@KajHansen Group theory - trying to show that diagonal matrices are a subset of the normaliser of diagonal matrices (under the group of invertible matrices)
@DiscipleofBarney, so far I've greatly enjoyed my algebra courses, so I might look into going down that path. From what I've read (and mostly not understood) Lie algebras and the sort look enticing to me. I've also had a blast in this semester's point-set course, so I might try out algebraic topology when I can.
Unfortunately, my GPA is not that great, so I'm afraid I might not have that much of a choice as far as grad schools. Or at the very least, I will need to send lots of applications.
Though I've enjoyed my point-set course, strictly point-set topology doesn't much interest me as far as a career path. I appreciate the link nevertheless!
@Incurrence, I think it was you I've been sharing music with. I found a new band recently. Try this out: youtube.com/watch?v=tQPNredrDO0
Oh I figured that, just I think its sort of out of fashion, even though there is still tons of cool stuff (I especially like the (infinite)combinatorial and games in topological spaces). Although I guess it was always out of fashion, the fields that study the more exotic/messy stuff almost always seems to be out of fashion. @KajHansen
It just seems a bit unmotivated @DiscipleofBarney. I'm all for doing math for the sake of doing math, but something about finding a topological space with obscure properties $X, Y$ and $Z$ but not property $W$ just doesn't get my blood pumping.
@Incurrence: The abstract answer is that there are lots of compact matrix groups, so the exponential map on their Lie algebra has to be a covering map. The simplest example is exponentiating real multiples of $\begin{bmatrix} 0 & -1 \\ 1 & 0 \end{bmatrix}$. Have you thought about that?
I am trying to find a counter example to injectivity of the exponential map(for real matrices)
He said take real multiples of this, but it isn't working
In forth step $(x-1)(x-2)$ is obtained by applying transformation R$1 \frac{1}{(x+1)}$ and R$2 \frac{1}{(x+2)}$.
But we get value of $x = -1$ or $ x = -2$ so $\frac{1}{(x+1)}$ and $\frac{1}{(x+2)}$ will be undefined because value of x can be -1 and -2.
So my question is can we apply R1i a...
I have a question about MVT: I saw some cases when the point c is included in the closed interval, and I know that it should be included in the open interval
Your talking about distance between points, and finding the smallest distance, but in calculus and analysis there is an "idea" of making distances as small as you want and it is important for the idea of continuity, integration, differentiation, etc
@DiscipleofBarney i think i am clear know, if i have points in a plane which are not collinear how do i prove that if i pass a line through n points there will always be a points opposite to the given line
@Rememberme It sounds like you are asking why given a set of colinear points there will always be a point not on a line through some of the points. But that is the definition of colinear (as far as I know)
it's a standard construction. take your point, draw an arc. the arc cuts the line in two points. pick the two points, draw arcs again. the two arcs intersects in a point. join the original point with this point. this is your desired perpendicular.
I have always tried since 5 grade look at one this one amazing.... For which values of n is it possible to cut a rectangle into n equal non-rectangular parts espsecially n odd
@BalarkaSen Sort of, the sort of it is that small cancellation conditions on a group give a lot of control over what elements in a group can be the identity. One of the reasons certain problems in free groups are easy is that the cancellation between the relations is very small (there are no relations!), so in a sense it is a generalization of that.
It gives a geometric way to thing about the defining relations in a group
@BalarkaSen Its sort of like Cayley graphs, but a little different. Relations can be seen as labeled circles where the boundary has the relation written on it, and conjugation can be an element would be a line sticking out from the circle. Consider $uru^{-1}$, if you think of a "balloon" where the string is labeled $u$ and going arround the balloon is labeled $r$, then as you travel up the string you pick up "$u$", then arround the balloon you pick up $r$ and then back down the string you pick
up $u^{-1}$
If you have a bunch of relations you have a bunch of balloons tied together at a common vertex basically
And you can travel around the whole outside
and come back to the start and you would have the product of all of them
@BalarkaSen The cancellation ends up corresponding to being able to identify "strings and edges of balloons" So that is how you can end up with the "wiener" picture I have a little ways up, because there was some cancellation (in the picture not everything that can be identified is identified)
Small cancllation conditions gives a geometric way to restrict how much identification is possible which ends up giving algorithms for things like the word problem and conjugation problem (I have only been describing things on a sphere, but you can do these diagrammatic stuff on toruses, etc)
@BalarkaSen For example remember that group the iwrite showed us and the word that we were trying to figure out if it is the identity, I am pretty sure that group is $C'(1/6)$ so when I get to the point of studying the word problem for that class I will see if I can apply it to that group.
@BalarkaSen Also, one of the main reasons I am studying it now is I am pretty sure it will give me some tools to finally settle a problem I have been working on and off for around 2 years (maybe a year and a half)
Okay, first I will describe the "game" theoretic problem, then the "selection principles" variation, and I am pretty sure there is a (infinite) Ramsey theory variant @BalarkaSen
Say we have a group $G$, then we will play a game, I will present sets that normally generate the group $G$ and you get to choose one element from each set I present @BalarkaSen
You win if you are able to collect elements so that your set will normally generate the group (this game is at most countably infinite length) and I win otherwise
So for example for finite groups you will always win
if you don't play like an idiot
My original idea for this is that you choose relations to add to the group and you win if you get the group trivial, this is obviously equivalent
@BalarkaSen So there are infinitely presented finitely generated groups, so unless you have seen something I haven't seen for 2 years then it shouldnt be obvious
@BalarkaSen It may be possible for me to keep on presenting you with sets (maybe with crazy long words in them) so that in the end you are forced into an infinitely presented group, which the trivial group is not infinitely presented
Or maybe a group where you can't even decided if it is the trivial group :D
I am showing you a set that normally generates the group, but you only get to choose one element, then I can show you a different set that normally generates the group.
@BalarkaSen The "selection principles" variant is I present you with a sequence of sets that normally generate the group upfront and you get to choose one element from each one. If for any sequence I present you can choose elements so that when those elements are added to the relations of the group makes the group trivial then the group is "$S_1$". This is different from the game version because in the game version I can "change" which set I present depending on what elements you end up choosing
But in this one I show the whole sequence upfront
I haven't come up with a reasonable Ramsey theoretic statement that is similar to these, but I think there should be because the topology variants of these types of games have closely related Ramsey theoretic statements. So there tend to be connections between these properties and infinite combintorics on whatever structure you are studying.
@BalarkaSen So I don't think that the free group on two generators, $F_2$, has the property $S_1$, and I think player one has a winning strategy (the one that presents the sets) and I think small cancellation theory will help me show this
Basically my strategy (that I will have to figure out the details on) is this:
I will have to construct a sequence of sets so that any set will normally generate $F_2$ (so when added to the relations makes the group trivial) but any one element choice from each set will in the end give you a group that satisfies the small cancellation condition $C'(1/6)$, which means I will have to be able to construct a bunch of sets that have very little cancellation between each other. In the end I don't think it will be difficult, but to actually prove it I think I will need the
I actually came up with the idea that I need small amounts of cancellation about a year ago, but was at a loss of how to construct such a sequence and proved it had the properties I wanted, and I had heard about small cancellation theory before, but I didn't make the connection till recently! @BalarkaSen
Can I have a hint for proving that $PDP^{-1}$ is still diagonal? I can see that it is true, with many of the diagonal elements being permuted, but I can't find a way to prove it
Doesn't help that I am bloody tired, but I have to do a few more questions(this is my last assignment that was handed in as garbage) to make sure I don't screw up the next one - and I have complex due tomorrow
@BalarkaSen So I have only read a small fraction of what I am going to share, but I would probably recommend looking at the BoazSametRamsey files and the Math580Notes (although those are notes a friend took in class so they are not complete or polished, but they are a good spot to start)
Oh I figured that, just I think its sort of out of fashion, even though there is still tons of cool stuff (I especially like the (infinite)combinatorial and games in topological spaces). Although I guess it was always out of fashion, the fields that study the more exotic/messy stuff almost always seems to be out of fashion. @KajHansen
I think it is one of the reasons I like group theory, is that I can zoom in easily and look at all these super nice, interesting concrete groups or I can look around at the insane mess and complexity of general groups, but it still has some relevance (normally) to the rest of group theory and relations to other fields.
there was this guy named Daniel Rust who used to come to the chat. he's a shape theorist, and we used to discuss loads of stuff about it since at that time i was interested in p-adic solenoids (for completely different reasons : solenoid spaces provides insanely nice geometric representation of absolute galois groups).
i had the impression that those were not-so-bad stuff.
@DiscipleofBarney me neither. i just think that some shape theory would provide a concrete connection between solenoid spaces and profinite groups. in particular, i think absolute galois group of function spaces acts geometrically on solenoid riemann surfaces.
all of it were just some pipe-dream, but i kinda keep it at the back of my head. it was a sound idea.
Its definetly fun to see if your sort of vague intuition about how something, you know next to nothing about, could interact with something you now a little bit about, I think its one of my driving forces in learning a lot of math
I was reading about these things called "constellations", which have relations to drawing maps on Reimann surfaces, which of course has relations to dessin d'enfants, about a year ago..., forgot most of it I think