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4:00 PM
I typeset everything (homeworks, reports, notes, etc.) I give to others. But can't remember seeing anyone else do the same (especially using LaTeX).
and it's kinda disappointing that instructors don't consider this when grading homeworks, etc
 
@Mostafa I also do this.
@Mostafa Why?
Do you honestly expect higher grades for superior typesetting?
lol
 
@Danu I think a small amount of extra credit (some %5) would be fine
It both helps the grader, and the students for their future works
I've seen courses that do this.
for example this one https://courses.engr.illinois.edu/cs498374/fa2014/hw-policies.html
 
Sounds pretty outrageous to me.
 
@Danu maybe where you are a lot of people do this
 
Where I am, something like this would probably get uni sued :P
 
4:12 PM
I thought they didn't do frivolous lawsuits in mainland Europe
 
Me neither, until I arrived here and learned that this is the reason they are not allowed to have homework count toward your grades, here in Munich.
 
what
homework doesn't count for a grade?
what on Earth is the logic behind that?
 
@0celo7 I'm reasonably sure that if they made it count towards the grade, they'd be obliged to ensure the students don't cheat, which is impossible.
 
...
is that standard in Europe?
seems rather crazy to me
 
so why are students obliged to even turn in homeworks
 
4:17 PM
@0celo7 Not at all standard in Europe
@BalarkaSen You're not obliged to.
I think it's just Germany :P
 
@BalarkaSen Sometimes they aren't, sometimes a certain percentage of correct homework are required to be allowed to take the exam
 
sounds fun
 
In Amsterdam they had a decent system that most courses used: There was homework that counts for something like 20-40% of the grade, plus a test which counts for the rest of the grade. EXCEPT if you get a score better than 80% on the test: Then you can make that count for 100%.
Doesn't screw good students who can't be bother to do boring homework ^^
 
I envy people who don't have to do homework
I never have to study hard, but if I don't do homework I get lost instantly
 
@BalarkaSen Not fun at all. %100 of the grade being in the exams seems like a nightmare to me
 
4:20 PM
Yeah I thought homeworks were a good way to keep a student attached to whatever is going on the class.
@Mostafa Please note the order of the messages as posted :P
I wasn't replying to the message posted after I replied.
 
@BalarkaSen ?
 
^
 
my thermo class was 95% exams
A little 5% homework as fuck you
 
4:22 PM
@Mostafa The pressure is pretty shitty
 
weird, that's not how the order shows up for me
might be the bad internet
 
@0celo7 I think the more elementary courses are mostly exam-based, and the more advanced courses are mostly HW-based
 
I have heard a lot of graduate courses are homework based, with a take home final at the end
in US
 
@Mostafa one of my classes next semester is attendance based
@BalarkaSen that's how algebraic topology was
 
@BalarkaSen Right, and I think nobody really cares about grades at that point, since "you're in" already.
once you have a PhD position grades don't matter
 
4:25 PM
agreed
 
@Danu my QM prof made us do everything in class because people got caught cheating on homework
 
@BalarkaSen Sadly not there yet :(
Though I don't need any more exams... Just need to get a PhD :P
 
@0celo7 That should be an advanced advanced course
 
@Mostafa yes, operator theory
 
@Danu Soon, presumably :)
 
4:28 PM
@BalarkaSen I really hope so. I have some interviews coming up in the next few weeks.
@ACuriousMind By the way, Klemm's talk was pretty nice.
He doesn't seem to give a crap about speaking in mathematically precise language though
Seriously, why do physicists think one should "tensor" (product) manifolds?!
 
lol
 
Nevertheless, this TCS stuff seems pretty nice.
@0celo7 Too much Hilbert space theory, I guess...
 
@Danu from a famous physics book...
 
So sad... Zee's group theory book is the most hilarious thing
 
every physicist I have talked to LOVES his QFT book
 
4:31 PM
not me :P
 
since when are you a physicist?
 
used to be, at least
And who knows, I might do a PhD in physics if I can't find one in math.
 
like Witten I guess
 
@Danu I may also do a PhD in physics if I can't find one in EE.
Like Dirac I guess
 
@Mostafa Someone else is supposed to do the comparison ;)
 
4:39 PM
@Danu didn't risk waiting for that. Just did it myself
 
was Dirac a EE?
 
@JohnDuffield hi
247 days to go
 
Sid
Lol, that starred message at the top...
People seem to get offended way too easily..
 
yes
 
Anonymous
4:55 PM
@BalarkaSen There are a couple of things to understand here: 1) +Inductive Effect 2) +Hyperconjugation Effect 3) Ortho Effect . You have understood the Inductive Effect. Good! Now, CH3 has three H's which can show hyperconjugation. So the ortho and para substituted toluene ring's sigma complex is more stable. So ortho and para products will be formed in greater quantity than meta product.
 
Anonymous
Now coming to ortho effect. Here the Cl-substituent is quite large and would cause steric hindrance at ortho position due to presence of -CH3 group but no such hindrance would occur at the para position of the toluene ring.
 
Anonymous
This is the major reason for the para product being major. BTW if you are facing difficulty with Organic Mechanisms I'd advise you strongly to buy and follow this set of lectures. They helped me immensely during my prep days.
 
can we please move chemistry discussion to Chemistry?
 
surely if psychedelic death metal fits in this room, chemistry does too? :P i probably won't be continuing it for long
@Blue Ok, reading.
 
Anonymous
@0celo7 When you move your Mathematics discussions to the Maths chat we will listen to you. Anyhow, I don't think we will be discussing Chemistry here that frequently.
 
4:58 PM
what Mathematics discussions am I having?
I have mostly moved my mathematics discussions to Skype
 
no need to be hostile, @blue
Ah, ok, so the thing is steric hindrance. Got it.
 
Sid
the h bar usually has everything but Physics.
 
@0celo7 With ACM?
 
no
 
:(
 
Anonymous
5:04 PM
@BalarkaSen I don't see where I was hostile. I just pointed out the hypocrisy prevalent here. Anyhow, welcome and good luck with Organic.
 
what hypocrisy?
 
that's how 0celo speaks in real life
don't mind him
 
What are you on about
 
I think it's a fair request to move non-physics discussions to other rooms anyway.
 
@Blue Implicitly calling someone a hypocrite sounds pretty hostile to me. (Also, asking to move one topic but not another is not inherently hypocritical)
 
Sid
5:05 PM
Whoa whoa, guys, calm down.
 
@Blue Thanks for pointing out the hyperconjugation thing. That's a helpful set of comments.
 
@ACuriousMind Have you ever seen something regarding the following idea: Take the TCS, but identify the solid tori not in the way that yields $S^3$, but rather so that you get a lens space.
Does the construction still work?
 
TCS?
 
twisted connected sum
(way to get $G_2$ holonomy manifolds)
 
@Danu I don't know what solid tori you're talking about I'm afraid
 
5:10 PM
no wiki article on TCS
what is it?
 
@ACuriousMind Okay, so the way you do TCS is: You start with these asymptotic disk bundles over a K3, right
(non-compact CY 3-folds)
 
then you take the product with S^1 (tensor, hurr durr)
And the TCS is done as follows:
 
Asymptotically cylindrical CY, to be precise - they're $K3\times [0,1] \times S^1$ asymptotically. Ohh, do you mean the $T^2\times I$ part with "solid tori"?
 
Take the disk times the circle in both spaces, and glue the resulting solid tori in the way that yields $S^3$
yes
Now, what if you "twist" this TCS (haha) and do it so that you get a lens space instead of $S^3$
 
5:13 PM
Well, what is essential about the gluing is that the two $S^1$ are glued to each other, since that ensures that the fundamental group is finite
 
It's actually zero, right
That's the $S^3$. For lens spaces it is still finite, I expect, since they have finite $\pi_1$.
 
@Danu Depends on whether your CYs had zero
 
Ah, okay, I don't know much about this---Klemm was incredibly imprecise
In any case, you should probably get something finite out for $\pi_1$, no?
 
You just need to kill the loops in the $S^1$ and that's OK (up to finite) for the lens spaces
@0celo7 facepalm
SOMEONE GIVE THIS GUY A LIST ENVIRONMENT
 
5:15 PM
@Danu I'm not yet sure how "gluing to lens spaces" actually modifies the construction
Simply asked: What do I have to do differently to the $S^1$ to get a lens space there?
 
@Danu there are several places where there are multiple remarks right after each other
 
You have to glue the solid torii by a p/q diffeomorphism on the boundary torii. That is, f : T^2 --> T^2 sending p/q curves on T^2 to the meridians.
 
So the $S^3$ is what you get when you identify the longitude of the one solid torus with the meridian of the other
 
the record is seven
 
Now glue the longitude of the one to the knot (p longitude+q meridian) of the other
(what Balarka said)
 
5:18 PM
Well, to answer the original question: No, I have not seen that.
 
:D
@0celo7 So much space wasted... :P
Stupid question: If I have a Riemannian metric on a non-orientable manifold, where does making the normal Riemannian volume form go wrong?
 
it's not possible to consistently patch together the $dx^1\wedge\cdots\wedge dx^n$ across chart intersections.
 
You need a choice of a normal vector field, do you not? (I might be wrong)
Oh, you mean actual volume form on M, nothing to do with metric on normal bundles of submanifolds.
well, the top de Rham cohomology is 0
 
when you write $\sqrt{\det g}dx^1\wedge\cdots\wedge dx^n$, you are implictly using an oriented coordinate system
so if that doesn't exist, you get issues on overlaps
 
There is a paper by Acharya about G2 and lens spaces, though. Making it a lens space is nice, it gives you non-Abelian gauge groups.
 
5:23 PM
@0celo7 That's just a rephrasing of "it's not orientable" but I guess there isn't much more to say.
@ACuriousMind Oh, that's sick
Original discovery confirmed
That's why it has already been done :D
 
I mean if you had a volume form then you are orientable. You have a consistent choice of orientation given by volume(X_1, X_2, ..., X_n) = 1 on each tangent space.
 
@Danu ...that about sums it up.
It's exactly the same issue as declaring every chart to be positively oriented
maybe not "every", but you get the idea
 
@ACuriousMind Link?
 
I'm actually not sure whether one can modify the TCS to get a lens space though, I'm not seeing that the SvK argument for the fundamental group goes through
 
The fundamental groups of the $S^1$'s get killed (up to finitely many non-trivial elements)
 
5:27 PM
@Blue you should chase them away
 
A clearer way to think about that maybe that orientability is a reduction of structure group of TM to GL^+(n), and volume form is a reduction of the structure group of TM to SL(n), which is a subgroup of GL^+(n)
 
@Danu btw engineers use $+$ for group product (nonabelian groups)
sometimes $\oplus$
 
??
 
@Danu arxiv.org/abs/hep-th/0011089v2, the mention of the lens space is shorter than I remembered, though
 
like $g\oplus h =g'$?
 
5:30 PM
@Danu $g\oplus h\equiv g\times h$
and $2g$ for $g\times g$
 
@ACuriousMind rofl, capitalizing the l in "lens" space
@0celo7 But what does $g\times g$ mean for you?
an element of a direct product of groups?
 
@Danu These spaces were discovered by Prof. Dr. Wilhelm Lens, surely :P
 
@ACuriousMind The name is actually pretty cool
They look like lenses, at least in a certain construction
 
@Danu I thought you were using small letters for groups. The product of groups $G$ and $H$ is sometimes written as $G\oplus H$.
 
@0celo7 Ah, but that's not so bad..... Oh, you said non-Abelian. :(
 
Anonymous
5:44 PM
@ACuriousMind "Also, asking to move one topic but not another is not inherently hypocritical". Really? How do you define "hypocrisy" then? (Don't take this as an attack. I'm seeking a logically sound argument.) I personally use the definition given in Wikipedia(en.wikipedia.org/wiki/Hypocrisy).
 
Anonymous
"Hypocrisy is the practice of engaging in the same behavior or activity for which one criticizes another."
 
@Blue you need to attack the math discussion above
 
Anonymous
@0celo7 I have no problem with the math discussion.
 
@Blue "Discussing topic 1" and "discussing topic 2" are not the same behaviour. There is only hypocrisy if you assume the behaviour being criticized is "not discussing physics", which isn't what's being said. (I'm not exactly trying to say it's a good thing to not want any specific topic here or not, I'm just saying it's not inherently hypocritical to want topic 1 here but not topic 2)
 
Anonymous
@ACuriousMind Ok I see. I was assuming the behaviour being criticized as "not discussing physics". I get your point of view now. Thanks for clarifying.
 
5:52 PM
@Blue but apparently 0celo has a lot of problems with your chemistry discussion even if it's just a couple of messages
 
you people need to chill. 0celo is allergic to chemistry and JEE; i'm allergic to analysis. but we strike a balance
 
@ACuriousMind 2020 Bethesda Conference: Elder Scrolls 6: Skyrim
 
to be fair i'm also allergic to chemistry and JEE so hell yeah
 
Anyways, this is a fact that physicists generally have far less problems (if any) with mathematics compared to chemistry
 
physicists like mathematics. especially Urs Schreiber's formulation of quantum field theory
 
5:56 PM
@BalarkaSen exercise...show that if a compact simply connected 3-manifold admits a metric with positive Ricci curvature, it is a sphere
 
@0celo7 ooh nice. I don't know what Ricci curvature is yet though
 
@BalarkaSen Riemann curvature is $R^i{}_{jkl}$, Ricci curvature is $R_{jl}=R^i{}_{jil}$
"positive" is in the sense of bilinear forms
 
i don't understand indices. what does that mean coordinate-independently?
 
@BalarkaSen Riemann curvature is a mapping $\mathfrak{X}(M)\times\mathfrak X(M)\times\mathfrak X(M)\times\mathfrak X(M)\to\Bbb R$
 
mhm
 
5:59 PM
trace over the first and third slots
 
ahhhhh, ok
so a generalization of mean curvature for surfaces?
except the factor of 1/2
 
It's more of an average of Riemann curvatures over planes
 
right, that's what i thought
 
mean curvature is extrinsic, it doesn't really have a generalization in that sense
you can have mean curvature for arbitrary submanifolds
in any case, that's not an exercise, unless you're willing to accept the Poincare conjecture :)
 
heh
I realized it's relevant to Poincare
 
6:04 PM
It was the first "big result" from Ricci flow
One evolves a rescaled metric and in finite time one obtains a constant curvature metric.
Simple connectedness + classification of space forms gives the result.
 
Can't you just prove the Poincaré conjecture and be done with it
 
The PC takes far longer to prove, and the proof method is quite different.
 
I think that, historically, it was sort of the justification of the notion of Ricci flow. Hamilton proved it in soon (immediately?) after defining Ricci flow.
 
@Danu Exactly.
I think that he proved in the first Ricci flow paper.
Perelman's approach to Ricci flow was completely different and it took years for people to understand what he did.
 
Yeah
There's a really nice overview of Ricci flow stuff in German
 
6:10 PM
He said he was motivated by string theory.
 
wish i knew this stuff man
 
String theory ain't easy
well, it's not that hard, either, but it's a lot of things at once
 
@0celo7 He said that? Really?
 
i don't think i want to learn string theory tho
lol
 
@Danu Yeah. The keys to Ricci flow are the Hamtilon and Perelman entropies. Perelman entropies are string theory Lagrangians.
$$\int_M(R+|df|^2)e^{-f}\,dv$$
I think that's a dilaton coupled to gravity
 
6:16 PM
yeah
okay, that's pretty great
 
$$\int_M(\tau(u^{-1}|du|^2+Ru)-u\ln u-\frac{n}{2}\ln(4\pi\tau)u-nu)dv$$
not sure what that's supposed to be
Ah, it's the F entropy + Hamilton entropy
which is just Boltzmann entropy
The whole process of Perelman's proof seems amazing to me. I don't dare try to read Morgan and Tian's book yet.
 
6:34 PM
Why is time taken in two halves of projectile motion equal?
 
I edited a question but realized somebody had suggested an edit on it while I was editing, and my edit caused his (which could be better than mine) to get rejected by Community. I feel guilty now.
 
@Abcd because it's symmetric about the apex
 
6:50 PM
@0celo7 Is it the same when ball is thrown upwards and then returns? is the time same in both the cases?
 
yes
physical laws are time symmetric
if you reverse time, they are identical
 
7:07 PM
@Slereah Ok TY
 
@Slereah you might have to C and P too
 
plz I'm talking classical
 
8:02 PM
I cannot see any rooms listed here chat.stackexchange.com/rooms
Anyone else having the same problem?
Oh wait, never mind
 
I went to the store again and forgot soap again
 
Just be smelly
 
I'm using dish soap as hand soap rn
pretty ghetto
 
RIP hands
 
they seem to be fine
what is supposed to happen?
 
8:07 PM
Nothing much, just your oil-vaseline budget goes up.
 
order from Amazon now
make sure it has free shipping
 
Depends on the dish soap
Very dry hands are likely
 
how does one pronounce "moduli"
is the d a j
 
modulai
 
so you say it with a hard d?
 
8:15 PM
yes
 
god, this book is painful to read
 
I say "modjyoolaye"
 
how am I supposed to absorb that
@DanielSank same
 
Sir
8:32 PM
does any one do much programming here got a physics question about 3d vectors and applying gravity
 
This make sense?:
 
did you use mathematica?
 
It's from a susy book, what kind of book would put something like this in it
 
what?
 
9:28 PM
Makes sense, wahoo
 
@Danu
 
I think Ringstrom is too lazy to actually write text so he just puts together disjointed remarks everywhere
 
recursive remarks!
 
10:14 PM
> 65 million miles
Sigh
 
what
oh, that should be kilometer
well a mile is longer
so they would see older dinosaurs
 
10:46 PM
@ACuriousMind I need a mod
am I allowed to call a post a "shitshow" in my answer?
 
@DanielSank I told you about this!
And you wouldn't do it because you're a security freak
 
@BernardoMeurer so are you coming to visit me in August?
or is that Michelle or is that no one
everyone thinks they're visting me but no one thinks anyone else is
it's confusing
 
Michelle told me she and Ron are driving there in August, to see you, Bob, and Ron's mother or father I don't remember
And invited me to drive along with them and Nuit
Which I accepted
 
I talked to Ron two days ago and he knew nothing of it.
My sister talks to you more than to anyone in her family, husband included.
2
We are concerned.
 
10:55 PM
Kat is too, because she hasn't heard of this plan.
Nor has Kevin or Bob...
 
Good lord
 
Feb 26 at 22:38, by Kristina L
@Kaumudi.H Bernardo is the cutest nerd I know
 
@Mostafa That is not my sister.
And Bernardo isn't even a nerd.
 
@0celo7 I know, just wanted to reaffirm that your concern is totally on point
@0celo7 He's a geek?
 
@Mostafa Yes.
A geek is someone who is functional.
A nerd is a parasite to society.
2
 
11:02 PM
Goddammit
They whacked him. They finally whacked AFT. I knew.
 
@0celo7 What do you think?
@Mostafa ...what?
Please do not make baseless assertions about other users' feelings or motivations
Also, explain what you mean by "whacked".
 
AFT got banned?
He's the Bill Cosby of the hbar!
 
@BernardoMeurer No.
 
@BernardoMeurer No
 
11:05 PM
That's no longer a good thing
nevermind
 
whacked
 
What does that even mean?
@Mostafa You gotta stop with this man
You're worse than my ex girlfriend
@ACuriousMind God bless
 
is AFT alive?
@ACuriousMind I think I am allowed to do it unless a mod sees it, then no.
 
@0celo7 Then you have a weird conception of what "allowed" means, but in any case: No, you're not allowed to call other people's posts "shitshows".
 
@ACuriousMind I went with "This post has a really bad case of physics math."
is that allowed?
 
11:09 PM
I see no objection to that
 
@BernardoMeurer God?
Don't you mean papá?
 
@0celo7 Read my mind
 
@ACuriousMind I have a suspicion that this book is taking $\Lambda\ge0$, but I can't find that anywhere. Suggestions?
 
11:31 PM
-6
Q: Light and Photon

user160001I have heard many times that the speed of light is what we could call THE SPEED LIMIT OF UNIVERSE. I have seen many books that says that photon could travel at the speed of light. Because it is without mass and, all that, it does not interact with the Higgs field. So, what that suppose to mean th...

what a fantastic cocktail of pure confusion
 
@EmilioPisanty What is even going on there?
 
@BernardoMeurer who knows
 
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