$$\dfrac{x^2}{r_1^2-x^2}=\dfrac{(y-a)^2(r_2-y+a)(r_2+y-a)}{(y^2-2ay+a^2-r_2^2)^2}$$
So, I tried to solve the abovementioned equation using [Wolfram-Alpha](https://www.wolframalpha.com/input/?i=%5Cdfrac%7Bx%5E2%7D%7B%28r_1%29%5E2-x%5E2%7D%3D%5Cdfrac%7B%28y-a%29%5E2%28r_2-y%2Ba%29%28r_2%2By-a%29%7D%7B%28y%5E2-2ay%2Ba%5E2-r_2%5E2%29%5E2%7D) to find the relationship between $x$ and $y$, keeping $a$, $b$, $r_1$ and $r_2$ constant. The solution included terms like $r(1)$ and $r(2)$ instead of $r_1$ and $r_2$. I've never used Wolfram Alpha before and I would like to know if $r(1)$ means $r_1$, in …