@Cowsquack If you are trying to write a compiler that can quickly parse large source files, one at a time, where the lexer and parser run in separate threads. But this is probably unnecessary for whatever you're doing - all at once should be okay
@ASCII-only If you want to support out-of-order access (e.g. function odd is defined on line 1 and calls function even which is defined on line 10) you would probably need to parse the whole thing before you can do that
It depends on how you run the Python interpréter. If you give it a full source file, it will first parse the whole file and convert it to bytecode before execution any instruction. But if you feed it line by line, it will parse and execute the code bloc by bloc:
python script.py : parse full fi...
" I have read that the interpreter runs the code line by line and reports the error if any at the same time and stops the further execution. So in python, consider the file ex1.py,
print "Hello world" 12variable = 'bye' print 12variable Now according to the working of interpreter, the interpreter would run the first line i.e. it prints hello world first and then show the syntax error in the next line (line-by-line working). Hence the expected output is:
Hello world 12variable = 'bye' ^ SyntaxError: invalid syntax
I need to parse RFC 3339 strings like "2008-09-03T20:56:35.450686Z" into Python's datetime type.
I have found strptime in the Python standard library, but it is not very convenient.
What is the best way to do this?
Note in Python 2.6+ and Py3K, the %f character catches microseconds.
>>> datetime.datetime.strptime("2008-09-03T20:56:35.450686Z", "%Y-%m-%dT%H:%M:%S.%fZ")
See issue here
@MartinEnder I'm glad you enjoyed it. I'm not super pleased about needing multiple playthroughs for all the story either, but Bastion was the same way. The item for the trial that gave backstory on Rucks only was available in NG+.
Guidelines
Task
Write a method that takes an array of consecutive (increasing) letters as input and that returns the missing letter in the array (lists in some languages).
Rules
This is code golf so the shortest answer in bytes wins!
You will always get an valid array
There will always be ...
Based on this challenge.
In the rhythm game osu!, the difficulty modifier "Double-time" actually only increases the speed by 50%.
Your task, is to write a program that outputs a positive even integer (higher than 0), and when each character in your source code is duplicated, it should output th...
@Mayube Nice, my most upvoted one was on that challenge with XKCD by BetaDecay, I got ~90 upvotes there, and another one was It was just a bug, by Kevin, where I got ~60
please, "ninja'd" should be restricted to when you actually post the message a split second later than somebody else posting the same message, and then you are the one who is ninja'd
@Mayube Do you really think my challenge was too trivial?
It depends on how you run the Python interpréter. If you give it a full source file, it will first parse the whole file and convert it to bytecode before execution any instruction. But if you feed it line by line, it will parse and execute the code bloc by bloc:
python script.py : parse full fi...
I need to parse RFC 3339 strings like "2008-09-03T20:56:35.450686Z" into Python's datetime type.
I have found strptime in the Python standard library, but it is not very convenient.
What is the best way to do this?
Note in Python 2.6+ and Py3K, the %f character catches microseconds.
>>> datetime.datetime.strptime("2008-09-03T20:56:35.450686Z", "%Y-%m-%dT%H:%M:%S.%fZ")
See issue here
Guidelines
Task
Write a method that takes an array of consecutive (increasing) letters as input and that returns the missing letter in the array (lists in some languages).
Rules
This is code golf so the shortest answer in bytes wins!
You will always get an valid array
There will always be ...
Based on this challenge.
In the rhythm game osu!, the difficulty modifier "Double-time" actually only increases the speed by 50%.
Your task, is to write a program that outputs a positive even integer (higher than 0), and when each character in your source code is duplicated, it should output th...
