-13
-4
With n >2, no possitive integers X,Y,Z
$X^n+Y^n=Z^n$
so
$Z^n-Y^n=X^n$
$Z^n-X^n=Y^n$
The little known notable product difference nth power says that
$a^n-b^n=(a-b)(a^{n-1}+a^{n-2}b+a^{n-3}b^{2}+...+b^{n-1})$
and i have observed that
$a^n-b^n=(a-b)(a^{n-1}+ab\frac{a^{n-2}-b^{n-2}}{a-b}+b^{n-1})$
an...
-3
Does the sum of the squares of the unit vectors sum to 1 when there is an equation variant like the following?
\begin{equation}
\begin{aligned}
\mathbf{Q}\mathbf{a} &=a(\cos \theta) \mathbf{I}+(1-\cos \theta)\mathbf{A} \cdot \mathbf{a} \\
&=\mathbf{a}(\cos \theta) \mathbf{I}+(1-\cos \theta)\left[...
1/16, 1/8, 3/16, 1/4, 5/16, 3/8, 7/16 ___, ___, ___
