« first day (2731 days earlier)   

12:39 AM
does anyone know where i can buy steroids for a butterfly, i need it to deploy my wsbsite
 
I dunno
 
the files are too big. i need more Bandwith. anything you know about butterflies helps.nthanks
 
Uh... they have 4 wings
 
except for that, I already knew that
means you need 4 times the restraints
 
They taste with their feet
 
W W
12:44 AM
Have you tried 2 or 3 butterflies?
maybe the solution is breadth not depth
 
@WW they dont work in parallel.
Tried it
 
W W
Moths?
 
33 secs ago, by FreezePhoenix
They taste with their feet
 
only solution is to flap faster
 
wut.
 
12:46 AM
Do your butterflies look like fuzzy worms?
 
@quartata How about keeping one butterfly at the client and sending differences via radio?
 
what is radio
 
A line of butterflies
 
oh. it would take a lot of butterflies
let me do the math
 
You're right...
 
12:47 AM
What on earth.
 
Can you add a wing to the side so they can flap like hummingbirds?
@Zacharý What? WHAT?!?!?
 
This conversation is very strange.
 
OK so I did the math
 
And? What does the math tell you?
 
It would take 7*10^16 butterflies
dont have that many. good idea though
 
12:50 AM
That is a lot of butterflies
Um... Hummingbird assists? Let the hummingbirds carry part of it?
 
how fast can a hummingbird move
 
Faster than a butterfly
Although they do need to stop often for a drink...
 
Can't you just use the butterfly effect instead of actually sending it?
 
thats what i do
 
@quartata Have you tried github? They have a lot of butterflies.
 
12:52 AM
but they dont flap fast enough for this
 
Multiple butterflies in parallel ought to work, maybe you're not sychronizing them correctly.
 
Or weebly, They also have a lot of butterflies.
 
a quick google says salt has a good affect. does anyone know what exactly salt is
 
@quartata I think it's from the ocean. I heard it also know as "snail-bane"
 
oh that. all right
we have a lot of oceans here.
ok thanks everybody. im going to research a couple things
 
12:55 AM
You're welcome!
 
if you dont here from me i probably got crushed by an ant while visiting the Oceans
 
They have a week spot in the joints of their legs - a knife there should work.
 
._.
 
@FreezePhoenix legs?
maybe we're talking about different ants
anyways later
 
@quartata Yeh. Dey got six of them
@quartata Bye!
@Zacharý ... What is it?
 
1:03 AM
@FreezePhoenix ._. this conversation.
 
What about it?
@Zacharý
Hello DJMcMayhem!
 
1:24 AM
Random conversation about butterflies ...
 
1:49 AM
@quartata I know a guy in a parking lot, how much
 
really all I need is the recipe
i can sign something not to redistribute
shipping here might be tough is all
 
NodeList.prototype[Symbol.iterator] = [][Symbol.iterator];
holy shit this line is genius
 
wait no it isn't NodeList already has a default iterator ¬_¬
 
1:53 AM
Ok... this one is funny not useful: gist.github.com/rlemon/48a08b1fb7ac288a3d0d
 
Surprise, surprise, Valve is as bad a place to work as any other game company: pcgamer.com/…
 
Goodnight
 
Disappointed but eh. It's an industry problem.
 
 
2 hours later…
4:19 AM
@Pavel joke is google doesn't like to respect standards, they want everything to be made in their proprietary way
 
4:30 AM
embrace extend extinguish etc etc
 
 
1 hour later…
5:58 AM
Funky2 is now TC, so that's nice.
 
 
4 hours later…
9:41 AM
hi all.. I have an edit distance question if anyone likes algo-chat
 
 
1 hour later…
10:46 AM
when is (-1)^p real? Is it only when p is even and at least 0?
 
ngn
11:10 AM
@Anush it doesn't need to be ≥0
 
@Anush (-1)^p has a real solution when p is an integer or the reciprocal of an odd integer.
 
11:27 AM
Thanks!
I am unconfused now :)
ok here is more coding/algo question
 
ngn
11:45 AM
@Anush ...and it doesn't need to be even, (-1)^1 = -1 is real
@Anush if p itself is assumed to be real, you can imagine exponentiation of -1 as going around the unit circle of the complex plane. When p=0, you're at (1,0). When p=1, you've travelled half a circle to the opposite point: (-1,0). When p=1/2, that's the square root, i=sqrt(-1), at (0,1). It's easy to see that you only cross the real line (x) when p is an integer.
@Adám or the reciprocal of an odd integer - that depends... you're assuming -1^(1/3) is -1 as the cubic root of -1, but there are in fact 3 different cubic roots of -1 and the one that calculus considers as -1^(1/3) is a complex one
 
@ngn I said has a real solution.
 
ngn
@Adám as I said in my comment above, that depends on the definition of -1^(1/3)
the question was "when is (-1)^p real?", so even though p=1/3 is indeed real, it's not a solution, because (-1)^p is not real (according to the calculus definition of exponentiation to a reciprocal)
 
12:15 PM
Is there a faster way to force Windows Server to install all available updates than sconfig > 6 > a > a? It takes many minutes just to check for updates (!)
 
 
1 hour later…
1:24 PM
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A: Sandbox for Proposed Challenges

Beta DecayWhere's Blackhat? code-challenge test-battery image-processing Challenge Write code which, given an image of a panel from a random xkcd comic, returns 1 if blackhat is in the comic or 0 if not. Who is Blackhat? Blackhat is the unofficial name given to the character in xkcd comics who wears a...

 

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