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3:00 PM
Yeah typo
 
@b
 
@Slereah Are you sure? I thought rotational inertia depended on the fact that the point masses can't go flying off in straight lines because they are electrically bonded to each other
@0
@0
 
xD
 
Stupid keybord
 
if they were point masses why does it become $r^2$? @slereah
 
3:00 PM
@barrycarter within reason :)
@Obliv prove it
Use the formula for moment of inertia
 
@0celo7 no he's pretty dumb actually. He just recites everything from the txtbook, makes a lot of logical fallacies, lies a lot, and overall clumsy. I think it's because he's fresh.
 
@Obliv he's a prof at a university (community college?)
He's not dumb
 
@0celo7 dumb relative to profs. at any good school.
 
The moment of inertia for a point mass is $mr^2$
For instance for a pendulum
You can consider a solid object as a collection of point masses
 
Who wrote the textbook? @Obliv
 
3:03 PM
A simple pendulum @Slereah, yeah
 
@Obliv A freshman? The word 'fresh' has a different meaning.
 
@barrycarter fresh as in new.
 
THIS IS WRONG: If you rotate a mass in a circle you do m * pi * r^2 work (not sure that helps)
@Obliv Used as a compliment in the US
 
Fresh means frech to me, ask @ACuriousMind for a translation
I can't into English
 
wet-behind-the-ears amateur unseasoned would be more appropriate
 
3:05 PM
Rookie
 
@slereah What do you mean by moment of inertia then? Is it simply the rotational analogue to mass in translational motion?
 
Yes, that sounds about right.
 
Yes.
 
@slereah How come the approach to developing mass in translational motion is different from rotational?
 
$T = I\omega$
 
3:06 PM
is that angular momentum o.O?
 
I'm torqued about that
 
Torque, moment of inertia and angular speed
 
I still think there's a fundamental difference between rotational and non-rotational energy/momentum.
 
same.
 
Thingies don't normally go in circles unless you make them.
 
3:07 PM
Oh wait should be $\dot \omega$
I guess
 
Yes, change in angular momentum.
 
planets do
 
Yes, but that's because something makes them, son.
 
@barrycarter There is - one is the conserved charge associated to translations, the other to rotations.
 
well everything doesn't move in general unless you make them @barrycarter
 
3:09 PM
@Obliv Hello there, Aristoteles!
 
@Obliv But an object in motion remains in motion (straight line).
 
That^ is inertia
 
@ACuriousMind That's what I meant ha ha... you mean the charge between the particles of a solid, right?
 
you knwo what I meant
things at rest won't move unless you make them
 
Yes, but once you make them move, no force is being applied.
 
3:10 PM
this is why words fail to describe nature :(
 
For angular momentum there IS a force being applied though we ignore it.
 
@barrycarter No, I mean the Noether charge. By Noether's theorem, there is a conserved quantity associated to every continuous symmetry. Linear momentum is the one associate to the spatial translations being a symmetry, angular momentum the one associated to the rotations.
 
@ACuriousMind You used a lot of big words I don't understand, sorry.
 
@barrycarter What are you saying? angular velocity will remain constant unless a force acts upon it, no?
 
3:11 PM
@barrycarter ummm...without friction, stuff that rotates keeps rotating, e.g. a space station, once in rotation around an axis, keeps rotating.
 
@ACuriousMind @skillpatrol @Slereah and even Ocelot: are we in agreement that an object's angular momentum remains constant only because some force acts on the object, even if it's only the force that holds a solid together?
 
In that sense, there is no difference between linear and angular momentum
@barrycarter No
 
@ACuriousMind German detected.
 
In the absense of forces, angular momentum is conserved.
 
@ACuriousMind So you're saying that if the space station disintegrated, its individual particles would remain in rotational motion?
 
3:13 PM
Civilization calls him Aristotle.
 
Harris Turtle
 
h is silent
 
@0celo7 Just because you barbarians butcher Greek and Latin names doesn't mean I have to.
 
wow! shots fired
 
@ACuriousMind How do you pronounce De Broglie
 
3:14 PM
@0celo7 in Spain we say Aristoteles as well (then again, calling Spain Civilization may be too much...)
 
I don't.
 
@Slereah With great difficulty
 
lol
 
@ACuriousMind Doch, sonst machen wir uns lustig über dich
:)
 
Ich bin ein jelly doughnut.
 
3:14 PM
@barrycarter Wait, now I have confused myself.
 
@ACuriousMind "no, that could never happen"
 
@barrycarter the sum of their angular momenta is constant
 
@slereah how is rotational mass derived? You just gave me a torque equation. What do I do with that? Torque is $I\alpha$ so how would I begin the derivation?
 
if they "spin" depends on the final configuration
@Obliv $F=ma$
 
Ocelot, even if that's true, it doesn't mean the object remains rotating.
 
3:16 PM
@slereah wait would I use the definition of torque via cross product instead? $r \times F$
 
@Obliv are you on university internet right now
 
@barrycarter No, I'm not saying that. but the total angular momentum is constant. If the station disintegrates, the particles don't continue their rotation, but they still have, in total, the same angular momentum
 
yes
 
@Obliv ok, read this:
 
Torque is defined easily, so is angular speed
 
Or you can use angular momentum
 
Everything is explained in this wonderful book
 
Then moment of inertia is just $I = \frac{L}{\omega}$
 
@ACuriousMind OK, but I'm saying: while a piece of mass IS revolving around a center, some force is being exerted that prevents it from going off in a straight line.
 
It's not too hard to derive it for a point mass
 
3:17 PM
@barrycarter Yes, that is true by Newton's laws.
Stuff that doesn't move in straight lines has some sort of force acting on it
 
@ACuriousMind I was just pointing out that we normally assume our masses are connected in a rigid fashion, and ignore that part.
 
Carry on, then :)
 
It bugged me for a long time, so I like mentioning it :P
It's also why you can't break relativity with really large disks.
 
@barrycarter but can you say the same thing where a force is being exerted on a object so that it doesn't start rotating?
 
@Obliv actually
 
3:19 PM
@Obliv Umm, what do you mean? If an object's not rotating, it won't spontaneously start rotating
 
I have a legit recommendation for something to read
 
@Obliv If you apply equal and opposite torque, sure.
 
why would an object need a force to keep it from going linearly then?@barrycarter
 
I think that explains everything
 
3:19 PM
@0celo7 I was re-reading that right now. xD
and damn you were right he does mention that the addition of a time derivative to the lagrangian leaves it invariant.
 
Inertia @Obliv
 
@0celo7 what do you mean by everything
 
@3075 I think literally every physics book mentions that at some point
 
@Obliv You mean, why would you need a force to stop it?
 
@skillpatrol that doesn't.. help.. @barrycarter says that a force exists so that an object who is rotating does not stop-rotating(or start moving linearly instead?) but the same cannot be said if you flip the terms around?
 
3:21 PM
@Obliv those are basically a good set of lecture notes on mechanics that cover a lot of what you need to know from mechanics.
 
God, I hope I never said that.
I didn't say the last part about flipping terms.
 
@Obliv you need calc 3 though.
 
"a force exists so that an object who is rotating does not stop-rotating(or start moving linearly instead?)"
Oh, OK
 
@barrycarter Oh I get it. You're saying there's a rotational analogue to the concept of inertia?
 
and I also said "an object moving linearly does not need a force to keep it moving linearly", correct.
 
3:23 PM
@barrycarter I don't think a force must exist for that to happen man.
 
@Obliv Without force, masses travel in straight lines.
 
Or stays put
 
But the force in this case is the rigid force that holds solid things together.
 
@Obliv well
there's also something called the inertia tensor
 
@skillpatrol I regard a point as a limiting case of a line :)
 
3:24 PM
and the moment of inertia is the trace of it.
 
@Obliv You might want to ignore what I said earlier. I was being... pedantic.
 
something like that
 
@barrycarter a rigid force that holds solid things together is not the same as what I thought you meant. :p
 
@Obliv Yes, we normally ignore that force, although we must take it into consideration to avoid relativity paradoxes involving really big sticks or really big disks.
 
@barrycarter OH wtf. did you just mean centripetal acceleration?
 
3:26 PM
@Obliv No, that's a little different. Imagine if you spun something and it came apart completely... the various pieces would go off in straight lines.
It saddens me that Archimedes was probably sort of wrong about moving the Earth.
 
@barrycarter well how is that different? All of those pieces were undergoing 'centripetal' acceleration. Even if they were not moving in a uniform circle.
 
31 mins ago, by skill patrol
Newton's first law of inertia. @Obliv says what?
 
@Obliv Hmmm... to me, centripetal acceleration comes from the center of the orbit. In this case, the acceleration is coming from neighboring particles.
 
@0celo7 you're right I just looked though some mechanics books and they all mention that.
I missed it somehow.
 
because you skim?
 
3:28 PM
xD
that's why I fail at life.
 
@skillpatrol newton's first law states that an object's motion does not change unless a net external force is acted upon it.
 
@3075 with that attitude, yes
 
@0celo7 :'(
 
@skillpatrol I'm just saying the external force that we're both talking about is the centripetal force or whatever you want to call it.
 
Imagine you have a bunch of M&Ms on a record player.... wait, does anyone know what those are?
 
3:31 PM
yes they're chocolate
 
OK, good, and a record player?
 
yes a disc rotating about an axis in the center of it
 
LOL! Best deinfition ever!
@Obliv OK, so M&Ms on a record player. If you start the player, do the M&Ms remain on the player?
 
no
 
Why?
 
3:32 PM
I KNOW WHY
 
Think
 
@Obliv That's all I was saying. Now, if you connect the M&Ms with little sticks and make a giant M&M/wood cookie, then would they stay on?
 
holy shit
 
An ephiany?
 
@Obliv fictitious forces dude.
 
3:33 PM
it's not fictitious
 
@Obliv They're not fictious!
It's the real force of bonds between atoms/molecules.
 
centripetal acceleration is caused by a real force
 
uh...
but its the centrifugal force that moves the chocolates off the disk.
which is fictitious.
 
Yes, we've moved on to sticking the M&Ms together with little wooden sticks.
 
This is fact not fiction
 
3:35 PM
The sticks are the bonds between the particles, the M&Ms are the molecules making up the rotating object.
All hail @JohnRennie
 
It's me, large as life and twice as handsome.
 
HAIL!!
 
@JohnRennie I have concluded that simultaneity is a bookkeeping measure, and that I can find a better way to do relativity problems.
 
In the sense that any coordinate system is just a bookkeeping device I agree.
 
@JohnRennie Sure, but assigning future times to something seems silly.
 
3:37 PM
This is especially marked in GR, where students get endlessly confused about what the coordinates mean.
 
@JohnRennie Also, the v * t part of the Lorentz transform is fairly obvious. I think I could modify the transform to take that part as implicit.
 
@barrycarter time doesn't flow in relativity, it's just a dimension. Assigning a future time is no different to assigning a positive value of x.
 
@JohnRennie Yes, but that annoys me. I want time to go only forward!
 
@barrycarter time doesn't go anywhere
 
I'm starting to think like that guy we don't mention :)
@JohnRennie The arrow of time points forward.
 
3:39 PM
@barrycarter that's an artefact of the way human brains work. See:
23
Q: What is time, does it flow, and if so what defines its direction?

John RennieThis is an attempt to gather together the various questions about time that have been asked on this site and provide a single set of hopefully authoritative answers. Specifically we attempt to address issues such as: What do physicists mean by time? How does time flow? Why is there an arrow of ...

The last section in particular.
 
@barrycarter did you read the link yet?
 
@skillpatrol The one you sent?
@JohnRennie OK, let me put it this way. 1) in everyday life, do we agree that we can't go backwards in time?
 
@barrycarter yes
 
2) In relativity, you can assign things times and then assign them a lower time coordinate later. Agreed?
Agreed on point 2, @skillpatrol or were you just editing to include my name?
Remember, arrow-up does not mean repeat last message :)
 
A coordinate is just a number.
 
3:45 PM
@skillpatrol But you agree with what I said, correct?
 
which part?
 
I'm THIS close to pulling in my diagram of awesomeness that I've already pulled in twice...
That, in relativity, we can assign something a time and later assign it a lesser time, effectively saying the object's time went backwards for us?
 
Who is us?
 
>we can assign something a time and later assign it a lesser time

Eh?
 
An observer... OK, you asked for it
In the diagram above, Black assigns time 2008 to Earth, correct?
 
3:48 PM
Which observer in which reference frame?
 
In the diagram above, Black, in his 0.8 c reference frame.
 
ok, go on
 
I have a link to my git thing of awesomeness if you'd like to see the calcs, ok good.
 
No, you're throwing around the phrase assign time willy nilly. In Black's coordinate system when the Earth is at the spacetime point (0, -6) a clock on Earth that reads +12.5 years when they meet will be reading +8 years.
 
Now, if Black were to come to a screeching halt, ... ok, wait
OK, but we agree that Black assigns the coordinates x=6 and t=8 to Earth, correct?
(note that I've reverse the directions, so x is towards Earth)
 
3:51 PM
>but we agree that Black assigns the coordinates x=6 and t=8 to Earth, correct?

No, that's a meaningless statement
Black assigns the coordinates (0,6) to Earth
 
Hmmm. Would you agree that Red assigns coordinates x = 10 and t = 0 ?
 
@barrycarter Yes
 
@JohnRennie And would you agree the Lorentz transform of 0.8 c applies? (I think you actually read my argument earlier and agreed with me, but OK).
 
Or more precisely, in Red's coordinate system when Red's clock reads zero Red assigns the coordinates (0, 10) to Earth.
 
@0celo7 can I read tong or does it require some math I don't know?
 
3:53 PM
@Obliv I don't know what you do and don't know
 
@0celo7 does it require calc 3 or any abstract/linear algebra?
 
Actually, let me update. Would you agree that Red assigns coordinates x=10 for ANY value of t?
 
@Obliv Yes
 
@barrycarter Yes, when Red's clock reads t Red assigns the coordinates (t,10) to Earth
 
And may I apply the Lorentz transform for 0.8 c to get Black's coordinates?
 
3:55 PM
@0celo7 Do you think learning the math prior to the applications is better than learning the math as you apply it? I'm accustomed to the former so I don't think I can read it.
 
@Obliv Math is awesome in and of itself. Know math, know peace.
 
The Lorentz transform will tell you what point in Black's coordinates the point (t,10) maps to.
 
@JohnRennie OK, good, but it's legit to apply it, right?
 
Yes
 
@Obliv Just learn calc 3 holy shit
@barrycarter Some math.
 
3:57 PM
$\{10,t\}\to \{16.6667\, -1.33333 t,1.66667 t-13.3333\}$ is what I claim we get (x,t) order because I'm cutting/pasting from my git explanation.
 
@Obliv I like how you completely ignored what I said.
 
@3075 what did you say?
 
lol
 
Ocelot, all math is good. All math is pure.
 
@0celo7 seven stars (and counting), that's really mean. You are all of you evil bastards.
 
3:57 PM
35 mins ago, by 3075
@Obliv you need calc 3 though.
 
@JohnRennie It's scrolled off though. We need to restore it to top position.
 
@JohnRennie Oh I'll just off myself or something
It's no big deal
 
Agreed
 
@3075 oh I'm sorry I didn't see that for whatever reason.
 
Video it for YouTube
 
3:58 PM
@0celo7 I didn't star it!
 
@JohnRennie I'll stream it
 
@3075 it's not too late
 
Might as well bring some enjoyment to your lives
 
Ocelot, come up with some original last words, though.
 
@0celo7 No :(
 
3:59 PM
If it was me I'd commit suicide by creating a micro black hole. Then you'd all be joining me a little while later :-)
 

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