Quixotic

Anybody here?

Hello everyone

Hi guys

But, $\sqrt{x + 4} \times \sqrt{x+4} \neq (x+4)$$ right?

\sqrt{(4+x)^2} = \pm(x+4)

Guys, is it wrong to say $$ \sqrt{x + 4} \times \sqrt{x+4} =\sqrt{16+8 x+x^2}=\sqrt{(4+x)^2} = \pm(x+4)$$?

Hello everyone!

Yep, that's right.

The solution.

I am have riddle that's seems interesting

Hey Kannappan!

Hey guys!

Aha Thanks!

Am I right?

and does not exists in cases where it is undefined.

I think it's better to say that the limit is infinity here.

\lim_ {x \to \infty} x = \infty can we say (here) that this limit does not exist?

I have a question,

Thanks @tb

There was a discussion in M.SE about this. I am not able to find it now :(

I was wondering does anybody remember the name of the mathematician who derived the general rule for finding $\sum_{i=1}^{n}i^k$ for any k in \mabb{ N}

Hello guys!

Kannnappan: Unit digit, that's easy with modular arithmetic and I can do the whole thing with modular arithmetic in a jiffy but as far I can think there exists a algebraic way of solving this one using some manipulation

@N3buchadne Why Eeeeek? lol

I have one problem, How to find the last two digits of $23^3+24^3+25^3+26^3+27^3$ using algebra.

Hey guys!

Guys, Does anybody know how to integrate $$ \int_0^1 \frac{\ln(1+x)}{x} \; dx $$?

I don't understand why is it not taking care of the case $(\pm 5, 0)$

I have to count the integer solutions of $x^2+y^2 \le 25$, I am getting $81$, but woframalpha says it's $79$.

Hey guys!

While I can understand "Since $3^3=1\pmod{13}$, $9^3=1\pmod{13}$. Since $10=1\pmod{3}$, $N=1\pmod{3}$" I can't understand how $9^N=9\pmod{13}$ is implied from the above two. Any ideas?

I am having a lil bit of trouble in understand this answer, "Since $3^3=1\pmod{13}$, $9^3=1\pmod{13}$. Since $10=1\pmod{3}$, $N=1\pmod{3}$ and $9^N=9\pmod{13}$."

Hey guys!

it's 7/16

I got it

@Sullpatrol:a second.

My calculation suggests that the answer is 1/4, is it correct?

A and B are friends. They decide to meet between 1 PM and 2PM on a given day. There is a condition that whoever arrives first will not wait for the others for more than 15 minutes. Find the probability that they will meet.

Guys, I have a problem

I have one problem, "There are an infinite number of polynomials P for which P(x+5) - P(x) = 2 for all x. What is the least possible value of P(4) - P(2)?"

Yo guys!

just wondering if it is right

I think the the answer is 1/3...

@Ilya: Elementary inequalities.

Hey guys

@Ilya: but I guess we still would need $12 a b m n$

but having a bit of trouble in extracting