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7:00 PM
superior to anything I would qualify as passable? No.
 
@Blue Isn't time pointless in the quantum world. Aren't things moving too fast and weird stuff happen with relativity?
 
Anonymous
@NovaliumCompany No.
 
@NovaliumCompany There are cases in which you want to look at a wavefunction that depends on time and cases where you don't. If your book doesn't explain that, I would submit it's not a good book :P
 
I'm actually not remembering the exact consequence of regular vs. regular singular vs. irregular singular point
 
Anonymous
You don't have to worry about relativity, now.
 
7:01 PM
@NovaliumCompany In some situations the wavefunction depends on time. In other situations it doesn't. The notation adapts to the requirements of the situation.
 
@NovaliumCompany Standard quantum mechanics has nothing to do with relativity - and time is not "pointless" even in relativity!
 
Anonymous
In case the wave function changes with time, it is a function of both $x,t$. Then you write it as $\psi(x,t)$, otherwise just write $\psi(t)$
 
Wikipedia says $y'' + a(x)y' + b(x)y = 0$ has an regular singular point at $x = x_0$ if $a(x)$ has a pole of order <= 1 at $x = x_0$ and $b(x)$ has a pole of order <= 2 at $x = x_0$.
 
@ACuriousMind time is just the fourth dimension, maaaan
 
for second-order ODEs, I think regular singular means you can write down Frobenius solutions in the vicinity of that point
 
7:02 PM
If something is not a regular singular point it's irregular
 
Ok then. Thanks. Last thing. Ψ(x, t) must be equal to something right? To what? I mean, since it's a function Ψ(x, t) = ?
 
so having irregular singular points means solutions don't even have to be that nice
 
@NovaliumCompany Your question is equivalent to saying "I sometimes see x used for position, e.g. when calculating the static equilibrium points of a system, and I sometimes see x(t) used with a time dependence, for describing trajectories"
there's no contradiction - just different situations.
 
Now I don't think I understand why that's equivalent to essential singularity of the solution at $x = x_0$
 
@NovaliumCompany Nope, there's plenty of time-dependent phenomena in QM.
 
7:03 PM
@BalarkaSen I don't think that's the precise statement, no
 
Ok I got it, time is important :D
 
56
A: Is there oscillating charge in a hydrogen atom?

Emilio PisantyIn this specific instance you are correct. If you have a hydrogen atom that is completely isolated from the environment, and which has been prepared in a pure quantum state given by a superposition of the $1s$ and $2p$ states, then yes, the charge density of the electron (defined as the electron ...

here's one example
 
Anonymous
@NovaliumCompany It could be equal to any function of $x,t$.
 
@BalarkaSen See for instance this: en.wikipedia.org/wiki/…
 
Anonymous
You need to define it according to the situation
 
7:04 PM
↑ there's a huge slew of examples
hmmm. didn't Amazon links onebox?
 
@Blue I don't get it. I mean, f(x) = for example x + 2. Ψ(x, t) = ?
 
@Semiclassical So what's the geometry/dynamics at irregular singular points?
 
confusing, that's what it is
 
You're supposed to know that, physicist!!!
 
@NovaliumCompany depends on the situation.
 
7:05 PM
Ok please give an example.
 
@BalarkaSen are physicists supposed to know that?
 
Anonymous
@NovaliumCompany Say Ψ(x, t) = xt or Ψ(x, t) = x+t, etc
 
This is why I hate you people
 
@ACuriousMind do you know anything about ODEs?
 
Oh, I got it.
 
7:05 PM
I have nothing but haaaaate for you
 
@BalarkaSen I am announcing my intention to flag.
10 seconds
5 seconds
 
@0celo7 Don't.
 
"Otherwise the point a is an irregular singularity. In that case the monodromy group relating solutions by analytic continuation has less to say in general, and the solutions are harder to study, except in terms of their asymptotic expansions."
 
@ACuriousMind Don't what?
I thought we were supposed to use our words before flagging?
 
ugh
don't give the rest of us a headache
 
7:07 PM
@Semiclassical you lost me at "monodromy group"
 
@0celo7 Yes, but you're not supposed to say "I'm gonna flag that" but instead explain what bothers you about the specific message/situation.
 
it's the kind of term that makes me go "well, shit. I should know this. But I definitely don't."
 
@BalarkaSen Hate isn't cool man
 
basically, how the various solutions of an ODE transform under analytic continuation
 
7:07 PM
@0celo7 HAH
 
@Semiclassical hmmmmm
 
Great use of words there, Shakespeare
Fucking Dante
 
@BalarkaSen ah
ugh
 
i.e. if you analytically continue one of the two solutions of a second-order ODE around a regular singular point, you'll end up with a linear combination of the two solutions
 
pffff
 
7:08 PM
@Blue Let's say I want to calculate (In a double slit experiment with electrons) the probability of an electron landing on x = 2m, without using time. How am I going to do that. I know I don't understand the stuff yet, but I'm still learning.
 
@BalarkaSen ok, please no foul language
 
and the monodromy group contains all the info about that
 
@Semiclassical oh, and the monodromy group is the matrix encoded by that linear combination?
 
@EmilioPisanty I only know about the monodromy group in the context of Riemann surfaces, which I can explain if you want.
Actually maybe you know that already
 
if there's only one singular point, yeah
 
7:09 PM
@Semiclassical ah
 
a lot of ODEs have more than one regular singular point, though
 
@BalarkaSen that's probably more intense than I have mental bandwidth for at the moment
 
in which case each regular singular point generates such a matrix
This does connect with the Riemann surface stuff insofar as a lot of the solutions to differential equations in mathematical physics can be understood as integrals on Riemann surfaces.
Airy's integral isn't one of them, though...wait. hmmm
 
btw, whatcha make of this?
> Unfortunately we couldn't access the thesis via the link you sent us, as it seems to be located on a private server, and so it is difficult to check this on your behalf. We would appreciate it if you could send us a copy of the relevant pages (p5?) of the thesis that you mentioned.
...
if you couldn't access my thesis
 
Anonymous
@NovaliumCompany I think you should learn about probability distributions first
 
7:11 PM
then how did you figure out which page the copyright declaration is on?
 
huuuuh
 
@Semiclassical Ah
@EmilioPisanty Hah fair
 
Anonymous
More importantly probability density functions
 
Where, for free :D?
 
@0celo7 Fuck, I'm sorry
 
7:12 PM
iirc you can view Airy's ODE as the confluence of two regular singular points in the hypergeometric ODE?
 
I'll try not to do that again
 
and confluence of singular points makes things weird
 
@Semiclassical ugh
 
Anonymous
@NovaliumCompany Check Khan Academy
 
@ACuriousMind Ok, I asked Balarka not to use foul language and he is deliberately trolling me.
 
7:13 PM
@Semiclassical but then that's true of, like, 50% of special functions, no?
 
@Blue I just clicked on the video, and you said that :D
 
yeah, for instance Bessel functions are like that
 
@0celo7 Oops, I fucked that up didn't I
 
@Semiclassical unsurprising
 
The biiiiig exception to all of this are the Painleve transcendents
 
7:14 PM
@Semiclassical possibly also the Gamma function?
 
But once you do that you're doing nonlinear ODE and then you're in for a world of hurt
 
@EmilioPisanty the amazing thing is that the spacing is right, so they did log\, u instead of \log u. Incredible.
 
@EmilioPisanty Maybe
 
@0celo7 @BalarkaSen I'm really not in the mood for this, can we just drop this?
 
which ones did Berry say?
 
7:15 PM
Not sure. I know the Gamma function has Stokes lines
 
@ACuriousMind Ok, sorry.
 
but I'm not sure how it works vis a vis differential equations
 
> For example, Mathieu functions fall outside the hypergeometric class, and gamma and zeta functions are not the solutions of simple differential equations
 
Mathieu functions are awful
 
7:16 PM
What I always really wanted to understand were finite-gap potentials. (by comparison, the mathieu equation corresponds to a cosine potential with infinitely-many gaps)
but I could not understand it
the Inverse Scattering Transform is tough going
 
@Semiclassical well, that one is worth learning
 
@Semiclassical wait, what?
 
yuuuup
 
whatcha mean by finite-gap vs infinitely-many gaps?
 
7:18 PM
lemme find a link
It's in the sense of band theory.
 
I have heard the CM theorists whisper about gapped potentials, but I've not idea what they actually are
 
@ACuriousMind Working in COBOL clearly made you lose your soul
 
LOL
 
@BernardoMeurer I'm flattered you think that I ever had one :P
 
who even uses COBOL in this day and age
 
7:23 PM
I'm a good Christian man, of course I think you had a soul
@BalarkaSen ACM
Banks
Old people
 
Fucking hell
 
This is a Christian server
no soulless people allowed
 
True
NOT ON MY CHRISTIAN CHAT
(g)old
 
Far Cry 5 is about misunderstood Christians you know
 
I only believe in Pagan Christianity
 
7:24 PM
systems for which the idea of upgrading your OS is a terrifying suggestion
 
I have donated my soul to the pagan gods
 
@BernardoMeurer ah, but are you John Oliver's #NotMyChristian?
 
@Semiclassical Ubuntu
@EmilioPisanty My name is not Christian, no
 
u sure bro
?
=P
 
Christian Meurer is his real name
I confirm this
 
7:25 PM
@BernardoMeurer hey do you wanna talk. I've got to fill out this Brazilian visa application
 
::checks passport::
I'm positive
@0celo7 Sure, gimme a call
 
@0celo7 r u going to the ICM
 
how do I apply for a weapons permit
@BalarkaSen yes
going to get shit-faced with Yau
 
bleh, I can't remember where I learned what I did about finite-gap potentials
mutter
 
well, hopefully I can at least meet him
 
7:26 PM
@0celo7 You can't
I can though
 
@BernardoMeurer I don't trust a Brazilian near me with a gun
no offense
but you're all kind of shady
 
This long article is a good summary of the history: pdfs.semanticscholar.org/a442/…
 
Don't worry, our police has got your back
 
@BernardoMeurer is this 805 number yours?
 
7:27 PM
Yea
 
But I'm not finding an easy summary of finite-gap integration
 
805-886
 
I didn't know I actually had a number for you. Huh.
I've always just facetime audio'd
 
I guess the simplest example is just the Lame equation?
 
@Semiclassical lame
 
7:28 PM
@Semiclassical nah, that's lame
 
@Semiclassical Wait, is it really called lame equation?
 
In mathematics, a Lamé function, or ellipsoidal harmonic function, is a solution of Lamé's equation, a second-order ordinary differential equation. It was introduced in the paper (Gabriel Lamé 1837). Lamé's equation appears in the method of separation of variables applied to the Laplace equation in elliptic coordinates. In some special cases solutions can be expressed in terms of polynomials called Lamé polynomials. == The Lamé equation == Lamé's equation is d 2 ...
 
@Semiclassical imagine being named Dr. Lame Tits
2
 
7:29 PM
no, I was just being Lazy
 
@0celo7 Oh god.
 
well
The Cox–Zucker machine is an algorithm created by David A. Cox and Steven Zucker. This algorithm determines if a given set of sections provides a basis (up to torsion) for the Mordell–Weil group of an elliptic surface E → S where S is isomorphic to the projective line. The algorithm was first published in the 1979 paper "Intersection numbers of sections of elliptic surfaces" by Cox and Zucker and it was later named the "Cox–Zucker machine" by Charles Schwartz in 1984. == References == Cox, D. A.; Zucker, S. (1979). "Intersection numbers of sections of elliptic surfaces". Invent. Math. 53: 1–44...
 
@0celo7 Relevant context for any potential flaggers: Lamé, Tits
 
from the talk page: "It's real, all right - Mr. Cox is my father, and he wrote the paper with Mr. Zucker specifically because it would be the "Cox-Zucker" paper"
 
@EmilioPisanty Risky move there, trusting yourself to find the links within the edit window ;)
 
7:31 PM
"Risky move there, trusting people judging spam flags to consider context"
 
There's a quora post where someone asks if Jacques Tits' last name is really pronounced like an american would pronounce tits and right below there's an answer by Jacques Tits' grandniece
 
(my cynical take)
 
a-w-k-w-a-r-d
 
@ACuriousMind I believe in living dangerously =P
@Semiclassical that was the real danger, indeed
 
@BernardoMeurer brazil.travisa.com
 
@BalarkaSen maybe we should add a clarifier to the room description?
 
@EmilioPisanty I'm not sure that "semi-regular discussion of Tits" is a good tagline...
 
What if Tits marries Cox but does the double name
 
Lol
@0celo7 Oh my god stop
 
@Semiclassical It has happened before
at least on occasion
 
7:36 PM
was not doubting you
I am pretty cynical about how flagging works
both w/r/t how it's applied and how it's assessed
 
@BalarkaSen 0celo7 is American. If I understand correctly, you need to say "omaigawdstaaahp".
 
Well unless he's an anime boi in which case,
 
I'm German, thank you very much
 
@0celo7 ah
then more of a "ach, mein Gott, bitte halt!"?
 
7:40 PM
...how did we get here from a discussion of gapped potentials?
 
I guess this is more appropriate: youtube.com/watch?v=P-3GOo_nWoc
@ACuriousMind eh, I sorta gave up on that
 
@EmilioPisanty That doesn't sound very idiomatic to me, actually :P
 
@ACuriousMind we were playing snakes and ladders and we hit a snake labelled "The h Bar"?
 
@EmilioPisanty Sounds legit
 
I'm pretty sure there's always a 10- to 15% chance that any discussion of stuff associated with Gabriel Lamé on this chatroom will send the conversation careening into a discussion of the names that just appeared.
 
7:43 PM
oh, right, Lamé equation
main point with that is that the continuous spectrum has one gap
 
I don't know that there's ever been a legit discussion of Jacques Tits's work, let alone one that wasn't immediately followed by such a careening trajectory.
 
whereas the Mathieu equation has infinitely many
 
@Semiclassical what?
ain't no gaps there
no?
 
in the spectrum, there are
 
@Semiclassical between what and what?
this is $H=\frac12 p^2$ over $\mathbb R$ we're discussing, right?
 
7:46 PM
No.
 
Mathieu is $H=\frac12 p^2+\cos \theta$
Lame still has a periodic potential but it's an elliptic function
 
@Semiclassical and that's the one with no gaps?
 
actually, it has one gap. but just one
 
@Semiclassical Jesus christ
 
7:49 PM
one way to look at it: you start with $H_0=p^2/2$, which has all periodic and antiperiodic solutions (except the singly-degenerate ground state $\psi=1$) being doubly-degenerate
 
@Semiclassical wait
domain?
boundary conditions?
 
If you're thinking in terms of periodic/antiperiodic, it's $[0,2\pi)$
but antiperiodic solutions are 4pi-periodic on the real line
This is all band theory stuff.
You're interested in solutions which remain finite on the real line
 
Since the potential is periodic, that means you end up with solutiosn of the form $\psi(x)=\phi(x)e^{i k x}$ with $\phi(x)$ being periodic
and real $k$ (if it's not real, then the solution diverges as x goes to plus or minus infinity)
 
7:54 PM
and that leads to pictures like this:
where the dashed line is what you'd have if the potential was zero
and the potential makes those into avoided crossings. (they've got $\kappa$ instead of $k$ there)
the point, though, is that in the cosine potential case you turn all crossings into avoided crossings
and wherever that happens, you get a gap
 
@Semiclassical yes
 
with the implication being that the solutions to the Schrodinger equation at that particular energy have $k$ being complex
 
and with Lamé that only happens with one of the gaps?
 
Right.
 
ah, fair enough
that's a pretty special case, though
 
7:58 PM
yeah
you can also do cases with finitely-many gaps not closed
 
42 mins ago, by Semiclassical
What I always really wanted to understand were finite-gap potentials. (by comparison, the mathieu equation corresponds to a cosine potential with infinitely-many gaps)
I was confused by "finite gap" implying that the gap's size was finite
 
ah, yeah
 
-1
Q: Proving that $⟨\phi_{n} \mid a + b \mid\phi_{n} ⟩ = ⟨ \phi_{n} \mid a \mid\phi_{n} ⟩ + ⟨ \phi_{n} \mid b \mid\phi_{n} ⟩ $

BahaaI am trying to prove to myself that this relation is true. $$⟨\phi_{n} \mid a + b \mid\phi_{n} ⟩ = ⟨ \phi_{n} \mid a \mid\phi_{n} ⟩ + ⟨ \phi_{n} \mid b \mid\phi_{n} ⟩ $$ Where $a$ and $b$ are 2 operators. So the way I was trying to solve this was by writing the state vector $\mid\phi_{n} ⟩$ as...

 
hence why i said 'infinitely-many gaps' for Mathieu, though
 
poor guy
 

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