I did $\log 81 < \log 83 < \log 84$ and some fancy factoring combined with $\log 3 > 1.09$ + $\log 2 > 0.69$ on the left handside and $\log 3 < 1.1$ and $\log 2 < 0.7$ on the right handside.
OK, @Mike, forget about my previous example. Forget that I ever said it. The trivial metric $d(x, x) = 0$ and $d(x, y) = 1$ if $x \neq y$ is the answer.
Im really getting annoyed by people who read things , i did not write !! Like assuming In the OP I required some function to be entire , WHILE i did not even wrote that !
Why do people assume things that were not written to conclude the OP was nonsense , rather then to read again and try to understand the sense of the question ??
@robjohn I seriously think that identity should have my name (if no one did it before). Maybe @r9m comes up with another paper by O'Connel and shows me it's already there. :-)
As an example , my recent question : ( where it was assumed the inverse of f needed to be entire ?? ) http://math.stackexchange.com/questions/984103/can-this-be-expressed-by-a-contour-integral
Let $f(z)$ be a real entire function of the form
$f(z) = a_1 z + a_2 z^2 + ...$
such that $0 < a_{n+1} < a_n$.
Consider $g(x) = f^{-1}(f(x)-f(x-1))$ where $x$ is a positive real and $f^{-1}$ is the functional inverse of $f$.
I know $f(x)$ and $f^{-1}(x)$ can be given by a contour integral.
C...
Vorpal sword is a phrase used by Lewis Carroll in his nonsense poem "Jabberwocky".
== Context and definition ==
Carroll published Through the Looking-Glass in 1871. Near the beginning, Alice discovers and reads "Jabberwocky". The word "vorpal" appears twice in the poem, which describes a young boy's quest to slay a monster called the Jabberwock:
He took his vorpal sword in hand:
And later,
One, two! One, two! And through and through
The vorpal blade went snicker-snack!
He left it dead, and with its head
He went galumphing back.
As with much of the rest of the poem's vocabulary, the reader is left...