The Nineteenth Byte - 2015-11-14 (page 8 of 9)

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Anonymous

10:00 PM

@Doorknob I don't think it's necessary to kb a user for abusing stars. Just take away their stars. Let them stay and chat, unless they break other rules too.

@Mego i agree...

@Mego On the main site, a 2k+ user abusing the edit privilege can be (and frequently is) suspended entirely.

The philosophy behind it is that if you're contributing negatively in one way, it's not likely that your other contributions are positive either.

The same idea can be applied here.

If you want to chat, don't abuse the starring privilege.

Anonymous

@Doorknob There's a large difference between abusing the edit privilege and slapping stars on everything, though.

4

exactly..

@Mego How so? They're both misuse of a site feature. "Abuse" of the edit privilege can constitute, say, excessive minor edits that bump posts to the top of the "active" tab.

10:03 PM

@Mego gets 3 stars

Anonymous

@Doorknob Abusing the edit privilege means defacing the public image of the site. Abusing stars means being incredibly annoying in chat, while not necessarily defacing anything.

@Mego Your first sentence is not necessarily true.

@quartata do you think it shouldn't have been starred?

Anonymous

@quartata the irony

@TanMath No, I just thought it was funny that it was.

10:04 PM

@Mego well said!

@quartata 'cause I just want to make sure about whar i should star and what i shouldn't

Anonymous

@Doorknob That's how I view it, at least. I certainly would not object to star abusers getting suspended/banned from chat. I'm just saying, if it was my call, I'd prefer to suspend their star privileges before their entire chatting privileges.

Anonymous

Because in my eyes, though it is still a nuisance that I would like to see dealt with, spamming stars is a more minor offence than abusing edits.

@Mego well said, well said!

@Mego Maybe "abuse" wasn't the best word. "Misuse" may have been a better choice.

In any case, a kickban != a suspension.

In fact, the first kickban only lasts a minute IIRC. (And hopefully comes after several warnings.)

Anonymous

@Doorknob I'm going to suggest we agree to disagree, since it ultimately boils down to personal preference. :)

10:12 PM

0

Q: Generate a programming language

Make a program that randomly generates a new programming language. This is a popularity-contest question, so feel free to use your own format for the output (everything goes, from a simple 2-column explanatory table to a formal grammar, whatever floats your boat). Points for variability in the ge...

popularity-contest generation language-design

feature-request downstars.

@NewMainPosts thank you for once again posting an off topic post!

@Mego Point taken. (Not that the discussion really mattered anyway, because we still can't even figure out who's starring things...)

Self-moderation is good. :D

Anonymous

@Doorknob fastest closehammer in the west

3

Anonymous

10:13 PM

@Doorknob Yeah, first and foremost, we need some way for chat mods and room owners (if not the entire chat) to be able to see who stars what, so that the chat can be better moderated.

@Mego Or go the other route and permit downstars for everyone - let the users decide what actually gets on the starboard.

El'endia Starman

@Sp3000, you(r language) beat me with Gol><>, but I beat @Mego's Seriously with Minkolang! :D

Anonymous

user image

Relevant:

21

Q: Provide a way to determine which user is spamming stars in chat

As a compliment or alternative* to not refunding cancelled stars, it'd be nice if chat would auto-raise a flag identifying someone starring n items in x minutes, or at least provide a list of unusually active starrers that could be consulted when there was a problem. While star-spam is fairly lo...

feature-request chat moderator-tools chat-stars

Anonymous

@El'endiaStarman How does the Minkolang loop/count?

10:16 PM

@Doorknob This has been posted in the last 20 or so minutes.

Anonymous

40 mins ago, by Mego

20

Q: Provide a way to determine which user is spamming stars in chat

As a compliment or alternative* to not refunding cancelled stars, it'd be nice if chat would auto-raise a flag identifying someone starring n items in x minutes, or at least provide a list of unusually active starrers that could be consulted when there was a problem. While star-spam is fairly lo...

feature-request chat moderator-tools chat-stars

Someday I'll actually make a sock account and then no one will believe me if I claim it's mine.

Anonymous

Nevermind, @Doorknob is the slowest carrot in the west

@VoteToClose oh I can't read

Anonymous

Wow I mortarboarded on meta

El'endia Starman

10:17 PM

@Mego Whoops, forgot to add that bit of explanation.

@Mego Is that even possible?

Anonymous

@El'endiaStarman Oh neat

@VoteToClose Yep. It's even possible on per-site metas.

Reputation isn't shown, but it's still tracked.

Anonymous

user image

user image

3

El'endia Starman

10:19 PM

@Mego You're one of eight!

@Mego How'd you do it? o-o

Anonymous

@El'endiaStarman I'm also the first person this quarter

Anonymous

I feel special

El'endia Starman

:D

1 min ago, by Doorknob

Reputation isn't shown, but it's still tracked.

Anonymous

10:19 PM

11

A: Disallowing Explicit Exclusion of Languages

Yes, challenges that specifically exclude certain languages or penalize them should be considered off-topic and closed as such The spirit of this site is to write the shortest code per language for a challenge, not just the overall shortest code. We do not forbid users from posting answers which...

Martin Büttner

@El'endiaStarman kinda weird how 4 of those happened this August

El'endia Starman

yeah

Anonymous

7 question upvotes, 11 answer upvotes

Anonymous

And two more answer upvotes here makes 20

25

A: Why can't I post my answer after others use my language?

You Can, Dogtor! The only thing is, the public mightn't approve. If they believe that adding your code after other, shorter, answers exist for the same language is pointless, then they'll downvote because they don't see a reason for the answer to be there in the first place. It is a competitio...

I got at least 20 of these in 1 day. :c

I feel robbed. o-o

10:25 PM

@VoteToClose But in one UTC day?

(that was posted at 17:00 UTC.)

@Doorknob OHH.

=.=

Anonymous

@VoteToClose You're even in England. Shame (ding)

Damn UTC, breakin' me chances of getting mortar boarding. o-o

@Mego My late (the time I get on) is its late.

Anonymous

It's a lot easier to mortarboard in the US :P UTC midnight for me is 6 PM

> The gamma function is defined for all complex numbers except the non-positive integers. For complex numbers with a positive real part, it is defined via a convergent improper integral:

@Mego halp how duz math :P

3

That Wikipedia page has some pretty neat and colorful pictures.

Unfortunately, they mean nothing to me.

10:27 PM

@Doorknob ?

> yay kolors!

Anonymous

In mathematics, a Riemann sum is an approximation that takes the form . It is named after German mathematician Bernhard Riemann. One very common application is approximating the area of functions or lines on a graph, but also the length of curves and other approximations. The sum is calculated by dividing the region up into shapes (rectangles, trapezoids, parabolas, or cubics) that together form a region that is similar to the region being measured, then calculating the area for each of these shapes, and finally adding all of these small areas together. This approach can be used to find a numerical...

@TheDoctor wait for @NewMainPosts... (or just check newest questions)

@Mego DAMMIT I JUST REMOVED GAMMA.

Martin Büttner

@Mego Can I use built-in (symbolic or numeric) integration?

Anonymous

10:29 PM

@VoteToClose DOESN'T MATTER NO BUILTINS

(~-.-)~ Whyyy?

@Mego Oh. :D

Anonymous

@MartinBüttner I should exclude that, too, though I think Sage, Mathematica, and Matlab are probably the only languages capable of symbolic integration of an improper integral easily

Martin Büttner

@VoteToClose also wouldn't have mattered because (provided you're using some sort of public version control) you could have participated with an old version of the language.

@MartinBüttner Gamma didn't work in the old versions. :D

hallo

Martin Büttner

10:31 PM

@Mego I don't think Matlab can do symbolic integration, but numeric should be enough?

What did I miss?

Anonymous

@MartinBüttner Does Matlab support numeric integration of an improper integral?

@quartata me

Martin Büttner

@Mego I have no clue.

Oh shit Gamma function

Anonymous

10:32 PM

user image

Naturally it had to get posted right before I got it working again in Rotor

Oh looks like I couldn't have used built-ins anyways

Anonymous

3 mins ago, by Mego

@VoteToClose DOESN'T MATTER NO BUILTINS

Anonymous

ninjo'd

@Mego by the way, you probably want to change the ideone link to a fork link so people can modify the input

So this: ideone.com/fork/cvDdYR

Anonymous

,Γ for Seriously if builtins were allowed :P

10:33 PM

Matter of a fact, you mind if I edit that right now?

Yay or nay?

Anonymous

I already did it

Anonymous

Ninjo'd

> nor may you use built-in numeric or symbolic integration functions.

;(

Only because you didn't give me approval

Anonymous

@quartata Because I am (normally) capable of editing my own questions :P

Martin Büttner

10:35 PM

@Mego would be neat if you included some more test cases in the question itself, so people can check some 10 (or so) values without having to rely on ideone

@Mego Is this OK?

Anonymous

@quartata If you can get the correct precision, sure

Anonymous

@MartinBüttner Ask and ye shall receive

It would probably be really long anyways...

my TI 89 says the second test case is undefined @Mego

10:36 PM

Hmm there must be a shorter way

Anonymous

@TheDoctor I promise you it isn't

^_^

Researching methods for doing it super short right now

Anonymous

Gamma(x) is defined for all x that are either positive or non-integers

lights.helloenjoy.com

10:40 PM

Ooh I think I've got one working in Rotor

4

Q: Gamma Function Golf

Given a real number t between [-1E9,1E9] as input, output Γ(t), also known as the Gamma function, which is defined as follows: You may not use a built-in Gamma function to solve this task, nor may you use built-in numeric or symbolic integration functions. Your output should be accurate to 6 s...

Except it returned NaN for -2.5 what

Ohh I see the problem

42- is actually 2-4

I could change that, but then it would invalidate my answer

Guess I'll just have to suck it up and use )

That website I just linked sends my CPU up to 170C, but it's totally worth it ;)

Anonymous

@NewMainPosts Hey that's a neat question

Anonymous

@MartinBüttner I've added more examples to the post, look good?

Martin Büttner

10:43 PM

yep

Ugh debugging this is painful

I so wanna be the first person to post on this though

I think I can do it in 25 bytes

instagram.com/p/-FQ7Dmumbl

Good evening

Oooh wait a second...

I don't know how Groovy's ln handles imaginary numbers

I think that's why it is giving NaN

Booo

Anonymous

@quartata Why do you need imaginary numbers?

^

Everything in this case should be real-valued, both inputs and outputs.

10:47 PM

$user image$

Anonymous

Yep

See the issue?

Anonymous

ln(-number)?

@Mego Yes.

Anonymous

Yeah that's a slight issue for that formula :P

Anonymous

10:48 PM

However

I was going to just e^x it back to size, but if it can't handle imaginary numbers then that's no good

BTW what's with Vihan doppelganging Digital Trauma? O.o

I'm going to use Octave which can handle that

Anonymous

If you exp both sides, the problem should disappear

Calvin's Hobbies

@Mego I'd vote to use 10^9 or 1,000,000,000 instead of 1E9. 1E9 is for when shortness is required and just looks weird...

10:48 PM

@Mego But if it can't handle the imaginary numbers the intermediate value is just going to get thrown out

Anonymous

@Calvin'sHobbies I can do that

I'm doing this in Rotor, remember.

Anonymous

@quartata If you exp both sides, then the lns should fall out of the equation

@BadCatEye has been for a while now :P

I was saddened to learn that R doesn't like this: integrate(function(x) x^(t-1) * exp(-x), 0, Inf)

10:49 PM

@Mego Oh I see what you mean.

Lemme see what that looks like.

@Doorknob Damn, I missed that completely :P

@quartata You can bypass this with Γ(x)Γ(1-x) = π/(sin(πx)) for 0 < x < 1.

@BadCatEye You never see them in the chat at the same time.....

Calvin's Hobbies

@quartata There are so many new languages kicking about recently: Rotor, O, Seriously, Minkolang... too many

Yay, I got a formula with no lns

10:51 PM

> for 0 < x < 1

@AlexA. There's also a special Γ(x) definition for negative numbers. :P

@Calvin'sHobbies they all match /[M-S][a-z]*$/. Coincidence? I expect languages that start with P and Q to appear soon... :P

@Doorknob cough Vitsy.

Calvin's Hobbies

@VoteToClose Is that your cat's name?

@Doorknob A language called Q already exists

10:53 PM

@Calvin'sHobbies ViT-C. <--- pronounce this.

What the hell I don't have base 10 log

gg

@quartata do you have any other type of log?

It would be a few extra chars, but...

I have natural logs but that's extra bytes

Better than no Rotor answer at all :P

Fair enough

This'll be plenty short anyways

Anonymous

10:55 PM

Seriously has only ln also, though I may change that, since I added 10^x

Calvin's Hobbies

Is a quartata a type of burrito or am I thinking of something else?

@Mego more-documentation-request

@Calvin'sHobbies It's a fencing maneuver.

Oh wait nevermind I don't need it.

Would you believe it I was looking at the wrong tab

Sep 25 at 1:01, by Geobits

I drink milk.... a quartata time.

rolf

10:56 PM

> rolf

Calvin's Hobbies

@VoteToClose Pretty sure it's a quarter of a tostada

rolfl, Canada

75.8k 10 147 340

java algorithm performance strings beginner sql optimization

o-o Welllll then.

@Mego Yeah but you still have z^(z-1), which can be complex for z < 0.

@Doorknob Ah yes, good old rolfl.

Anonymous

@AlexA. What? No.

10:58 PM

I got it

Too bad there's a bug in the interpreter

@quartata Did you name yourself after the fencing maneuver or...?

@VoteToClose Yes I did! How did you know?

I'm so pleased that someone got that.

@Mego If you exponentiate the right hand side of quartata's equation, you get sqrt(2pi) * e^(-z) * z^(z-1), which can be complex.

Two years of fencing. (~-.-)~

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The Nineteenth Byte

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