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03:00 - 16:0016:00 - 21:00

123
4:00 PM
Pls share few examples where use of newton's law is difficult to solve the equations and idea of energy is helpful.
 
@123 go through this playlist and your understanding of the topic will definitely increase. Follow the channel (Physics Galaxy) for more.
 
ABC
Guys in the drude-lorentz model for the current in a metal wire, the electrons can touch each other?

I'm talking about this model : https://en.wikipedia.org/wiki/Drude_model
 
@123 Conservation of energy and momentum is enough to solve an elastic collision easily but it's pretty hard to get the result just from Newton's laws directly.
 
@ACuriousMind Reminds me of a question in a high school assignment where I spent a really long time messing with the math to try and solve some problem about like a trapeze artist or something. Turns out it was like a 3 line answer when you used energy and not just forces and for some reason I just got laser focused on the wrong way to solve it.
 
123
@KenzoTenma Thanks for sharing the link.
 
4:06 PM
@123 Net Force
 
@JMac What it was?(I mean the question)
 
@123 Conservation of energy is an assumption that has been experimentally verified, what I did was just to show you the intuition
 
123
@ACuriousMind Ookay.. Why inelastic collision energy is not conserved (may be loss of energy by producing heat or changing shape of object) but how momentum conserved?
 
@JohnDuffield Hey, I just looked into your papers, those are great!
 
123
@Azmuth Azmuth thanks a lot you really helped me a lot to understand this topic.
 
4:08 PM
Do you have some more interesting stuff about Quantum Mechanics and GR? @JohnDuffield ?
welcome :)
 
@Azmuth : my papers? You mean the papers I referred to by guys like Born and Infeld?
 
@JohnDuffield Last time you showed me? Those were written by Penrose I really liked few of them, (rest were a bit out of scope)
Do you have more interesting papers?
 
@Azmuth : I've read hundreds of old papers. Some I think are great, some I think are awful. For example, I'm a big fan of Einstein, but I'm not a fan of Penrose.
 
123
For Integral you shared. We need mass, resultant of forces $\vec{F}(x)$ , velocity $\vec{v}(x)$ between two points. this is the requirement to solve the problem.
 
@123 yes! That by definition
@JohnDuffield Show some more!
related to QM, GR....
@JohnDuffield Have you read original Papers for Einstein-Podolsky-Rosen Paradox? and No go papers?
 
4:13 PM
@JackRod Don't remember exactly, but it had something to do with height and velocity, and for some reason I tried to solve like generic dynamics for it. I'm not even sure if there was enough information for it, and I just got sucked in trying to derive all the information I needed.
 
You'll love them!
 
@Azmuth : see this comment where I referred to a gamma-ray-burster paper by Friedwardt Winterberg: chat.stackexchange.com/transcript/message/55932640#55932640. He was the guy who came up with the idea for GPS.
 
123
for newton's second law we need acceleration and mass. What is the problem solving according to second law? What is mostly unknown/problematic parameter here
 
@Azmuth : yes, I've read the original paper on the EPR. I think it stinks. I'm reading it saying to myself: Albert, what are you doing getting mixed up with garbage like this!
 
@JohnDuffield okie dokie!
 
4:15 PM
@JMac In your days of high school you guys crammed the derivation?
 
@JohnDuffield Haha! So you don't really like copenhagen interpretation? :P
 
@JackRod No I just mean like I was trying to use the information I had to figure out the last piece of information I thought I needed to solve it, when instead you didn't have to do any of that and use energy instead.
 
Ok ok
 
@Azmuth : nope. Not a bit. I'm with Einstein on that. He was a realist.
 
@JohnDuffield Many World Intrepretation?
 
4:18 PM
@Azmuth : I hate it.
 
@JohnDuffield degruyter.com/view/journals/zna/56/12/article-p889.xml This paper is actually pretty useful and simple to understand! I like such papers! :)
@JohnDuffield Haha! Me too! But, its easy ones for beginners to get started with! :)
 
@Azmuth : read the paper by Winterberg, and also read the 1939 "black hole" paper by Einstein, (pdfs.semanticscholar.org/8dd0/…) and there's something that ought to jump out at you.
 
@JohnDuffield okay, lemme check it! :) :D
 
@Azmuth : It will take you too long, and I will have to go soon. So here's a clue. This is what Einstein said about the event horizon. There's something wrong with it: "This means that a clock kept at this place would go at the rate zero. Further it is easy to show that both light rays and material particles take an infinitely long time (measured in “coordinate time”) in order to reach the point r = μ/2 when originating from a point r > μ/2”.
 
4:24 PM
@JohnDuffield Wow! very very thanks for the papers :)
@JakeRose If you don't mind telling me which software & Tablet is that?
 
For this transformation, does it mean how I’ve done it? Namely, to first order?
Its an iPad Pro, Apple Pencil,and notbsility
notability*
 
Yo! Gr8 buddy :)
 
@Azmuth : here's another one, Oppenheimer and Snyder's 1939 "frozen star" black hole paper: journals.aps.org/pr/abstract/10.1103/PhysRev.56.455
 
@JohnDuffield You've a postdoc?
@JohnDuffield I've read this one before :)
 
@Azmuth : no, I'm just an IT guy. I have a computer science degree, and that's all.
 
4:28 PM
@JohnDuffield same for me! I too have a B Tech in Computer Science... (expected 2023)
 
@Azmuth : LOL, I am an old IT guy! When I started out, the computers had beads!
I hope you've read this article too: authors.library.caltech.edu/14972/1/…
 
123
@KenzoTenma I saw this link but this is very elementary. and he is explaining the topic as it is already written in books.
 
@JohnDuffield I've just passed out High School.... First week about to start in December.... (Although Tuition classes already started!)
@JohnDuffield Are you good with assembly and compiler design?
 
123
@Azmuth @ACuriousMind given me some basic ideas. Need of work done and energy.
Pls explain me this way.
 
@Azmuth : nope!
 
4:31 PM
Oh okay
@123 like?
 
123
Like explaining term by term.
And there usage. Difficulty in previous idea. That's why we need work done. How energy is useful. This way
 
@123 Try solving questions. We usually use energy when the path of the object is complicated enough, introducing energy concepts makes things easier. Try solving questions.
 
123
That's compelling answer so I can feel the problem. And benefit of energy. Thanks
 
:-)
 
123
But we must know force as a function of position for energy.. Is that true
 
4:38 PM
Depends on question, there's no hard and first fule...
 
@123 : you should read about the mass-energy relation: en.wikipedia.org/wiki/… . Gravity converts potential energy into kinetic energy, which is then dissipated, and then you're left with a mass deficit. That means the gravitational potential energy is mass-energy. Then if you read Einstein's E=mc² paper you will reason that mass-energy is internal kinetic energy. So gravity converts internal energy into external kinetic energy.
See this bit: "If a body gives off the energy L in the form of radiation, its mass diminishes by L/c²". Einstein used an L instead of an E.
 
5:05 PM
I have to go I'm afraid. Nice talking to you guys
 
5:37 PM
Can someone here tell me that when a pendulum is tied to the ceiling of an accelerating car does the Bob remain at its place due to inertia and rest of the string goes with the car ?
For some time ?
 
123
5:58 PM
@JohnDuffield Thanks ..
@Azmuth Okayie.. I there any GooD Book to read work energy theorem which explains my problems related to me in the topic. So, i can further consult with that.
I read Kleppner Kolenkow it was super nice to read.
If we know the Force as a function of position. We can easily determine the path.
 
6:34 PM
K&K explain how to view work-energy as arising from forces we know are position-dependent and have no idea how it's time-dependence is, another book that stresses this is Symon
 
123
@bolbteppa Hmm... That's new information for me. We know position dependent but don't know time dependent. $\vec{F}(x(t))$ this is full explaination.
 
Have a look at the first page of chapter 4 of K&K
 
123
I read this in K&K now i remembered.
Pls share the book name of the author Symon
 
stupid question here...
According to wikipedia, gravitational mass is the attraction between two objects
I think I am not quite understanding what they mean...
 
123
@traducerad Why you are angry man....? :p
 
6:45 PM
What do you not understand about that statement?
 
if I place a sandwich on my left side and a glass of water on my right side, they don t seem to be attracted, as they don t move towards each other (like eg magnets)
@123 Nah, not angry.
 
They don't move towards each other, but they are attracted
 
@Charlie How so? oO
 
123
@traducerad Because the force of attraction very weak due to low mass.
 
Because the force of gravity between them is not enough to overcome the frictional force of the table that stops them from moving towards eachother
 
6:46 PM
@Charlie so in outer space or in a vacuum they would gravitate towards each other?
 
Gravity is an exceptionally weak force, relative to the others
Yes
 
@Charlie not gonna lie, I find this very surprising
 
How so?
 
this means that in outerspace everything would just collude to one single large ball, no?
eg all those space debris are attracted to each other and form a ball
 
Well, some things do. Galaxies for example
 
6:48 PM
That's basically how planets get made; but also consider that when you do the mass the force is quite low unless they are massive.
 
put two people in a vacuum chamber and they ll stick together
 
Not really, because the gravitational force between two people is so small they could easily push each other away
 
123
$\vec{F} = G \frac{m_1\cdot m_2}{r^2}$
 
But they would slowly move towards each other, yes
 
Particularly if the room was also frictionless
 
123
6:49 PM
Put $m_1 = m_2 = r =1$ then $\vec{F} = G$
 
I see... funny... didn t expect that at all
 
123
then $\vec{F} = 6.67 \times 10^{-11} N$
 
If you're surprised that galaxies aren't just balls of matter, remember that satellites orbit the Earth and remain there indefinitely even though there is a force between them and the Earth. (ignoring atmospheric stuff slowing them down)
 
@123 well no, I think you d have $\vec{F} = m^2 G$
 
Well technically you'd have neither of those since you're equating a vector and a number but still :P
 
123
6:52 PM
How $\vec{F} = m^2 G$
 
@traducerad But if m's are 1, that's $1^2 G$
 
123
Put $m_1 = m_2 =1$ also
because the masses are low you put $m_1 = 1000 Kg$ and $m_2 = 1000 Kg$ force is still weak.
 
so basically 2 1kg objects 1m apart have like no gravitational force between each other ($6.67 *10^{-11} N$, or $0.0000000000667 N$ of force)
 
OK, I think I can just summarize this as: "Yes, there is such a thing as gravitational force but you barely notice it because it is so small. You would see it in a theoretical vacuum room with no frictional force and no earth, because then the two inert masses you placed in it would just move towards each other. If you d have a room of vacuum on earth you d still not see much because the gravitational force towards earth would be much larger than your 2 objects amongst each other"
Or am I drunk?
 
It's still barely any force regardless of if Earth was there. They would slowly accelerate towards each other; but it wouldn't even be noticeable for awhile assuming we aren't talking quite massive objects.
 
6:59 PM
The presence of the Earth beneath the two objects in the vacuum doesn't affect the force of gravity between them
 
123
@JMac If you two heavier objects each 1000Kg and placed carefully horizontal on the surface as lift with up with air jet you will definitely see attraction between them.
 
@Charlie But can t yiou say that the two masses would be attracted muuch more to the eart than to each other due to the earths mass? Which is why with the earth's presence you d barely see anything
 
123
Like an "Air track" experiment
arrange the setup of experiment. Then you will the gravitation without harm of attraction of earth.
Hello @JohnRennie , How are you sir.
 
@traducerad Your first statement is correct, the force between the objects and the Earth would be much larger (assuming they are a lot less massive than the Earth) but it does not then follow that you would see barely anything.
If you just let the masses drop towards the Earth and they hit the floor that would of course stop them from moving towards each other due to friction. But the presence of the Earth underneath them doesn't make the force of gravity between them any weaker.
 
123
Sorry not 1000Kg rather 100,000Kg each because we need to overcome $10^{-11} $
 
7:07 PM
@Charlie I see what you mean, fair enough
 
123
@Charlie Ookay now i see the problem.
 
@123 At 1m apart that's still only 0.00000667 m/s^2 of acceleration.
 
123
@JMac Yes if we increase the masses of objects the attraction between earth and masses become stronger.
 
@123 But with such large masses the acceleration between them is also small, even if they are somehow extremely close together. I don't think you would notice 0.00000667 m/s^2 of acceleration even if you somehow had a device that could make two 100,000 kg frictionless and 1m apart
 
123
I think $g = 9.8 \frac{m}{s^2}$ and it only depend on source mass mean Earth.
not the mass of object. Earth apply different force on different objects to keep g = 9.8
 
7:16 PM
@123 I'm talking about your comment "If you two heavier objects each 1000Kg and placed carefully horizontal on the surface as lift with up with air jet you will definitely see attraction between them." Which you then corrected to 100,000 kg. Even with those masses, you wouldn't notice the acceleration even if you got them 1m apart...
 
123
@JMac Yes you are right if we create a very big smooth surface and put 1,000,000Kg of masses of each then we can observe attraction.
@JMac Why.. we can not see attraction between 100,000Kg
 
@123 If you somehow had two 1,000,000 kg masses 1 m apart (not sure how you could get them that close) acceleration between them is 0.0000667 m/s^2, you likely wouldn't notice the acceleration even in that impossible scenario. I think you're forgetting the more massive the objects, the less the force accelerates them.
 
123
Ahaa.. OoKay... I calculate the force not acceleration. Hmm...
 
Yeah the force is 66.7 N; but that's nothing to something that weighs 1,000,000 kg
 
123
May be we need to setup such experimental setup at which we can see the acceleration. Like Torsion Balance
I forgot to calculate acceleration between them.
If we put $m_1 = 10^{11}Kg$ and $m_2 = 1kg$ we may see the effect of gravity. but how it is possible
 
7:38 PM
Isn t it actually weird to call "the coriolis effect" also "the coriolis force"?
As it is not an actual force. The object in question seems to deviate from its path but it s not. So no additional forces actually acted on it
 
Why would it be weird?
 
To me it looks like it should just be called "the coriolis (visual) effect"
 
We shouldn't use centrifugal force either then?
 
For instance take a sniper that wants to hit a target at 10km, he will see his bullet deviate because the earth and his target moved while the bullet was flying
but no additional/new forces actually acted on the bullet
 
123
In my opinion don't check gravitation with heavier masses it could be fatal for earth and moon :p :)) . Try careful and intelligent experiment with smaller masses which could be possible to do.
 
7:42 PM
@traducerad So we need to rename centrifugal force too you're saying?
 
123
Like Torsion Balance
 
@JMac eventually, dunno
 
@123 The way they did it back in the day involved just looking at the movement of planets around us, thankfully you don't have to actually make them smash together to understand the forces at play
@traducerad Well they are both pseudo-forces, yet they typically get called a "force" in physics; and it's generally just understood (and often stressed for centrifugal force) that it's an effect of non-inertial reference frames and not an actual force
 
@JMac "pseudo-force" that s an interesting way of calling it, I like that one.
 
123
@JMac ;p you are right.
 
7:45 PM
@traducerad I didn't come up with it. It's a pretty common term for it, along with fictitious force
 
This being said I just realised centrifugal force may actually be an actual force. When spinning in a carousel you do feel an actual outward force
 
@traducerad It's just as real as the Coriolis force (i.e. not really a force)
 
well, then it is not a "pseudo force"?
@JMac What is that "non-force" pushing me outwards when spinning in a carousel in that case?
 
123
@traducerad Yes it is psuedo force just a matter in which frame of reference you are.
 
This is what I mean by carousel, just to be clear: imgur.com/a/5oCVI0j
 
7:50 PM
@traducerad Inertia. To someone watching from outside, physics says you should keep moving straight forward with the same velocity unless a force stops you. The feel of being pushed away from the circle is really the force pushing in to keep the movement circular instead of allowing it to go in a straight line.
 
To someone standing watching you on the carousel there is no outwards force. The outwards force you feel is "fictitious" in the sense that you only observe it when you're in the non-inertial frame of reference riding on the carousel.
 
I see two things here:
 
To put it another way, the actual force is centripetal force for a non-rotating observer; when you're spinning in the circle, that force pushing you in a circular direction feels like you're being pushed back instead, due to the spinning frame.
 
In a similar way, if you're sitting in a car and a large force is applied to push the car forward, you (a passenger) feel as though you're actually being pushed backwards into your seat, even though the only external force being applied is in the direction of travel of the car.
 
A big reason it feels so different is because when you're spinning, you're always facing the same direction relative to the circle, so the force always acts on the same part of you; while to an observer, the force is constantly changing direction.
 
7:56 PM
1) you sit on the carousel and spin around. In this case you do feel an actual outward force, aka centrifugal force.
2) you sit on that carouse, spin around AND throw a ball to the guy sitting in front of you on the carousel. In this case there is no force felt or whatsoever when throwing the ball. It will just follow a straight path and while flying your friend will have moved/spun a bit further. You therefor have no force here, just some sort of illusion if you are in that framce of reference
So to me centrifugal force is an actual force, Coriolis is not.
 
Uh no, to my understanding the Coriolis force and the centrifugal force arise from the same issue
Although they are obviously different situations
 
@traducerad Centrifugal force isn't an "actual" force. Just because you feel a force, doesn't make it a true force. It's because a rotating reference frame is always changing direction that gives the appearance of true forces.
 
@JMac I see
 
Just like if you're in a car that accelerates, it feels like you're being pushed backwards; but the real force acting on you is pushing you from behind.
 
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