I applied the formula $\rho=\sqrt{z^2+r^2},\ \ \theta=\theta , \ \ \phi=\arctan \left (\frac{r}{z}\right )$ for the point in cylindrical coordinates $\left (1, -\frac{\pi}{6}, 0\right )$.
To calculate $\phi$ do we write it as followed?? $$\phi=\arctan \left (\frac{1}{0}\right )$$
Or is there an...
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$\DeclareMathOperator{\orb}{orb}$
Say I have a group "polynomial", $p$, on $S_n$, that is $p(x)=a_1 x^{\epsilon_1}...a_n x^{\epsilon_n}$ for all $x \in S_n$, fixed $a_i \in S_n$ and fixed $\epsilon_i \in \mathbb{Z}$. Let $p S_n$ be the image of the polynomial. Generally, I am looking for $$ X(S_n...
