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3:26 PM
Good grief - MSE seems to be throwing badges at me today
 
Wasn't there another John too? He used to have the logo of this site...
 
i need advice on going in the right direction with this problem
 
@KaliMa Have you asked in the main site?
 
well you could give the problem instead of just the name and there might be some people who can help you
SPOILER:
This may contain the solution so don't look if you want to find out for yourself www.tanyakhovanova.com/Puzzles/solballs.html
I assume this is your problem
 
Is there a good troll on here who has nothing good to do?
 
3:35 PM
why?
 
@DumbCow mr.FS is the needed troll.
 
really? how is that?
 
@GustavoBandeira I'm looking for someone to troll the noobz at OpenStudy.
Formatting fail
 
I don't know but if you're looking for a free linear algebra book, I have heard this is good joshua.smcvt.edu/linearalgebra, it has the solutions to the problems as well
 
3:40 PM
Not exactly for a free book, I need a good book.
As calculus have apostol and spivak, what are the equivalent books for algebra?
Lang's?
 
I don't know, we use this one at our university amazon.com/Linear-Algebra-Edition-Stephen-Friedberg/dp/…, but I have no idea how it compares to other ones or really if it is considered to be any good. I like it, I guess, but I don't know if that is an opinion which is shared by other people
 
Got it.
 
ok and what do you think about it
 
@Gustavo: Have you read all the books stated in the List of Books spreadsheet?
 
The book you mentioned?
@DumbCow Nope. I guess such an achievement would be impossible.
 
3:46 PM
:p
 
anybody here?
 
yes
 
could you help me with one 1 really easy excercise?
 
@Gustavo: So, what books do you prefer for cognitive sciences (psychology)?
 
@DumbCow "List of Books" spreadsheet?
 
3:47 PM
@mr.FS Yes.
 
@mr.FS think about what?
 
the book
 
6* 7^(x+3) - 7^(x+2) = 82
 
@DumbCow Where could I find it
 
@Gustavo: Am I allowed to disclose it?
 
3:48 PM
@DumbCow Always.
 
probably using some tricks with logarithms
 
o it doesn't matter if it's something private
 
@GustavoBandeira dhanyavaad
 
@mr.FS The free book you mentioned is beautiful. =)
 
@DumbCow Thanks
@GustavoBandeira Yes I agree
 
3:49 PM
@DumbCow Don't spread it.
 
wow that list
 
@GustavoBandeira Hence my username ;)
 
It seems Ramanujan was right about mock modular forms ... whatever they are
 
@OldJohn interesting! However, "A devout Hindu, Ramanujan said that his findings were divine, revealed to him in dreams by the goddess Namagiri." is quite wrong! (Is this how legends are made? God recited the XXX to YYY and so on? (simple typography erros?)) He always said that Namagiri was his inspiration, enabling him to plow on through his life irrespective of what happened to him. :-)
 
@EinsteinsGrandson :

This is what Mathematica gives me:

$6\cdot 7^{x+3}-7^{x+2}=82$

Solve for $x$

$c_1\in \mathbb{Z}\land x=\frac{2 i \pi c_1}{\log (7)}-2+\frac{\log (2)}{\log (7)}$

I don't know what it means though.
 
3:54 PM
@JayeshBadwaik Yes - it always pays to be sceptical about some of these stories about mathematicians. It seems a lot of them are wrong
 
@JayeshBadwaik he's a genius QED
 
@Charlie of course! :-D
 
@JayeshBadwaik :-D
 
@einsteinsgrandson: hmm
 
@Charlie He is one of my other inspirations. ;-)
 
3:56 PM
@DumbCow E-mail.
 
@JayeshBadwaik yes he inspires everyone.
 
@DumbCow Send me an email!
 
@JayeshBadwaik k.
 
@EinsteinsGrandson $6\cdot 7^{x+3}-7^{x+2}=42\cdot7^{x+2}-7^{x+2}=41\cdot7^{x+2}=82$
 
@JayeshBadwaik i send you an email, do you want?
 
3:58 PM
@Charlie
 
@Charlie Yes yes.
@Argon
 
@argon !!!
 
@Charlie Oui?
 
@JayeshBadwaik done
@Argon wassup?
 
@Charlie Nothing :)
@JayeshBadwaik Are you around?
 
4:02 PM
@Argon yup....
 
@Argon hmm...
 
Anyone here who has an idea how to find the biggest order of an element in $\mathbb{Z}_m$, with $m\in \mathbb{N}$? It's not necessarily $\phi(m)$ is it?
 
@JayeshBadwaik I'm using Fritzing to make a PCB. What component connects a PCB to outside components?
@Charlie hmmm...!
 
@JayeshBadwaik ;) ;)
 
@Argon connectors?
 
4:04 PM
@JayeshBadwaik Is that what they are called? One sec
 
or solder
 
@mr.FS If I remember correctly, it is only $\phi(m)$ for cases where $m$ has a primitive root
 
@Argon what does mean hag sameah?
 
@Charlie Happy holiday, literally
 
@Argon yes, you need to have special type of connectors. Better use standard ones, else various problems (like parasitic capacitance, impedance mismatch) can crop up.
 
4:05 PM
@Argon oh! Fascinating !
 
@OldJohn Ok
 
@Argon I did not know about Fritzing.... its really really cool. :-)
 
@mr.FS and that only happens for something like $2, 4, p^n, 2p^n$ with $p$ prime (I think)
Not sure I know anything about finding elements of maximal order when the group is not cyclic :(
 
@OldJohn ok I'll have to take a better look at this stuff. Thanks for the help
 
@JayeshBadwaik did you see Jonas' proof of competency?
 
4:08 PM
@Charlie I don't think so, what is that?
 
@JayeshBadwaik he wrote about hermite polynomials. very nice
 
@Charlie hmm, link?
 
@mr.FS I already understand the solution to the problem, I am asking about how to tackle a variant of it
 
@KaliMa ok but you didn't pose your question did you?
 
@JayeshBadwaik sec
 
4:12 PM
@Charlie I got it.
from his site
a review of mehler kernel
 
I have a feeling this isn't difficult, but I'm not seeing how I would get a general expression for $\displaystyle \textrm{gcd}(\underbrace{1\ldots1}_\textrm{n ones},\underbrace{1\ldots1}_\textrm{m ones})$
 
@JayeshBadwaik got?
 
@Charlie yes.
 
@JayeshBadwaik :)
 
:)
cornucopia ? hehe
 
4:19 PM
@JayeshBadwaik really funny :)
 
@mr.FS is it maybe just $1\dots1$ with $\gcd(n,m)$ ones?
 
@JonasTeuwen Dude, you write really well. I like it!
 
@OldJohn that would be nice, let me check it with what examples I wrote down
 
@JayeshBadwaik it's inspiring , isn't it?
 
@OldJohn It works :), I will have a look why. Thank you
 
4:23 PM
@mr.FS can probably be proved by noting that $1\dots1 = (10^n-1)/9$
 
oh yes
 
not totally sure, though
 
looks like it could work though
 
@Charlie yes.
 
Bugger - my recent soft answer is now my highest rated answer :(((((
 
4:26 PM
haha, MSE problems.
anyway, I'm leaving to have dinner. See you all
 
@mr.FS later
Time this old geezer took a nap - bye for now.
 
This cow with hat...
What did you do?
 
Just trolled a little...
No way to apologize
 
@DumbCow what kind of troll?
@jas hey!!!
 
user19161
4:41 PM
@Charlie I just watched the movie "Knowing" on TV starring Nicholas Cage, very meaningful...
 
@JasperLoy hmm i like nicolas cage
 
@DumbCow i waiting someone to do it!
 
;)
 
4:56 PM
lol
 
Linear Algebra seems to deal with matrices... I always thought that "Linear" had something to do with lines.
 
@GustavoBandeira o.o
 
@GustavoBandeira It does!
Matrices deal with lines.
 
@JayeshBadwaik Yes, but it seems that matrices are more the point of it.
And I guess matrices deal with other stuff too.
@mr.FS omg, the free book you mentioned is very nice
There's a timetable for one semester! I loved it.
 
5:21 PM
Linalg is funny.
 
@Charlie Hmn...
 
@GustavoBandeira hmm what?
Hi @anon bananon!
 
@Charlie About being funny: You're an untrustowrthy source of information, you laugh for no reason. :P
 
@Charlie hey charlie
 
@anon you too!
@GustavoBandeira @skullpatrol thinks I'm funny...
 
5:31 PM
@Charlie He's also not trustworthy. =D
 
@anon what have you been doing, mr.ymous?
 
just woke up
 
@anon what time is it? 9h?
 
11:30am
 
@anon oh! Here is 15h35
 
5:37 PM
@GustavoBandeira yes and what's good as well (as long as I prevent myself from cheating :P) is the fact that the solutions are also available
 
Strange. anon is becoming more sociable... Hmn. In the recent past, he only emerged from the dark to answer math questions, after the questions were answered he used to disappear in the fog again.
Uh uh uh uh ah ah ah ah
 
I also respond to pings when I'm around and feel like it.
 
@GustavoBandeira hahahah
 
@anon Dude.
 
Brah.
 
5:39 PM
@anon nice!
So i will start to annoy anon
 
@anon Grnahrl?
 
You cannot annoy anon on purpose.
 
[MSE Is our world, our life, MSE is our world ](youtu.be/R2AhjhYWDUM?t=1m40s)
 
Except if you don't put spaces after commas and make "I" lowercase.
 
@anon yes i can :P
 
5:42 PM
¬¬
 
Hey,do i look like annoying,i mean, is this enough. ?
 
@Charlie I'll make a video: LEAVE ANON ALONE!
 
@PeterTamaroff Wharrgarbl.
 
@anon You ain't giving me a 404, are you?
 
how fucking dare, anyone out there make fun of anon? After all the answers he answered? @Charlie
 
5:45 PM
@anon I wanna talk about $S_n$
 
First I ws afraid of Anon, now I like him. If I like someone I annoy this person :P
 
In grade school they told me that was flirting.
 
okay, what's up about Sn?
 
@anon no it is not flirting. I'm being annoying
 
5:47 PM
As you wish. :)
 
@anon Well, I guess you have interesting things to tel me about it.
Yo @leo
 
leo
@PeterTamaroff sup!
 
The conjugacy classes are in canonical bijection with integer partitions. Every finite group embeds into a symmetric group. The only non-inner automorphisms of Sn occur when n=6 (I recently made an answer about this). The irreducible representations are tabulated with tableau methods via Specht modules. Every group with an n-transitive action on a set of cardinality n has Sn as a quotient.
 
Hola @leo? Que tal?
 
On this meta question Gone and Asaf are discussing something big that happened on the site a few months back. Asaf calls it the "MK heat." Could someone explain what they are referring to or point me to some thread that explains it?
 
5:51 PM
@MikeSpivey Makoto Kato, search that
 
leo
@Charlie Hola! todo bien y tu?
 
@anon Thanks.
 
@MikeSpivey Why the hell would you want to know about that?
 
leo
do you find something odd in this?
 
@GustavoBandeira Because I want to be an informed user of the site. Recent events, coupled with the results of the last election, indicate to me that there aren't enough sufficiently informed users of the site.
 
5:53 PM
@MikeSpivey What are the lots of informed users going to do?
 
@leo estoy muy bien.
 
@leo \melikes
@leo It is "prove something", rather than "proof something"
"proof" is the noun and "(to) prove" is the verb
 
leo
@PeterTamaroff do I have some "to proof"?
 
@leo Ah?
 
leo
@PeterTamaroff in my answers
 
5:56 PM
@PeterTamaroff ?
 
@leo Yes, I edited some.
 
Oh. Oh.
 
But a grace note is also nice
 
leo
@PeterTamaroff oh thanks man!
 
@JayeshBadwaik I'm understanding the meaning of linear.
 
5:57 PM
@GraceNote Where did you sprout from?
 
I've been sitting here for a while.
 
@GraceNote I see you're from GameDevs
 
@GustavoBandeira he's sleeping sshhhhh
 
Actually, I'm from everywhere, I'm a Community Manager. I just have Game Dev as my parent site for the picture.
 
I am disappointed at the GPU of my laptop. =/
@GraceNote Oh, OK.
@GraceNote Omnipresent!
 
5:59 PM
It is as it is.
 
@GraceNote Pardon?
 
@PeterTamaroff Just acknowledging my omnipresence, that's all.
 

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