Mathematics - 2017-02-21 (page 4 of 8)

A. Napster

12:02 PM

can anyone help please? just check if my reasoning is correct

MartianCactus

12:13 PM

RS agarwal

@user400188

user400188

@MartianCactus
Thank you.

MartianCactus

np

user400188

12:35 PM

Goodnight everyone

user84215

12:51 PM

Hello everyone

user84215

according to ZF, How can it possible a set belong to itself ?

DHMO

@aminliverpool it is not possible

user84215

I mean ZF without the axiom of Foundation

DHMO

then how is it not possible?

user84215

bring an example

DHMO

12:56 PM

just declare it to be

user84215

I cant understand

DHMO

@aminliverpool just erect an axiom saying there exists a set which belongs to itself

user84215

I need a model in which this case happens. An example.

DHMO

replace the axiom of foundation by an axiom declaring the existence of a set which belongs to itself

user84215

why dont you bring an example?

DHMO

12:59 PM

Aczel's anti-foundation axiom

In the foundations of mathematics, Aczel's anti-foundation axiom is an axiom set forth by Peter Aczel (1988), as an alternative to the axiom of foundation in Zermelo–Fraenkel set theory. It states that every accessible pointed directed graph corresponds to a unique set. In particular, according to this axiom, the graph consisting of a single vertex with a loop corresponds to a set that contains only itself as element, i.e. a Quine atom. A set theory obeying this axiom is necessarily a non-well-founded set theory. == Accessible pointed graphs == An accessible pointed graph is a directed graph with...

@aminliverpool because I don't know much about alternative models of set theory

oh it's you again

you who challenged us yesterday

user84215

Did you reach the answer?

DHMO

of what

user84215

an uncountable set without any perfect subset

user84215

back to previous question. I still have problem

DHMO

are you trying to have a conversation or are you challenging us?

user84215

1:08 PM

I just want to solve my questions by discussing. Is this bad?

DHMO

@aminliverpool it is not bad, but you sound like you are challenging us.

Please go on

Alessandro Codenotti

@aminliverpool can you show that an uncountable closed set of the reals contains a perfect subset?

BAYMAX

how the Lebesgue integration is 1?

user84215

this is true.

Alex

Hi, how can I prove that the map $f:B^n\to S^n$ given by $x\mapsto cos(\pi \Vert x\Vert)u+sin(\pi \Vert x\Vert)\frac{x}{\Vert x\Vert}$ is onto? Where $u=(0,\cdots,1)$

DHMO

1:13 PM

@BAYMAX desmos.com/calculator/zl3m9vfvov

BAYMAX

what does the lastline mean regarding f is linear on [1,1/n] and [2,2/n]?@DHMO

user84215

I still hve problem in viewing math formula. They appear in mathjax code.

arctic tern

@BAYMAX google "linear function."

BAYMAX

yes

but in the graph its 0 ,

for [0,1/3]

arctic tern

f(x)=0 is a linear function

DHMO

1:19 PM

@BAYMAX it's not well-termed. It just means what I plotted

arctic tern

also no f(x) does not equal 0 on [0,1/3]

DHMO

@arctictern what?

arctic tern

f(0)=0 and f(1/n)=n so f(x)=n^2 x on [0,1/n].

DHMO

oh

@BAYMAX sorry

I thought it said [0,1/n)

you know, the brackets are important

user84215

please help me. I have problem in viewing math formula.

arctic tern

1:21 PM

@aminliverpool see LaTeX in chat in room description, top right corner

user84215

I have done it. But the problem remains

DHMO

@BAYMAX desmos.com/calculator/x6qgf6kezh

@aminliverpool are you on mobile?

user84215

No. laptop

arctic tern

you're clicking the "start chatjax" button on your bookmarks toolbar while on this tab?

DHMO

@aminliverpool did you use https:// ?

https can block javascripts

user84215

1:24 PM

I dont think so

Alessandro Codenotti

@aminliverpool I know, but can you prove it? I don't think it's true for generic uncountable sets, maybe looking at where the proof for closed sets fails will help

user84215

First, lets speak about the fact whether that is consistent with intuition.

DHMO

@aminliverpool intuition isn't that useful

user84215

But it only can develop mathematics

user84215

I mean math intuition

Balarka Sen

1:29 PM

what's up

DHMO

@BalarkaSen welcome back

Compulsive Mathurbator

@BalarkaSen yo

Balarka Sen

Hi stranger

user84215

please dont forget my problem on viewing math formula.

DHMO

@aminliverpool this is a viable alternative

Alessandro Codenotti

1:32 PM

Hi @Balarka

DHMO

@AlessandroCodenotti do you have exmaples where $\int \sum$ and $\sum \int$ give two different real numbers?

Little Rookie

Hello all, please help me with my question,thanks :) math.stackexchange.com/questions/2151770/…

Compulsive Mathurbator

@aminliverpool Does mathjax not work on your system?

user84215

yes

user84215

@DHMO. I have done it. but no improvement

Alessandro Codenotti

1:33 PM

@DHMO don't have one off the top of my head but it shouldn't be difficult to cook one up with a series that doesn't converge uniformly

DHMO

@aminliverpool I mean, copy the mathjax into the website to render

@AlessandroCodenotti I don't see how they can give two different real numbers

I can see that maybe one converges and one diverges

user84215

copy mathjax? I cant understand.

DHMO

@aminliverpool you tell me that you are viewing $e^{i\pi}+1=0$ instead of the formula

so you can copy e^{i\pi}+1=0 to the website I gave you

and to render the LaTeX there

as an alternative

Alessandro Codenotti

Hm, I guess we can cheat by using an example where $\lim\int f_n(x) dx$ and $\int\lim f_n(x) dx$ are different real numbers and then defining a series so that the $n$-th partial sum is precisely $f_n$

DHMO

@AlessandroCodenotti is the former possible?

Alessandro Codenotti

1:37 PM

sure, if we're talking about pointwise convergence for the sequence $f_n$

(while you can safely swap integrals and limits if the convergence is uniform)

user84215

I did it and it works well on that website. but the problem remains in this chat room.

DHMO

I have made mental peace with the fact that $\mathscr P(\mathbb N)$ is uncountable long ago. In fact, it has become so ingrained in my mind that I find hard to accept that the set of finite subsets of $\mathbb N$ is countable! — triple_sec Jun 5 '14 at 11:04

I guess I can relate to ^

Alessandro Codenotti

take those functions, they converge pointwise to the $0$ function while their integral is always $1$

DHMO

@AlessandroCodenotti ok

user84215

I did it and it works well on that website. but the problem remains in this chat room.

Balarka Sen

1:39 PM

It's easy to come up with examples to those, yes.

Think about a small triangle with height $n$ with base $[0, 1/n]$. That's the graph of $f_n$.

Alessandro Codenotti

so $\int\limits_{[0,1]}\lim\limits_{n\to\infty} f_n(x)dx=0$ while $\lim\limits_{n\to\infty}\int\limits_{[0,1]} f_n(x)dx=1$

DHMO

@aminliverpool I said it's an alternative...

fluffy_muffin

Does anyone know how to show that half planes are non empty sets? This question has been stumping me.

DHMO

@fluffy_muffin which half plane?

Balarka Sen

In which case $\int_0^1 f_n = 1/2 \cdot n \cdot 1/n = 1/2$, but $\int f = 0$ where $f$ is the ptwise limit

Alessandro Codenotti

1:40 PM

Actually I thought baymax's functions are like those Balarka is suggesting, but they are different, use Balarka's functions

fluffy_muffin

Sorry every half plane is non empty set. My book defines a half plane "loosely' imo. It defines what a convex set is then simply defines the Plane Seperation Postualte stating that the half planes H1 and H2 are the half planes associated with the line l that divdes the plane containing these.

user84215

How can this problem resolve in this site?

DHMO

@fluffy_muffin can you give me an example of a half plane?

user84215

other suggestions ?

DHMO

@aminliverpool you said you still have a problem with the negation of axiom of foundation

what is your problem?

Danu

1:43 PM

@MikeMiller I'm reading up on the gauge theory background stuff some more and I've got a small question about Spin structures. I found some statement of the form: "Let $H\to X$ be a real, oriented vector bundle and $(\mathfrak s,J)$, $(\mathfrak s',J')$ two Spin structures for $H$. Then the/a line bundle $L$ such that $\mathfrak s\cong \mathfrak s'\otimes L$(as Spin^c structures) satisfies $2c_1(L)=0$" but I have reasons to suspect that it may not be precise. Is this a correct statement?

fluffy_muffin

@DHMO Mathematically no, I'm not sure my notation would be correct. I think an image would suffice better here. This is what my book states: s17.postimg.org/vtdpee5xb/Capture.png

user84215

why can we derived this fact without the axiom of foundation?

DHMO

@aminliverpool that fact does not derive from the negation of the axiom of foundation

you need an additional axiom stating that those sets exist

user84215

why ?

DHMO

removing that axiom does not immediately give you a set X={X}

fluffy_muffin

1:45 PM

I tried using the plane seperation postualte to suppose we had two half planes. Then if the point lies i the half plane we want we are done. Otherwise, there exists a point on the line through the point in the other half plane. Then we can construct a point in the other half plane such that it is between these two points. Thus, lying in the other half plane. However, this felt like I was using what I was trying to prove...

user84215

without the axiom of foundation, I cannot understand why a set can belong to itself

DHMO

@aminliverpool because there is no axiom in the remaining ZF axioms to contradict a set belonging to itself

user84215

show me

DHMO

show you what?

I can't prove this.

user84215

ok. back to the other question. An uncountable set ...

DHMO

1:49 PM

@AlessandroCodenotti sei qui?

fluffy_muffin

Any ideas? Or is that actually valid proof?

DHMO

@fluffy_muffin do you have any theorems regarding a line?

fluffy_muffin

@DHMO The incidence axioms, segment construction theorem, betweeness etcetera. I have everything available in neutral geometry. Well up to saccheri quadrilaterals anyways.

Alessandro Codenotti

@DHMO always

DHMO

@AlessandroCodenotti oh sorry, I misread a word.

My question is cleared now

Alessandro Codenotti

1:53 PM

ok

DHMO

maybe you might want to answer the person above you

Alessandro Codenotti

I already asked him or her a question related to the one he's trying to answer

user84215

an uncountable set without any perfect subset
back to previous question.

DHMO

@AlessandroCodenotti heh?

Alessandro Codenotti

that and that one

DHMO

1:56 PM

@AlessandroCodenotti no, not him

I'm referring to @fluffy_muffin

Alessandro Codenotti

Ah, I don't know about axiomatizations of geometry

user84215

I think it is better to go out. Come back soon. Goodbye.

Alessandro Codenotti

2:19 PM

Is there an explicit example of an $\alpha$ such that $C+\alpha$ contains no rationals? Where $C$ is the standard middle-thirds Cantor set

DHMO

@AlessandroCodenotti what is the cardinality of $C$?

Alessandro Codenotti

$\mathfrak{c}$, the same as the reals

DHMO

@AlessandroCodenotti all the real numbers in [0,1] with no 1 in one of their ternary representation?

Alessandro Codenotti

right

for numbers like $1/3=0.1_3$ with a finite ternary expansion ending in $1$ you use the representation ending with infitely many $2$, in this case $0.0\bar{2}_3$ and they are in the Cantor set

DHMO

@AlessandroCodenotti assuming that $\pi$ is normal, $\pi$.

@AlessandroCodenotti I figured out that probabilistic arguments aren't good

Alessandro Codenotti

2:31 PM

I'm not convinced that works

Balarka Sen

I have no reason to believe pi works

@Alessandro Existence is easy by measure theoretic considerations.

Alessandro Codenotti

yeah, we did this problem before Balarka

DHMO

@BalarkaSen can you instruct me?

Alessandro Codenotti

you asked it to me actually. I recently learned that you can do this via Baire category too since it's a countable union of closed sets with empty interior

DHMO

wait

isn't $C$ perfect?

Balarka Sen

2:34 PM

Yes.

DHMO

@BalarkaSen do you have any answer in mind, to the rational problem?

Balarka Sen

What problem?

DHMO

16 mins ago, by Alessandro Codenotti

Is there an explicit example of an $\alpha$ such that $C+\alpha$ contains no rationals? Where $C$ is the standard middle-thirds Cantor set

Alessandro Codenotti

I'm also trying to find a reference for this construction since I need for my essay, but the only construction I found of a perfect set with no rationals in "counterexamples in analysis" went the direct way by modifying the construction of the Cantor set

DHMO

@AlessandroCodenotti how would you say "you should have called me" in italiano?

Alessandro Codenotti

2:38 PM

avresti dovuto chiamarmi

DHMO

that's strange

"you have should called me"

Alessandro Codenotti

chiamarmi is the contraction of chiamare me, accusative personal pronouns are absorbed by the verb if possible

DHMO

@AlessandroCodenotti I know this

I'm talking about "aversti dovuto"

Alessandro Codenotti

while the "you" is superfluous, we never have an explicit subject if the subject is a personal pronoun

Balarka Sen

@DHMO I can give you a Cantor set inside $\Bbb R - \Bbb Q$ but not sure of this particular sort.

DHMO

2:40 PM

@AlessandroCodenotti I'm also not talking about that

I'm talking about "have should"

@BalarkaSen sure

Alessandro Codenotti

@DHMO a lot of things are written in the opposite order in Italian when compared to English. Adjectives after nouns for example

DHMO

@AlessandroCodenotti but adjective after nouns I've seen that in French and Spanish

Alessandro Codenotti

I don't know how verb conjugations works in those languages

DHMO

@AlessandroCodenotti in Spanish, the conditional carries a meaning of "should". Does that occur in Italian?

Alessandro Codenotti

yes

DHMO

2:43 PM

@AlessandroCodenotti they're mostly similar

@AlessandroCodenotti then why did you include dovuto?

Alessandro Codenotti

because it's the past form of the conditional

dovresti chiamarmi is you should call me

DHMO

@AlessandroCodenotti can't I just say "avresti chiamatomi"?

Alessandro Codenotti

no, that doesn't work

DHMO

@AlessandroCodenotti isn't that past conditional?

Little Rookie

Hello all, i need serious help here,
i want to prove that
y=sin(t^2) cannot be a solution on an interval containing t=0 of an 2nd order linear homogeneous differential equation.
using the Wronskian.
The Wronskian is 0 at t=0, but how does this contradicts Abel's Theorem?
I am stuck for a long time, please help me :(

DHMO

2:46 PM

@AlessandroCodenotti oh, I have another question, this isn't consistent among French and Spanish: can you translate "it is I/me who said this"?

Balarka Sen

@DHMO Actually, I can show that there exists an $\alpha$ of that sort.

It's not particularly hard.

DHMO

@BalarkaSen how?

Balarka Sen

Look at all the rational translates of $C$. That's measure 0, so is not all of R, correct?

DHMO

@BalarkaSen oh $C$ has measure 0?

Balarka Sen

So pick a point from there and translate using that.

@DHMO Sure

?? irrationals have measure 1

DHMO

2:49 PM

@BalarkaSen what?

Alessandro Codenotti

@DHMO no, past conditional of dovere, for example is (io) avrei dovuto, (tu) avresti dovuto, (lui/lei) avrebbe dovuto, (noi) avremmo dovuto, (voi) avreste dovuto, (essi) avrebbero dovuto

DHMO

you mean the irrationals in [0..1]?

Balarka Sen

Irrationals in R, or [0, 1], sure.

DHMO

@AlessandroCodenotti I mean, in Spanish, "you should study" is "estudiarías"

we don't need to say "debes estudiar"

@BalarkaSen wait what

irrationals in R is also 1?

Alessandro Codenotti

in Italian is dovresti studiare, we have a lot of so called composite tenses

DHMO

2:50 PM

@AlessandroCodenotti oh, I thought you mean that dovere is not necessary

Alessandro Codenotti

@DHMO lo ho detto io or sono stato io a dirlo

DHMO

@AlessandroCodenotti couldn't you start with ___ io che ...?

Balarka Sen

Sorry, I meant in (0, 1)

DHMO

@BalarkaSen I didn't know that uncountable sets can also have measure 0....

Alessandro Codenotti

sono io che lo ho detto, sounds a bit unnatural though, maybe if you want to stress the I

Balarka Sen

2:52 PM

Sure they can

DHMO

@AlessandroCodenotti so nobody says this? not even in songs/poetry?

@BalarkaSen any trivial examples?

Balarka Sen

Cantor set... :P

Alessandro Codenotti

nah, it wouldn't sound weird even in spoken italian, but I'd use one of the other constructions

Balarka Sen

It's the easiest example

DHMO

@AlessandroCodenotti this agrees with Spanish... in French we say "c'est moi qui l'ai dit" which would be directly "e io che lo ho detto"

@BalarkaSen measure is mind-boggling

Balarka Sen

2:53 PM

Nah

Not once you actually study it from somewhere other than wikipedia

6

DHMO

@AlessandroCodenotti so in Italian there is no distinction between past tense and present perfect?

@BalarkaSen burnt

Alessandro Codenotti

@DHMO there's not a perfect 1-1 correspondence between present perfect and an Italian tense I think, depends on context

there are a lot of past tenses in Italian though

DHMO

@AlessandroCodenotti you do have the -ava tense right? Not sure how you would name it.

In Spanish we say "estudiabas"

Alessandro Codenotti

that's the imperfetto I guess

DHMO

@AlessandroCodenotti I only know two...

@AlessandroCodenotti yes, the imperfetto

Alessandro Codenotti

2:58 PM

indicative has passato semplice, imperfetto, trapassato prossimo, passato remoto and trapassato remoto as past tenses (a couple of those are not widely used in modern Italian), conditional has a past tense, subjunctive has 2 past tenses

DHMO

@AlessandroCodenotti you win

you can also say English has "I had", "I had had", "I had been having", "I would have", ...

Alessandro Codenotti

there's also infinitive, gerund and participle past, but they're weird, they only have one person rather than 6

DHMO

@AlessandroCodenotti does devo studiare mean anything?

Alessandro Codenotti

I must study, rather than dovrei studiare, which is I should study

DHMO

this is really strange

I thought they mean the same

$\text{I must study} \iff \text{I should study}$

Alessandro Codenotti

3:01 PM

as you said conditional has a "should" connotation

DHMO

If I am not wrong, in Spanish debo estudiar = estudiaría = I should study

Alessandro Codenotti

I'm don't know about Spanish. But they are different in Italian, at least in some contextes, for a practical example say that you ask me whether I want to come to the cinema tonight. "I can't, I must study" would be non posso, devo studiare while "I should study, but I'll come" would be dovrei studiare, ma verrò

DHMO

@AlessandroCodenotti interesting

@AlessandroCodenotti I guess I would say no puedo, necesito estudiar

Alessandro Codenotti

oh, nice, pointwise limit of continuous functions can be bad but not that bad, it must be continuous on a dense set at least

DHMO

and estudiaría, pero vendré

@AlessandroCodenotti a limit is continuous?

Alessandro Codenotti

3:08 PM

a limit of a sequence of functions is a function

Balarka Sen

@AlessandroCodenotti Yeah

DHMO

@AlessandroCodenotti ah, nice

@AlessandroCodenotti how would you say acabo de comer = I just ate?

Alessandro Codenotti

I wonder why Munkres calls this fact "more amusing than profound"

DHMO

(In English it's in the past tense but everything is in the present tense in English)

Alessandro Codenotti

@DHMO Ho appena mangiato

DHMO

3:10 PM

@AlessandroCodenotti no present tense formation?

I just checked that Spanish has apenas comí also

Balarka Sen

Is this an application of Baire category

Alessandro Codenotti

nope, it's a past action after all. The "appena" signals that it just ended

DHMO

@AlessandroCodenotti you can see this

I guess it's idiomatic

Alessandro Codenotti

@BalarkaSen yeah, it's not an immediate one though, I have yet to read the proof in detail

DHMO

but in French we also have je viens de manger = vengo di mangiare

Alessandro Codenotti

3:12 PM

doesn't work in Italian

DHMO

interesting

Balarka Sen

@AlessandroCodenotti Well, pointwise convergence is like, dumb and nobody cares about them

DHMO

@AlessandroCodenotti could you read comer = mangiare without the translation?

Alessandro Codenotti

LoL

Balarka Sen

It's not the right topology in the space of functions at all

Alessandro Codenotti

3:13 PM

but it's the product topology on $\Bbb R^\Bbb R$ I think?

Balarka Sen

Yes. And product topology is super-dumb in that context

Alessandro Codenotti

@DHMO nope, comer doesn't look like anything in Italian

Secret

in The h Bar, 2 mins ago, by Slereah

But...why...?

What has Jennifer lawrence had to do with group theory?

Alessandro Codenotti

@BalarkaSen Fair enough

DHMO

@AlessandroCodenotti which gives rise to Cómo como? Como como como. = Come mangio? Mangio come mangio

BAYMAX

3:15 PM

Dont we get MSE T shirts ??

DHMO

@Secret welcome back

Alessandro Codenotti

that's a funny sentence

DHMO

@AlessandroCodenotti Italian ranks at the 18th in terms of population of speakers...

whereas Spanish ranks at the 3rd

@AlessandroCodenotti how do you say "July 4"?

Alessandro Codenotti

we write 4 Luglio and read Il 4 di Luglio

DHMO

@AlessandroCodenotti expand 4 please?

Balarka Sen

3:18 PM

Product topology is never the right thing for infinite products; the open sets are huge. Indeed, I think box topology (the correct alternating for product topology in some cases) is finer than uniform topology.

Alessandro Codenotti

quattro, non quarto (four rather than fourth)

BAYMAX

Hey everybody relax as i am BAYMAX!!!

DHMO

@AlessandroCodenotti I see

do you trill the r in both words?

Alessandro Codenotti

yep

misread what you wrote

Balarka Sen

:)

DHMO

3:19 PM

@AlessandroCodenotti cuatro, no es cuarto

Alessandro Codenotti

wait what do you mean with the uniform topology? I need a space of functions with codomain $\Bbb R$ or can it be generalized?

well to linearly ordered sets probably

DHMO

I came across this fascinating and humbling sentence:

> The set $V_6$ contains $2^{65536}$ elements, which very substantially exceeds the number of atoms in the known universe. So the finite stages of the cumulative hierarchy cannot be written down explicitly after stage $5$.

(regarding the von Neumann universe)

s.harp

@DHMO consider a $10\times10\times10$ lattice. On each lattice you have a spin that can either be oriented $+1$ or $-1$. In statistical physics the expressions to get an expectation value involve summing over all possible states, for such an extremely small and easy lattice, how many terms must you calculate to find the expectation value?

What I wrote is actually wrong, there are many tricks to calculating the expectation values of that you can actually get analytic expressions easily in this case

but if you want to find the ground state of a quantum spin system analytically there is almost no way of going around this gigantic number, even for this super tiny lattice that is way to small for solid state applications ($10\times10\times10$? you really want something like $10^6\times10^6\times 10^6$ size lattices..)

DHMO

@AlessandroCodenotti how on earth do you distinguish the two pronunciations of e?

Alessandro Codenotti

there are at least $3$, è, é, and e, but a lot of people pay no attention to the first $2$. The difference between an e and an accented e is very strong to me though

DHMO

3:32 PM

@AlessandroCodenotti for example?

bene?

Alessandro Codenotti

that's hard to explain by writing, you should look at some recordings of Italian speakers

DHMO

@AlessandroCodenotti IPA?

Alessandro Codenotti

I don't know how it works well enough to write it

DHMO

alright

could you give me a word though

and I can look for recordings

Do you distinguish beve vs bene?

@AkivaWeinberger hola

bienvenido

Alessandro Codenotti

no, it's mostly at the end of words. You should look at words ending in e and words ending in è or é

Akiva Weinberger

3:36 PM

Hola

DHMO

@AlessandroCodenotti can you give me an example?

@AkivaWeinberger we're discussing Spanish vs Italian

Alessandro Codenotti

also look at the difference between e, which is the conjunction and, and è which is a form of the verb essere

DHMO

(mostly it's me annoying him with questions about Italian)

Alessandro Codenotti

that works for other vowels too, pero is a pear tree, però means but, papa is pope, papà is father

DHMO

@AlessandroCodenotti I hear "questo è" being pronounced as quest'è

@AlessandroCodenotti però vs ma?

In Spanish the former is used much often

Alessandro Codenotti

3:41 PM

sometimes we do skip the last vowel of a word if the following one begins with a vowel too, quest'anno sounds better than questo anno, I wouldn't skip it in questo è though

I think they have the same meaning in most contextes

DHMO

In Spanish mas seems very old

SteamyRoot

This "skipping the last vowel" was very common in Latin poetry :O

DHMO

@SteamyRoot hmm...

for example?

SteamyRoot

Well, take my favourite poem "Odi et Amo" by Catullus

rudy.negenborn.net/catullus/text2/sc85.htm

DHMO

in where I live... it's the 7th case of secondary school student suicide this month....

SteamyRoot

3:44 PM

You'll note that every vowel has something above it, either a curve line (meaning "short") or flat line (meaning "long")

DHMO

none of you probably cares about where I live though

SteamyRoot

the ones that don't have anything, are actually absorbed by the vowel next to them

So you'd say "Od'et amo, quar'id ... senti'et ..."

DHMO

@SteamyRoot What I don't like is that the spondee and the [insert name] don't follow the word boundaries...

it makes keeping track of the rhythm very difficult

SteamyRoot

Well, the rhythm is very different from "modern" poetry :P

DHMO

compare it to iambic pentameter

SteamyRoot

3:47 PM

They're dactylic penta- & hexameters :P

s.harp

Did anybody else just get pinged about the even in hbar?

SteamyRoot

Not that I noticed

Akiva Weinberger

@DHMO Oh my god, that's horrible

DHMO

@AkivaWeinberger it is...

considering the smallness of our city...

Akiva Weinberger

Hong Kong, right?

DHMO

3:51 PM

even one case is too many..

@AkivaWeinberger yes

while all the Westerners know is that asians are somehow gods

Akiva Weinberger

I've heard about student suicides in Korea as well

DHMO

I've heard that the students in Korea have much more pressure than in Hong Kong

Secret

The suicides seemed to be close to the start of the TSA or something similar in March. Just like what happened last year where there are 16 something cases of suicides

DHMO

@Secret oh, I forgot that you are also from Hong Kong...

but that was 16 cases in a year

this time it's 7 cases in a month

Secret

Those 16 cases, if you read closely, really only started to escalate during the start of march. So it is possible they are correlated to the TSA and the pressure stemmed from it

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