The Nineteenth Byte

quartata

9:00 PM

Good afternoon, world!

Zach Gates

Ditto

El'endia Starman

@BetaDecay "!thgindooG">:#,_@

quartata

::print("Good night!");

flawr

public class BB{public static void main(String[]a){System.out.println("Good Night everyone!");}}

Zach Gates

print"Goodnight!"

Alex A.

9:05 PM

'Goodnight!'

El'endia Starman

Dangit Golfscript.

flawr

Is there a language even more verbose than Java?

quartata

INTERCAL

Alex A.

Assembly

flawr

Ok, my next codegolf challenge will be intercal only^^

bb everyone

quartata

9:08 PM

Good

Zach Gates

(337343635537761436988449).to_bytes(10,'big').decode()

minxomat

Applescript beats INTERCAL.

tell application  "Microsoft Word"
    open file "Diplomarbeit" of folder "Dokumente" of disk "Studium"
end tell

quartata

Applescript is actually not that bad

Zach Gates

Is there such thing as inverse code golf

minxomat

Yes

Zach Gates

9:14 PM

Where the goal is to get the most bytes?

quartata

can anyone who knows ><> tell me why this prints Good night! and then an error?

pastebin.com/rh95CMug

Oh wait I'm stupid nvm

Zach Gates

Found it. code-bowling

minxomat

Oh wait I'm stupid nvm should be a button on SO questions. :)

quartata

I would post my Good night in ><> answer but chat seems to eat the whitespaces

Alright so I'm gonna write this challenge really quick and then ask you guys what you think

You're my focus group

Except you don't get paid

Any way to do LaTeX on SE?

minxomat

AFAIK no. But you can use codecogs and include the image.

codecogs.com/latex/eqneditor.php

El'endia Starman

9:21 PM

Thought making a Befunge answer vertical would save bytes. Nope. Newlines.

quartata

Alright

Focus group are you ready?

El'endia Starman

@quartata A few SE sites have the ability. Math.SE being an obvious one.

You can also do LaTeX in chat if you have the ChatJax extension.

quartata

Hmm

Oh well it doesn't matter

Here's the challenge

Let x be a number of arbitrary base such that D is the set of its digits. x is a ***Can't think of a name Number*** if for any number n between 1 and the length of the number, D_(n+1) = D_n + D_n-1 + ... + D_1 + n. So for example, let's take the number 349 in base 10. If we label the indices for this number, we have:

1 2 3

3 4 9

Starting from the first digit, we have 3 + 1 = 4. Then with the second digit we have 3 + 4 + 2 = 9. So this number is a Can't think of a name Number.

Here's the challenge. Given a base between 1 and 62, calculate all the Can't think of a name Numbers for that ba…

Tell me whatcha think

Zach Gates

Can you put it in the Sandbox? Chat is not a place for posting a question

quartata

Oh sorry

I did it before and I didn't get yelled at so I thought it was OK :P

My bad

minxomat

9:31 PM

Works. Just use [upload...] -> [from the web] -> http://latex.codecogs.com/gif.latex?<putlatexhere>

Doorknob

$user image$

^ or use a direct link

(pro tip: use a ! at the beginning of a message to force image oneboxing)

Zach Gates

Does this look familiar to anyone: b'I\x1fD\xb4\xf5\x91\x1fA\xbd\xb3`f\x86\xc2\x88\x91JP\x8c\xcf\xac\x88\xfa\x1d&'

quartata

I posted it on the sandbox zach

meta.codegolf.stackexchange.com/questions/2140/… if you want to take a look

Zach Gates

Ok

quartata

Sorry about that again :P

oops forgot a number

Zach Gates

9:45 PM

I think you should come up with something else to call the "Can't think of a name Numbers" @quartata

quartata

Yeah that's just temporary

Hmmmm

I would call them Quartata Numbers but that's a little egotistical

feersum

Just pick a random work from the dictionary.

quartata

Confidant Numbers it is then

Little strange but ok

feersum

Your secrets are safe with these numbers.

2

minxomat

Hah. ifaq.wap.org/computers/compilersarefemale.html

quartata

9:50 PM

I'm a little worried people will be confused cause the indexing starts at 1 but it doesn't really work otherwise

or at least it's not as cool

Zach Gates

> [...] if for any number n between 1 and the length of the number, D_(n+1) = D_n + D_n-1 + ... + D_1 + n.

That doesn't make much sense @quartata

quartata

What part doesn't make sense?

Zach Gates

The part I quoted

The formula after the comma ^

quartata

Well basically it's saying the sum of the previous digits plus the index of the current digit is equal to the next digit

so with the 349 example

let's take the 4 digit

4 + 3 + the index 2

Zach Gates

Ok I got it now

quartata

9:54 PM

gives us the next digit 9

It's in set notation which was probably not the best way to explain it :P

It would be nicer if I did it up in LaTeX

One second actually

New Sandboxed Posts

0

A: Sandbox for Proposed Challenges

Confidant Numbers Let x be a number of arbitrary base such that D is the set of its digits. x is a Confidant Number if for any number n between 1 and the length of the number, D_(n+1) = D_n + D_n-1 + ... + D_1 + n. So for example, let's take the number 349 in base 10. If we label the indices for...

quartata

Now with latex

Didn't want to do the whole thing up cause it wouldn't stay in line

Max

should be: D(n+1)=D(n) + ... + D(1) + n

quartata

but that equation I latexed so it's understandable

?

It's not a function it's a set

Max

or with square brackets

quartata

9:58 PM

Oh I see what you mean

Yeah didn't mean to have the -1 out there

It's better now with the picture

Well I got an upvote so that means someone liked it

I figured it was an interesting enough challenge I was just worried that it wasn't explained properly

Does it make sense?

Max

yeah with the picture it's more clear

El'endia Starman

It makes sense to me, but then again, I'm a mathematician. I also immediately figured out how to generate the numbers. :P

quartata

Heh

Max

also I should change "any number n between 1 and the length of the number," with "any given n between 1 and the length of the number,"

quartata

Alright

Ill fix that and then post it

0

Q: Confidant Numbers

Confidant Numbers Let x be a number of arbitrary base such that D is the set of its digits. x is a Confidant Number if for any given n between 1 and the length of the number, So for example, let's take the number 349 in base 10. If we label the indices for this number, we have: 1 2 3 3 4 ...

Have fun!

New Main Posts

10:05 PM

1

Q: Confidant Numbers

Confidant Numbers Let x be a number of arbitrary base such that D is the set of its digits. x is a Confidant Number if for any given n between 1 and the length of the number, So for example, let's take the number 349 in base 10. If we label the indices for this number, we have: 1 2 3 3 4 ...

code-golf number number-theory

Justin

I just passed off my CS lab, but for some reason, the pass-off computer didn't have boost (but it should...) so I zipped boost with my lab.

The zip file was 16 MB.

Someone else passed off their lab, at 4 KB.

quartata

CS labs are notorious for not having stuff

I went to my CS lab once and it had Java 8 and yet it had a version of ant that was 7 years old

Justin

@quartata But it's weird, since when I ssh into the lab, it has boost. That's why I thought I could use boost.

@quartata Wow.

It was pretty funny, though. The TA was surprised. He didn't expect anyone in this class to know Boost, Git, SSH, unit testing, etc.

Zach Gates

I just edited your question. Feel free to revert any edits. @quartata

Justin

I used all of the above.

quartata

10:13 PM

Sorry I'm back

OK thanks Zach

You made a mistake with the equation

It's D(1) + n

Zach Gates

I fixed it

It should be g(n+1) = f(n) + g(n) + f(n+1), where f denotes the index, and g denotes the digit at an index.

Your use of D makes no sense, because of your prior definition of it.

quartata

Uhh

That's the idea though...

You add the index only once

You take each of the previous digits + the index

and that makes the next one

Sorry if I didn't make that clear initially

Zach Gates

No, I understand how the equation works

You said

> D is the set of its digits

quartata

Yes

Zach Gates

Thereby making this equation

> D(n+1) = D(n) + D(n-1) + ... + D(1) + n

Reading where D is the set of its digits

quartata

10:22 PM

Yes....

Zach Gates

The set of digits of n+1 equals: the set of digits of n, plus the set of digits of n-1, plus the set of digits of 1, plus n.

quartata

..?

No the way I had it should have meant the N+1 element in set D

Other than that all the other edits you made are great, thanks for that

I'm not great with formatting

Zach Gates

If you applied what you wrote on the second index of 349, you would get 3=2+1+1+2

I'm going to edit your Sandboxed version to see if I can make what I'm saying more clear

I'll leave your main post alone

Justin

Does anyone have any opinions on this? I think I might post it soon.

Zach Gates

10:37 PM

I just made an edit which should fully explain my point. @quartata

quartata

OK I think I see what you are confused about

Two things.

One when I say D_n+D_n-1+...D_1 I'm essentially saying sum all the elements in D between 1 and n

that's what the ... is for

Secondly, D is not a function. D is a set (or an array in CS) that contains the digits of X, which is the number we are testing

Zach Gates

You aren't using D correctly then.

quartata

How, exactly?

Zach Gates

Did you look at my Sandboxed edit?

El'endia Starman

@NewMainPosts FOR ONCE I have the first answer! :D

Zach Gates

10:43 PM

@quartata I added two full verbose examples of the equation I added

quartata

Yes I did

Zach Gates

You have your description and equation mixed up

quartata

As far as I understand it, that appears to be index + digit + index + digit

this is digit + digit +... +digit + index

here maybe if I put it in psuedocode it'll be better

Zach Gates

I know what your intent was with the equation, but your description does not reflect the equation.

quartata

So let's say we start with n=3

Then I don't understand what the confusion is here.

Zach Gates

10:46 PM

The part where you said 1 + 3 = 4, for example.

According to your equation, it's actually 1 + 3 + 0, which is reflected in my rewritten equation. Either your description is wrong, or your equation is wrong.

quartata

No it's not. My equation says sum the digits between 1 and n and then add the last index to it

if n=1 then that is 3 (first digit) + 1 (index)

Zach Gates

The sum of digits between 1 and 20 is equal to 100..

quartata

Sum of the digits of x

the number

Zach Gates

But you just said

> sum the digits between 1 and n

El'endia Starman

> The key insight here is that given a sequence x (like, say, [1,2,5]), you can get the next term in the sequence with sum(x)+len(x), which gives 11 in this case (B).

Zach Gates

10:50 PM

So if the input was 20, the sum would be 100

El'endia Starman

That's how I interpreted it.

quartata

That was a typo

Zach Gates

That's not summing the digits, it's summing the integers.

[...] + 10 + 11 + 12

That's what you meant, correct?

El'endia Starman

Are you thinking all numbers are in decimal?

Zach Gates

Because the say it's written, it means [...] + 1 + 0 + 1 + 1 + 1 + 2

quartata

10:52 PM

I meant summing the digits of the number

Here I'll write you a program that tells whether or not a number is confidant

El'endia Starman

@ZachGates Ah, actually, you would write [...] + A + B + C. Then A,B,C are digits.

Zach Gates

Let's take this discussion here. @quartata

PhiNotPi

11:23 PM

@AlexA. I've been trying to get ElementaryOS to dual-boot, but it's not happy.

I ran into a problem where it just freezes on the loading screen.

By some miracle, Windows still works.

I'm gonna try to ask a question at elementaryos.se

quartata

Zach -[~~>+<]>--.[--->+<]>--.+++..+++++++.-[---->+<]>++.[->+++<]>++.[--->+<]>----.~~.[->+++++<]>+++‌.

That came out weird

pastebin.com/J8AXtFNe

Apology BF program

El'endia Starman

Lolz. ---x--- => x.

quartata

Yeah not sure how that happened

El'endia Starman

Hey, asterisk!

*

Zach Gates

> Sorry, bro.

Haha, no problem @quartata

quartata

11:33 PM

Didn't output the comma did it?

I might have made a mistake LOL

It was supposed to just be Sorry bro.

I appreciate the other edits you made at any rate

Now it looks so pretty

Zach Gates

The comma is correct grammar

quartata

I know but I didn't program the comma in by accident so if it showed up that was a double accident

Zach Gates

Ah, ok

It's 200 bytes now; it was 201 before. @El'endiaStarman

El'endia Starman

Wait no, 203 now, 204 before.

whoops

No, forgot to take out one line that did nothing useful in my saved program.

@ZachGates No, it's definitely 199 bytes. Did you forget to take out the trailing newline?

Zach Gates

I got 200 bytes. @El'endiaStarman mothereff.in/byte-counter

What are you using to count bytes? (just wondering)

El'endia Starman

11:49 PM

@ZachGates len(""" ... """).

I get 199 that way. I also get 200 with your linked online byte counter.

Zach Gates

It's because in Python, the "\n" is interpreted as a single character. @El'endiaStarman

El'endia Starman

AH! Yes, exactly.

Zach Gates

:P

Doorknob

You know, you could just use wc. :P

El'endia Starman

So...should I use 199? \n does count as a single byte...

quartata

11:51 PM

Yeah that's what I do

wc

El'endia Starman

You guys using Linux or something?

Zach Gates

Use "<s>201</s> 200" @El'endiaStarman

quartata

Yes..?

Zach Gates

I'm on Mac

El'endia Starman

Windows here, using IDLE. No wc for me.

quartata

11:52 PM

Then you can use wc too

If you are on Mac

wc -c FILE

Doorknob

Ok, let me restate that: You know, you could just use wc if you're on a sane OS. :P

El'endia Starman

Hey, I like Windows 10.

Zach Gates

@El'endiaStarman It counts as two bytes because it saves as plain text. Not an actual newline. Otherwise, your program wouldn't run.

quartata

@Doorknob Burnt

Doorknob

The OS wars have begun!

El'endia Starman

11:53 PM

@ZachGates Alright, that's reasonable. I'll do that.

quartata

Dundundundundundun

Doorknob

(Surely Windows has some method of counting characters?)

quartata

@Doorknob (I know, right?)

Zach Gates

@Doorknob Its browsers sure do. :P

El'endia Starman

Probably. But again, I'm already working in IDLE. It's quicker to just do len("""...""") than it is to open up a command prompt, navigate to the right directory, and execute the command.

Doorknob

11:54 PM

I just pinged myself that was weird

feersum

No, Windows doesn't have stuff like that.

Zach Gates

@El'endiaStarman I guess. I have that site bookmarked right next to PPCG, though :P

feersum

I paste the program into a new file in my text editor and see what the file size is.

Doorknob

I just count chars from within my editor (vim).

:%!wc