\begin{eqnarray}
[\mu_{\mu\nu} (\varepsilon + \frac{1}{2}(a^a (x_2, e_1))] &=& |(\kappa^a|^2) \sigma^a (x_2, e_1)\\
\end{eqnarray}
\begin{eqnarray}
[\mu_{\mu\nu} (\varepsilon + \frac{1}{2}(\kappa^a (x_2, e_1))] &=& \varepsilon \sigma^a (x_2, e_1)\\
\end{eqnarray}
\begin{eqnarray}
[\mu_{\mu\nu} (\varepsilon + \frac{1}{2}(\kappa^a (x_2, e_1))] &=& \varepsilon + |\sigma^{a}|^2 (x_2, e_1)\\
\end{eqnarray}
\begin{eqnarray}
[\mu_{\mu\nu} (\varepsilon, \frac{1}{2}(\kappa^a (x_2, e_1))] &=& \varepsilon + |\sigma^{a}|^2 e_1 (- \varepsilon + \frac{1}{2}(\kappa^a (x_2, e_1))\\