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7:00 PM
Did we define poset
It's a bunch of things with a "less than" relation except sometimes we neither have $a\prec b$ nor $b\prec a$ nor $a=b$
Example: Sets, using $\subset$ as our order relation
A maximum element is $\succ$ everything else. A maximal element is not $\prec$ anything.
In mathematics, especially order theory, a partially ordered set (or poset) formalizes and generalizes the intuitive concept of an ordering, sequencing, or arrangement of the elements of a set. A poset consists of a set together with a binary relation that indicates that, for certain pairs of elements in the set, one of the elements precedes the other. Such a relation is called a partial order to reflect the fact that not every pair of elements need be related: for some pairs, it may be that neither element precedes the other in the poset. Thus, partial orders generalize the more familiar total...
 
@AkivaWeinberger do you want to discuss something ?
I want to discuss this proof here
for the first thing the result is true for n - 1 the reason we require whenever $j \neq i$ because if $j = i$ then we are done by hypothesis right ?
 
Remind me what a prime ideal is?
Generated by one element?
 
If you have a set $X$ with a minimum and maximum.
Consider $\varnothing \subseteq X$.
 
@AkivaWeinberger an ideal is prime if whenever $ab \in I$ $a \in I$ or $b \in I$.
 
Then $\inf \varnothing$ is the maximum and $\sup \varnothing$ is the minimum.
 
7:05 PM
Yup @SteamyRoot
 
So it is really like prime numbers.
 
Which is one of the reasons it's terribly important to exclude the empty set (if necessary) when working with subsets :D
 
@AkivaWeinberger okay ?
 
Finished reading it
Yeah, the first bit with the $i\ne j$ follows from the induction hypothesis
 
Then why does $y \notin p_i$?
I don't understand the concluding remark.
 
7:10 PM
Because all of the terms except for one are in $p_i$, and the last one isn't.
The "last one" is the one with $x_i$ omitted.
Because all of its factors are not in $p_i$ by the way we chose our $x$s.
 
i just fried up some salt pork and it doesnt taste good
I thought it would be like bacon, but ugh
 
oh ok I see it now. The way they phrased the last statement caught me off guard. that is $x_i \in p_i$ for all i.
but yeah here we have $x_i$ missing so that makes sense ok yeah thanks @AkivaWeinberger
 
what's nu
 
$c/\lambda$
 
nah that's $n$
 
7:20 PM
Hi chat
 
I guess this makes also intuitively this proposition.
I guess what this proposition says is that ideals can't spread over many different ideals.
It must be contained in one of them, which makes sense intuitively.
 
Hi @Astyx
 
@Adeek Also note the similarity between this and the condition to be a prime ideal (if you write this result for two prime ideals)
 
Yeah @TobiasKildetoft
I guess this condition captures intuitively what it means to be prime ideal more.
 
How can an endomorphic ring be isomorphic to a quadratic order?
 
7:33 PM
can you fix something when you don't know what's broken?
appereantly yes, format c and install the OS again
 
@Extrarius what does it mean to be endomorphic?
 
Test: $\displaystyle\operatorname*{\bigtriangleup}\limits_{i=1}^3A_i$
 
@TobiasKildetoft err I meant endomorphism ring
 
@Extrarius And by quadratic order, you mean an order in a quadratic number field?
 
@TobiasKildetoft The paper I'm reading says "Let $\mathcal{O}$ be an imaginary quadratic order identified by its discriminant D". A few sentences later it refers to the same object as "the lattice $\mathcal{O}$"
 
7:39 PM
Test: $\displaystyle\operatorname*{sum}\limits_{i=1}^n\operatorname*{prod}_{\substack{‌​1\,{\rm le}\,j\,{\rm le}\,n\\i\,{\rm ne}\,j}}\frac{x-x_j}{x_i-x_j}$
 
@Extrarius Right, an order is a maximal lattice (i.e. maximal free $\mathbb{Z}$-subalgebra)
 
I'm not familiar enough with group theory to understand that. I just recently wrapped my head around an endomorphism ring being a "function rings" with composition for multiplication.
 
@Extrarius In that case I think reading a paper on algebraic number theory is getting way ahead of yourself
 
Wait, does ANT refer to algebraic number theory or analytic number theory
 
@AkivaWeinberger Depends on who says it probably
 
7:44 PM
a small insect when said by most people
 
That's ant
ANT is much bigger
$\huge{ANT}$
 
@TobiasKildetoft It is worse than that, I'm reading a paper on accelerating the CM method for constructing elliptic curves =-) What titles/labels should I search for to find material that can help me understand orders and lattices and such
 
@Extrarius I would start with some basic algebra, so rings and group and such. There is a long way to go to the topics used in papers
 
@AkivaWeinberger what about TNT
transcendental number theory
 
@TobiasKildetoft: When you say basic algebra, would that be abstract algebra? It makes me think of solving simple equations and polynomials etc, but I'm guessing that isn't what you mean
 
7:48 PM
@BalarkaSen Don't give it to the ants.
 
@Extrarius Right, abstract. I never add that word because it should be implied from the context of university math
 
@TobiasKildetoft Do you know of any good books or other resources on the topic?
 
@Extrarius I usually recommend Artin since it is often recommended by others. Haven't read it myself though
There are tons of good ones to pick from
 
@TobiasKildetoft When I search for author:Artin on amazon, I get a LOT of books by a few different artins (Michael and Emil, mostly). Any idea which one(s)?
 
@Extrarius Michael
Book is simply called "Algebra"
not sure which is the newest edition
 
7:55 PM
@TobiasKildetoft Thanks. I wish self-education was less expensive =-(
 
Ahh, there are probably also free books that are good. Let me take a look and see
 
artin can be downloaded
eg from libgen
 
8:07 PM
abstract.ups.edu and math.uiuc.edu/~r-ash/Algebra.html both look like pretty decent free options. The latter even has a chapter on algebraic number theory
 
@TobiasKildetoft Thanks
 
Okay, I'm-a grumpy now.
 
Bummer, our AIM SQuaRe proposal was not approved, so no free trip to the US for me this spring
 
ack
 
Context: On Thursdays this semester, I'm supposed to coordinate two discussion sections in a row for my students. That's standard, and I'm used to it.
 
8:20 PM
Not sure how good out chances even were. I have a feeling they get a ton of applications
 
However, the room got changed without my realizing it. (The way it's posted is never very clear, but I should've checked to see if something had happened. My bad.) So I first off was in the wrong place at first.
 
on what basis do they approve/decline these proposals?
 
The real problem, though, is that the new room is on the west bank of the Mississipi river (which runs through the middle of campus).
 
@BalarkaSen Not sure how much they bring in specific experts or whether it is a set panel of people evaluating all proposals all the way through
 
The other, along with the room I have before that, is on the east bank.
 
8:21 PM
But basically like most grant proposals I would think
@Semiclassical So swim ?
 
Not the best option at -20 degrees, I don't think
 
Or build a boat out of those students who ask stupid questions
 
Google maps, for reference, puts the travel time between the two rooms as 21 minutes at least.
By comparison, I'm allotted 15 minutes to get from one to the other.
 
@Semiclassical Does that include the time it takes to build said boat?
 
I assume that counts extra.
 
8:24 PM
@Semiclassical Run. Run fast.
 
@BalarkaSen: No, the answer is obvious based on his handle: Tunnel!
 
I am not in a good mood, to put it nicely.
Basically, it's a mile in 15 minutes.
 
bring a bike
 
For clarity, this is what I'm talking about: google.com/maps/dir/44.9782063,-93.2346436/''/…
 
Don't do it then
 
8:27 PM
I may have to.
 
Time to change your research interests to teleportation
 
Just walk and get there late
 
@MikeMiller Not really an option. There are four quizzes during the semester, each of which have a group portion.
So my being there on time is not really an option.
 
Are you unionized?
 
Nope.
Plus this is Minnesota we're talking about. I can't rely on the weather being non-shitty.
 
8:30 PM
Then also bring skis or iceskates
 
I guess so.
This is as bad a room placement as I've had in my entire time here.
So I'm just apoplectic right now.
 
Can't you bring the issue up to someone
 
I am. Hopefully it'll go somewhere.
I literally learned about this an hour ago, so I haven't heard back yet.
 
Yeah, let's see
 
It is too bad that administrators etc don't have technology to help them avoid putting a person in two rooms 21 min apart and allocating 15 min to make the travel. Oh, wait...
 
8:33 PM
But I be grump, so I rant.
This is a weird question: math.stackexchange.com/questions/2104781/…. Are there uni's which have profs who do research in several complex variables? Definitely. But you'd never have a "complex analysis program."
 
@Semi You should really talk to admin for a while. Make a beef with the department. If they don't resolve it go to the Ombudsman
 
Yeah. Right now I'm just waiting, which is good because I'd probably lose my temper about it atm (which wouldn't help)
Other rant: Am I wrong to be annoyed by the sole comment here? math.stackexchange.com/questions/2104820/…
 
Definitely not
 
@Semiclassical I certainly don't see which equations those would be, so I would be annoyed too
 
8:41 PM
Thanks. I was worried I was being obtuse.
 
I mean even if it were quite (I can't judge) simple what's the point of such a comment?
 
Oh good god
Also hi chat!
 
@AlessandroCodenotti Exactly.
I can maybe guess what they're getting at, namely to write $\frac{c-a}{c+b}=\frac{p_1^2}{q_1^2}$, $\frac{c+a}{c-b}=\frac{p_2^2}{q_2^2}$, and rearrange this to get a Diophantine system.
 
@Semiclassical Yeah, but not a linear one
 
8:45 PM
@Daminark \begin{align} \end{align}
 
Hi everyone! I need your help, if you have a moment. It's rather a standard problem in statistics, but I'm not much familiarized.

Assume that we draw samples from a normal distribution $N(\mu,\Sigma)$, whose parameters are not known. How many samples should one generate in order to obtain a good estimation of the sample mean $\mu=\frac{1}{N}\sum_{i=1}^{n}x_i$? How is this related to the dimensionality of the samples?

Thank you very much!
 
FYI, there's a stats Stack Exchange (whose name I forget)
They've got a chatroom as well.
 
 
Cross Validated
I haven't seen the chatroom though
 
There we go.
 
8:48 PM
@Semiclassical, thanks for your response. I know the site, but its chatroom is often empty :/
 
Fair enough.
 
But I'll give it a try. I just thought I might have better luck here, no intention to spam :)
 
I have no insight, so I thought I'd point it out.
 
@Semiclassical, thanks anyway :)
What I really need to know is asked here. Again, no intention to spam, it just drew very little attention so far.
 
I don't know the answer, but I gave it an upvote.
 
8:54 PM
@BalarkaSen many thanks!
 
Same. It's a well-constructed question, even if I don't know the answer
 
@Semiclassical, much appreciated! Many thanks :)
 
Plus, it seems like there should be a good answer.
 
Also, it's perfectly fine that you're asking it here. Spamming is a more tedious process of asking the same (usually bad, unlike yours) question over and over again throughout various chatrooms.
 
One way to proceed might be to consider a special case, e.g. an n-dimensional gaussian.
 
8:55 PM
@Semiclassical, same thought here. It seems a rather trivial questions for statisticians, but personally I can't even think of how to start or where to look.
 
What might make it hard is that it should work for an arbitrary distribution, and for many variables I presume that can get weird.
oh, wait, you say that it is a multivariate normal.
 
@Semiclassical, I consider n-dimensional Gaussians, and I run some numerical experiments, but I'd like to have a more sound way to find the answer. Concerning the arbitrary function, I just want a methodology to work with. I know that there should be no answer for any arbitrary function h.
 
Then yeah, there definitely should be stuff that's known.
I think the phrase "concentration of measure" is relevant? I know I've heard that tossed about in such contexts
see for example the notes here: cseweb.ucsd.edu/~dasgupta/lt1/lec1.pdf
Lemma 1 is a good example of what one might hope for.
 
Speaking of stats, I had a question about index numbers that I forgot to think about...oh well.
 
@Semiclassical, thanks for the link; I wasn't aware about concentration of measure. I'll take a look :)
 
9:08 PM
@BalarkaSen
 
@ForeverMozart
 
i have no more ideas :(
 
play videogames
let your subconscious ponder on it
 
maybe I should just put it on Arxiv anyway?
 
ishrug
 
9:09 PM
i think i drank too much coffee
now i feel frantic
frazzled
 
Coffee brain isn't fun, no.
 
it feels so good for a while
but then overload
 
"Finish" lel
 
hi guys
 
9:11 PM
That map is hilarious
 
i have to find the volume bettwe z= 2 and z= (x^2+y^2 ) ^1/2
(x^2+y^2 ) ^1/2 < z <2
but when i set (x^2+y^2 ) ^1/2 = 2
I dont get full circle only upper half
does that mean theta goes from 0 to pi ?
 
@nullgeppetto Wow, Batman gave quite a nice answer already.
 
@BalarkaSen i could send you the "paper"
and you can think of stuff :)
 
this contradicts the picture i drew can someone tell me where i went wrong ?
 
@Semiclassical hell yeah! I'll need some time to study his stuff though!
 
@ForeverMozart Nah, I probably won't be able to contribute much to it.
 
Abortugal
lol
this is a very interesting paper arxiv.org/pdf/1509.07769.pdf
on when does the set of all one-point deleted subsets of a space determine the entire space?
 
On what conditions does a finitely generated module have a basis ?
And hi to everyone I haven't seen today yet
 
@Astyx Well, whenever it is free :)
 
@LeGrandDODOM Sorry I didn't respond in a while, I wasn't on my computer. But on my side, when I open the page, it goes to the next line
 
9:21 PM
He :p
For instance does a finitely generated $\Bbb Z$-module always have a basis ? What if we replace $\Bbb Z$ by any ring $A$ ?
 
Donald Trump woohoo
 
@Astyx Being free and having a basis are equivalent (and no, not all modules are free unless you work over a field)
 
@Tobias Isn't being free by definition having a basis ?
 
@Astyx Having a basis, yes
 
@Astyx Z/3Z as a Z module
 
9:24 PM
(well, one definition)
 
Or any abelian group with torsion elements should work
 
And if we have a group with no torsion ?
 
a finitely generated torsion free abelian group is Z^m, yes
same is true over a PID
you're out of luck in general
 
How would you prove the first ?
 
with gusto
look it up in any algebra book
 
9:43 PM
Okay, thanks !
 
I thought of quite a nice proof in the train
To prove that $-1$ is a square $\mod{p}$ iff $p \equiv 1 \mod 4$
I think it's enough to say that $i^p = i$ iff $p \equiv 1 \mod 4$ implies that $i \in \mathbb{F}_p$
 
you're a square, mod p or not
i mean, sure, it's easy to see that -1 can't be a square mod doubly odd p
 
Yeah, but no one ever told me that it could be done this easily
 
Hey everyone, are the any examples of Theorems for the product and box topologies, for which the results are equivalent, but the proofs are not similar?
 
9:58 PM
So, talked with the admin secretary for Physics who deals with the undergrad classes
And apparently they hadn't been informed of it either. There's an office of classroom management for the entire campus, and someone swapped my room without telling anyone in Physics.
The secretary told me she'd get it squared away, so hopefully things won't be craptastic next week
 
10:32 PM
Donald J Trump baby
pwns noobs everyday
 
I thought Trump isn't topic here. No nukes fired yet, so who cares who is the primeape of the US?
 
Politics isn't a topic of discussion in this chat. Please respect this!
3
 
@OskarTegby Why is it not?
 
You guys can always talk about Trump, but remember to act civilized.
You can talk about whatever you want, really.
Just keep things PG13, since this site is PG13.
 
10:48 PM
Can we talk about the Tits Theorem then?
 
@Krijn well, if cleverly. Like the Butt-curve
 
And don't get me started on the Cox-Zucker Machine
 
haha
 
@Krijn the usual proof is to calculate $(-1)^\frac{p-1}{2}$?
 
10:52 PM
@AlessandroCodenotti I know the usual proof, but I like mine better
 
mine was a question
 
I though that it was a rule, but apparently it isn't. Thus, my claim was false. "(...) and on the other there is no requirement that the topic of discussion be mathematical.". My personal opinion is that it's nice to have some place where everyone isn't talking about politics, but you don't need to care about that.
 
I think political discussions here are rather rare, short-lived and usually not too serious...
 
@AlessandroCodenotti Yeah, it's almost the same, here are some nice proofs as well math.stackexchange.com/questions/1275461/…
 
is any one familiar with the software maxima
 
10:58 PM
I like Daniel's answer
 
FWIW there is a lengthy very recent discussion on the main Meta.
347
Q: If you're gonna talk Politics, you must respect those who disagree

Shog9This is sort of a follow-up to two past discussions: Toward a philosophy of Chat Does the Be Nice policy require SE users to "be nice" to people who are not SE users (e.g. public figures)? Over the past year, there's been an uptick in discussions of politics in chat. JUST LOOK AT THIS CHART! ...

Sorry for the "boxing," in case somebody minds.
 
"If you're gonna talk Politics, you must respect those who disagree" - unlike actual politicians, then.
 
11:14 PM
you don't actually have to respect those who disagree, you just have to occasionally accept a slap on the wrist
that's the trick
 
Since this is a math chatroom, anyone who wants to moderate anything I say should be better than me at math.
I have a proof that the world ends at noon tomorrow, alas it is too long to fit in this chat message.
 
noon what timezone?
 
@PVAL-inactive that can't be a mathematical one. Therefore we will know in 2 days.
no matter which timezone
math.stackexchange.com/a/2105282/346682 my best answer, if votes are the only measure. Quite silly.
 
11:36 PM
@PVAL But how do we decide who's better?
 
So, I just got chat priveleges.
 

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