I have 2 python list label and presence. I want to do cross-tabulation AND get count for each block out of 4, such as A,B,C and D ine below code.
Both the lists have values True and False.
I have tried pandas crosstab function, however its slower than my code which is below.
One problem with my ...
Good morning all,
I'm looking to loop around to find my pattern in a large raw. For this I scan my rawdata variable 4 by 4.
rawdata is heavy and it takes too long.
I've tried going through a vectorization technique but it doesn't work.
Thank you
for(p in seq(0, length(rawdata), by = 4)){
...
I've created the following SEDE query which calculates the reputation averages of users on a particular site. It also optionally excludes "new" users (users with rep of 1 or 101 so note 100% accurate).
DECLARE @exclude_new_users INT
SET @exclude_new_users = ##ExcludeNewUsers:int?0##
DECLARE @exc...
In Python 3.7, I find myself writing this a lot:
class Bar:
def __init__(self):
self.foo: Optional[Foo] = None
def build(self, qux):
self.foo = Foo(qux)
I justify this to myself as:
Wishing to keep __init__ light (for maximum reuseabilty) or
Being unable to complete Bar...
I'm creating a protocol to abstract different models (hand-crafted, decodable, and thrift-generated) like so:
protocol FeedItemModeling {
var text: String? { get }
var url: URL? { get }
}
protocol FeedModeling {
var items: [FeedItemModeling]? { get }
}
This would work great except t...
I have a WHM cpanel with over 10 + domain
say site 1 to site 10
i install ssl in site no. 8 , 9 , 10
now if i i call non ssl version like http://www...
for site no 8,9,10 , it call the first site hosted on my whm no matter the domain called
I have most of the websites that are related to
[Matrimo...
The challenge is to sort an integer array containing only ones and zeros with the lowest complexity possible.
As always, I am interested in any improvements suggested but in this question I am most interested in whether the complexity that I have assigned to the algorithm is correct (as well as t...
I just completed the first release for my first game on Python, called Dungeon Ball. I'm looking for people to test out the app and give me some feedback and constructive criticism. I'd like to use this project as a way to improve my programming skills and hopefully learn some efficient programmi...
I've written a python code for finding the distribution of the leading zeros of SHA-1. Using random inputs and hashing than counting. Normally it is expected to fit the n/2^i curve where n is the number of trials. After this, a plot is drawn.
import hashlib
import random
import matplotlib.pyplot ...
I use the following code which works as expected, which use open ID connect to login user, as Im pretty new to node and express, it will be great if I can get some tips for the async usage if im doing it right and the error handling.
The code is doing connect via oidc layer
https://en.wikipedia.o...
I have a Spring service that calls a few methods to
@Service
@RequiredArgsConstructor
@Slf4j
public class CarService {
private final CarRepository carRepo;
private final Mail mail;
public void syncCars(Set<CarInfo> carInfos) {
carInfos.forEach(carInfo ->
...
When I first tried to implement std::function I thought it would as easy as creating a class that holds a function pointer. Consequently, I quickly figured out that I was wrong when I tried to use it with a capturing lambda and got an error message. As a result, I quit and until recently I wonder...
Purpose. Provides a background task queue so that code can ask for a function to be run at a specified point in the future. They indicate what to run (a closure) and when to run it (also a name just used for tracing). My use case is typically 2-3 items queued at any time, typical items are very ...
Given a list of numbers p[i] for i=1,...,n what is the best way to generate a list N[i] in python where each element of N[i] is such that
N[1]=1*(1/p[0])
N[2]=2*(1/p[1])-2*N[1]
N[3]=3*(1/p[2])-3*N[1]-2*N[2]
N[4]=4*(1/p[3])-4*N[1]-3*N[2]-2*N[3]
...
N[n]=n*(1/p[n-1])-n*N[1]-(n-1)*N[2]-...-2*N[n...
