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8:00 AM
if you take a slice out of it, isn't the rest connected?
 
i am not sure what you mean
 
slice the torus in half
 
if you slice $T_1$ in half then $T_2$ inside is no longer connected.
you won't get a connected space, no.
 
oh
you may be right but I am surprised
 
anyway give some thought to it @TomCruise. if not this, continuums are the place to be looked for such spaces.
well, now you have some food for thought at least
 
8:04 AM
what if you just take a nested sequence of cylinders, one from each $T_i$
its intersection would be a proper closed connected set
 
an open cylinder? the intersection would just give you an open interval.
 
no you could do closed
 
oh a closed cylinder. then just a closed interval :P
 
yeah
so it doesnt have the property
 
it's a cute question to think about @TomCruise. i am beginning to appreciate it.
 
8:07 AM
I can give you one example if you like
it takes a little time to work out the details though
 
ok?
 
do you know the Knaster continuum?
 
nope
 
you take the cantor set
 
oh that one
 
8:09 AM
and then connect the points with these arcs
 
yes, yes, it's connected.
 
yeah
but it too has proper closed connected sets
it has intervals
 
mmyeah.
 
but you have $2^\omega$ of these loops such that no proper subcontinuum hits any two of them
to construct our space $X$ we choose a point from each of these loops in a special way
 
"special way"?
 
8:13 AM
it is clear that no matter how we choose the points we will get a space with no nondegenerate closed connected sets
but we have to choose them so that $X$ will be connected
you take a bijection $\varphi$ from the set of $\mathcal C$ loops to the set $\mathcal S$ of closed subsets whose complements are disconnected. Then you choose one point from each $C\cap \varphi(C)$ and call this $X$.
like I said there are some details you have to check, but this does it
 
eh. i don't see why this would make $X$ connected
yeah, there's some work to be done i guess
but i believe you
 
yeah its not obvious
anyway, the interesting thing is that the answer to the problem I mentioned is yes for this $X$
 
ok i forgot what the problem was :P scrolls above
 
every proper subcontinuum of $\beta X$ is nowhere dense
 
right, right.
hmm.
 
8:19 AM
but, is it a rational belief @BalarkaSen? ;-)
/joke
 
@TomCruise i can't visualize $\beta X$.
 
yeah that's tough to do
it is not metrizable usually
 
indeed. if you can give me a sketch of the proof, i am interested.
 
me too pal :D
runs for cover
 
well it turns out that the Knaster continuum has this property
and $X$ is dense in it
somehow $X$ inherits the property, and then $\beta X$ gets it
 
8:24 AM
lol
 
I have a page or two of lemmas that lead to this
the Knaster continuum is indecomposable - that is the key
 
might be. OK, I gotta go. do think about the solenoid stuff i mentioned above - i am pretty sure that it's a space with the properties you want. not sure how the compactification looks like though.
 
See you later my friend
 
but the solenoid contains closed intervals
 
 
1 hour later…
10:01 AM
@Venus Speaker?
 
10:17 AM
@Sawarnik Yup! :D
 
Hi there
If the det of a set of vectors is zero, why does not span a vector space?and why there is at least one solution from the vector space that ins`ton the set?
This is linear algebra
 
10:42 AM
@KellyBlunie I'm not good at linear algebra, maybe you should wait until this chat crowd enough & you may ask your question again. :-)
Just be patient
 
 
1 hour later…
11:50 AM
hi
anyone interested in probability? math.stackexchange.com/questions/1059379/… has no answer
 
@TomCruise it contains something homeomorphic to the closed interval you mean? i don't see why that is true.
 
 
1 hour later…
1:01 PM
@Venus I didn't understand :D
 
@Sawarnik I asked Anna yet you replied my comment. So, I suppose you as Anna's Speaker :D
 
1:13 PM
hi guys
is there anyone who knows a bit of conformal mappings?
 
I know a bit. Not much, so don't expect much out of me!
 
@Venus Oh lol :D
 
yeah, it's probably a silly question anyway, so I encourage you not to expect much of me!
:P
can we talk in private?
 
This is so LOL
11
A: Ways to write "50"

VenusWe can use only two famous numbers in mathematics, $\large\pi$ and $\large e$, to produce number $50$. $$\bbox[8pt,border:3px #FF69B4 solid]{\color{red}{\Large \lfloor e^\pi \rfloor + \lfloor \pi^e \rfloor + \lfloor \pi \rfloor + \lfloor e \rfloor = 50}} $$ Click the box to see Wolfram Alpha's ...

 
Why @Sawarnik does your avatar say "404"?
 
1:16 PM
@skullpatrol For no reason.
 
There's no private rooms, @GennaroMarcoDevincenzis, unless you just mean going to a separate, less populated room. (Others can still see it, though.)
 
I've just answered this question about 3 hours ago & before that it has lots of good answers. I'm so lucky :D
 
1:40 PM
@Venus u there?
 
@TheArtist Yup
 
@r9m. Last episode of Naruto is GREAT!!!!! I thought there was going to be a string of fillers. I'm glad that came to quick end.
 
@Venus I got an idea for a question, dono if it's possible to ask it here properly
 
@GustavoMontano You know it has ended right?
 
r9m
@GustavoMontano haven't seen it yet ! ;) no spoilers please ! ;)
 
1:46 PM
Hahaha. I watch anime.
@r9m. Tell that to @N3buchadnezzar.
Hahaha :D!
Get to it! You don't want to miss it!
 
r9m
okay :D
 
Wait, you have be on facebook, right?
 
@Venus What do you think about adding a question and tagging the top users at Integrals, asking them to share how they became so good at it. What resources came into help the most....wouldn't that be very helpful for readers ? :D
 
I don't remember if you added be before. WHATEVER YOU DO - DON'T LOOK AT MY COVER PHOTO!
 
r9m
@GustavoMontano I haven't checked fb yet ;) :P
 
1:48 PM
@GustavoMontano meeeh. Mainstream people. Hipsters watched the anime/read the manga before it was cool ;)
 
@Venus But then again :/ we are not sure if the users would answer it :/ what do u think? :D
 
Hehehehe.
 
@TheArtist I have seen a similar question
 
Hello @GustavoMontano
 
@BalarkaSen. How are you?
 
1:49 PM
So-so.
 
What did you get up to today?
 
@BalarkaSen many exams?
 
@N3buchadnezzar Finished.
 
33
Q: Some users are mind bogglingly skilled at integration. How did they get there?

JessicaKLooking through old problems, it is not difficult to see that some users are beyond incredible at computing integrals. It only took a couple seconds to dig up an example like this. Especially in a world where most scientists compute their integrals numerically, I find it astounding that people e...

 
r9m
@GustavoMontano Madara Uchiha Rises .. ! I'm on it :D
 
1:50 PM
Woooooooo!
 
@Gustavo I'm fiddling with solenoids.
What kind of math are you doing right now, @GustavoMontano?
 
@BalarkaSen How many?
 
Well, I recently finished Differential Geometry and Topology.
 
@N3buchadnezzar All of 'em. Even the results are out.
 
I've actually completed my undergraduate pure math courses.
I however want to go over Real/Complex Analysis and Topology.
 
1:51 PM
Topology is cool stuff.
 
Perhaps some abstract algebra as well.
How about you?
 
@BalarkaSen What is the cardinal number to your exams ;) I have six this semester
 
I'm learning algebraic topology @GustavoMontano
 
How is it? Any recommendations on books for it?
 
@N3buchadnezzar 7.
@GustavoMontano I'm studying Munkres.
It's good enough.
 
1:52 PM
@Venus but one answer ? Yes Ron Gordan is awesome. But it would be so cool if we can get so many users to answer a community wiki question, users like : soso45 , Chris's sis, Robjohn, Felix Martin, RON GORDAN, random variable, etc etc
@Venus Thanks for the link btw :D
 
Awesome!
 
@BalarkaSen Isnt Munkres Point set topology?
 
@N3buchadnezzar There is also a Munkres for alg top.
 
Ah, nice
 
@TheArtist I doubt there's a user will answer such question as stated in Ron G's answer, he himself was reluctant to answer it.
 
1:54 PM
@Venus Just practice. I have like 3-4 books on integration ^^
 
@TheArtist Try to set a bounty for that question instead of asking a new one because it will be likely closed as a dup
 
@Venus exactly coz no one tagged them, if the OP has tagged the users and seem like they are addressing them, she would have got more responses .....
 
@N3buchadnezzar So answer in the main then :D
 
@Venus He was reluctant to answer it because he didn't want to admit that he's awesome when it comes to Integrals ? :p
 
@N3buchadnezzar If I were asked such question, my answer would be three: 1. Practice 2. Practice 3. practice ^^
 
1:57 PM
@Venus and the answer by Ron Gordan is kinda generalised.....what I'm talking about is kinda like their lifestory (only about integrals) , how they achieved this. What books they read, etc etc :)
 
@TheArtist Just ask @Chris'ssis to answer it
 
@Venus but a post where all the stated users answer would be so perfect and beautiful
 
Hey @r9m did yous ee the RMO paper of thsi year? :P
 
@TheArtist Anyway, Ron G indeed mentioned some users that he considers as Integration Gurus on Math SE
 
@Venus yes I read. I want all those users to give an answer :/ and some more users
@Venus can I do like this ? Set a bounty saying : For soso45 to answer ? :p after he answers then set another bounty for another user?
 
2:04 PM
@TheArtist The experts tend to likely be humble. As the highest form of intelligence is knowing when to speak and to shut up ^^
@TheArtist I don't know. Let's ask our beloved moderator, @robjohn
@TheArtist If this is permitted, you must set 500 bounty to get a good response :D
 
@Venus Are you on FB?
 
@Venus I have 1k reputation , so I will only be able to get two users to answer
 
@Sawarnik FB?
 
FaceBook.
 
@Sawarnik Not online right now
Why do you ask?
 
2:09 PM
Do you ave an account?
 
@Sawarnik I do :p
 
@TheArtist no thanks :p
 
Ave?
 
@Sawarnik Don't you have RMO coming up?
 
@BalarkaSen Done.
Last Sunday.
:D
 
2:11 PM
Ah. How did you do?
 
3 solved.
 
Out of?
 
Could have done 4, but didn't pay attention :( :((
Out of 6.
 
@Venus we can start something like "bucket challenge" as "bounty challenge" , the user who gains the bounty must give it back by placing a bounty :p
 
Not bad at all, @Sawarnik. Don't fret about it.
Most barely do 2.
 
2:11 PM
@TheArtist Instead you spend lots of rep to get answer for your question, why don't you email/ chat them one by one? Maybe they will answer it if you ask them personally
 
Yeah, sure. Though the paper was easy this year, so cutoff is high and i won't qualify :O
 
The problems were all geometry?
 
@BalarkaSen No it was peasy this year.
@BalarkaSen lol, no way!
 
@TheArtist That's not how the system here works
 
@Venus good idea but how do I email them? Not like their email addresses are shown on the profile
 
2:13 PM
@BalarkaSen 2 geometry (both done easily), 2 number theory, 2 algebra.
 
Hey!? Since when I begin an expert on this site :D
 
No combinatrnics this time :O :O :D :D
 
What were the number theory ones, @Sawarnik?
 
@Venus but that's a one time exciting thing :D
 
Both were really easy.
 
2:14 PM
@Sawarnik combinatorics
 
I solved NT :D
@BalarkaSen Yes, I know.
 
@TheArtist You can chat them here for users like Chris'ssis or robjohn. Ron G & sos440 can be reached by using simple Google search
 
r9m
@Sawarnik no .. do you have them ?
 
@Venus okay :D thanks
 
^^
 
2:18 PM
@r9m not now :d
 
r9m
@Sawarnik you didn't appear for the test ? :o
 
you can't possibly forget all the questions @Sawarnik!
 
@r9m no i did.
:O
Ok, the questions are:
@bala Prove there is no natural n<2310 such that n(2310-n) is a multiple of 2310. Such easy.
 
basic modular arithmetic.
 
Even easier.
 
2:22 PM
you just need to prove that n^2 is not a multiple of 2310 for any n < 2310
 
@r9m The circumcircle of AOB intersects BC at X if O is the circumcenter. Prove that OX is perpendicular to AB. This was the easiest :D
@BalarkaSen Yup, exactly.
 
and note that 2310 is primorial 11.
 
Yeah.
 
r9m
I don't understand .. is it rmo or primary school selection exam ?! -_-
 
You did it in a whisper :O
 
2:23 PM
it's basic.
 
@r9m lol
RMO, actually.
It was so easy :O
 
never knew RMO was so easy
what was the other NT question?
 
r9m
@BalarkaSen I appeared in 2009 .. that year the paper was easy too (both rmo and inmo)
 
How many did you solve?
@BalarkaSen Find the all three digit numbers that S(S(n))=2 if S(n) is the number of digits.
 
i am not going to take MOs.
 
2:25 PM
Takes time, but nothing special.
@BalarkaSen We know.
 
@Sawarnik Ah. That is slightly better.
 
r9m
@Sawarnik rmo ? all .. ;) inmo (didn't appear ... final school exams)
 
@r9m Oh gawd.
 
use the explicit formula for number of digits, use some heuristics to bound up.
S(n) is the floor of log_10(n)
 
@BalarkaSen simply divide into cases..
3 digit numbers are no big deal :D
 
2:27 PM
so S(S(n)) is bounded above by log_10log_10(n)
 
r9m
@Sawarnik I remember a guy left the hall 15 mins before me =P ..
 
@r9m Couldn't you have seriously requested the school to shift the dates?
 
it's even simpler, actually.
S(n) is a 2-digit number
 
@Venus so what is your story :) You are good at Integrals too
 
@BalarkaSen true.
 
r9m
2:29 PM
@Sawarnik doesn't happen in my school (there were 4 others from my section who cleared the rmo .. two of them were prepared enough to ignore the school exams during the inmos .. ) but not me (I never studied the arts subjects)
 
@TheArtist Nah, I ain't good at it. Just learn from many gurus around here
 
@r9m Why did you give it only once?
Other years?
 
well you have a whole load of n-s, @Sawarnik
 
r9m
@Sawarnik I was on 11th grade (2009) :-)
 
it's tedious, neither hard nor tricky.
one has to look for such numbers via case-by-case analysis
 
r9m
2:32 PM
Naruto time BBL :D
 
@Sawarnik S(n) = 10 has solution n \in {10^9, ..., 10^10-1}. S(n) = 11 has n \in {10^10, ..., 10^11-1}, etc.
So your solution set is n \in {10^9, ..., 10^98-1} i guess.
 
WOOOHOOO! Go for it :D
 
WAT @GustavoMontano
 
Haha, talking to r9m. But I do not want to tag him as that will interfere with his current activity.
 
SHEESH. You guys are so serious with Naruto.
3
 
2:36 PM
I have been watching it for a very very very very VERY long time. It has become a part of me.
 
@Venus are u studying in undergrad?
 
Are you watching 391, @r9m?
 
r9m
2:53 PM
@Khallil ya ! just finished watching :D
@GustavoMontano ;) :D !!
 
What did you think?
 
r9m
@GustavoMontano there is no war without burning flesh and boiling blood !!! (evil grin) AWESOME
 
So good!
Ok, with that - I am off to bed. Far toooo tired! Goodnight! Can not wait for next weeks episode.
 
r9m
@GustavoMontano cool ! good night ! :)
 
@TheArtist Yes
You?
 
2:58 PM
@Venus I've suggested your nomination!
 
I am expecting a good answer for @Chris'ssis's question but what I got is so disappointing
-1
A: Evaluating $\int_{0}^{\pi/4} \log(\sin(x)) \log(\cos(x)) \log(\cos(2x)) \ dx$

Ferdinando RandisiMathematica cannot find an expression of this integral in terms of elementary functions. However, it can be integrated numerically, like this NIntegrate[Log[Sin[x]] Log[Cos[x]] Log[Cos[2 x]], {x, 0, Pi/4}] to yield the result -0.05874864

I downvote it
 

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