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8:53 AM
Q: Was riemann aware of the issues with *i*?

Dan supports MonicaSo, when the zeta function was created, were they aware that i^4 equals 1, therefore (by commutation) i = 1? Were the various workarounds (if they even exist) available in his time or was he just ignoring that imaginary numbers arent actually valid within standard axioms? And (apparently) the rie...

Q: Is possible another solution to Fermat-Wiles theorem?

Alberto IbañezWith n >2, no possitive integers X,Y,Z $X^n+Y^n=Z^n$ so $Z^n-Y^n=X^n$ $Z^n-X^n=Y^n$ The little known notable product difference nth power says that $a^n-b^n=(a-b)(a^{n-1}+a^{n-2}b+a^{n-3}b^{2}+...+b^{n-1})$ and i have observed that $a^n-b^n=(a-b)(a^{n-1}+ab\frac{a^{n-2}-b^{n-2}}{a-b}+b^{n-1})$ an...

9:13 AM
Q: The four-square theorem of the unit vector is equal to 1?

user36327Does the sum of the squares of the unit vectors sum to 1 when there is an equation variant like the following? \begin{equation} \begin{aligned} \mathbf{Q}\mathbf{a} &=a(\cos \theta) \mathbf{I}+(1-\cos \theta)\mathbf{A} \cdot \mathbf{a} \\ &=\mathbf{a}(\cos \theta) \mathbf{I}+(1-\cos \theta)\left[...

Q: sequencing fractions. What are the next 3 in the sequence

Tony B1/16, 1/8, 3/16, 1/4, 5/16, 3/8, 7/16 ___, ___, ___

[ SmokeDetector | MS ] Link at beginning of body (42): removing i,j,k coefficients by josh.bauer2020 on math.SE
3 hours later…
12:50 PM
Please forget my previous post. The answer is a real answer now.
5 hours later…
6:20 PM
@XanderHenderson The OP has edited that question a bit. He says: "I have edited it to clarify there is a question being asked".
This was mentioned in another chatroom. Since the question was pointed out by you, I thought it might be reasonable to let you know - in case you have something to add to that.
5 hours later…
is it possible to delete a question if no one upvoted it and the answers just point out I was ignorant on the subject?
11:28 PM
@JorgeFernández-Hidalgo first, you should not deface the post. Second I don't think the question is that bad. I'd leave it around (unless somebody comes up with a duplicate).
Fine whatever
I never should have even asked it in the first place
deep down I knew it would just worsen my anxiety
I'll just forget about it
I'll remember to stick to just answering questions
@JorgeFernández-Hidalgo if you want you can ask to be disassociated from the post. But again I think the question is not bad.
that would be awesome I would really appreciate it
if it isn't too much trouble
sorry for the trouble
@JorgeFernández-Hidalgo I'll need to ask SE to do it, thus it might take a little while.
But it is not difficult to do.
Oh, don't worry about it then
11:35 PM
@JorgeFernández-Hidalgo Alright. If you change your mind later feel free to raise a flag.

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