@JohnRennie No, I haven't watched it yet because it doesn't have any subtitles :-( I'll see if it can be done on my phone on which I can use my earphones.
Re: YouTube was a dating site in 2005:
(^ Comments on Hank's video in which this enlightening piece of information was revealed to us!)
I'll be getting the DVD at the end of July, though you'll be in MEC by then. However if you're still interested you're welcome to a copy of the film with subtitles.
@Kaumudi.H In my experience I thought it'd be terrifying living in a new city, but it's surprisingly easy to adjust to. You can make new friends quickly and share cool stories about your home town. Plus a lot of them are probably from other areas, so you won't be alone
Oh, my sisters and begging me to get off my arse and buy them some chips but I haven't even showered yet! I'll catch u later. I hope u're able to fall asleep soon...
Suppose Amazon want their site to work quicker than anyone elses. So they approach the big Internet companies and say we'll pay you to prioritise traffic to and from our web site so it's faster than anyone elses.
Right now that's illegal because net neutrality says you have to treat all Internet traffic with equal priority.
If the net neutrality laws are repealed then the biggest (and richest) companies can pay to freeze out competitors.
In particular it makes it hard for small companies with new ideas to get started because they won't have the money to compete for Internet bandwidth with big established companies.
But of course the Internet companies would love it because they'd have an extra source of income from those payments.
I've seen this expression in two spacetime dimensions,
$$ \langle \bar{\psi}(x) \psi(0) \rangle = \gamma^\mu{\partial_\mu} \langle \phi(x) \phi(0) \rangle $$
The LHS is the fermion propagator, and the expectation on RHS is the scalar propagator. For 2 dimensional case, the scalar propagator is ...
At every point of the 4-D space-time, it's metric, being a symmetric 2-tensor, has $\frac{D(D+1)}{2}=10$ independent components. From this we can subtract four degrees of freedom according to the four coordinate transformations; Hence, we have six independent degrees of freedom at every point. Th...