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5:03 PM
what about this one?
same format
0010011001001100
1 1 2
1 4 5
1 6 7
1 8 9
1 11 12
1 13 14
1 15 16
3 1 6
3 7 13
4 3 10
7 1 16
 
ah
Pyth does give 11 for that one
and so does your answer aditsu
guess that is a legit 11
 
See GitHub's help center, and the following silent movie:
 
<nothing follows>
 
Uploading that one takes time...
So, nothing follows.
 
5:09 PM
def runs(s):
    runs = []
    for p in range(1, len(s) // 2 + 1):
        i = 0
        while i + p < len(s):
            if s[i] == s[i + p]:
                j = i
                while j + p < len(s) and s[j] == s[j + p]:
                    j += 1
                if p <= (j + p - i)//2 and (i, j+p) not in runs:
                    runs.append((i, j+p))
                    i = j - 1
            i += 1
    return runs
@Lembik pretty sure that's correct
 
Oh cool, you got the runs.
 
the loops could be simplified with some logic
 
@orlp nice!
@orlp you should post an answer :)
 
it's O(n^2) though
 
@orlp well it's a start :)
 
5:11 PM
@Lembik it's not golfed
 
oh.. which question are you answering?
the one we are talking about is code-challenge (not golf) question
 
this one is for simply getting the number of runs in a single string
 
It would be great to have it online to inspire other people who find the question confusing
 
heya guys, what are you up to?
what is usually being discussed in this chatroom
 
nonsense and my challenge :)
 
5:14 PM
wheres your challenge!
 
Well today people were actually talking about programming
 
thats quite a difficult challenge
 
5:29 PM
> ".Trash-1000" can't be put in the trash. Do you want to delete it immediately?
 
That would be an interesting topological exercise
 
@Geobits HE HAS LEARNED WELL
@Mɪɴɪʙɪᴛs Cᴏɴɢʀᴀᴛs!
 
5:46 PM
Small caps are a travesty to mankind. I don't even like them for problems
I just do all uppercase like PRIMALITY
 
"I don't know what travesty means, but whatever it is, it's not. must resist posting the disapproval face"
 
@EᴀsᴛᴇʀʟʏIʀᴋ I thought you valued golfiness. Your name is 24 bytes
trav·es·ty
ˈtravəstē/
noun
1.
a false, absurd, or distorted representation of something.
"the absurdly lenient sentence is a travesty of justice"
synonyms: perversion of, distortion of, corruption of, misrepresentation of, poor imitation of, poor substitute for, mockery of, parody of, caricature of; More
I mean nevermind the fact that they literally don't render on anything
They're also ugly and cause kerning problems
 
im trying to extract the string between two [] using regex but i can only get the end ] to be conditional.

anyone got some advice?
http://regexstorm.net/tester?p=(.*%3f)(%5c%5d%7c%24)&i=%5b1%2c2%2c3%2c4%5d%0d%0a5%2c6%2c7
 
\[(.*?)\]
 
Will there ever be nested []?
 
5:53 PM
he comes
 
If there's nested [] you'll need balancing groups of some sort
 
^ Or recursion or whatever
 
no nested [] from what i can see right now
 
Then \[(.*?)\] is fine
 
but that requires the first bracket to exist
 
5:54 PM
Um, yes?
 
o.o
 
i want it to extract between the 2 brackets. or form the beginning of the string if the first bracket doesnt exist and from the end second bracket doesnt exist
 
Do you want to match either the whole string or the string except for [] at the beginning and the end?
 
sample input/output requested
 
Why not just ^[^\[\]]*$
 
5:56 PM
yea. but both brackets dont have to necessarily be gone. only 1 could be there
[1,2,3,4]
[9,8,7,6
5,6,7
[4,5,6,7
all of these should match with or without the brackets
 
Are they all going to be lists of numbers like that?
 
no. arbitrary strings
i cant match by their value
 
This feels like it might be an XY problem, what are you actually trying to parse?
 
@downrep_nation If the elements are arbitrary strings regex is the wrong tool
use a parser
 
get the string between the first occurance and or the second occurance of 2 other strings
but regex can work with conditionals
 
5:59 PM
@quartata Not using a special encoding like the one I have on my computer? :D
 
What if you have ["[","1]","asdf"]
 
@quartata true, but I don't care
 
@EᴀsᴛᴇʀʟʏIʀᴋ You can't change the encoding SE uses
 
Maybe (^|.*\[)(.*?)(]|.*$) would work?
 
@quartata anything must refer to outdated computers/OSes, correct?
@downrep_nation ded link
 
6:00 PM
@EᴀsᴛᴇʀʟʏIʀᴋ No, I really meant anything but ok
 
I'm a bit rusty on regex
 
im super rusty.
 
@BusinessCat Regex isn't the right tool here
 
@quartata I mean, most modern computers shouldn't have problems.
 
It ruins searchability if nothing else.
But yes, it also looks bad.
 
6:02 PM
\[*(.+)\]*?
 
regexstorm.net/tester?p=(.*)&i=ignore%5banystring%5dignore%0d%0aignore%5b‌​formthestart%0d%0atotheend%5dignoreignore%0d%0aallofit%0d%0a
 
^ Your links are breaking because of the bracket characters FYI
 
@downrep_nation does \[*(.+)\]* work?
 
not for me
 
6:03 PM
3 mins ago, by quartata
What if you have ["[","1]","asdf"]
 
9 mins ago, by downrep_nation
no nested [] from what i can see right now
@downrep_nation can I see all the test cases?
 
6 mins ago, by downrep_nation
no. arbitrary strings
6 mins ago, by downrep_nation
i cant match by their value
 
regexstorm.net/tester?p=(.*)&i=ignoreZanystringZignore%0d%0aignoreZformth‌​estart%0d%0atotheendZignoreignore%0d%0aallofit%0d%0a&o=s
does this work?
 
Like I said, if that's what he meant regex is the WRONG tool
 
should i use a shortnerer?
 
6:04 PM
@downrep_nation What is this for exactly?
 
quartata i would accept that, im just trying different methods
 
No, I think you need to use a URL escaper, but I also agree with quartata, I think you are using the wrong tool here
 
i actually came to work on this problem form this codegolf.stackexchange.com/questions/84332/…
but i needed a solution to this nontheless since it continued to bother me i couldnt make a regex query for it
i eventually made it match numbers etc in this challange
 
@HelkaHomba lavers
 
6:07 PM
There wouldn't be any missing []'s in the input for that challenge though
 
yes there would. if a number isnt a bag
 
Oh, true
 
http://regexstorm.net/tester?p=(.*)&i=ignore[anystring]ignore
ignore[formthestart
totheend[ignoreignore
allofit
&o=s
still breaks
if you copy this into your browser it will work tho
 
@orlp do you mind if I use your code to give some more answers in my question?
 
@Zgarb Just pulled it.
 
6:17 PM
@Lembik no
 
thanks
 
@Katenkyo thanks :D
 
@orlp question updated with your lovely answers
the question is looking much better now :)
 
where did you get those optimals?
 
your code
 
6:25 PM
I never posted code that found optimals
 
I just iterated over all the strings and ran your runs function on each
brute force
it starts to get slow at n = 22
 
@Lembik how is 00000 2 runs?
there's one with period 1, doing all 5
but the one with period 2 would have an overlapping period
 
Can someone give me an integer 𝑛 > 1 such that 𝑛² ≡ 5 (mod 6)?
(or prove that there is no such 𝑛)
Wait nvm
 
6:42 PM
none within the first 100000000 squares
 
@CᴏɴᴏʀO'Bʀɪᴇɴ Mathematica says there's none at all
 
a whole lot of numbers that are 5 mod 6 are prime ._.
about 51% of the first 166 numbers like that are prime ._.
 
@LegionMammal978 wolfram alpha agrees
 
@orlp bug!
 
But could you have integer 𝑛, 𝑘 with 𝑛 > 1 such that 12𝑛³ + 12𝑛² + 1 = 36𝑘² + 60𝑘 + 25?
 
6:47 PM
@Lembik I suggest you remove those numbers for now.
 
@orlp your code gives 00000 [(0, 5), (1, 5)]
 
@LegionMammal978 n = 1, k = 0
 
> with 𝑛 > 1
 
oh
I read as >=
 
𝑛 = 1 is the trivial case
 
@orlp ok so your code is a little buggy it seems
 
@Lembik I know what this issue is
 
@orlp cool
 
def runs(s):
    runs = []
    for p in range(1, len(s) // 2 + 1):
        i = 0
        while i + p < len(s):
            if s[i] == s[i + p]:
                j = i
                while j + p < len(s) and s[j] == s[j + p]:
                    j += 1
                if p <= (j + p - i)//2 and (i, j+p) not in runs and not (i > 0 and s[i-1] == s[i]):
                    runs.append((i, j+p))
                    i = j - 1
            i += 1
    return runs
that fixes this issue
but not sure if there's other issues
 
@CᴏɴᴏʀO'Bʀɪᴇɴ Because such an 𝑛 > 1 would be the least non-trivial order-5 cannonball number according to the challenge:
 
6:53 PM
@LegionMammal978 None within the first 10000000 possible values for both equations
 
-1
Q: Cannonball Conundrum

DerpfacePythonLifted too many cannonballs, too tired to write a backstory. - DerpfacePython Your task is to, with an input number n, find the second-smallest cannonball number of order n. Definition A cannonball number (of order n) is a number which is both: An n-gonal number (e.g. square number, pentagon...

 
@LegionMammal978 5 is a quadratic non-residue modulo 6. To verify that, it's sufficient to test the squares of 0, ..., 5.
 
this is why I love J, it's so easy to do these types of things
 
@Dennis That was a mistake
 
6:55 PM
   nc
3 : '(12*y^3)+(12*y^2)+1'
   has
#@[ ~: #@-.
   kc
3 : '(36*y^2)+(60*y)+25'
   (nc has kc)>:i.10000000
0
 
But yeah, I can say with certainty that such an 𝑛 > 2^16 = 65 536
 
@orlp so it seems you can get to about n = 26 with the naive approach
although it is tempting to just copy the prefix from the previous optimum and carry on from there in a sort of greedy approach
that's how I would try to answer this challenge right now :)
hmm.. greedy
 
7:47 PM
wolfram alpha says that no solutions exist for 3 mod 4, 5 mod 6, or 7 mod 8
 
conjecture: no solutions exist for (n) mod (n+1) for n > 2
 
Solutions to what?
 
@CᴏɴᴏʀO'Bʀɪᴇɴ false. 4 mod 5
 
@HelkaHomba n² ≡ x (mod y)
 
7:50 PM
Where n>1
 
also, odd/even isn't true
n² ≡ 25 (mod 26) has solutions
as well as 9,10
(because they are squares)
 
conjecture: no solutions exist for (n) mod (n+1) for n > 2 and n is not a perfect square
 
oddly enough, they also have other solutions than the easy one
oh, nevermind, it makes sense. 25 mod 26 has two solutions, 5 and (26-5)
 
@HelkaHomba: Your Minecraft puzzle rings makes me think you could make a challenge out of it. Given an initial scrambled state, output the minimum number of steps to a solution.
 
@El'endiaStarman elaborate on the puzzle rings?
 
7:58 PM
conjecture: numbers just keep on going
 
simple question.....consider strings of length n made only of 1s and 0s. How would you iterate over all such strings except never consider a string and its complement. That is never have 010 and 101 for example
I am sure this is basic but it has confused me :)
 
@NathanMerrill I'm referring to his YouTube video, but I'll elaborate. The rings are linked in a chain, and every pair of adjacent links intersects and shares a cube. You can rotate the rings independently, which will move different cubes into the intersection point(s).
 
@Lembik enforce that all strings start with a 0
 
@NathanMerrill ah.. that simple :)
I thought it might be something trivial
thank you
 
8:01 PM
brain freeze :)
 
oooh Helka Homba voice
I've never heard him before
 
@CᴏɴᴏʀO'Bʀɪᴇɴ Euclid (or was it Euler?) proved this for primes a while ago. Should be trivial to extend the proof.
 
@HelkaHomba its what I'm watching
 
@El'endiaStarman well, numbers are all different. primes are complex enough, but all numbers? I think that's too complex
 
8:04 PM
what is it that you want to prove?
 
@CᴏɴᴏʀO'Bʀɪᴇɴ No, no, I've got it. As proven already, there are an infinite number of primes. You can associate each of these with a natural number, and bam, there's a proof that the natural numbers are infinite!
 
oooh, yeah. if you square a prime, you get a natural number
 
@HelkaHomba Why did you use lever instead of a button?
 
@El'endiaStarman but I don't have the axiom of choice
so I cant choose to accept your theorem
 
8:05 PM
@drobilc Buttons have a lag.
 
oh you are trying to prove that there are an infinite number of natural numbers?
 
x = 16, y = 16, rule = B3/S23
oobobobbbooobboo$
bbbboboobobobboo$
booobbobboboooob$
bobobobooboboooo$
bbbbbbbboobbbbbb$
boobobbbboboooob$
bboboooobobobobb$
bobbbbbbbbbbbbob$
bobbobbbooobbooo$
oobobboboboooboo$
oboobbbboobbbbob$
oboboobobboboobb$
oboooboobooooobo$
bbbbbbbobboobobb$
obbooboooooobboo$
bbobbobboboobboo!
^ You should try running it ;)
 
@El'endiaStarman Oh, seems logical
 
@Lembik Yes. It's pretty challenging.
 
@drobilc Watch til the end and I explain why. Basically buttons are slower.
 
8:07 PM
@El'endiaStarman I assume this is a joke of some sort?
 
@El'endiaStarman Definitely :D (feel free to make the challenge, no need for my permission or w/e)
 
@Lembik Well, I was responding to Conor's initial statement:
8 mins ago, by Cᴏɴᴏʀ O'Bʀɪᴇɴ
conjecture: numbers just keep on going
 
oh I see
 
Think of a really big number, and then you can add 1 to it to get an EVEN BIGGER NUMBER
 
actually, solving Helka's puzzle is easier than hungarian rings
 
8:07 PM
QED
 
because there's only 1 intersection for the end rings
 
@CᴏɴᴏʀO'Bʀɪᴇɴ The set of natural numbers exists in ZF by the axiom of infinity
 
@LegionMammal978 well, I only have F
@BusinessCat :o
how do I know I can add 1 to all numbers
 
@CᴏɴᴏʀO'Bʀɪᴇɴ Hahaha, I don't think that even makes sense. :P
 
@LegionMammal978 I think your use of exists is suspect :)
 
8:08 PM
@CᴏɴᴏʀO'Bʀɪᴇɴ Where are you hiding Fraenkel?!?!
 
also, I'm pretty sure that any permutation of Helka's puzzle is possible, but that's not true of hungarian rings
 
@LegionMammal978 it was only fair. people took away my C from ZFC, so I took their F.
2
 
@NathanMerrill Yeah it is easier, but still not totally trivial
 
@BusinessCat If p is a prime ≡ 1 (mod 4), then there exists an x so that x² ≡ p – 1 (mod p).
 
@CᴏɴᴏʀO'Bʀɪᴇɴ In fact, you could say that you had no... choice badum-tsch
 
@NathanMerrill /me googles Hungarian rings Oh yeah, that's basically exactly it, except there's only one intersection between adjacent rings.
 
@Lynn AHH MY EYES TOO MUCH NUMBER
 
For example, 5² ≡ 12 (mod 13), but 12 isn’t a square.
 
@LegionMammal978 ahahaha
 
@CᴏɴᴏʀO'Bʀɪᴇɴ ahahahahAHAHAHAHAHAHAHAHAHAHAHAHA
 
8:16 PM
evil laugh
 
What if you started only using U+200A HAIR SPACEs?
 
@LegionMammal978 Ermahgerd, constant growth!
 
@zʏᴀʙiɴ101 And a pretty small initial bounding box, too
 
@LegionMammal978 What's a hair space?
 
8:21 PM
O r , e v e n w o r s e , u s i n g t h e m t o p r e v e n t p r o p e r k e r n i n g ?
 
( A l s o s i m u l a t e s f u l l w i d t h c h a r a c t e r s ! )
 
Hair spaces are rather tiny, aren't they?
 
@LegionMammal978 * twitch *
 
M a y b e I s h o u l d j u s t w r i t e l i k e t h i s w h e n i n T N B
( d e l e t e d )
 
8:25 PM
>_>
ahem Sandbox?
 
@LegionMammal978 you should write a chrome extension for that
 
@Maltysen S o r r y b u t I u s e F F
 
bookmarklet?
 
P o l l : h t t p : / / w w w . s t r a w p o l l . m e / 1 0 6 8 2 7 7 8
 
Cheating. He's counting method parameters.
if you're going to bash do it right
 
so I need to bash the thing to the right of me
 
hopefully that's your js interpreter
 
;_; you don't want me here? kek
hey I have 25 rep on ppcg
 
What?
 
8:38 PM
25 rep
3
 
Oh haha
 
:P
alright, I'm posting this today if no one has any objections
1
A: Sandbox for Proposed Challenges

Cᴏɴᴏʀ O'BʀɪᴇɴLanguage succession answer-chaining string Given two words (two strings of lowercase-only letters separated by a space) as input to a program PX written in language X, output two programs in languages Y and Z such that program PY outputs the first word and program PZ outputs the second word. Yo...

 
You might want to edit bump it so it's at the top of the sandbox for a bit, find some sentence you think could sound better or whatever
 
Also I assume your "first post" section will go into an answer an not the post?
 
@CᴏɴᴏʀO'Bʀɪᴇɴ I really like this challenge. BRB going through all your esolangs again.. :P
 
@EᴀsᴛᴇʀʟʏIʀᴋ xD
 
:P
@CᴏɴᴏʀO'Bʀɪᴇɴ why do you always use prntscr.com?
 
6
A: Leave a Comment

R. KapPython 3.5 with Selenium Webdriver, 485 427 469 461 449 414 bytes: from selenium.webdriver import*;from time import*;D=Firefox();I=lambda k:D.find_element_by_name(k);C='comment';D.get('http://www.codegolf.stackexchange.com/users/login');I('email').send_keys(U);Z=I('password');Z.send_keys(P);Z.su...

Finally got it down to 414 bytes, even with the fact that I cannot use a URL shortener
\^u^/
 
> Unfortunately, the ppcg.lol URL can't be used, because it doesn't pass POST requests through.
@Quill could you make it do that?
 
8:51 PM
@CᴏɴᴏʀO'Bʀɪᴇɴ You could probably write a stack snippet to generate a list of languages that were used already? That was one of the biggest pains with some of the answer chaining challenges before.
 
probably would be non-competing, but nice for the future
^
 
Tech history poll again: strawpoll.me/10673742
 
@EᴀsᴛᴇʀʟʏIʀᴋ yeah. I have lightshot
@FryAmTheEggman I am not good with SE api :/
 
Hmm, well I won't have time today but I might be able to adapt one of the other snippets to make you one.
Thanks to the format requirements it shouldn't be too difficult (I hope... :P )
 
@EᴀsᴛᴇʀʟʏIʀᴋ It's set to DNS level redirect, POST requests usually work fine with redirects
 
@FryAmTheEggman thanks :)
 
@drobilc I think it might be a dupe? Feel like I've seen something like this before, but with an different card game like Euchre or Bridge...
 
0
A: Sandbox for Proposed Challenges

drobilcLet's play some Briscola Briscola is an Italian game, played with a deck of 40 cards, divided in 4 suits - coins (denari - D), swords (spade - S), cups (coppe - C) and clubs (bastoni - B). The values on the cards range numerically from one through seven, plus 3 special cards - knave (11), knigh...

 
@CᴏɴᴏʀO'Bʀɪᴇɴ now get 12,782 rep!
 
I don't quite follow.
 
9:06 PM
@FryAmTheEggman Yeah I had a Bridge Hand Scoring challenge but this is different
 
There are quite a few hand scoring ones, I'm having trouble finding trick winning ones
 
I don't recall ever seeing one
 
Although I found 2 skat hand scorers, didn't look closely enough to see if they are dupes of each other, though.
Ok, the closest I found was codegolf.stackexchange.com/q/49033/31625
 
So it should be okay?
 
But that has no trump, not sure if that's sufficiently different?
Hrmm, actually it does have the leading suit rule, so the only difference is that you also have to read a trump suit, I think it's probably a duplicate
 
9:11 PM
Dammned, i thought i was onto something :(
 
Kind of sad, I played Briscola quite a bit with my grandparents when I was younger... Didn't Briscola have a sort of crazy scoring method? That would probably make an ok challenge.
 
@FryAmTheEggman it does yeah, en.wikipedia.org/wiki/Briscola#The_cards
 
Hmm, I think I was probably thinking of Scopa: en.wikipedia.org/wiki/Scopa#Scoring
 
@Dennis Are you sure you're pulling the right version of Grime? I'm not seeing my debug-mode changes on TIO.
 
@CᴏɴᴏʀO'Bʀɪᴇɴ look at the image.
 
9:16 PM
ahhhhhhhh
 
@Zgarb Are there several versions? I'd have to check when I get back phone.
 
A note for anyone else who programs with Forth:
Ideone.com is objectively better than repl.it as an online IDE,
because it supports floating point input and extended float operations.
 
What's your favorite quadrilateral?
 
For some reason, the JSForth interpreter has the FLOG word commented out. idk why
 
@HelkaHomba squares
 
9:22 PM
@HelkaHomba kite
 
so you can't flog your numbers (find the log-base-ten of them)
 
Parallelograms are fun to say :)
 
@CᴏɴᴏʀO'Bʀɪᴇɴ same :D
 
@FryAmTheEggman parallelepiped
 
9:22 PM
@FryAmTheEggman I never know where the the double-L is
parallelogram? paralellogram? parallelogramm? parallelopound?
 
@mbomb007 what is it called in 4 dimensions?
 
@mbomb007 Parallelepipeds are my favourite 3D object :)
 
@Zgarb Err, would I have to compile Grime? I just pulled.
 
I like squares, because there's only really 1 square in existence
 
parallelehyperped?
 
9:24 PM
@HelkaHomba Idk, but I just discovered Prismatoids
@HelkaHomba Hyparallelepipeds?
 
paralleloplexed?
 
everything else has infinite versions, but I like the purity of 1
actually, that's an interesting question. Are there more parallelograms than rectangles?
or can you do a 1 to 1 mapping?
 
@HelkaHomba The generalization is called a Parallelotope. So it'd be a 4-Parallelotope.
 
Spectrahedrons are cool too.
 
In convex geometry, a spectrahedron is a shape that can be represented as a linear matrix inequality. Alternatively, the set of n × n positive semidefinite matrices forms a convex cone in Rn × n, and a spectrahedron is a shape that can be formed by intersecting this cone with a linear affine subspace. Spectrahedra are the solution spaces of semidefinite programs. == References... ==
._.
 
9:28 PM
^ parallelepiepan
2
 
parallel epipens
 
Huh, what are the green epipens? Mine have always been yellow since they started to look like that.
 
Isn't it just a different dose?
 
1
Q: Antiprime Champions

ClashsoftConsider the following table for the function d(n), which calculates the number of factors that n is divisible by without a remainder: n | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | ... d(n) | 1 | 2 | 2 | 3 | 2 | 4 | 2 | 4 | 3 | 4 | 2 | 6 | ... Going from left to right, it is pos...

 
Makes sense, I couldn't find anything in like 10 seconds of googling so I gave up :P
 
9:34 PM
@FryAmTheEggman Just click the image=)
 
Ah you're right, but the dose is pretty tiny so I don't feel bad for asking :P
 
 
you broke them :|
 
@FryAmTheEggman So what are these things for anyway? I just know that in some kind of emergencies you have to push those fuckers in your thigh down to the bone.
 
extreme allergic reactions
(and maybe other things too)
 
9:37 PM
That's basically it, they contain epinephrine which is like adrenaline, so it's mostly a quick fix for things like allergic reactions where you just need to stay alive a while for it to pass.
Or to get you to the hospital, etc.
 
So people who have severe allergies to certain things can get those?
 
Yeah, that's what mine are for.
 
@VTCAKAVSMoACE updated my small script keyboard layout to add superscript small caps and emojis (¯_(ツ)_/¯, ( ͡° ͜ʖ ͡°), ᴀɴᴅ ಠ_ಠ)
 
@FryAmTheEggman I wonder whether they could be abused for performance in sports=)
(not that I want to try...)
 
that is horrible ._.
 
9:47 PM
@flawr ᴜʜ-ʜᴜʜ....
 
what is epipen?
 
@Optimizer a shape
 
19 mins ago, by Helka Homba
^ parallelepiepan
18 mins ago, by flawr
parallel epipens
 
@Optimizer a syringe shaped like pen for injectly epinephrine (a stimuluant of sorts) to stop anaphylictic shock
 
9:49 PM
it's effectively Adrenaline
 
@Quill how would CR feel about a vbscript that spams text?
in an application text box
 
@EᴀsᴛᴇʀʟʏIʀᴋ simple guide for CR on-topicness: Is it A) working code and B) complete and not hypothetical at all
 
@Dennis Yeah, if you're running the executable (as opposed to using runhaskell), you need to recompile it.
 
][;'
 

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