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Anonymous
2:00 AM
@AlexA. That's not in the tag wiki. Also there's no specified way(s) to break ties.
 
El'endia Starman
El'endia Starman
It'd be hard to get a final tally considering how many esolangs there are that ignore many/most characters.
 
Alex A.
Alex A.
@Mego Oh, okay.
 
Anonymous
@El'endiaStarman Do you know of any algebraic expression equivalent to 0 if n%2 else 1?
 
El'endia Starman
El'endia Starman
Other than n%2? Algebraic?
 
feersum
feersum
Is mod even algebraic?
 
Anonymous
2:03 AM
Alternatively, an algebraic expression for 0 if n != 0 else 1
 
Anonymous
Well, algebraic + mod
 
Anonymous
So no transcendentals preferably :P
 
feersum
feersum
0 ** n is a Python golfing trick
 
Anonymous
And abs would lead to nightmares
 
Anonymous
@feersum Ooh perfect
 
Anonymous
2:05 AM
0^(n mod 2) will get me what I want
 
feersum
feersum
If you already used mod then why wouldn't you do 1-x ?
 
Anonymous
@feersum Because I'm quartata
 
Anonymous
The best thing is, 1-n (mod 2) == 1 - (n mod 2)
 
Anonymous
happy dance
 
feersum
feersum
@Mego I don't know what kind of mod you're using there...
 
Anonymous
2:08 AM
@feersum First one is the same as (1 - n) mod 2
 
Anonymous
The notation is more common in modular arithmetic
 
Anonymous
Specifically for congruence mod some number
 
feersum
feersum
oh ok, the notation looked different for the 2 sides somehow
 
Anonymous
3 ≡ 1 (mod 2)
 
Calvin's Hobbies
Calvin's Hobbies
@Mego Keep in mind that -1 mod 2 -> -1 in Javascript and other languages, but -1 mod 2 -> 1 in Python and such.
 
feersum
feersum
2:15 AM
@Calvin'sHobbies You mean -1 remainder 2 = -1.
 
Anonymous
@Calvin'sHobbies In math, -1 mod 2 == 1
 
feersum
feersum
Unless it's OCaml where the named the remainder operator mod.
 
Calvin's Hobbies
Calvin's Hobbies
@feersum I mean the built in % operator, whatever you want to call it
 
Anonymous
I think I have a closed-form expression now
 
Calvin's Hobbies
Calvin's Hobbies
Tell us o penguin
 
Anonymous
2:23 AM
hfjhkjbjksfgbytn
 
Anonymous
This OEIS entry is stupid
 
Anonymous
a(n) = 0, a(2n) = a(n), a(2n+1) = a(n) + 2^([log2(n)]+1) is what it says. It should be a(0) = 0, a(2n) = a(n), a(2n+1) = a(n) + 2^([log2(n)]+1).
 
Anonymous
Given that correction, what is a(1)?
 
Anonymous
1 = 2(0)+1, so a(1) = a(2(0)+1) = a(0) + 2^([log2(0)]+1)
 
Anonymous
Anyone else see the issue?
 
El'endia Starman
El'endia Starman
2:26 AM
...and log2(0) is undefined....hmm.
 
Anonymous
That definition is wrong in so many ways
 
Anonymous
It's incomprehendable
 
Anonymous
Ok, screw OEIS
 
Doorknob
Doorknob
20:28 -!- ERROR Closing Link: 98.196.38.177 (Sorry, server is full - try later)
20:28 -!- Irssi: Connection lost to chat.freenode.net
Server is... full?
 
Anonymous
I'm getting my own recurrence relation, with blackjack and hookers
 
Doorknob
Doorknob
2:29 AM
How is the Freenode IRC server full? O_o
 
quartata
quartata
@Doorknob wat
 
Anonymous
@El'endiaStarman Wanna take a stab at this together? :P
 
quartata
quartata
@Mego oh shit
You did not just go there
 
Anonymous
I did
 
Anonymous
I called myself an idiot
 
quartata
quartata
2:31 AM
THERE CAN BE ONLY ONE
 
Anonymous
Idiot duel? Wait we'd just stab ourselves on accident
 
quartata
quartata
 
Anonymous
a(0) = 0, a(1) = 1, a(2n) = a(n)
 
Anonymous
I just dunno how to fill in the rest of the values
 
El'endia Starman
El'endia Starman
@Mego a(2) = a(1) = 1. In general, a(2^k) = 1.
Okay, a(3) = 3.
In fact, a(2^k-1) = 2^k-1!
 
Anonymous
2:37 AM
Is that a factorial in your equation or are you just happy to see me?
 
El'endia Starman
El'endia Starman
It doesn't matter! :D
....wait, yes it does.
 
Alien G
Alien G
If I were to star an Australian, am I really down-starring them?
 
Anonymous
It does a little
 
El'endia Starman
El'endia Starman
I am not happy to see you!
 
Anonymous
Yay!
 
Anonymous
2:38 AM
I mean
 
Anonymous
Yay¡
 
El'endia Starman
El'endia Starman
I......I dunno. I'mma stop digging this hole.
ANYWAY...
a(6) = 3 as well. a(p*2^k) = a(p).
a(5) = 5.
But that's because it's palindromic in binary.
Wait, hold on. I should be approaching this differently.
How does a(2n) relate to a(2n+1)?
Well, a(...0) ?-> a(...1)...
If we flip them, we get a(0...) ? a(1...).
0... + 2^m = 1...
For some value of m.
Specifically, m = floor(log_2(...0))+1.
 
Anonymous
a(0) = 0, a(2n) = a(n), a(2n+1) = 2^(n+1)+a(n)
 
El'endia Starman
El'endia Starman
But you have to floor it.
 
Anonymous
So in general, a(0) = 0, a(n) = (n mod 2)*2^(floor(lg(n/2)+1)) + a(floor(n/2))
 
Anonymous
2:45 AM
@El'endiaStarman floor((2n+1)/2) == n
 
El'endia Starman
El'endia Starman
You're missing the log_2.
 
Anonymous
Oh right
 
El'endia Starman
El'endia Starman
I could do this in Minkolang.
 
Anonymous
Fixed it
 
Anonymous
Does that look right to you?
 
Anonymous
2:47 AM
lg == log_2
 
El'endia Starman
El'endia Starman
Hmm. I think (1 - n mod 2) should just be (n mod 2). You only want the more complicated part when n is odd.
 
New Sandboxed Posts
New Sandboxed Posts
0
A: Sandbox for Proposed Challenges

sysreqPrettyprinted Titleboxes please read the whole post before answering! This is a prettyprinted titlebox, using unicode box-drawing characters (code points U+2550, U+2551, U+2554, U+2557, U+255A and U+255D) for the box's borders, generated with a small fair amount of Python. Everything is built f...

 
Anonymous
True
 
El'endia Starman
El'endia Starman
Edited for you.
 
Anonymous
ty
 
El'endia Starman
El'endia Starman
2:51 AM
Edited again to swap lg and floor. We want to floor after, not before.
 
Anonymous
We also want to floor before
 
Anonymous
2^floor(lg(floor(n/2)+1))
 
Anonymous
hue hue floor before rhymes
 
El'endia Starman
El'endia Starman
hmm
Will it be such a problem to not floor n/2?
Hey wait! lg(n/2)+1 = lg(n)!
 
Anonymous
Tricksy starmans
 
Alex A.
Alex A.
2:55 AM
Starmen?
 
El'endia Starman
El'endia Starman
Also, since floor(n/2) = (n - n%2)/2, lg(floor(n/2)) = lg(n - n%2)-1.
 
Anonymous
@El'endiaStarman Not true, let n=1
 
SuperJedi224
SuperJedi224
Apparently, the Burgess Meredith penguin doesn't know how bad an idea a solid gold tank is.
 
El'endia Starman
El'endia Starman
@Mego whoops, edited
 
Calvin's Hobbies
Calvin's Hobbies
What problem are you guys solving again..?
 
Anonymous
2:58 AM
11
Q: Reverse and square

orlpIn this challenge you will compute numbers from a curious sequence. Your input is a single decimal nonnegative integer. Reverse the bits in this integer and then square the number to get the required output. When reversing the bits you must not use any leading zeroes in the input. For example: ...

code-golf arithmetic sequence number-theory base-conversion
 
SuperJedi224
SuperJedi224
I'm just watching the Adam West batman tv series
It's kind of silly
 
Calvin's Hobbies
Calvin's Hobbies
@AlexA. Starmoon
 
Anonymous
I'm doing something horribly wrong with this recurrence relation
 
Anonymous
Because I keep ending up with lg(0) in a(0)
 
El'endia Starman
El'endia Starman
Err...base-case it?
 
Anonymous
3:01 AM
I mean solving the recurrence relation :P
 
El'endia Starman
El'endia Starman
oh
I'm just gonna implement it directly in Minkolang.
That'll be eligible for the bonus, I'm sure.
 
Anonymous
Well the OP specifically mentioned an algebraic solution
 
Anonymous
Oh wait he said "such as"
 
El'endia Starman
El'endia Starman
> -50% bonus if you never convert the number to/from binary.
 
Calvin's Hobbies
Calvin's Hobbies
@Mego The OrlP ;)
 
Anonymous
3:05 AM
I'm 99% certain I can't implement the recursive form in Seriously in under 14 bytes
 
SuperJedi224
SuperJedi224
...they changed the riddler
 
El'endia Starman
El'endia Starman
a(0) = 0, a(1) = 1, a(n) = (n%2)*2^(floor(lg(n - n%2))) + a(n//2)
Crap. I don't have floor. Oh well. Guess I'll have to use d1%-...
 
Anonymous
Yep, it's way too long
 
Anonymous
I've got 18 I think
 
El'endia Starman
El'endia Starman
That's quite close though.
 
Anonymous
3:08 AM
I can't do recursion well in Seriously
 
SuperJedi224
SuperJedi224
Neither Microscript nor Microscript II does it very well yet either
 
Anonymous
And my brain is too broken to work out a closed-form solution
 
SuperJedi224
SuperJedi224
I should add a feature to Microscript II for that
 
Alex A.
Alex A.
@Calvin'sHobbies Sailor Starmoon
 
Anonymous
I'll just wait until someone else figures out the closed-form and grab it :P
 
Calvin's Hobbies
Calvin's Hobbies
3:17 AM
@AlexA. Sail to the stars and moon earth
 
Geobits
Geobits
It's not often you leave for a week or so and come back to find your prayers have been answered :D
 
Alex A.
Alex A.
@Geobits Welcome back. <3
 
Calvin's Hobbies
Calvin's Hobbies
@Geoblitz >:[
 
Anonymous
@Geobits You left? I guess that explains why I haven't been getting downvotes.
 
Geobits
Geobits
It wasn't like a planned leave of absence or anything, just haven't been hanging out here over the holiday.
 
Anonymous
3:20 AM
@VoteToClose You should change your name to GoatToClose, to match @Downgoat
 
Calvin's Hobbies
Calvin's Hobbies
@Mego Oh, here, hang on
 
Anonymous
@Calvin'sHobbies ;_;
 
Geobits
Geobits
I can go back over the new Q/As if you want me to catch up :P
 
Calvin's Hobbies
Calvin's Hobbies
@Geobits Yes iff I end up with net positive rep
 
Geobits
Geobits
Hmm. I very seldom find something of yours to downvote, to be honest. You should answer more; you're too good at asking :P
 
Alex A.
Alex A.
3:24 AM
The problem is that his answers are good too
However sparse
 
Calvin's Hobbies
Calvin's Hobbies
Mine? Meh, they're ok
 
Geobits
Geobits
Ah. I don't really remember his answers much. I just know he's good at posing challenges.
Let's see... clicks profile
 
Calvin's Hobbies
Calvin's Hobbies
Questions are way easier than fussing with golfing. My last 3 were super easy to write
One more rep point and my rep will match my id number 26997 :O
 
Geobits
Geobits
It's not easy to get exactly one rep ;)
You could accept something and then downvote an answer, I guess.
 
Anonymous
I wonder how much of a correlation there is between the number of days a user has been a member of PPCG and the ratio between their rep and their user ID
 
SuperJedi224
SuperJedi224
3:29 AM
Goodnight everyone.
 
Anonymous
Or more generally, the correlation between the ID and the ratio of rep to ID
 
Anonymous
Quick someone calc it on data.SE
 
Calvin's Hobbies
Calvin's Hobbies
@Geobits Downvoting codegolf.stackexchange.com/questions/65290/… didn't seem to do anything
 
Geobits
Geobits
@Mego I'd guess the higher the ID, the lower the ratio (in general). Crunching the numbers is left as an exercise for the reader ;)
 
Alex A.
Alex A.
@Calvin'sHobbies There's no rep penalty for downvoting questions
 
Geobits
Geobits
3:31 AM
> downvote an answer
 
Calvin's Hobbies
Calvin's Hobbies
@AlexA. Woah O.O How did I not know this!
 
Alex A.
Alex A.
Uh, idk. How didn't you know that?
 
Anonymous
@AlexA. News to me, brb
 
El'endia Starman
El'endia Starman
...what is up with you high rep users not knowing basic things about the SE system?
 
Anonymous
downgoats everything
 
Anonymous
3:32 AM
@El'endiaStarman My account is barely a month old. Granted I'm not a high-rep user, but I wanted to weigh in anyway.
 
Geobits
Geobits
I'm not high-rep either, I just know things >_>
 
Anonymous
Calvin is too busy writing questions all the time to notice minutae like that
 
Alex A.
Alex A.
There's no rep penalty for the downvoter that is. The user whose question is being downvoted loses rep.
 
Anonymous
@Geobits Like who starred what? :P
 
Alex A.
Alex A.
@Geobits You're not high rep? I would say so.
 
Calvin's Hobbies
Calvin's Hobbies
3:33 AM
@El'endiaStarman Hey, you didn't know about the self-deletion no editing rules
 
Anonymous
@AlexA. No he only has 80
 
El'endia Starman
El'endia Starman
@Calvin'sHobbies That's not basic...
 
Geobits
Geobits
@AlexA. I don't know what counts for "high-rep" here, to be honest. I don't feel high-rep.
 
Anonymous
@Geobits Dennis and Martin :P
 
Alex A.
Alex A.
@Geobits You're high rep to me. <3
 
Geobits
Geobits
3:35 AM
@Mego Exactly! :D
 
Anonymous
Dennis and Martin are high-rep. The rest of us are loser peasants who grovel at their feet to have a chance to gaze upon their glorious Legendary badges.
 
Alex A.
Alex A.
Speak for yourself :P
 
Geobits
Geobits
Legendary is one badge I just know I won't ever get, so I don't gaze longingly at those. The ones that feel obtainable are the worst.
 
Calvin's Hobbies
Calvin's Hobbies
How many users are the sole owners of one type of badge?
 
Anonymous
@AlexA. Right, you don't grovel, you're just a loser :P
 
Calvin's Hobbies
Calvin's Hobbies
3:37 AM
(me! :D)
 
Anonymous
@Calvin'sHobbies You
 
Anonymous
:P
 
El'endia Starman
El'endia Starman
@Geobits 1) You're on the front page of users sorted by all-time rep, and 2) you have more than 10k. You're high rep.
 
Anonymous
Martin used to be until Dennis got Legendary
 
Alex A.
Alex A.
@Calvin'sHobbies Well, I know Martin is our only Copy Editor.
Or is close to it
 
Anonymous
3:37 AM
Martin also has the only Refiner
 
Geobits
Geobits
@El'endiaStarman Ok, #1 sounds like a pretty good qualifier. #2 uses straight numbers, so it's iffy. 10k on some sites is a lot different than 10k on others.
 
Calvin's Hobbies
Calvin's Hobbies
And refiner
 
Anonymous
Justin has Research Assistant
 
Anonymous
@Calvin'sHobbies ninjo'd
 
Anonymous
So Martin x2, Calvin, and Justin
 
Anonymous
3:38 AM
Copy Editor, Refiner, Socratic, Research Assistant
 
Calvin's Hobbies
Calvin's Hobbies
2 silver, 2 gold
 
Geobits
Geobits
Only 3 Reversals, and two of them from the same [code-trolling] Q.
 
Doorknob
Doorknob
@Geobits I like Reversal. I have 6 of em on meta.SE. :D
 
Geobits
Geobits
Stop answering bad questions then :P
 
Anonymous
sepp2k has Meta Guru, PhiNotPi has Meta Populist, Martin has Meta Strunk and White and Meta Sportsmanship
 
Anonymous
3:40 AM
So if we count Meta: Martin x3, Calvin, Justin, sepp2k, PhiNotPi
 
Geobits
Geobits
There are a few for the taking; we have several badges that haven't been awarded at all yet.
 
Anonymous
Until Martin nabs them
 
Geobits
Geobits
I think he's too far gone for Tenacious or Unsung Hero ;)
I'm not sure those will ever be given to anyone (here).
 
Doorknob
Doorknob
I'm 67/100 of the way from stealing @Calvin'sHobbies's Socratic sole-ownership-ness. :P
 
Alex A.
Alex A.
>:D
 
Anonymous
3:43 AM
Nobody has the election badges? Did the pro-tem elections not count?
 
Alex A.
Alex A.
No
 
Doorknob
Doorknob
What pro-tem elections?
 
Alex A.
Alex A.
They were informal
@Doorknob Dennis and me
 
Anonymous
Ahh
 
Calvin's Hobbies
Calvin's Hobbies
@Geobits @AlexA. @Mego The 4 of us combined are about a Dennis' worth in rep
 
Doorknob
Doorknob
3:43 AM
@AlexA. You weren't elected
You were appointed
 
Anonymous
@Calvin'sHobbies \o/
 
Doorknob
Doorknob
In technical terms, at least.
 
Alex A.
Alex A.
36 secs ago, by Alex A.
They were informal
So yeah, not in technical terms. But in spirit. :P
 
Geobits
Geobits
@Calvin'sHobbies I can't decide whether to feel elated or depressed at this. I may go with indifferent.
 
Doorknob
Doorknob
I share Inquisitive on meta with Martin, but I got it over a year ago and he just got it a few months ago. :P
 
Anonymous
3:45 AM
So really we have 4 badges that we can get, until New Years Day
 
Geobits
Geobits
@Doorknob Huh, go figure. People who were mods earlier got meta badges earlier :P
 
Calvin's Hobbies
Calvin's Hobbies
And @Geobits @AlexA. and @Mego alone are about a Calvin's Hobbie
 
Anonymous
Illuminator, Marshall, Tenacious, and Unsung Hero
 
Alex A.
Alex A.
@Doorknob Don't you have the moderation one?
 
Doorknob
Doorknob
@Calvin'sHobbies Is that the proper singular of Calvin'sHobbies?
 
Alex A.
Alex A.
3:46 AM
@Mego I'm about halfway to Marshall on SO, if that counts :P
 
Geobits
Geobits
I'd have thought a 'y' was appropriate there.
 
Doorknob
Doorknob
@AlexA. Yes, but so do all the protems, including Chris, dmckee, and gnibbler.
 
Anonymous
@AlexA. Hmm... Lemme see here... Nope. No cigar.
 
Doorknob
Doorknob
@AlexA. You don't have it yet? Pshh, slacker. :P
 
Alex A.
Alex A.
>:O
You have to be a mod for a year, right?
 
Doorknob
Doorknob
3:47 AM
Yes.
 
Alex A.
Alex A.
I've been one for like... a month? :P
 
Doorknob
Doorknob
Oh, right. 3 months actually.
 
Geobits
Geobits
That's, like, the entire lifespan of some bugs.
 
Alex A.
Alex A.
Or the memory span of goldfish, per some research
Well, I've survived a few months of pro-tem moderating, I guess I can die happy.
 
Calvin's Hobbies
Calvin's Hobbies
@Geobits Whatever sounds good
 
Anonymous
3:48 AM
@AlexA. grabs the sword
 
Geobits
Geobits
@Mego Just let him make the first cut, so he can die with dignity.
 
Calvin's Hobbies
Calvin's Hobbies
@AlexA. You survived Alexgate
 
Alex A.
Alex A.
What in the world is Alexgate?
 
Geobits
Geobits
^^ t-shirt
 
Anonymous
At least Alex, Dennis, and Martin won't have to wait long until they get their mod badges
 
Geobits
Geobits
3:50 AM
Because we're graduating soon?
 
Alex A.
Alex A.
Martin should be really soon if he doesn't already have it
 
Anonymous
Just until New Years Day
 
Calvin's Hobbies
Calvin's Hobbies
@AlexA. Don't encourage his gold medal count >:G
 
Alex A.
Alex A.
Really though, what is Alexgate?
 
Calvin's Hobbies
Calvin's Hobbies
@Geobits December 19th!
 
Geobits
Geobits
3:51 AM
No offense, but I have no idea what a >:G face is supposed to mean.
 
Doorknob
Doorknob
@AlexA. The fact that you don't know what Alexgate is. Scandalous!
(and yes, I realize that's a paradox-ish)
 
Geobits
Geobits
"How do you respond to charges that you aren't even informed about the ongoing scandal?"
 
Calvin's Hobbies
Calvin's Hobbies
@AlexA. It was just after carrotgate
 
Geobits
Geobits
Carrots makes terrible gates. Waaaay to easy to break through.
 
Alex A.
Alex A.
 
Calvin's Hobbies
Calvin's Hobbies
3:53 AM
@Geobits I do take offence :g
 
Geobits
Geobits
That one looks like a snail mouth.
 
Anonymous
How could Alex not know about Alexgate?
 
Anonymous
I've been here for barely over a month and I know about Alexgate
 
Anonymous
Oh well, maybe it's better that he doesn't know
 
Calvin's Hobbies
Calvin's Hobbies
^
 
Geobits
Geobits
3:55 AM
^
 
Anonymous
v
 
Geobits
Geobits
December 19th? Niiiiice.
 
Calvin's Hobbies
Calvin's Hobbies
dam u
 
Geobits
Geobits
Depends on the cake. If it's cheesecake, then it's true for sure.
 
Anonymous
In my headcannon, the mods actually know when PPCG will graduate, but they don't tell us because they're entertained by our guessing. It's like the Truman Show. Same with @ಠ_ಠ's identity.
 
Anonymous
3:56 AM
@Geobits Sopapilla cheesecake?
 
Geobits
Geobits
Pretty much any cheesecake.
 
El'endia Starman
El'endia Starman
0
A: Reverse and square

El'endia StarmanMinkolang 0.14, 43 - 50% = 21.5 First answer to claim the bonus! Thanks to Mego for inspiring this. n1{d1`,2$3*&$z2zd2%-2l$Md1%-;z2%*z2:{+}2;N. Test the code here and check all test cases here. Explanation This uses this recurrence relation: a(0) = 0 a(1) = 1 a(2n) = a(n) a(2n+1) = a(n) + ...

@Mego ^
 
Geobits
Geobits
@Mego They do know. They told me and swore me to secrecy.
 
Calvin's Hobbies
Calvin's Hobbies
@Geobits Code Review got their refurbish. Bracket medals and all
 
Anonymous
I have a pan of sopapilla cheesecake in my fridge right now
 
Anonymous
3:58 AM
The urge to get a slice is hard to resist
 
Alex A.
Alex A.
@Mego We do know who ಠ_ಠ is, but we can't say because it's private information. Although the speculation can be amusing.
 
Geobits
Geobits
@Calvin'sHobbies Oh, that looks pretty nice. I wasn't sure what to expect for their theme.
 
Alex A.
Alex A.
Yeah. I like it.
 
Anonymous
@AlexA. You mean "we won't say because it's me"?
 
Calvin's Hobbies
Calvin's Hobbies
Q
 
Doorknob
Doorknob
3:59 AM
@Mego It's not. :P
 
Alex A.
Alex A.
@Mego That is not what I mean
 
Geobits
Geobits
@Calvin'sHobbies The rivers in the text are an 'A' if you squint at them :P
 
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