If we have two irreducible tensors $U$ and $T$, we can construct a reducible tensor $P$ by multiplying the two initial tensors. However, we can form another irreducible tensor $S$ by this linear decomposition
$S_{\kappa}^{(k)}=\sum_{\kappa_1, \kappa_{2}} a_{\kappa_{1}, \kappa_{2}}^{k\kappa } P_{\kappa_{1}, \kappa_{2}}^{\left(k_1, k_{2}\right)}=\sum_{t} a_{\kappa_{1}, \kappa_{2}}^{k\kappa } T_{\kappa_{1}}^{\left(k_{1}\right)} U_{\kappa_{2}}^{\left(k_{1}\right)}$
My question is why $S$ is irreducible since it is a sum of reducible tensors up to multiple scalar coefficients?