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15:00
7.7 million people reached
And not famous ? :P
- John Rennie doesn't need to do renormalization...the infinities remove themselves.
Are you kidding me ? :P
- There is no general relativity. Spacetime merely bends to John Rennie's will.
When Jon Skeet and John Rennie get together, the universe is unable to take it, so they can't meet. Jon Skeet is coding a feature to remedy this.
Anyone knows why Andre Nicolas on Math SE left ? He was the highest rep member there. But since October he didn't come online. His answers were great and I miss them :/
Okay, I'll stop now =P
"In a while, I will for some time not be able to answer questions I am asked about past posts (medical). Apologies!"
^seems to be a medical problem @anonymous
Medical problem for 4 months ?
Weird. Really weird
Hope he is safe and sound
HE DEAD
mono lasts for a while, doesn't it?
@Slereah Whaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaatttttttttttttttttttttttttttttttttttttttttttt‌​ttttttttttttttttttttttttttttttttttttttt ??????????????????////
15:07
I dunno lol
@Slereah -____________________________________________-
@anonymous whoa lol
Anyway
@anonymous that looks like a whale =P
Apparently embedding distributions into *R is pretty easy
15:08
@heather Whale sized shock!
It's just the convolution of the distribution with a delta function
still working on hyperreals?
it seems he may have been considering leaving the site for a bit.
@heather That was long ago. 2014! Probably not the reason...
If he wanted to leave he wouldn't have waited for 2 years
Perhaps he had problems on MO also.
Who knows...
aka not enough information
15:17
@heather I assume you mean the disease and not the programming language :-)
or perhaps he was expecting unrealistic results :P
@JohnRennie yes, the disease =P
Is he this guy in the picture ? :P astro.umontreal.ca/~chene (Astrophysicist on Math SE ? )
Just a google search "Andre Nicolas Maths"
How can you @heather in middle school believe 1/0 is infinity? Are you already taking Calculus?
@Pissedofflayman Who need calc for that ? Intuition serves well.
15:23
@Pissedofflayman no, I'm not taking calculus, though I am reading about it. But I always thought it made more sense - division is how many times something goes into something else. zero never "fills up" a number, so it goes in an infinite number of times.
it would also mean the slope of vertical lines is infinite, not undefined, which makes tons more sense.
What about zero times any real number equals zero?
yeah, i thought about that.
0/0 is any real number. =)
^something like that.
(perhaps)
No! 0/0 is division by 0.
15:25
@LuBu Its undefined. Not only a real number.
Yeah, it is undefined because it can be any real number.
@LuBu No. It is the other way round.
@Pissedofflayman that's my problem, once I start thinking about it logically, it doesn't make sense. but it just makes sense before you get into the details.
Division by zero has no meaning.
@LuBu LuBu, ignore everything I said, I was talking about something far from reality.
@Pissedofflayman in mathematics currently, yes.
15:26
In mathematics, the Riemann sphere, named after Bernhard Riemann, is a model of the extended complex plane, the complex plane plus a point at infinity. This extended plane represents the extended complex numbers, that is, the complex numbers plus a value ∞ for infinity. With the Riemann model, the point "∞" is near to very large numbers, just as the point "0" is near to very small numbers. The extended complex numbers are useful in complex analysis because they allow for division by zero in some circumstances, in a way that makes expressions such as 1/0 = ∞ well-behaved. For example, any rational...
@AccidentalFourierTransform that looks a lot like the Bloch sphere.
okay, so random hypothetical question for everyone:
$\sqrt{-1}=i$
what if there was such a thing as $|x|=-1$?
@heather that's the thing about spheres, they all look alike ;-)
@heather Square both sides and see what happens
@AccidentalFourierTransform well yeah, but they also both have the complex plane involved and stuff =P
In linear algebra, functional analysis, and related areas of mathematics, a norm is a function that assigns a strictly positive length or size to each vector in a vector space—save for the zero vector, which is assigned a length of zero. A seminorm, on the other hand, is allowed to assign zero length to some non-zero vectors (in addition to the zero vector). A norm must also satisfy certain properties pertaining to scalability and additivity which are given in the formal definition below. A simple example is the 2-dimensional Euclidean space R2 equipped with the Euclidean norm. Elements in this...
15:29
@anonymous $|x|^2=1$
$|\cdot|$ is the usual notation for norms
and norms are, by definition, positive
Dividing by 0 would mean multipying by the reciprocal of 0, but 0 has no reciprocal because 0 times any number is 0, not 1. Therefore division by 0 has no meaning in the set of real numbers @heather
In mathematics, the absolute value or modulus |x| of a real number x is the non-negative value of x without regard to its sign. Namely, |x| = x for a positive x, |x| = −x for a negative x (in which case −x is positive), and |0| = 0. For example, the absolute value of 3 is 3, and the absolute value of −3 is also 3. The absolute value of a number may be thought of as its distance from zero. Generalisations of the absolute value for real numbers occur in a wide variety of mathematical settings. For example, an absolute value is also defined for the complex numbers, the quaternions, ordered rings,...
@Pissedofflayman I know it doesn't actually.
@AccidentalFourierTransform I thought $||x||$ was notation for norms
@heather None of the solutions of $x^2=-1$ satisfies the equation. So $|x|=-1$ has no solution. Moreover magnitude is ALWAYS positive.
@heather people are lazy
we just drop the second $|$
but its in general the same
15:31
@AccidentalFourierTransform oh, okay.
@anonymous well...doesn't $x=i$ in that case?
the absolute value is just an example of norm
there are other examples, and we use the same notation for all of them
@heather $|i| \neq -1$ Also $|-i| \neq -1$
@AccidentalFourierTransform yeah, that makes sense - norm is length in two dimensions, absolute value is length in 1 (kind of)
@anonymous now I'm going to be messing with this all day =P
i want to create a |x|=-1 now.
@heather Basically the thing is magnitude of any number (no matter what) is always and always positive by definition.
|x|=-1 has no meaning
Just like distance.
@anonymous i know, that's why I want to break it =P
length cannot be negative, but it would be fun to make a negative length.
@heather Hmm, its like saying "I want to make 1=2"
that came up with a fun fake proof! it was a valuable waste of time =)
15:37
1=2 is division by 0.
@Pissedofflayman What?
the fake proof uses division by zero.
That's why its fake :)
exactly.
15:38
0 doesn't go into any real number
including 0
=/ no $\infty$
"infinity" is not a real number
It is not "unique", right? @heather
nope, it's a concept.
@Pissedofflayman ?
i'm not sure what you mean.
It may be a number if you define it like that
It all depends on what number means
Unique means there is one and only one value @heather
15:43
So it can be more than a concept, but certainly not a real number, yes
Like any particular real number that a variable can represent. @heather
@heather Have you learnt integration ?
@anonymous yes, a bit.
@Pissedofflayman I understand that, but I didn't understand quite what it meant in this context. now, i think i do, and i would say no, it isn't quite unique.
@heather Try proving this
In your spare time
15:50
@anonymous what? that's pretty much a definition, right?
@AccidentalFourierTransform No. Definitely not. There is a logical proof behind it.
Actually it is the definition
Of the Riemann integral
@anonymous or else what is the definition?
@heather you can think of "infinity" as the opposite of unique because unique means one and only one, right?
@DHMO Okay, I agree that is how you define Riemann integral but what I meant is that the equality has a logical proof.
15:52
oh, you mean slicing areas
@DHMO Yes. Precisely.
@anonymous ::gulps::
that looks monstrous.
"infinity" is defined as not having one and only one "value", it's just bigger than any value...I'm sure you've seen the graphical approach of 1/x from the right and from the left...
@Pissedofflayman right, it doesn't have a unique value.
So 1/0 is not infinity
15:57
@Pissedofflayman One can divide by zero by nuking enough of the field axioms. However as long associativity is intact, you will not go very far. For reciprocals of zero read about riemannin sphere and wheels
That is not actually how you define the Riemann integral.
@BalarkaSen hmm?
@Pissedofflayman i know it isn't infinity, it just "feels" right in some situations. feelings don't matter in math; it isn't infinity, it's undefined.
It's defined to be the unique number sandwiched between the upper & lower Riemann sums, for any partition of $[a, b]$.
This pic might help
@heather
It will take some time but it is worth it
15:59
Guys division by 0 is undefined
Let's not go down @Secret's rabbit hole :P
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