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6:00 PM
Alright... but if we project x onto n... then we get a value of a*b right ?
That should fit... in order to get the distance to the plane we used en.wikipedia.org/wiki/Hesse_normal_form in school... which tells us : E: ((x-a)*n)/|n| so we project our x onto n and divide it by |n|... so we would get b as a result, right ?
 
I feel like a technologically impaired old guy, but how can I get a list of all the papers published on the ArXiV in a field (let's say logic) in a specified time interval?
Oh I figured it out, the category option was well hidden in the search form
 
I hope the question is understandable... its quite hard for me translate our german lessons to english...
 
Orb
Hello is there anyone active
(?)
 
A few people are active. If you have a question, you should ask, though.
 
what if I claim that I am inactive
 
Orb
6:08 PM
I would know that you were active, then
 
That would be neither a true or a false statement
 
Orb
If someone were to respond, then I know that they are active.
Now, onto my question.
Surely all of you know how to graph n-balls in Cartesian coordinates, right>?
 
$x^2+y^2+z^2\le n^2$?
 
$\sum\limits_{i=1}^nx_i^2\leq k^2$
 
Orb
First of all, I am not fluent in MathJax.
 
6:12 PM
$\langle x,x\rangle\le n^2$?
 
@Orb There's a link in the top-right
 
Oh, Thorgott's is likely the best
 
that lets you enable it in your browser
 
Orb
Ok thanks
 
Orb
6:13 PM
Ok.
I cannot drag it to the bookmark.
Oh, well.
 
Is $Hom(N, Hom(L,K)) = Hom(Hom(N,L), K)$ ?
 
@Astyx No. However, there are some interesting, closely related canonical bijections, such as the tensor-hom adjunction.
 
Hom(N, Hom(L, K)) = Hom(N $\otimes$ L, K) is the correct thing (Karl beat me to it)
 
For a counterexample of your statement in the category of sets: meh
(in sets, you'd use the cartesian product for the left-adjoint)
oh, man, I need to fix my counterexample
 
And $Hom(Hom(N,L), K) = Hom(N, L\otimes K)$ I guess ?
 
6:22 PM
haha no
 
Why should that be true?
 
I don't know, I kinda derived it from what you wrote and hope it worked
 
@BalarkaSen sent you something elswhere
 
Is Hom(Hom(N,L), K) something nice ?
 
For a counterexample of your first statement @Astyx use a three element set for all three of them
 
6:23 PM
think of tensor as product and contemplate functions of type A -> B -> C and A x B -> C
and then you should see why that's not the same as A -> B x C
@MikeMiller long time no see
 
I'm being asked to see when N$\mapsto$ Hom(Hom(N,L), K) is left/right exact
I'm not sure how to go about that
 
@Astyx set $N = V, L = K = k$ for a field $k$ and you already have the double dual operation, which preserves finite-dimensional vector spaces but sends $k^\kappa$ to $k^{|k|^{|k|^\kappa}}$ for an infinite cardinal $\kappa$
hi soham
 
Hom(-, L) is always (contravariant) left-exact, which is right exact iff L is an injective module @Astyx
So you go through that two-fold
I hope my left is right
Yes, OK, it is
 
This I agree with, so we know that if L and K are injective we're right exact
 
That is it say, my left isn't right
3
@Astyx So you should cook up some counterexample when one of them is not injective
 
6:31 PM
ok so from the implicit function theorem we know that the principal branch of log satisfies $\mathrm{Log}'(e^w) = 1/e^w$, from the ${f^{-1}}^\prime(f(x)) = 1/f'(x)$ thing
how do we go from there to $\mathrm{Log}'(z) = 1/z$
 
exp is surjective onto C\0
the domain of principal log is contained in C\0
 
i keep thinking "so for every such z i have to find a unique w and plug it in"
 
wait just spell it out for me
exp surjects onto C\0
 
For any z in dom(Log), choose a w such that e^w = z
the "a" is what resolves your issue
No need for a unique w, just suffices to choose a single preimage by exp
 
6:37 PM
there's more than one such w but since we apply exp to it again on the rhs of the first equation i wrote it all works out
derp
 
Yup
 
do you know anything about harmonic functions or potential theory
 
very little
 
looks so mysterious
 
what, in particular?
 
6:40 PM
why real methods should have so much to do with questions of a very complex nature
 
/
 
/, kari
 
Been ages!
How's it going, @BalarkaSen and @SohamChowdhury?
 
probably likewise, i came back to this room after something like 2 or 3 years last week
 
Me too but only a few months!
 
6:41 PM
@Soham Hm, well, it's useful to understand that 2D harmonic functions are exactly the real/imaginary parts of holomorphic functions.
That's a cool little exercise which you might already have done
 
Does this mean we're Stack Alumni, @SohamChowdhury? :p
 
i just did
 
Hi @Kari
 
ahaha
i'm recovering from a really horrible burnout thing but i'm keeping my head above the water and starting to find maths fun again so yay i guess
 
Burnout brothers!
I finished at uni and had a bad supervisor so I gave up on maths for a while
 
6:43 PM
wait no i meant i just learned that theorem, @Balarka, not that i proved it
oof
 
Ah ok
 
Cauchy-Riemann equations come in very handy for that exercise/theorem
 
but i guess it's just applying C-R and hoping the algebra works out
ah i see
 
The other direction (given a harmonic function, come up with a holomorphic function with that as real part) is a little tricky
But essentially
All of these conditions are at it's core the "mean value property" - the value of the function at a point is the average of the nearby values. It's possible to prove that a continuous function satisfying this property is harmonic and vice versa.
 
that feels very "heat"-ish
 
6:48 PM
Yup
 
It reeks of PDE :p
 
like you say that and i think of those infrared images of plates from years ago looking at the wikipedia pages for fourier-stuff
 
If you heat a solid metal disk at the center and let it stabilize the temperature reading at every point is a harmonic function on the disk, I believe
 
what does the corresponding holo. function represent i wonder
 
I have a question which is bugging me
 
6:50 PM
It keeps track of the "real harmonics" and the "purely imaginary harmonics", sort of. You'll see if you do the exercise
It's the usual physics trick of complexifying a real wave I guess
 
ok i'll think about it in bed
anyone here know Miranda's riemann surfaces/algebraic curves book?
it's getting late
messages out of order ree
 
I read in a set of notes that $\text{SL}_{n}(\mathbb{K}) = \text{ker} \left( \det|_{\text{GL}_{n}(\mathbb{K})} \right)$.
 
isn't that the definition
(invertible) matrices of det 1
 
Isn't the codomain of the determinant map restricted to GLnK supposed to be $\mathbb{R}^{\times}$?
I thought the kernel was everything in the domain that maps to $0$
 
not 0, the identity
which in this case is 1
 
6:53 PM
Ahhhhh
I've lost it confirmed
 
marble-less brothers
 
Another funky way to interpret harmonicity is through probability
 
mean value property vs expected values?
that sounds ... unexpected
tss
 
Yes
 
6:56 PM
Given any continuous function $f : S^1 \to \Bbb R$, consider a Brownian motion $B_t$ starting at the origin
$\tau$ be the "first stopping time" of the Brownian motion, which is the time the particle first exits the unit disk $D^2$
 
Now we're talkin
 
dynamical systems wutface
 
Eh, I should have said $B^x_t$ is a Brownian motion starting at $x \in D^2$
 
I remember seeing the word 'harmonic' pop up in my discrete stochastic processes course like three years ago
 
I need a Brownian motion starting at every point on the disk
$\tau < \infty$ with probability 1, as for every other bounded domain, so we can forget about that measure zero event. Define $F : D^2 \to \Bbb R$, $F(x) := \Bbb E f(B^x_\tau)$
This is harmonic because of the expectation analogy you said @Soham, plus the fact that Brownian motions are Markov processes
And this construction gives an immediate solution to Dirichlet boundary value problem
 
7:00 PM
huh.
 
(Given any continuous function on the boundary, there is a harmonic function on the disk which extends it)
 
what does $B^x_\tau$ represent
 
@Rithaniel All derivatives positive when $x>0$?
 
the number of iterations by time $\tau$?
 
So you start a Brownian motion at $x$, and look at the first time this particle escapes the disk. The point on the boundary circle through which it escapes is $B_\tau^x$
 
7:02 PM
oh
 
Because $\tau$ is the time it is at the boundary
 
ok now i understand
cool
 
$B^x_t$ is really the position of the particle starting a Brownian motion at $x$, at time $t$
Right? It's amazing
 
yeah i just looked at the type of $f$ and felt silly
yeah it's quite pretty
 
Indeed, Ted. Also, yeah, thinking about it now it terms of derivatives, it makes sense that that it would necessarily go to infinity as $x\to\infty$
Also: Heya @TedShifrin
 
7:05 PM
Heya @Rithaniel :)
hi a @Balarka, @Soham
 
Hi @Ted!
 
hello, Ted
 
there's an excellent book by Greg Lawler on this harmonicity vs random walk stuff which requires 0 prerequisites in anything
 
is that where you learned all this?
 
well also from probabilists
they're swarming all over the place
 
7:07 PM
sounds neat, maybe i'll look at it sometime if i feel a probabilistic "pull"
ah right
 
probability is really nice
but probabilists are strange
especially probabilistic methods people
 
^
 
Kari, what's happenin
 
Your name has definitely changed, @ShineOnYouCrazyDiamond
Are you secretly semiclassical in disguise?
 
No
I'm BananaCats
and I'm EnjoysMath
 
7:12 PM
ASOINQEFANOQBGIPWJFOAPS;LM
 
ahh enjoysmath
rehi
 
I don't know none of these peoples.
 
It's been so long :0
 
i know enjoysmath
 
That's because you're getting old, @TedShifrin :b
 
7:13 PM
D:
be nice
 
Not getting.
 
I'm EnjoysMath commander of the coalition for the liberation of itenerant tree dwellers
 
You mailed me a pdf of your book a long time ago, @TedShifrin.
 
I never wrote a book
 
Regardless, I really enjoyed the book. Thank you <3
 
7:13 PM
@Kari what book
 
What did your name used to be?
 
Khallil --> Kari
 
English is so weird. I think about that more and more as I have to explain syntax, grammar, vocabulary to a non-native speaker.
 
What about Kali
 
Oh, right, that name I remember.
 
7:14 PM
^
 
@Kari what book?
 
One of my books, @Shine.
 
i'm slightly hurt Ted forgot me, what with how obnoxio- uh, active i used to be here back in the day :P
 
@ShineOnYouCrazyDiamond, it was the preliminary (summer 2016) version of 'DIFFERENTIAL GEOMETRY: A First Course in Curves and Surfaces'
 
@Kari wasn't me. You've got the wrong guy
 
7:15 PM
Oh, I never forgot you, Soham. You're unforgettable.
@Shine can't read.
There's a slight revision since, @Kari. You can get it by clicking on my profile.
 
Yeah, I can't read. Qed
 
It feels like a reunion today!
 
we just need both Pauls back
and Tobias the representer
 
Does Daniel Fischer still roam these parts?
 
Mike came by earlier
 
7:17 PM
i havent talked to the ggt paul in a long time
 
You only need them up to unique isomorphism
 
I miss Daniel Fischer, Pedro, anon, robjohn, and all sorts of folks who used to be regulars.
 
he was in brazil ICM iirc
 
anonnnn
 
ROBJOHN
 
7:17 PM
anon was a nice person
 
Pedro is full algebro now
 
I suppose we're not that nice
 
I wonder if anon is now in grad school. They had him teaching classes when he was an undergrad. I hope he's OK.
 
I honestly expected no less, @BalarkaSen.
 
@Balarka: My influence on Pedro was clearly insufficient.
 
7:18 PM
Pedro always used to try and tempt me to take number theory as a gateway drug.
 
Dewit
never too late
 
What do algebros do late at night
 
Investigate torsion
 
Study homomorphisms.
:D
 
We cry at being alone
 
7:20 PM
Your influence definitely got to me, @TedShifrin. I ended up studying the Atiyah-Singer Index Theorem via psuedodifferential operators and heat trace asymptotics for my dissertation.
 
hoists Free Hugs flag
 
I almost became an algebro as well :0
 
Well, I wouldn't say that was my doing, @Kari, but neat. That stuff was really big back when I was in grad school. I'm glad people are still thinking about it.
 
one of those "steal his look" memes but you steal the theming for Vakil's book instead
 
well I actually spend most of my time learning number theory, which makes me cry even harder
 
7:21 PM
upright math looks very nice
why does it make you cry
 
Whatever happened to Chris'sSis?
 
Because he's studying numbers, lol!
 
She was the #1 troll back in the day
 
number theory is soul crushing
 
chrissis goes by simply beautiful art now, i believe
shes still around
 
7:22 PM
Welp
 
at least was when i tried to return here last june
 
doesnt come to chat
 
oh, I didn't realize (s)he had become SBA. The book is published, someone announced in here.
 
lol
 
ohh
t h e b o o k
i forgot
 
7:23 PM
Wasn't it a book of integrals or something?
 
@Soham because it's hard lol
 
arcane integrals and series, yes.
 
but very rewarding
 
Or amazing Ramanujan-esque results
Yea, that's the one!
 
@ÍgjøgnumMeg interesting sequence of messages
 
7:24 PM
lmao
 
heh heh
Modular forms is cool for the completely made up results
 
Is your name secretly Gabriel, @ÍgjøgnumMeg?
 
It.. is not..
:D
 
If it were, he'd have to toot his own horn.
 
ahahaha
 
7:26 PM
such puns
much wow
 
It's all I'm good for, a @Balarka.
 
is the a french
 
I don#t understand, am I being bullied
 
yes youre an algebro
youll not understand
 
7:28 PM
i'm an algebro and i understand
don't paint us all with the same brush
you won't ever finish painting him, for one
;)
 
@ÍgjøgnumMeg: Surely you've heard of Gabriel's horn?
 
No lol
but now I have
 
I've talked about that in every calculus class (covering integrals) I've ever taught.
 
Does Martin Sleziak still frequent these parts as well?
 
The site, yes, muchly, @Kari, but not this chat.
 
7:32 PM
He was here a couple days ago, I think
 
That's wicked! I need to drop him a line at some point.
 
some people were discussing set theory in here sniffs
 
Yea, he really enjoyed set theory and linear algebra from what I recall!
 
You'll find him in the set theory chat
 
Hi @Alessandro
 
7:34 PM
Hi @Balarka
 
i placed an order for a nice rubik's cube just now
yay
 
@Alessandro 1. kf3
 
heya, demonic @Alessandro
 
or nf3 in modern notation
 
7:35 PM
interestingly enough, many years ago i went to a little class on solving rubik's cubes and asked the guy who was teaching about solving cubes in the fewest moves possible
 
learned that was a thing
and that there were wonderful things called "commutators" and "conjugation"
 
@BalarkaSen Ah, I was like 1.kf3? I don't think so
 
Wow, that must have been when you were in diapers, @Soham.
 
I still don't know how to solve one.
 
7:36 PM
well, it was a significant fraction of my life in the past, but not that big a fraction
@Kari memorise a bunch of steps, essentially
 
Can't play right now Balarka, believe it or not but I'm actually getting math done
 
i never did learn fewest-moves solving but that's actually pretty mathy
 
Lol oh well
I should get math done as well
 
@AlessandroCodenotti Should I be shocked? Any queries for me?
 
Nah I'm looking at some topology you'd probably call ugly :P
 
7:38 PM
OK. It's nice not to be needed.
 
I found a tactic while playing blind chess with someone a while ago.
 
Topology? Sounds... fundamental
Make sure your proofs don't have any... holes
 
ponders investing in a muzzle for @Kari
 
The puns!
 
"E infinity, and beyond"
there i found MO htpy theory room a new slogan
 
7:41 PM
I'm looking at productivity of ccc and Baire spaces
 
Productivity?
 
I'm a bit too dense to understand those spaces
 
cartesian closed categories? productivity like for codata?
 
Or am I not dense enough?
runs
 
Whether being ccc or Baire is preserved under products (answers: depends on set theoretic assumptions and just no)
 
7:43 PM
I've been out of the game for so long that puns are all I'm good for
 
ah nvm
 
So hard to remember games
 
purchases the muzzle
What is ccc, @Alessandro?
 
It went like e4e5, Nf3d6, Bc4Be7, O-O Nf6, Nc3Nc6, Re1 O-O
then Nd5Nxe5, exd5Nb8, d3f5
Now the tactic is Nxe5, exN5, d5-6
discovered check from bishop
 
It seems like the countable chain condition on a space, @TedShifrin
 
7:48 PM
Ah.
 
At least that's what Google tells me
 
I guess the general Tychonoff Theorem is equivalent to AOC, so ... none of this is too surprising when Alessandro is involved.
 
AOC = Zorn's lemma?
 
AOC = Axiom of Choice, silly.
 
Every collection of pairwise disjoint open sets is countable
 
7:51 PM
Oh, this sounds a lot like second countability.
 
Aren't they equivalent, @TedShifrin? (^_−)−☆
 
AOC is equivalent to Zorn's Lemma, though
 
Mwahahahaha
 
Ah, ninja'd
 
Yes, but equality?
 
7:52 PM
It's been years since I've seen 'ninja'd' used
 
Well, how do you define equality of lemma and axioms?
 
Damn, I thought I typed '≡'
 
Syntactically usually
 
You got me
 
Is "lemma" the plural of "lemma?" Or is it "lemmas?"
 
7:53 PM
lemmata
in English we ordinarily say lemmas
 
Honestly, I was about to accept lemmata
 
what is the plural of locus?
loci right?
 
lemmata is absolutely correct
yes, it should be loci
 
That one I know. Loci is the plural of locus
 
any of you taken Latin course?
 
7:54 PM
Same as focus and foci
Words are funny
 
@Rithaniel lemmings
 
はい, @Jacksoja
 
You are funny Kari
 
I took Latin in high school, yes ... 50 years ago.
shrieks and hides
 
cogito ergo sum
 
7:55 PM
Ted do you ages faster than most people ?
 
Yes, I am in my grave.
 
there is no way that it was 50 years ago
 
I prefer the old adage 'incognito por favor' @Thorgott
 
LOL
 
You look 50 years old on the series you made
 
7:55 PM
One muzzle has been insufficient for @Kari. We need multiple muzzles.
Well, @Jacksoja, that was 5 years ago.
 
@TedShifrin Yes that is my point !
 
tempora mutantur et nos mutamur in illis
 
You are not as old as you trying to convince us haha
 
So you're off by 10 years, more or less.
 
lorem ipsum dolor sit amet morbit bio
 
7:57 PM
No, I am as old as I said. I took Latin in 1966-68.
 
Wait a second.
 
Well if you say so haha
 
Has my name changed on here?
 
it will eventually
 
Age is just a number anyway
 
7:58 PM
I was just telling the truth, @Jacksoja, not feeling sorry for myself.
 
I know
 
Age might just be a function of time.
 
I thought you were exagerating
 
Might. Care to compute the correlation?
OK, lunchtime. Bye :)
 
@TedShifrin Enjoy
 

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