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10:06 AM
guys i am getting hungry
 
pizza!
 
I have lunch in fact
bye
 
Why are high school maths teachers so bad? What do they do in their free time?
 
getting worse it is not that easy
 
Are you a high school student?
 
10:20 AM
Yeah, final year.
 
High school teacher especially in North american require very little qualifications
teachers*
 
Do you have a library nearby?
 
wth is a libary
 
If I was a high school maths teacher I would spend all my free time learning about maths and training my students to the best of my ability but I think most teachers have a very low IQ so they can't learn anything beyond high school curriculum
 
A library is a place where you can check all kinds of books
Whenever I was dissatisfied with my education in school I'd go to the library or internet.
 
10:23 AM
Im only half jokeing O.o n im almost a half generation older then Alexander
 
One shouldn't let the quality of their school determine the quality of their education.
Alexander, what math courses have you taken thus far?
 
Yeah, school, school environment, parents etc. can very negatively impact one's education
I have completed high school maths, now training for IMO and studying single variable calculus, linear algebra and learning about differential equations and analysis
 
Yeah i guess i was lucky my math prof had a masters degree in physics
 
Well, then a library is a good place to escape. Some libraries even have sharing programs with other libraries so that you can checkout books you can't find.
 
when i was in high school
 
10:28 AM
My teacher at school doesn't know basic maths like proving that sqrt2 is irrational or proving AM:GM inequality or any of these famous proofs. I complained so they replaced her. Luckily the new teacher is pretty good.
 
those kind of things arent important
specially in high school
 
I am a strong believer in that 'you are who you are with' so I spend a lot of time in the library, I have heaps of books on my computer and I ask questions here :)
Well, it is part of the syllabus so they are important
 
very very very very few people in a high school math class will be going to university to do math
 
I finished high school having completed only algebra 2.
 
In 2010 they asked to compute zeta 2, I'm pretty sure 70% of teachers can't do that...
 
10:31 AM
I'm studying mathematics at a university now. I didn't even know how to prove things in basic geometry.
 
Really? How are you finding maths at uni?
 
@Faust7 Sorry to drop in, but at least here in the Netherlands, the education system is so messed up that it is virtually impossible to discover that one likes mathematics by just going through the high school curriculum.
 
geometry can be veyr hard if u dont use modern techniques
 
I found geometry to be very intuitive once I encountered Felix Klein's method.
 
as i earlier mentioned didnt find out i liked mathematics until i did sevral 3rd math class's
in university
hated the first 2 years and high school math
 
10:33 AM
High school maths is basically training you to do the test, not really teaching you maths
 
The worst part about most 1st and second year math class's in university is that
 
I started off as a computer science major, but when I got into more advanced concepts, I realized I enjoyed the mathematical aspects even more. So then I switched to maths, but it was a difficult process to gain some measure of competence with proofs.
 
the course is taught in a way that is not geared towards any students enjoying it
its just like high school gear towards plug n chug an answer
 
Well, even the 1st and 2nd year math's are not deep enough.
 
so math students hate it
and eveyrone else hates math
 
10:35 AM
I decided to do engineering + maths at uni. It is a 5 year degree but there are more jobs
 
eh i already have a job
i do math for fun.
 
It's when you actually start learning things like analysis, abstract algebra, etc that you really begin to appreciate it.
 
my first 3rd differntail equations class i really enjoyed
 
Many of my friends doing maths at uni say they love analysis
 
Analysis is very nice, I enjoyed it thoroughly.
 
10:36 AM
analysis is a very useful set of tools
 
Do you guys agree that algebraic geometry is very difficult? I heard that from many people.
 
youd have to explain what u mean by algerbraic geometry
 
I haven't done it so I don't know :(
 
honestly if u make it past the first 2 years of math
 
@AlexanderJones It requires a quite different mindset. You have to be very strong in the commutative algebra department.
 
10:38 AM
everything is really easy
at least compared to before
 
@Faust7 So why haven't you proved the Riemann Hypothesis yet?
 
not part of my class's
 
Alexander, that's more specialized, once you get that deep you kinda have to decide what you want to specialize in.
 
im just saying that 3rd n 4th year math class's though they can cost a hefty work load
 
@Lord_Farin yesterday a proof for the weak goldmann conjecture was uploadet to arxiv
 
10:39 AM
are signifigantly easier then 1st n second year math class's
 
Can you guys explain to me the reimann hypothesis in one sentence? I read about it on wikipedia but it is hard to understand what it is hypothesizing
 
@AlexanderJones $\zeta(z) = 0 \land z \notin -2 \Bbb N \implies \operatorname{Re} z = \dfrac12$.
 
have you started calculus yet?
 
@DominicMichaelis Link?
 
@Lord_Farin Great! Really great.
 
10:40 AM
Yes, I have done a lot of calculus
 
@Lord_Farin hmm that made no sense to me :(
 
@Faust7 RH is unproved for like 200 years. xD
 
Learn some complex analysis Alexander.
 
It's a millennium problem.
 
10:42 AM
Try getting Real Analysis done asap, then move onto complex analysis.
 
What textbooks do you recommend?
 
It should make the terminology for the underlying theory of the Riemman Hyp more digestible.
 
@Lord_Farin What's the meaning of $-2\mathbb{N}$?
 
@GustavoBandeira he was being a smart ass and he knew it, comment was to emphasis the fact that hes a troll.
 
@DominicMichaelis Thanks. I see Mellin transforms and the like; probably better not spend my time on that right now.
 
10:43 AM
First time I see this.
 
@GustavoBandeira Well it's a special form of a set-product: $aB = \{ab: b \in B\}$.
 
For a beginning class in real analysis, start with Bartle and Shebert intro to Real Analysis
 
I am currently using Apostol but it is hard :( I will use the one you suggested
 
once you're done with that, for a complex analysis course, I suggest you look at An Introduction to Complex Function Theory by Bruce Palka
 
@AlexanderJones Try not to struggle too much - search for another books.
 
10:44 AM
@Dominic It's unbelievable. I just came up with a combinatorial argument for a combinatorial identity.
 
As an adjunct to you studies in complex analysis, I suggest you look at Tristan Needham's Visual Complex Analysis
 
@AlexanderJones Peter Smith wrote: "I very strongly recommend tackling an area of logic (or indeed any new area of mathematics) by reading a series of books which overlap in level (with the next one covering some of the same ground and then pushing on from the previous one), rather than trying to proceed by big leaps."
 
@GustavoBandeira This is very good advice.
 
How good are you with proofs Alexander?
 
I know basic proofs, nothing advanced
 
10:47 AM
Are you comfortable with logical patterns behind their reasoning?
 
@Lord_Farin Yeah. Perceiving it helped me a lot, I was stuck in the "strugle to read the hardest book!" - I wasn't doing any progress.
 
@GustavoBandeira I agree with Peter Smith, thanks :)
 
For example, are you comfortable with the notions of DeMorgan's Law, Contrapositive, an Indirect proofs, etc.?
 
Some one told me to learn proofs from Daniel Vellemann Proof book but it is a bit hard
 
@GustavoBandeira More so considering that books are still easy, compared to research papers.
 
10:48 AM
If you found that hard, then I have some suggestions for you.
 
I haven't done any of those :( What are your suggestions?
 
@AlexanderJones I really loved this book‌​.
Look the quote from the author in the website.
 
Anyone have that webcomic picture witht eh graph of understanding of 1+1?
 
Let's start with the following books: Intro to Inequalities by Beckenbach and Bellman, a Primer of Abstract Mathematics by Robert B Ash, and Mathematical Thinking by Douglas West
 
@Lord_Farin yeah it seems to be not that trivial
 
10:52 AM
looks like a double bell curve its got a funny comment at the lowest point "define 1?" with a picture of a guy with a phd?
 
@EdwinMontufar Thank you, I will look for these books on the internet.
 
@DominicMichaelis No surprise of course; otherwise it would have been solved long ago.
 
The inequalities book will help you tackle some fundamental concepts in real analysis.
 
Nice talking to you guys, I will go do some studying now :)
 
@AlexanderJones Bye, good luck!
 
10:55 AM
@Alexander Jones Good luck.
 
@AlexanderJones http://ramanujan.math.trinity.edu/wtrench/texts/TRENCH_REAL_ANALYSIS.PDF

imho is a great intro to Analysis textbook and its a free pdf
 
@Faust7 that book looks really good. Reminds me a bit of Bartle and Sherbert's book, but it has more topics.
 
I had never taken analysis before n that was recommended to me by a prof at my uni.
Sadly its out of print spent an hour on a crappy mac at the local print shop trying to crop and print the pdf. Something about math i just can't handle it as a pdf =(
 
Same here, too much eyestrain.
Plus I like to write on margin spaces
 
specially in a class like analysis!
 
11:03 AM
@EdwinMontufar Interesting; I never do that.
 
@Lord_Farin, do what?
 
@EdwinMontufar Write in margin spaces (or generally, in a book). Unless it is to indicate a typo/mistake.
 
Well sometimes the authors leave out details on purpose, so I just fill them in.
 
so i just realised the taylor expansion (1-x)^{-1} = 1+ x +x^{2}+.... actually comes from the geometric series...
(1-r)^{-1}
 
@EdwinMontufar An admirable practice; in hindsight I think I could've learned some things faster if I had done that as well.
But usually I just try to formulate the argument in my head, or when that does not work, write it out on some paper. Or sometimes I just take it for granted when it is a minor point.
 
11:06 AM
Thats why i alwasy keep my math textbooks, they are better then the original assumeing you can read my shitty wok writeing
 
For example some authors put (Why?) besides some of their statements, and so I put the answers in the margins. Of course there's also the occasional typo. Or sometimes I even generalize concepts in the margin space.
 
Cept this Calculus textbook im going to burn it as soon as i get home today after my test.
 
@EdwinMontufar Are you hoping to have your own "Fermat moment" one day? :)
@Faust7 If you keep it, the only thing that really matters is that you yourself retain the ability to read your writing (sometimes when I read old notes from lectures I attended I'm struggling to decrypt the ubiquitous abbreviations :)).
 
@Lord_Farin, well the problem with Fermat is that he didn't have enough space in the margins to put proofs for some of his theorems ;)
 
@Faust7 You have a test today?
 
11:10 AM
@Lord_Farin, sometimes if the book is too involved, I dedicate a notepad or journal to it.
 
@EdwinMontufar I'm impressed. I'm usually too lazy for that kind of stuff.
 
@Lord_Farin honestly i can't usually read my notes or problem sets i have started to just type them out in latex my marker appreciate it and both of us can read it.
Yes i have a test i was hospitalized during finals and missed a few exams i need a 3rd calculus course to be properly registered in Analysis. also I like Fermats little theorem more then his last one =)
 
@Lord_Farin I'm reading an introduction to category theory. =)
 
@Faust7 The LaTeX skill is indeed a very useful one. Good luck with your exam!
@GustavoBandeira Which one?
 
@Lord_Farin it's always good for me to keep records. I typeset a lot of my journals in latex to store the info electronically. I use a program called Lyx to typeset rapidly, almost like a word processor.
 
11:14 AM
@Lord_Farin An Introduction to Category Theory: Harold Simmons
 
@GustavoBandeira Nice.
 
@Lord_Farin What book did you used?
 
@Lord_Farin, the only problem with typesetting my work is that implementing diagrams can be rather tedious.
 
I Found a "Fermat Prime" while taking a 1st year math class i didn't know the theorem at the time but i was using a combination of mod and different base number systems and came to the conclusion the number i had was prime. ( turns out it was just very likely prime) but my prof was nice enough to explain the theorem to me =)
 
@EdwinMontufar I tried Lyx, but nowadays I just use WinEdt. For diagrams I use TikZ.
 
11:17 AM
I feel me attracted by some mathematical ideas. As I'm a noob, I have no idea of what most of them are. Category theory, topology, automata, etc.
 
@Lord_Farin Yeah, I've messed around with Tikz, the syntax is quirky, but it has good output.
 
@GustavoBandeira To get started I used CWM by Mac Lane and Category Theory by Awodey.
 
Yeah. I've heard about these ones.
 
@EdwinMontufar The syntax of all diagram typesetting mechanisms I've used cq. seen so far is quirky.
 
@Lord_Farin Asymptote is pretty straightforward actually, though it could use more documentation.
 
11:19 AM
if you got the coin fork out the dough for a laptop/tablet hybrid i got one with a 8.5x11.5 inch screen it takes some training the software but it can read any of your writeing and you can add vocab like the intergral sign with bounds and get the program to export your writing directly to latex
 
@Lord_Farin the syntax in Aysmptote bears some semblance to C++.
 
@EdwinMontufar I've done my fair share of programming, so it wasn't too hard to get used to TikZ (I mostly use the tikzcd environment which is relatively accessible compared to the full-fledged version).
 
Oh also im sure most of you have a program for type setting in latex? the program im using to make pdfs to send my hw assignments in is really annoying what do you guys use?
 
@Faust7 In set theory, we have things like this. I'm happy with the \aleph command :).
@Faust7 I use WinEdt.
 
Dude. In the future I'll build aquariums again. Look at this
 
11:22 AM
@Faust7, I'm a big fan of Lyx. It's a word processor like environment that uses latex to typeset your documents.
 
Damn beautiful.
 
ill check out both
 
If you don't want to worry too much about your latex code, then I suggest you go with lyx. It simplifies a lot of latex functionality and has autocompletion.
 
@Faust7 For your demands, Lyx is probably a good place to start. Once you get to need a lot of custom macros, a text-based editor like WinEdt (there are more good options, just do a web search) can become preferable.
 
@Lord_Farin I'll give it a try. I loved TeXworks.
 
11:25 AM
Im using Texworks
i dont liek that you need \\ to put a spcae between a line it formats everything veyr oddly
like worse then my typeing
it also compiles randomly and doesnt properly dump temp after each compile
 
@Faust7 It retains the auxiliary files to speed up future compilations.
 
@Faust7 But have you searched for solutions?
 
im more of an intuitive software user
 
so go with Lyx
 
Yeah. Just as I guessed. :P
 
11:29 AM
i work in the tech field, if i cant mess with it some way i find logical to get what i want
then i dislike it =)
but i did like read most of the option links u can click on but god knows i didnt open a help file
This book i have listed a formula for calculating surface integrals but i think its just a change of varibles written out funny
 
dropbox.com/s/rsq7dt83d5nfd3o/Assignment11.pdf Here's an example of some of my output with lyx
 
$\int \int_{S} F \cdot n dA= \int \int_{w} F(G(u,v) \cdot (dG_{u} X dG_{v}) du dv$
 
Lyx is pretty flexible with formatting so it'll make things pretty easy for you.
 
@EdwinMontufar Graphs are with TikZ? Or Pstricks?
 
Cause isnt that formula just a change of varibles on F and then a new normal vertor n_{1} that is normal to the change of varibles?
 
11:37 AM
@JayeshBadwaik those are with Tikz
 
i downloaded it and installed both will play with them tonight after my exam
 
@Faust7 look up a lyx tutorial on you tube to get an idea of what the workflow is like
 
Sankyuu =)
 
Good luck with the exam Faust. I'm out fellas, have a good one.
 
@EdwinMontufar Bye!
 
11:47 AM
its should be ok, studied like a slave for it and had 96%+ going in =)
 
@Lord_Farin What do you use to read PDF's?
I loved STDU Viewer. It's the only one that really stores the page I'm in.
 
@GustavoBandeira I generally just use Adobe XI Pro; for previewing my TeX documents I use SumatraPDF (because that one is designed to work well with WinEdt).
 
@Faust7: Have a look at your question. I made it better in looking. :)
 
lol yes you did =)
that "formula" has been driving me nutz where it comes from
its just writen down in my textbook as this exists use it if u want
 
12:12 PM
I'll be off to useful things. Bye all.
 
@Lord_Farin See ya
 
1:08 PM
hello
 
@Vrouvrou howdy
 
supposing $\displaystyle F_n(x)=\int_0^x t^ne^{-t}\,dt$ using induction how to prove that the limit exist when x tends to $+\infty$?
 
Q: i got a limit that defined to be 0 but as the derivative of my function aprochs this value from 0+ or 0- there is no neighborhood of 0+ that is strictly positive or strictly negative. how do i use that to violate conntinuity
i know that if i have some point x and x>0 then there exists a nieghbourhood of x that is stricly positive this is true for all x>0 but is violateing that suffient to say i am discontinous at my limit?
my confusion arises from if you take the actuall limit point ie x=0 then there is no neighbourhood of this point what my criteria above is satified can argue that 0+ or 0- are a limit and show they are diffrent then 0 to show im not continous?
 
@Faust7 It seems that the continuous function $f(x) = x \sin \frac1x$ provides a counterexample to your assertion.
OTOH it is necessary for the limit still to exist, given your condition, that the function value at zero is zero.
 
1:26 PM
not sure thats a counter example |Sin(1/x)| \leq 1 so you have lim x /to 0 of x*1
if you lose that x bound though
sin (1/x) x\to 0
defin f(0) =0
then f is discontinous at x=0
maybe im nutz
 
Yes $\sin \frac1x$ cannot be continuously extended to $x = 0$. But that's exactly my point.
$x \sin \frac1x$ changes it sign infinitely often when approaching $0$, but it still is continuous at $x = 0$.
 
so it you look at 0+ of sin(1/x) there is no neighborhood of 0+ s.t everything in that interval is postive
no matter how small you make that interval
that violates being continous somehow more directly because the definition of a point be continous is that that interval must exist or you have a limit point
 
What is your definition of "continuous", then? $\epsilon$-$\delta$?
 
no nothing that strong
but normally when u have a limit point at 0
 
(By the way, on the right you see a link "$\LaTeX$ rendering in chat" which may help you reading my messages, and possibly format your own.)
 
1:35 PM
i dunno i just seems to have it drilled into my mind that there must exist a neighbourhood of every positive/negative point that is stricly positive or negative in order for something to be continous
perhaps im out to luch
 
@Faust7 As I said, you are correct as long as the function value at the limit point is nonzero. In that case, if e.g. $f(x_0) = a, |a| > 0$, taking a suitable $\delta$ for $\epsilon = \frac a 2$ will provide you with the desired neighbourhood.
 
but o+ >0 by cant i make the argument about 0+ sinc eits not a limit point and no such neighbourhood exists as x \to 0?
even if my function did take the value 0?
 
The notation $\lim\limits_{x\to 0^+} f(x)$ means that the limit is taken as "approaching from the right".
See e.g. here.
 
sorry im not entirely following but 0+ is \delta >0 so why is there no neighbourhood about 0+ say \delta /2 thats stricly positive?
 
MJD
@robjohn In this month of moderators losing their heads, burning out, and resigning, it took me a while to remember which moderator has not done that. I think it's to your credit that I couldn't remember at first who the remaining moderator was, and I would like to thank you for your hard work.
 
1:43 PM
hmm ok well imt rying to prove that $\sin (x^{-1})$ where f(0)=0 lim x \to 0) does not exist and i can't use any epislon's or deltas how would i do this?
 
@Faust7 If $f$ were continuous, then for any sequence $x_n$ with $\lim\limits_{n\to\infty} x_n = 0$ one would have $\lim\limits_{n\to\infty} f(x_n) = f(\lim\limits_{n\to\infty}x_n) = f(0)=0$.
So all you need to do is conjure up a suitable sequence such that $\lim\limits_{n\to\infty} f(x_n) \ne 0$.
 
O.o
 
I apologise if I'm being too formal about it. But it has been a long time since I dealt with limits in an intuitive way.
 
haha =)
 
But you could e.g. take $x_n = ((n+\frac12)\pi)^{-1}$.
 
1:52 PM
its there some way i can bound sin(1/x) by something that converges to 0 from above?
 
@Faust7 No, because the sequence I just gave provides points $x$ where $\sin(1/x) = 1$ arbitrarily close to $0$.
 
oh im a moron nvm
last stupid question sin( \pi n) = -sin (n) ?
 
@Faust7 $\sin \pi n = 0$.
And $\sin -x = -\sin x$.
 
sorry not where n \ \mathbb N but n \in \mathbb R ?
 
In that case nothing can be said.
 
2:01 PM
@Lord_Farin well $\sin(\pi x)\in \mathbb{R}$ for $x \in \mathbb{R}$ :D
 
@DominicMichaelis Thank you, Captain Obvious...
 
rofl
 
@Lord_Farin i lost 3 of 4 points in a complex analysis exam cause i didn't proof that $\sin(i)\neq 0$ ...
 
that blows
 
@DominicMichaelis ... I say, trial by fire.
 
2:04 PM
thats ok i lost 0.5 marks on 2 questions my exam was out of 40 and marker wrote 31/40 on the front of my test
took my prof 10 minutes to figure out what my grade was supposed to be and to this day i havent any idea how he added the numbers together to get 31
as no combination of number gave an 8 =\
 
Couldn't you appeal or otherwise request justification for your mark?
 
Don't you know 40-2 * 0.5=31 because **** you ? :D
 
lol my prof eventually gave me 39/40
its just there no logcical way he could of added or subtracted the numbers i had on my paper to get 31
 
@Faust7 We conclude that mathematicians aren't necessarily adepts at basic arithmetic :).
 
well the heuristic is clear
 
2:09 PM
my prof really didnt like that grad student though =P
 
you don't have 40 points but that lose that much hence your points are 3x
because 2*0.5=1 it is 31
 
shoulda had 40 on that test but i used a method we allegedly didnt learn to solve one of the problems =\
but honestly who use a liaponov function to show that you have a limit cycle? poincare bendixion is clearly the most logical method.
does calculus ever get easier? it seems to take me 3-5x as long to get calculus concepts as well any other area of math?
 
@faust7 Show wheter $$\sum_{k=1}^\infty \left( \frac{(\sin(k)+2)^k}{3^k}\right)$$ converges
 
@DominicMichaelis $k = n$?
 
oh right
 
2:18 PM
(sin (n) +2 )^{n}< 3^{n} call it L< 3^{n} thus let r= \frac { L}{3^k} thus |r|<1 for all k hence it converges.
 
@Faust7 It gets easier. But it requires a lot of practice.
There is no $L$ that works for all $n$.
 
L is just defined to be < 3^{n}
im relabeling sin(n)+2 < 3^{n}
then i can make it into a geometric series
where r<1
 
@Lord_F hies
 
its just hard to write it without picking a letter to deifn it
 
nope you can't
 
2:20 PM
@Faust7 For all $\epsilon > 0$, there is are infinitely many $n$ such that $|\sin(n)-1| < \epsilon$. (You did notice the power $k$ in the numerator?)
@Charlie Hello there.
 
@Lord_Farin how are you doing?
 
@Charlie Quite fine, but busy.
 
@dominic hello
 
|sin (n)| /leq 1
 
@charlie hi
 
2:21 PM
@Lord_Farin oh!
 
so why cant i say sin (n) +2 \leq 3?
 
you can say $\leq$
but $\sum 1 $ doesn't converge
 
@DominicMichaelis :D
 
@Faust7 You can, but you can't say it is below $3-\epsilon$ for all $n$.
@DominicMichaelis I could imagine that it still converges... But it requires careful analysis.
 
oh your right there are values where my r=1
 
2:23 PM
@faust7 not $r=1$ but arbitrary near at 1.
@Lord_Farin yeah it converges indeed.
 
wellt here exists n s.t sin(n) =1
 
nope because $n\in \mathbb{N}$
 
so there exist n s.t r=1
oh i didnt realise n \in N
 
we sum over it ;)
 
then my r should still work no?
r<1 in my messed up geometric series?
i guess the ratio test might be a better choice
it will deal with the situation better
 
2:25 PM
no they all fail
even thought $\sin(n)< 1$ for all $n \in \mathbb{N}$ we find a subsequence converging to 1
 
no the ratio teest will let u bound 0\geq |sin(n)| and |sin(n+1)\ <1 which will elave u with 1/3 <1 so it converges
 
you missed a +2 there
 
the +2 will be on the top and the bottom
 
Yes, and $\dfrac{7+2}{3+2} = \dfrac 7 3$. Or not.
 
so they cancel out
 
2:29 PM
@Lord seems legit ;)
 
@DominicMichaelis It will probably be reasonably easy to prove $0 = 1$ from there.
 
@MJD Thanks, but Mariano, mixedmath, and Willie Wong will be hanging on, too.
 
@Charlie Hi
 
define it like this (sin(n+1)+2)^{n+1} *3^{n} / 3^{n+1} * (sin(n)+2)^{n}
dam that gives you 1 as well
i know it converges
how do you show it?
 
@Faust7 there is no $r$ that works.
 
2:33 PM
yeah i have figured that out
 
@pourjour hi Soufian, how are you?
 
@Charlie fine thanks and you?
 
@Faust7 You will probably have to use some intricate argument estimating how many $n$ have $\sin(n)$ close to $1$, and show that there are "few enough" of them.
 
@pourjour I'm fine.
 
@Charlie we started leaning organic chemistry (acid carboxylic ....)
 
MJD
2:50 PM
@robjohn Right, thanks for the reminder! The best moderators are the ones you can forget about.
3
 
3:12 PM
@Faust7 You do? Heuristically, it would seem to diverge.
Suppose that $y=\sin(k)$ the sum for the geometric series with ratio $\frac{2+y}{3}$ is $\frac3{1-y}$. The probability of getting a sin equal to $y$ is $\frac{\mathrm{d}y}{\pi\sqrt{1-y^2}}$. Since $\int_{-1}^1\frac3{1-y}\frac{\mathrm{d}y}{\pi\sqrt{1-y^2}}$ diverges, I would expect the series to diverge.
@Lord_Farin Ah, I just saw your comment. See my last comment to Faust7 :-)
 
3:34 PM
Meh. Wrote a really stupid bug into my code as a consequence of auto completion. Then spent 6 hours trying to find it. This is why I hate writing code.
@JonasTeuwen Ayt?
 
@pourjour that's cute :)
 
@MattN. Yes and no.
I am now.
Now I go again. Tralalaa. I need to tinkle.
 
4:06 PM
startet answering on the meta thread
 
4:41 PM
$n$ is odd $\Longrightarrow n^2\equiv 1 [8]$
I tried to prove the statement above
by supposing n=2k+1 but in vain
any suggestion
 
@pourjour For all integers $k$, $k^2+k$ is even.
 
$(2k+1)^2 = 4k^2+4k+1=4k(1+k)+1$ q.e.d. @pourjour
 
@Lord_Farin couldn't notice how to use this trick to solve the statement
@DominicMichaelis yeah that's what I get
 
one of $k, k+1$ is even
hence 8 divedes $4 k (1+k)$
 
4:45 PM
@pourjour I take it that Dominic's remark complemented my suggestion to a sufficient point.
@Chris'swisesister Hello. What happened?
Where have your pals gone? Did you sacrifice them for wisdom?
 
@Lord_Farin What happened? Yeah, I am upset on all of them and erase them.
 
@Lord_Farin @DominicMichaelis ok I get it
 
:D
@Lord_Farin I finished a whole math book in one day. Then I decided to put that "wise" to my nickname.
 
so we separate the cases if k=2p
then 8p(1+2p) can be divised by 8
the other case k+1=2p
.....
 
@Chris'swisesister Your choice.
 
4:52 PM
@Lord_Farin Now I'm trying to evaluate this in a different way math.stackexchange.com/questions/390640/…
(by using beta function in terms of trigonometric functions)
 
@Chris'swisesister Interesting. I've just been confronted with my daily vote limit :(.
 
@MJD See, it's so thankless that the guys who work efficiently in the background are easily neglected... :)
 

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