6:00 PM
@YashasSamaga When it is alone in aqeous phase.
@YashasSamaga This is inorganic

@anonymous ...

I guess it will comproportionate.

@0celo7 Discuss what?

What's comproportionate? o0

6:01 PM
Ah synproportionation

@skullpetrol Inorganic is mostly memorization.
With some logic though

which is why I hate inorganic

I love inorganic :)

especially block chemistry & qualtitive analysis
nothing is more fun than physics

It is logical.

6:02 PM
Organic chem is good though
logical stuff
Physical Chem is booooooooring but easy

Lets get back to the question.

the only annoying thing in physical chem is that you have too much to multiply, add, subtract, log, ln, etc -,-

My prediction is Nitrogen (I) oxide

@DanielSank Well, yes - you can sure say "I think you shouldn't flood the star board with trivial messages because it makes it useless" but that neither removes the stars already cast nor ensures it doesn't happen again in any way.
It's not really an alternative to cancelling the stars because it doesn't fix anything.

Hydroxylamine isn't organic, so I'd rule out NO2

6:03 PM

Okay! I was right. Answer is N2O! :)

Just like explaining to people that they shouldn't use sockpuppets to upvote themselves is not a replacement for deleting the socks, to extend your parallel to voting.

Three in the habitable zone!

user228700
@JohnRennie Haven't u been awake for awhile now? The Google doodle has been up since morning...

6:04 PM
@ACuriousMind It's not an alternative to removing stars, no.

You'll always get chem answers in the exam

It is a way forward.

@anonymous half of the options will have unbalanced charge/oxidation number

@Kaumudi.H I don't waste my time surfing the Internet :-)

@anonymous you can easily eliminate a few

6:05 PM
(I waste it talking about food here :-)

@YashasSamaga What is the product when NaNO3 is very strongly heated?

user228700
@JohnRennie Lol, suuure x'D Nope, this guy only scours the internet for shiny and cute laptops to buy every so often!

@ACuriousMind homology of boundaries

@anonymous O2, NO2, Na2O?
or it just gets reduced to NaNO2 and O2

@0celo7 Well, I currently have no new idea, so I have nothing to discuss :P

6:07 PM
@anonymous I'd guess if the options were there

@YashasSamaga No.

@Kaumudi.H I buy PCs too! In fact I bought one yesterday (for my aunt-in-law).

@ACuriousMind Lee has the one and two dimensional cases separately. I'll try to do those

@anonymous If those two are wrong,t hen the only answer remaining is Na2O and NO2

@YashasSamaga If you need options to answer a question then you haven't learnt Chemistry.

6:08 PM
@ACuriousMind (I am caring about topological manifolds all of a sudden because we are doing them in alg. Top)

@YashasSamaga Still wrong.

@anonymous I need options for block chem questions

user228700
@JohnRennie Yes of course, PCs too, how dare I forget about them?! :-) When are u going to fix it for her?

@YashasSamaga What will you do if such questions are asked in Integer type?

@anonymous whats the answer?

6:09 PM
@Kaumudi.H Weekend after next. That's the first weekend I can get away.

@anonymous I will be revising block chem a week before JEE

@YashasSamaga Hint: NO2 can't be formed in such a reaction.

user228700
@JohnRennie Cool :-)

@anonymous What?
@anonymous Pb(NO3)2 gives NO2, PbO, O2

6:09 PM
@JohnRennie "in-law"!

@anonymous I can give countless reactions where you get NO2

I thought you were unwed.

@YashasSamaga s(I) block elements are special.

AHA! John Rennie is married!

think why.

6:10 PM
@DanielSank his brother's in-law

user228700
^

@Kaumudi.H I might give her a wireless router as well. My niece is always complaining there's no wifi at granny's house.

@DanielSank Brother's mother in law

user228700
@JohnRennie Aww <3 :-)

6:11 PM
@JohnRennie I already said that >:(

Sorry, I've been working for 13 hours and the brain is on the fritz.

Should I ask my question as a full-fledged question on the site?

@whatin1992 what's the question?

John Rennie is enjoying a happy polygamous life with his laptops :D @DanielSank

@JohnRennie Maybe you should post a question We seem to be over-eager to star in meta.
46

Take this question: Dark matter clumping This is an excellent question and the answer is not at all obvious. I assume it was downvoted just because it's a duplicate, but is this really appropriate? Downvoting can be used to make questions disappear from the home page, and also to deter people f...

6:12 PM
@JohnRennie Why is it that a system can be entirely "described" by its Hamiltonian? I see the Hamiltonian as only an operator. Isn't the wave function the true way to fully describe a system?

wawe-functions

@whatin1992 The wave function describes the state of the system, the Hamiltonian its time evolution.

@YashasSamaga Did you understand why s(I) block doesn't produce NO2?

@anonymous I did not check yet. Tell me why.

user228700

user228700
6:14 PM
@AccidentalFourierTransform ^

@JohnRennie right, but I was curious about the wording in my book. They say this multiple times "a system described by the Hamiltonian $H$..."

@Kaumudi.H lol, who's the guy? he sounds familiar for some reason

@whatin1992 the Hamiltonian gives you the eigenfunctions, but the initial state of the system can be any linear combination of the eigenfunctions. The Hamiltonian then tells you how that state will evolve with time.

user228700
@AccidentalFourierTransform He is the infamous John Green :-)

@whatin1992 Don't overanalyse the language, it's rarely worth it. The Hamiltonian "describes" the system in the sense that given an initial state, you can predict the future state with it.

6:15 PM
@YashasSamaga One reason is their very high stability. Now think why they are highly stable. Their e.c. and electronegativity plays an important role.

@anonymous stablity of?

@YashasSamaga Nitrates.

@ACuriousMind that's my biggest problem :( I should have been a mathematician...

@anonymous somewhere earlier I had told NaNO2 + O2 too

@Kaumudi.H and... why the paint? lol

6:17 PM
@YashasSamaga That happens on mild heating

user228700
@AccidentalFourierTransform "Sharpie face" is a thing :-P Here:

user228700

@YashasSamaga Next question: NH2OH + H2O2 = ?

It oxidizes, hmm.

To what?

6:19 PM
@Kaumudi.H oh well, I was expecting something like "his two-year-old daughter" or something :-P

@anonymous thinking...
@anonymous I have seen that combination in organic chem
@anonymous not sure where
@anonymous I am trying to recall that reaction and its mechanism

@whatin1992 You're now officially a physicist. Congratulations!

user228700
@AccidentalFourierTransform Interestingly, he does have a 2 year-old daughter :-) Anyhoo...

@AccidentalFourierTransform Saying one should have been a mathematician is the hallmark of a physicist?

6:21 PM
@anonymous I am not sure. What's the answer?

Did anyone here feel like their undergrad career was mostly frustrating? I'm in the U.S. and my undergrad studies don't make me feel like I'm really understanding the physics behind it all.

@YashasSamaga A blue liquid.....

It just feels like I'm learning the top layer of something and before I can go deeper into it I'm rushed off to learn the top layer of something else.

@anonymous NH3? =.=
nvm

@YashasSamaga No.

6:22 PM
reduction gives NH3

@ACuriousMind of course. As soon as we realise we are not getting a real job anyway, we all regret not studying mathematics :-P

NH3 is blue ! OMG XD

@ACuriousMind I have the one-dimensional case.

@anonymous it's yellow
@anonymous I got confused

It is a nitrogen oxide

6:23 PM
It's the old "remove a point from a line"

@anonymous nitrogen which oxide?

@whatin1992 a physics degree has to cover such a wide range that it inevitably can't go too deeply into any particular subject. That doesn't stop you reading up anything that particularly interests you, or even asking about it here.

I need help with my math :-(

@anonymous H2O2 is a weak oxidizing agent?

@YashasSamaga A nitrogen oxide whose color is blue in liquid state. Finding it out is your homework. Seriously revise your inorganic!

6:24 PM
@anonymous In ozonolysis, we use it as a strong oxidizing agent, right?

@YashasSamaga It can be either oxidizer and reducer depending on the substrate.

@JohnRennie totes.

does $$\int\mathrm d^3x\ |f(x)|^2<\infty\quad\Rightarrow\quad|f(x)|\sim |x|^{-2}$$, right?

@anonymous ... yes it is but you use it as a strong oxidizer in ozonolysis?
@anonymous if u use a super strong oxidizing agent, u'd get N2

@YashasSamaga Its not very strong compared to say K2Cr2O7 or KMnO4

6:26 PM
@AccidentalFourierTransform don't scare me!! I'm convinced that with my skills I can get a job anywhere in tech. Do you agree? I think I should be fine because they're not only teaching us to be physicists but also part mathematicians and programmers

@anonymous well, it breaks the double bonds in ozonolysis
@anonymous milder oxidizers such as SRR, PCC, ColR don't

@whatin1992 will you take me with you? I want a job too :-(

It is a medium range oxidizer

@AccidentalFourierTransform omg you're scaring me. Now I feel like I should have gone to the career fair today...

@AccidentalFourierTransform I can help with math - algebraic topology

6:29 PM
I just want to get an A in my QM class and also in my EM class :/ my undergrad career would feel complete if I did...

I want to be rich just like my dad
he is not rich, but he also wants to

@AccidentalFourierTransform I chose physics but I have a knack for business. I plan on starting a few of my business ideas after I finish
@AccidentalFourierTransform LOL I get it
twas funneh

@whatin1992 oh well, good luck with that :-)
and, if you ever succeed, remember who encouraged you
and hire me and give me loads of moneys

@YashasSamaga can you help me in that

@0celo7 I need help with $x^2+1=0$

6:33 PM
@ACuriousMind There should be an alternative proof via the invariance of domain theorem.
@AccidentalFourierTransform algebraic geometry is also something I can't help with

is it $x=i$ or $x=-i$? or is $i=-i$?

@AccidentalFourierTransform Start astrology as a side job. If you can fool people well you can even become a millionaire. :D

@AccidentalFourierTransform both

@Koolman I forgot how those expressions are written

@anonymous tbh, I like astrologists better than astrophysicists.

6:35 PM
Anyone else help me in that

@Koolman It is just a double OR with a connecting AND

@AccidentalFourierTransform ???

That is one of the simplest questions you will ever find in your paper ;')
@Koolman

I dont trust astrophysicists
and cosmologists

Why?
Racism I bet

6:37 PM
@anonymous That I know , but now how to find output

@AccidentalFourierTransform Yeah, I like them too. They know how to earn money without any struggle, unlike astrophysicists :P

(removed)

@Koolman (A OR B) AND (A OR C).

@anonymous how ???

@Koolman Read up some examples from ncert. It is given clearly man!

6:39 PM
My avatar is pretty great right now

Watch this :

What is it? @0celo7

@ACuriousMind inclusion induces a _____ on fundamental group
Injection?

@YashasSamaga Which metal hydroxides can dissolve in excess ammonia solution?

@0celo7 No, consider $S^1 \to S^2$

6:43 PM
Dammit
This problem is too hard

Have you seen the Chembot in action? @ACuriousMind

what is the rank of the homogeneous Lorentz Group? two, right?
and what are the Casimir operators? one is $J_{\mu\nu}J^{\mu\nu}$, but what is the other one?

@ACuriousMind I have a proof for two dimensions. Would you like to hear my proofs? Maybe it will inspire you
@AccidentalFourierTransform rank?

@0celo7 yes, the dimension of the Cartan subgroup

Oh god

6:50 PM
in general, equal to the number of Casimirs

Not you too

I... what?

@skullpetrol no
@0celo7 You can write them down here, but I'm cooking for the next twenty minutes or so

@ACuriousMind Ok. One is wrong anyway.

@anonymous we can solve that when a,b,c are numbers and drawing truth table

6:52 PM
Fundamental group is so counterintuitive.

Would you be opposed to putting a fork in here? @ACuriousMind

@Koolman Why use truth table when you can use Boolean Algebra.....

But here they re represented by A , B ,C @anonymous

I hate writing out truth tables anyway

@anonymous @Koolman @YashasSamaga Can JEE people please make a separate chat?
3

6:53 PM
@0celo7 No, I like this room. Feel free to click on ignore.

@anonymous Fine.
I can't ignore on mobile.

@anonymous truth table

We are talking about Physics anyway. I don't see the problem. Even when you and ACM talk I get distracted. Learn to live together. @0celo7
2

Similarly for others

@skullpetrol What does it do?

6:56 PM
@anonymous I was here first.

@0celo7 So?

Nothing very useful really @ACuriousMind :P

@anonymous I shouldn't have to learn to live with invaders

Build a wall :P

@skullpetrol can't, on mobile

6:59 PM
@anonymous Don't you think it would be even better for you to have all your discussions on JEE in some dedicated room?