks in a proton is fixed at 3.
 
4:13 PM
What is a fact is that hadrons are messy QCD bound states that are rather difficult to understand in terms of their bound constituents
 
@ACuriousMind Well you know, it's easier to compute if you think of it this way :p
 
the definition of proton is three quarks, no?
 
@AnimatedPhysics Nah, you get plenty of quark antiquark pairs
 
uud
@Slereah those are virtual though
 
They are all virtual, @0celo7
 
4:14 PM
@EmilioPisanty 580 images!!! That will keep me busy for a while ...
 
Absolutely @slereah, they are called mesons
 
They all get destroyed and created all the time
The 3 is just an average number
 
@JohnRennie @EmilioPisanty The query also returns imgur links, which don't need to be fixed
For me, it returns all 10 of my posts that contain any images at all
And all of those are imgur links
So I can't even say whether it returns non-imgur links at all
@Slereah ::twitches::
 
Well what do you want me to say instead, "It's all some kind of soliton on a hilbert space we can't divine"?
I mean rigor is nice but in QCD it doesn't lead you far
 
4:17 PM
Silly question that I'm somehow not sure about.. In the absence of a magnetic field and such, do the different states (-1, 0, 1) of a spin-1 particle have a different energy? For spin 1/2 you have that -1/2 and 1/2 have the same energy when not split by a magnetic field; I'm assuming this should also hold for spin-1 right
 
I guess you could talk about lattice QCD but I don't know anything about it
 
@Slereah It's not about rigor, it's about this silly myth that virtual particles are "particles" at all.
 
user228700
BTW, @JohnR: The site decides to ping when one has explicitly "joined the event". I, for one, didn't get pinged because I didn't RSVP.
 
@ACuriousMind well what is a particle
 
@ACuriousMind technically, perhaps, but it's a very useful way of thinking about proton structure in high-energy phenomenology at least
 
4:18 PM
@user129412 Free particles don't have any spin interaction, yes
 
They only exist in a perturbative formulation - you can't even say what the hell a virtual particle is supposed to be in a non-perturbative formulation where you don't have Feynman diagrams
 
All spin orientations have the same energy
@ACuriousMind well yeah
 
If the "existence" of a physical object depends on you using a particular approximation method, it's not a meaningful physical object to begin with
 
@Slereah Picture from the conference, 3 quarks, a bunch of gluons and a bunch of mesons (quark/ant-quark pairs)
 
@Kaumudi.H and yet the chap who was wondering why he got pinged had not explicitly joined the event ...
 
4:20 PM
@DavidZ I think it's fine when experts use such phrasings as long as they're clear about the actual meaning, but I really think it's rather misleading to present this interpretation to laymen without a host of qualifiers
 
Eh in the end the layman doesn't need to understand it nor has the mean to
(here is me being an elitist)
 
@EmilioPisanty the query gives me a big list of imges with no indication as to whether they are on imgur or not.
 
@ACuriousMind Yeah, that's fair
 
user228700
@JohnRennie Huh. I see...
 
what would be the rigorous description
I guess the conserved isospin charge of the proton bound state?
 
4:22 PM
@yuggib Are you here?
 
@Kaumudi.H Over the years we've had other people say they've been pinged apparently for no reason. I wouldn't be surprised to learn the SE software is a bit buggy in this respect.
 
@yuggib Yosida Corollary 3, p. 114 doesn't make much sense to me without a proof. My proof seems to be pretty convoluted.
 
0
Q: Implementing Miller-Rabin in C

Bernardo MeurerI'm trying to implement the Miller-Rabin primality test in C99, but I'm coming across some problems getting it to work. I crafted a small test-set to verify whether or not the implementation works, here's how I'm checking for primes int main() { int foo[11] = {0, 1, 2, 3, 4, 7, 28, 73, 125,...

 
@JohnRennie I think the algorithm randomly decides to ping people who've been here at some point in the last few days and are currently in another chat
 
hello specail event
 
4:23 PM
If anyone knows C or Miller-Rabin :P
 
vzn
@ACuriousMind it would be nice to see an entire paper/ study/ survey on the concept of "virtual particles" by leading authority/ expert... there have been some major debates in here/ on site wrt topic (some wrt a "gadfly"/ "black sheep" member)... has caused a lot of thought/ consternation maybe even among experts...
 
@vzn There are probably several out there already. Certainly it's addressed in most QFT books, at least.
 
@BernardoMeurer OK remind me which #include the rand function is in
 
@yuggib I'm not sure why the weak* closure of the ball of $X$ should be contained in the ball of $(X_s')_s'$. Conway says it's obvious. The topology is not first countable so I'm not sure if I can use sequences
 
is it obvious
 
4:29 PM
Oh, random note since I'm here: I'm in the midst of a very busy few weeks IRL, so I'll be scarce on the site for a little while
just in case anyone notices and wonders about it
 
@yuggib But I do think that closure = set + limits regardless of the countability. So I need to show that a weak* limit of elements of ball $X$ remains in ball $X''$?
But that's probably easy using the simple convergence definition of the weak* topology + the definition of the embedding $X\hookrightarrow X''$
A sequence in ball $X$ gives rise to a sequence of operators on $X'$ with norms $\le 1$. It doesn't make sense that these could converge outside of the unit ball in $X''$ in any topology.
But maybe I need to check that. I don't know.
 
I guess the proof of the boundedness of the causal diamond in Minkowski space would just be like
 
@JohnRennie yeah, I've seen it, working on it
 
Show that everything is within the bounds of an area delimited by the coordinates of $p$, $q$, the past cone of $q$ at $p$ and the future cone of $p$ at $q$
 
4:43 PM
@ACuriousMind It's curious that they haven't rewritten all the stack.imgur links here
 
So just take the min and max of all those and it should be a cube large enough to encompass everything
 
@EmilioPisanty I noticed that, but the http ones seem to still work fine
It's odd
Maybe we're the last site to get any update, now :P
 
Like the $t$ coordinate is $t \in [\phi(p)_t, \phi(q)_t]$
while the $\vec x$ will be bounded by the limits of the lightcone on the Cauchy surface of $p$ and $q$
 
@0celo7 you should use the bipolar theorem
the bipolar of a set is the closure (in the weak*-topology) of the convex hull of the original set
and you can easily see that in Banach spaces the polar of a ball centred in zero is the ball with inverse radius
(as you can imagine, you can find the definition of a polar, and the bipolar theorem in Bourbaki's TVS)
 
@yuggib I'm sure there are other ways of doing it, but I'd like to understand the comment in Conway and what Yosida is doing
Why is it clear that the closure of the X ball is contained in the X" ball?
Closure in the weak* topology
 
4:55 PM
you are taking the continuous dual of $X$ with respect to which topology? The Banach norm topology (supposing it is Banach) ?
 
I think Conway talks about polars
 
And then, you take the dual of the dual with respect to which topology?
 
@yuggib $X$ is a Banach space, take $X'$ with the strong/norm topology
Then take $X''$ and let $b(X'')$ be the closed unit ball with the strong topology
But we give $X''$ the weak* topology when viewed as the dual of $X'$ (which still has the strong topology)
Then, embed the ball $b(X)$ into $X''$, and take its closure wrt. the weak* topology
The claim is that this closure = $b(X'')$
So, is $b(X'')$ closed in the weak* topology?
 
yes
 
I don't even need that, I just need $\overline{b(X)}\subset b(X'')$.
Conway says it's clear, but I don't see it...
 
5:04 PM
do you agree that $e(b(X))\subset b(X'')$? (where $e:X\to X''$ is the embedding)
 
That's clear since the embedding $X\to X''$ is isometric if we give $X''$ the strong topology.
 
then you just need to convince yourself that the ball is weak*-closed
 
The ball $b(X'')$?
 
yes
 
Will I need some version of Hahn-Banach?
 
5:06 PM
Hint: by Banach-Alaoglu, the ball is compact
 
I don't have Banach-Alaoglu
 
?
 
It's proved on page 137 of Yosida, I'm on 114
Hmm, when does Conway prove it
Ah, Conway does have it available.
So I think the Yosida proof should be different
I'm going to think more about this
 
probably there is also a direct proof of its closedness, but it is essentially mimicking the proof of banach-alaoglu
 
@yuggib And a compact subset of a hausdorff space is closed, I know
@yuggib Do you know the book by Brezis?
 
5:18 PM
OK, @ACuriousMind @JohnRennie It seems that there isn't really a good way to find those images
2
A: Help us fix broken images!

CaiI've written the following snippet so you can return and filter the Crowdcrafting tasks by site. It currently returns up to 100 tasks (the maximum the API allows). It looks like a lot of sites have fewer affected posts than that, there's no instant way to get further posts for the ones that do t...

that's probably the best way
but that looks tricky to modify to return posts for a single user
 
@0celo7 which one?
 
@yuggib Functional analysis, sobolev, PDE
 
Would anyone be able to help with a buoyancy question?
A balloon has an initial volume of 0.5m^3 containing air at atmospheric pressure. 2.5x10^2kg weights are attached to the balloon, the system is placed in water and floats. Assume the skin of the balloon has negligible mass and elasticity.
 
@0celo7 I have it in pdf, but I did not read it
 
The balloon is then pushed further under water until it remains in equilibrium. Find the depth under water which it must be pushed
 
5:29 PM
@yuggib I need to rewrite the proof on page 69
I think that's what Yosida has in mind
 
heheheh
$69$
 
@0celo7 it seems pretty easy
 
@yuggib did you look at page 114 of Yosida? His lemma has $||x||\le ||x''||+\epsilon$, so if $x''$ is on the boundary of $b(X'')$ then you get $||x||\le 1+\epsilon$ which is worthless
and it's $x=x(\epsilon)$ :/
 
@0celo7 no I did not look...
however in the end the important thing is that you can find a proof (even if it is not the same as in Yosida)
 
Sure
 
5:40 PM
@yuggib have you read TVS?
 
@bolbteppa yes
 
That is incredible
 
why?
it is a very neat book
and I use it in my work
 
What is TVS
 
Espaces Vectoriels Topologiques
 
5:42 PM
I want to know it
 
@bolbteppa know what?
the book?
 
Yeah
In mathematics, particularly in functional analysis, a bornological space is a type of space which, in some sense, possesses the minimum amount of structure needed to address questions of boundedness of sets and functions, in the same way that a topological space possesses the minimum amount of structure needed to address questions of continuity. Bornological spaces were first studied by Mackey. The name was coined by Bourbaki. == Bornological sets == A bornology on a set X is a collection B of subsets of X such that B covers X, i.e. X = ⋃ B ...
 
Is TVS only chapters 1-5 or are there more?
 
One of my friends is struggling in high school physics
Anyone recommend her a good book?
 
Maybe she is meant for STEAM
 
5:47 PM
:36186375 She says her teacher doesn't know physics
 
@0celo7 only 1-5
 
So...anyone have a good textbook?
 
@bolbteppa yeah that is interesting stuff
 
@SirCumference Feynman
Good for basic physics
 
5:49 PM
@Slereah High school
 
Weinberg
@SirCumference
@yuggib Springer Link has TVS then
 
You guys...
 
Not sure if I really need it
 
Feynman's physics lessons has plenty of high school level stuff
 
@Slereah I remain highly skeptical
 
5:50 PM
Then I don't know
 
vzn
@Slereah ? did you mean not meant for STEAM?
 
@Slereah Well, what book did you use in high school?
 
@vzn The joke is that @0celo7 said STEM
 
@0celo7 I know ;-) I have it in french however
 
The difference being art
send her to the humanities
 
vzn
5:51 PM
@SirCumference it will not help unless its a better textbook than the one she has, does she have trouble understanding her textbook? which one is it?
 
@SirCumference I just used whatever book was used for the class
They weren't particularly good or bad
 
serious question, how is someone who is failing high school supposed to succeed in life?
 
vzn
@Slereah lol ok that occurred to me
 
Also I don't recall their titles
 
@vzn She doesn't have a textbook
 
5:52 PM
nothing against your friend @SirCumference
 
vzn
@SirCumference lol then theres her problem right there :P
 
@vzn Yes, you have any recommendations?
 
Well, with the economy the way it is
Most people will fail, anyway
 
vzn
@SirCumference any std high school physics textbook there are many
 
Simple maths question for the panel: suppose I want to calculate $a^d mod n$, but I only have 32 bit integers so I can't let any intermediate number get larger that $2^31$. What's the easiest way to step through the calculation making sure the numbers don't get too large?
 
5:52 PM
@0celo7 She says she likes learning about the universe and she likes math, but her teacher is awful
So she's looking for a textbook
 
vzn
not sure how anyone can take a physics class without a textbook, incl high school level...
 
@vzn std? o_O
 
sexually transmitted textbook
2
 
@JohnRennie Are $a$ and $d$ integers
 
vzn
awww geez, peanut gallery ppl triggered by chat abbrevs, yeah luv it, whats new around here
 
5:54 PM
Yes, it's all integer arithmetic
 
I always abbreviate "standard deviation" as "STD" in my notes, if the professor talks ridiculously fast
Just habit
 
@JohnRennie Why would you have intermediate numbers that are larger than the starting number?
 
vzn
@SirCumference are you in HS yourself? do you have a book?
 
@vzn College
No idea what book I had
 
Is there an equality like $(a \times b) \mod n = (a \mod n \times b) \mod n$
 
5:55 PM
@Slereah ??
 
I dunno
 
vzn
struggling to remember a high school physics book name
 
Trying to think of ways
 
@ACuriousMind for example 14^9. If I just feed this into Excel it's bigger than a 32 bit integer
 
(a + b) mod n = [(a mod n) + (b mod n)] mod n.
 
5:56 PM
@JohnRennie Oh, you want to give the tuple $(a,d)$ and not $a^d$ itself as input?
 
ab mod n = [(a mod n)(b mod n)] mod n.
Those are properties yeah
 
Can I multiple 14 by 14 8 times and keep reducing intermediate values to keep them small
 
So I guess for $a^d$, just do $a*a$ d times, but do mods in between?
 
@vzn She says a good website would be nice too
 
that way you don't risk overflows
 
vzn
5:56 PM
@SirCum Halliday & Resnick is popular in colleges, not sure if it is HS level, think it might be
 
Well, then you just use that taking modulo n is a group homomotphism, so you just take $(a\mod n)^d \mod n$
 
yeah
pretty much
Although if you do that directly you also risk an overflow
 
If you fear that $(a\mod n)^d$ might be too large still, then apply mod after each multiplication by $a\mod n$.
 
I mean 2^50 mod n would overflow
 
The thing about high school physics is that a mediocre teacher can confuse everyone
She's dealing with that
 
5:58 PM
@ACuriousMind $a$ is always less than $n$
 
Even better then
Just do $((a * a) \mod n * a) \mod n * a ...$
 
^yeah, that
 
By the way, anyone want to hear an amazingly stupid joke?
 

« first day (2329 days earlier)      last day (2603 days later) »