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7:00 PM
@Alizter Wa..... wat ??
 
@TheGame familiar yet?
 
@Alizter >:c I have 2k rep
 
@TheGame OK. I have no idea how to answer your question. I shall stop being silly.
 
xD
 
Hmmmm
 
7:03 PM
Why is nobody upvoting my lhf?
 
@Alizter At least upvote it :) it's interesting, isn't it ?
 
Hi guys, can anyone recommend an elementary yet thorough treatment of linear algebra?
 
@TheGame I can't upvote what I don't understand.
 
Say, upper undergraduate level
 
@Danu How elementary and how thorough?
 
7:04 PM
If I am stranded on a desert island with nothing with paper. And a monkey will not give me his coconut if I do not approximate $\log 83$ what do I do?
4
 
@Alizter Ah that's another problem xD
 
hehehe
 
@Danu Petersen's Linear Algebra, 2012.
 
@N3buchadnezzar Silly monkey
 
give up, because you don't have a pencil to write with
 
7:04 PM
@JasperLoy Thanks, I'll check it out
 
@N3buchadnezzar Know your basic log table
 
also, do you mean natural log?
 
@N3buchadnezzar $\log(8)=0.903$
 
@MikeMiller Sorry, was away. But I have already done it. $(X, \bar{d})$ where $\bar{d} = d/(1+d)$, $(X, d)$ being a metric space.
 
@N3buchadnezzar And $\log(3)=0.477$
Done
 
7:06 PM
@JasperLoy hah, the description has 'upper undergraduate' in it. Great.
 
^_^
 
I did $\log 81 < \log 83 < \log 84$ and some fancy factoring combined with $\log 3 > 1.09$ + $\log 2 > 0.69$ on the left handside and $\log 3 < 1.1$ and $\log 2 < 0.7$ on the right handside.
@TheGame Silly man $83$ is prime.
 
@N3buchadnezzar xD my bad
 
@TheGame No coconut for you. Please proceed with your plan
 
@N3buchadnezzar COCONUUUTS
 
7:07 PM
@N3buchadnezzar why don't you just do $\int_1^{83}\frac{dx}x$
 
Turn the monkey into a BBQ?
 
then do some riemann sums
or trapizoid
surely there is sand and a stick to write with
 
@Alizter or gauss quadrature
 
Off to have lunch with my son. BBL
 
@JasperLoy okay, looking through it, I'd like to have something a little more abstract/difficult
Any more suggestions?
 
7:10 PM
@Danu Are you sure it is not good enough? It suffices through the entirety of grad school as well.
 
Meh @Mike actually the trivial metric works well.
 
@JasperLoy Not at all, just a quick glance. It's very explicit, which is certainly not a big problem
 
@Danu OK. Try Roman's Advanced Linear Algebra then.
 
...but I thought maybe there'd be something succinct
Thanks! :) This is great
 
OK, @Mike, forget about my previous example. Forget that I ever said it. The trivial metric $d(x, x) = 0$ and $d(x, y) = 1$ if $x \neq y$ is the answer.
 
7:15 PM
@JasperLoy this seems to be at the right level. Many thanks!
 
@robjohn do you think I can put my name to that identity?
 
@Chris'ssis Yes, I think you can. =)
 
@Chris'ssis Then we will know your name :D
 
@TheGame lolllll :D
 
@Chris'ssis Also put your age and a picture too, LOL.
 
7:16 PM
Tanya Khovanova Uh no she's too old and not even Romanian xD x-DDDDDDD
 
:-)))
 
@TheGame That sounds like my enemy X.
 
@JasperLoy Uh ?
 
@TheGame Oh, never mind.
 
Our caring friend's here.
 
7:17 PM
@CareBear Hey there, a question to close ?
 
Hello @CareBear
@BalarkaSen have you seen this elementary solution to $x^2+1=y^3$ problem?
 
It's flawed.
$x^2 + 1 = y^3$ does not imply $x^2 = \sqrt{y^3-1}$
 
How to find the limit as x----> 0 in sin (1-cos x) /x ?
 
@BalarkaSen go tell him
 
@TheGame Who is Tanya Khovanova? I've never ever heard of this name.
 
7:26 PM
tanyakhovanova.com @Chris'ssis
 
@Alizter someone already said it.
 
@BalarkaSen It was too good to be true :P
 
and what @DanielF said
 
@TheGame How on earth did you get to the wrong conclusion I'm that girl? :-)
 
7:27 PM
@Chris'ssis That's what you told us -___-
 
^^ so many questions, so few votes...
 
@TheGame What?????? lollllllllllll When?
 
Im really getting annoyed by people who read things , i did not write !!
Like assuming In the OP I required some function to be entire , WHILE i did not even wrote that !
 
@Chris'ssis You told us you were the sis of someone called Chris when we asked you about your username
 
@TheGame Indeed, but this has no connection to what you previously said. And I'm from Romania.
 
7:30 PM
@Chris'ssis If you're the sis of someone then you're a girl -__-
@Chris'ssis OOH wait
@I read ''How on earth did you get to the wrong conclusion I'm a girl"
 
@TheGame lollllllllll
 
Why do people assume things that were not written to conclude the OP was nonsense , rather then to read again and try to understand the sense of the question ??
 
@TheGame You're terribly awesome !!!!! :-))))
 
:DDDD
@Chris'ssis I didn't think you were her, but you're both addicted to maths
 
in particular I NEVER assume that an OP was nonsense if it was asked by someone above 1900 rep.
 
7:32 PM
@mick Some weird people have 1900+ rep :c
 
isnt it the goal of reputation to give an indication of how seriously to take the OP ?
 
@Chris'ssis why were you called Chris previously?
 
@robjohn I seriously think that identity should have my name (if no one did it before). Maybe @r9m comes up with another paper by O'Connel and shows me it's already there. :-)
 
not talking about a German doctor at all
 
Is it possible to find a basis of Mn(R) that has only diagonalisable matrices ?
 
7:33 PM
@Chris'ssis The titan Vorpal identity ?
 
should I lol @TheGame
Because I do not know who your talking about
 
@TheGame Is he already above 1900?
 
@TheGame Like me, LOL.
 
@DanielFischer Yep
 
:(
10
The answer-ban threshold is too lenient. And too many people upvote crap here.
 
7:34 PM
@DanielFischer LOL.
 
@DanielFischer Does he not get stopped from posting answers after a significant amount of flags or something similar?
 
@DanielFischer Upvote my question :D
 
As an example , my recent question :
( where it was assumed the inverse of f needed to be entire ?? )
http://math.stackexchange.com/questions/984103/can-this-be-expressed-by-a-contour-integral
 
Can someone see my lhf here and upvote if correct? =) math.stackexchange.com/questions/984666/…
 
@TheGame Vorpal identity?
 
7:35 PM
@Chris'ssis Yep :D
 
Haha someone downvoted, LOLLOL.
 
@TheGame Why this name? :-)
 
I do not downvote
 
@Chris'ssis Because it's powerful ?
@Chris'ssis Search Vorpal on google
 
@TheGame Ah yeah, I got it. :-)
 
7:36 PM
Maybe you guys can help here
0
Q: Can this be expressed by a contour integral?

mickLet $f(z)$ be a real entire function of the form $f(z) = a_1 z + a_2 z^2 + ...$ such that $0 < a_{n+1} < a_n$. Consider $g(x) = f^{-1}(f(x)-f(x-1))$ where $x$ is a positive real and $f^{-1}$ is the functional inverse of $f$. I know $f(x)$ and $f^{-1}(x)$ can be given by a contour integral. C...

 
@Chris'ssis sword of omen ? excalibur ?
 
Vorpal sword is a phrase used by Lewis Carroll in his nonsense poem "Jabberwocky". == Context and definition == Carroll published Through the Looking-Glass in 1871. Near the beginning, Alice discovers and reads "Jabberwocky". The word "vorpal" appears twice in the poem, which describes a young boy's quest to slay a monster called the Jabberwock: He took his vorpal sword in hand: And later, One, two! One, two! And through and through The vorpal blade went snicker-snack! He left it dead, and with its head He went galumphing back. As with much of the rest of the poem's vocabulary, the reader is left...
 
oh frabjous day!
 
I thought you were into math .... dissappointed ... :p
I voted to close my own question hahaha
 
7:40 PM
calloo callay indeed
 
Unbelievable , i can vote to close my own question
Lets try a downvote
 
user18991
You cannot up- or downvote it.
 
hello @Mike
 
Common is my question so bad / unclear ?
 
hello
 
user18991
7:42 PM
It's unclear to me, but that's because I'm unfamiliar with the subject!
 
I hate it when I get negative comments and then they run away , not responding to my " defense " .
Ill sew their ass :)
 
@mick Sure $g(x)$ can be given by contour integral
$g(x) = \int_{\Bbb R} g'(x) dx$ where $g(x)$ is $g(z)$ on $\Bbb R$.
:P
 
lol
 
@BalarkaSen Ok I will make a small edit , see if you like it ...
 
Silly mick.
 
7:50 PM
@mick Yiorgos also didn't assume $f^{-1}$ was entire. Only that it existed.
 
@MikeMiller unfortunately ln is not entire ??? is what he said ?? I dont get it.
@BalarkaSen I edited , what do you think ?
@BakralaSen
 
@mick the answer is still a yes. $g(x) = \int_{\Bbb R} \lim_{h\to 0} \frac{f^{-1}(f(x+h)-f(x+h-1))-f^{-1}(f(x)-f(x-1))}{h} dx$
there you go
 
no you took the derivative of g ... which was prohibited in the edit.
Also its not a contour , unless considered on a riemann sphere.
 
@mick i never explicitly "took" a derivative. i just made used a limit in the integrand. and $\Bbb R$ is a contour.
 
I can't be arsed to try and do what I actually want to prove
And I don't want to do homework before I prove that
I'm in a loop
 
7:57 PM
@BalarkaSen when you take the limit , it is the derivative
 
@Studentmath Clearly, you need to spend time in a chat room on the internet.
 
ok. then $\int_{\Bbb R} [\int_{\Bbb R} g''(x) dx] dx$, @mick
 
maybe I should add , not using f^{-1} ?
@BalarkaSen
 
@mick it's very vauge. what do you mean by "using"? rigorously define "use this" and "don't use that"
 
@BalarkaSen Thats not a contour , but a double contour.
 
7:59 PM
@mick the integrand is an integral.
 
ok , no use of limits or integrals in the integrand ... going edit
 
and there is nothing called a "double contour".
@mick again, define "use"
 

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