The Nineteenth Byte

4:16 AM

Ok, does {:Y} print the stack (or until it gets to something falsy)?

If it's a prime, there's no output, otherwise, there's potentially server "AHH NOT A PRIME"s printed.

@ATaco +1 for yodo

@ATaco Syntax errors all over the place.

I'm writing it as I read the spec.

You get me an interpreter, I'll get you code.

Comments are `text` not #text

#text only works on the first line, to allow for shebangs

4:19 AM

Why

hey, if you want me to do that

i can allow the comments to be # on every line

should I?

Why not

parsing

The way eLisp does it is it's a comment if it's the start of a line.

I can just delete all \n#.+\n

4:20 AM

@Pavel reeeally needs to be yoda instead

thanks pavel

It can theoretically be yoda without any problems.

@Pavel yes

...no

it ends up printing half the elements, since the loop pops the test's result

o

Oh,the loop is poppy?

4:22 AM

{:aY}?

something like {pa:Y}

no wait that's silly

yodo				# Read from STDIN a number
-1no 				# This will be the incrementer, so lower it by one
pa					# Duplicate the top of the stack
1no 				# But leave the other two as the original number.
pa					# Twice
{-1nupupapu-2nono:	# While the decremented bottom of the stack is truthy, leaving one of them on the top of the stack
	2no				# We subtracted two from that incrementer before, so that it would skip 1. Undo that.
	zo				# Modulus
	(to)?			# if the top of the stack is 0, thus, this is a factor.

Is there a way to print the stack? You can't distinguish 0 from empty.

{pa:y}up

4:22 AM

@MistahFiggins Syntax error, unfortunatly.

We can't add vowels to constructs.

@Pavel I replaced the goat with a test for empty.

Coolio

{goto:Y}

Y and y should be switched.

What will you do more often, print or take input?

Take Input, you don't own me

4:26 AM

No idea, but that will break all existing programs.

>_>

Anonymous

I don't think changing your username to promote a product is really appropriate for SE

Anonymous

Even if it's a non-commercial, open-source programming language

Riker

nice photoshop skillz

4:30 AM

I need to give RProgN a logo.

Can't be open-source if there is no source

@Riker MSPaint lol

@Mego It's been like that for a couple days, unless mods can change usernames it's not fixable for a month.

Anonymous

@Pavel Mods can change usernames, and have done it in the past for certain cases

@Mego I can't really see a problem with it...?

4:33 AM

There is also the fact that it's not causing any issues, yes.

Anonymous

Changing your username to promote a product is borderline spam imo

I was only going to keep it like this for a month.

@Mego "Product"

It's not like I changed my username to "Inexpensive Computers"

Conor O'Brien

@DJMcMayhem I answered your VBDay in Jolf. 7 bytes behind lol

DJMcMayhem

@ConorO'Brien I was literally just typing a message about that lol

Conor O'Brien

xD

now I need to study for my chem test tomorrow. o/

DJMcMayhem

4:39 AM

Your Jolf begrudgingly wishes V a happy birthday! Made me literally burst out laughing. :)

Conor O'Brien

:D

@DJMcMayhem I've been trying to learn Emacs Lisp today just so I can answer that challenge.

@CheckOutTomato Someone needs to draw an ASCII art tomato

                   ,
                  /.\
                 //_`\
            _.-`| \ ``._
        .-''`-.       _.'`.
      .'      / /'\/`.\    `.
     /   .    |/         `.  \
    '   /                  \  ;
   :   '            \       : :
   ;  ;             ;      /  .
    ' :             .     '  /
     \ \           /       .'
      `.`        .'      .'
        `-..___....----`

nvm, found one.

5:15 AM

let me design one

That looks like a Pumpkin.

@ATaco As far as I can tell, it is the only Ascii art tomato on the internet.

6:11 AM

@DJMcMayhem Happy birthday, V! Now in a month and a half, I'll have to come up with a birthday challenge for Pip. Hm...

DAE ever change their password, then type the new one accidentally?

6:33 AM

@CheckOutTomato you should make a way to apply multiple vowels to a consonant.

7:00 AM

Hello

7:11 AM

Is it possible to have a loop in 1D cellular automata?

@Qwerp-Derp Well, there has to be something akin to a loop, at least, for Rule 110 to be considered Turing-complete. But I don't know what that would look like exactly.

So, like a "clock" of repeating states, which doesn't stop or evaluate to anything.

I'm not sure if those exist, because altering one cell alters all the cells next to it as well

hi I need help with a thing

@Pavel That's supposed to be one of the difficulties, and what makes it an esolang. You can't just apply one vowel.

so, say I have 1/11, and 3/32, I add the numerators and the denominators for 4/43. how would I write this as a function?

in proper maths

(/ spreadsheet maths)

7:21 AM

@DestructibleWatermelon What do you mean "in proper maths"?

@Qwerp-Derp If you're looking for a periodic configuration in an elementary cellular automaton, those are pretty easy to come by. (E.g., have a rule where 010 -> 1, 110 -> 1, 011 -> 1, 101 -> 1, 111 -> 0 and give it an initial configuration of 01010: you get a period-2 oscillation.) If you're looking for a periodic configuration in a Turing-complete ECA, probably a lot harder.

@DLosc Nah, just this is fine. Thanks!

@Qwerp-Derp no awful hacks

@DestructibleWatermelon I'm still confused... do you want a MathJax thing or what?

Or like an Excel formula?

DestructibleWatermelon-- Let me paraphrase to see if I understand what you're asking. You have two rational numbers, x and y. Let x = a / b and y = c / d. Are you asking for a formula in x and y that results in (a + c)/(b + d)?

Anonymous

7:29 AM

@DestructibleWatermelon I'm assuming you want decimal input/output. For rational numbers, there are two cases: terminating decimals and repeating decimals. For terminating decimals, it's easy: write the value as a fraction with denominator 1, multiply by 10/10 until the numerator is an integer value, and reduce by dividing the numerator and denominator by their gcd. For repeating decimals, there's a well-known method.

Anonymous

So then you have a, b, c, and d (where x = a/b is the first input and y = c/d is the second input), so you can compute (a+b)/(c+d).

Anonymous

Now to get a formula for that algorithm, you just have to combine the various steps together

Anonymous

The method for computing the numerator and denominator of a repeating decimal works for terminating decimals too, so you don't even need the distinction between the two

@Mego What langs do you usually program in?

Anonymous

@Qwerp-Derp Python, C, JS

7:33 AM

In unrelated news, I made a sidebar thing in Clojure and CLJS!