@BalarkaSen If $S=\cup_{d\in\Bbb R}S^d$ is a "filtered * algebra" does that just mean that there's a multiplication $S^d\times S^e\to S^{d+e}$ and an involution $*:S^d\to S^d$?
Pulled pork is a method of cooking pork where what would otherwise be a tough cut of meat is cooked slowly at low temperatures, allowing the meat to become tender enough so that it can be "pulled", or easily broken into individual pieces. Pulled pork is found around the world in a variety of forms.
== Preparation ==
Pulled pork, usually shoulder cut (sometimes referred to as mixed cuts), is commonly slow-cooked by a smoking method, though a non-barbecue method might also be employed using a slow cooker or a domestic oven. In rural areas across the United States, either a pig roast/whole hog, mixed...
@BalarkaSen I am derping though. If $S^d_p$ is the the space of variable-coefficient polynomials in $n$ variables of degree $d$, why is $S^d_p/S^{d-1}_p$ isomorphic to the space of homogeneous polynomials? Something something mod the inhomogeneous terms?
@0celouvskyopoulo7 Is $S_n^d$ the space of polynomials of degree $d$ with $n$ variables? Define a map $S_n^d \to H_{n+1}^d$ (latter the space of homogeneous polynoms) as follows. If $P(x_1, \cdots, x_n)$ is a polynomial, send it to $X_0^d P(X_1/X_0, \cdots X_n/X_0)$. That's a homogenenous polynomial of degree $d$ and $n+1$ variables.
@BalarkaSen I think it's much simpler. You just drop all of the terms of degree $<d$ to get $\tilde p$, and this is equivalent to saying that $p-\tilde p\in S^{d-1}_p$.
So $H^d_p=S^d_p/S^{d-1}_p$, where you do the quotient in the sense of vector spaces
> Unless your puberty has been delayed by you moving at relativistic speeds your whole life, I think you will get a far better response (as well as answers from experts) from Health.
:-) I'm pleased the comments have been basically kind. The poor chap has obviously posted on the wrong SE and is probably feeling pretty embarrassed right now. A cruel comment wouldn't help.
@Fawad The field can be written as a function of $x$ i.e. $E = f(x)$. The direction of increasing field is the direction in which the $E$ becomes more positive (or less negative).
I have heard of entropy.a doubt araised in my mind that what will happen if I created a machine that spontaneously obtained energy from gravity?does the universe will end?
My machine use gravity and spring power alternatively to obtain spontaneous energy
@BernardoMeurer I've been told that people tend to be e.g. more flexible when it's warm so are (depending on the exercise) better than when it's winter. Perhaps a better way of putting it is that you don't have to do (quite) as much 'warming up' to a certain extent :P
"And we break up our PC's, and yawn, and run to the center of things, where the John Rennie says: Boys! Boys! It's a sweet thing (laptop) If you want it, boys, get it here thing..."
@Mostafa Yeah... It took me three months before I managed to actually be able to hit someone in sparring (read: gently nudging them with my knuckles on their chin)
King Gizzard & the Lizard Wizard is an Australian psychedelic rock band that formed in 2010 in Melbourne, Victoria. The band consists of Stu Mackenzie (vocals, guitar, flute), Ambrose Kenny Smith (vocals, synths, harmonica), Cook Craig (guitar), Joey Walker (guitar), Lucas Skinner (bass), Eric Moore (drums), and Michael Cavanagh (drums).
The band is noted for its energetic live performances and prolific recording output, having released nine full-length studio albums since 2012. King Gizzard & the Lizard Wizard's early work was primarily a blend of surf music, garage rock and psychedelic rock,...
"The spin follows from the fact that the source of gravitation is the stress–energy tensor, a second-order tensor (compared with electromagnetism's spin-1 photon, the source of which is the four-current, a first-order tensor)." hmm