while defining boundedness for a subset $S$ of a topological vector space .. we require $S \subset \alpha U$ for all $\alpha \ge c > 0$ for 'every neighborhood' $U$ of $0$ .. is there an example of such a space where 'every neighborhood' is actually required (for example, if the space is normable .. only one nbd suffices)?
maybe it is defined somewhere in the script of your docent?
guys, really dumb and short: we know that if f'(x) > 0 and f''(x) != 0 x is an extremal value. Is this an equivalence or an implication? I would say it's the first but... is it?
my guess is the numbers have to all add up to 1 and its less likely that people have 4 TVs than 3 so find two numbers that all the numbers add up to 1 then the smaller value goes to the 4 TVs
maybe, but this is not my real problem... i have another task to do, and im to stupid for that. if this would be an aquivalence the solution would be too ez, though
Anna and Zach each have 600 to invest. Anna's investments earn a rate of 10.5% and Zach's investments earn a rate of 6.5%. Approximately, how much more money will Anna have than Zach when Zach's investments are worth 900?
Anna and Zach each have 600 to invest. Anna's investments earn a rate of 10.5% and Zach's investments earn a rate of 6.5%. Approximately, how much more money will Anna have than Zach when Zach's investments are worth 900?
There is a limit what a human can parse per time. So when one says humand judgement will always be superior to an algorithm processed by a machine, one implicitly says that a machine can't parse more per time than a human. Because if it could, there are certainly cases where the judgement of a machine is superior.