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23:00
@DanielSank why
@FenderLesPaul What does high energy theory have to do with quantum info?
@DanielSank wow no imagination
@0celo7 I'm sure you can figure that out yourself.
@DanielSank lol
you people have waaaaaayyyyy too much confidence in me
@0celo7 Lol yourself. We just went through the fact that the wave was moving at velocity $\omega/k$ and you said you understood that.
I'm sick of this.
23:01
@DanielSank exactly
so if $k$ is less than $0$, $\omega/k$ is also
Draw pictures. If you aren't seeing those waves moving in your head, plot them for different times to see what is happening.
@DanielSank well idk about at ucsb but at Stanford for example there's a lot of communication between the QI people and hep-th people because current research interests in quantum gravity incorporate QI rather fundamentally
but that means a negative velocity, i.e. left
23:02
and I was wondering if people at ucsb also did that
@DanielSank I'm just confused, why are you upset?
@0celo7 You can't say you know that something is the velocity of a wave and then say you don't understand why the wave is moving. What does "I know that is the velocity" even mean if you don't know that something is moving?
@ACuriousMind I know that it's moving!
I'm confused about the direction.
Hecht Optics first chapter has a good intuitive discussion of wave motion from roughly first principles
23:07
@ACuriousMind @DanielSank I'm not trying to piss you off, I'm genuinely confused.
Well, I'm confused about what confuses you
@ACuriousMind Ok, why is $f(x)\mapsto f(x+c)$ a left translation of the graph?
That's all I'm confused about.
Hecht discusses this
Anybody have a hand-wavey understanding of why a closed Bosonic string is of the form $H \approx (a_{-n} a_n + \tilde{a}_{-n} \tilde{a}_n)$ while an open string is of the form $H \approx a_{-n} a_n$?
@0celo7 Because the point where the graph has the value $f(x_0)$ is now $x_0 -c$, and $x\mapsto x-c$ is a left translation.
@ACuriousMind I know that.
23:12
@FenderLesPaul I think there may be an enormous gap between quantum information in the case of cosmology etc. and quantum information as relevant to e.g. quantum computers.
@bolbteppa In the closed string, the left- and right-moving modes are independent, while in the open string, the boundary conditions force them to combine into a standing wave, meaning the left- and right-moving modes are related to each other, so you only need to care about one of them.
FenderLesPaul I mean a cultural gap.
$a$ and $\tilde{a}$ are the left-/right-movers, right?
@DanielSank I see
It's been a while since I looked at that
23:14
@ACuriousMind You're right.
@0celo7 Then what are you asking?
@ACuriousMind I'm just having a crisis.
Oh wow, cool, thanks a lot
:(
@ACuriousMind Do you never get it where you understand all of the equations, can derive and explain everything but don't get it
That's where I'm at
Ok, yes that's an uncomfortable position to be in.
23:17
It's the same feeling I get when I disprove something via counterexample.
Look, suppose I have some lumpy shape $f(x)$.
Now I push it to the right a bit by a distance $\delta x$.
I can write that as $f(x-\delta x)$, right?
@DanielSank Yes, but I don't get why
The reason this works is that I now have to go a little further in $x$ to recover the same argument in the function.
@0celo7 We're working on that.
@DanielSank I understand that
@0celo7 If you get that, then why do you say you do not get why?
23:19
Pretty sure Hecht explains this with a picture so you'll get it immediately
4 mins ago, by 0celo7
@ACuriousMind I'm just having a crisis.
$g(x) \equiv f(x - \delta x)$ is a new function with the same shape of $f$ but it's moved a bit to the right.
@0celo7 That's not a relevant statement.
"I'M CONFUSED" doesn't help.
@DanielSank I know.
Anyway... I move my lump to the right a bit... I want to express that in math so I write $f(x-\delta x)$.
I'm not sure I can help you understand that. This may require you to just suffer for a while in the confines of your own brain.
I'm pretty sure I understood it when I learned quantum mechanics.
23:22
Hullo
Leave @Danu, nothing good happening here.
@DanielSank ...
You're such a nice guy
38 mins ago, by ACuriousMind
@0celo7 Plug the solutions for $t_0$ resp. $x_0$ for the two respective equations Daniel derived into the $f_1 + f_2$ and stare at that until you get it.
@DanielSank Eh??
What, ocelot homework hour? :)
stare at it @0celo7
23:23
@Danu I, uh... how'd you know that?
@Danu My homework ended long ago, I'm trying to understand something else
@DanielSank It's 23 hours per day ;)
@Danu Actually, it's me being stupid h---yeah homework hour.
@Sᴋᴜʟʟᴘᴇᴛʀᴏʟ I don't know what was meant by that.
51 mins ago, by DanielSank
Read the log.
What I gathered was: there are points in space where the wave is zero at all times and there are points in time where the wave is zero for all points of space.
But I'm pretty sure that's just a standing wave.
23:28
@Danu "ocelot homework" sounds like were zoologists
So I don't know what this business about two standing waves is.
@0celo7 Forget the notion of "two standing waves". That was a misstep on our part.
@DanielSank You're...shitting me, right
I've been sitting here for an hour trying to find the standing waves
The point is more that a standing wave has two kinds of nodes: one which is zero at all space for certain times, and one which is zero for all time at certain positions.
@0celo7 No, I said that above already.
@DanielSank Nah, I still think that works. One is drawing amplitude against space and varying it with time, the other is drawing amplitude against time and varying that with space
23:31
@ACuriousMind Oh yeah ok good point.
I mean, to me that's one standing wave viewed two different ways.
If I could project GIFs out of the pictures in my head, I could express that better
It sounds like a misrepresentation to say there is a "space standing wave" and a "time standing wave".
@ACuriousMind How the heck can you picture this in your head
@ACuriousMind I get it.
@0celo7 It's just two independent variables. Your brain is highly evolved to plot in 3D.
23:33
@DanielSank mine apparently isn't
@0celo7 because you refuse to sketch it
@Sᴋᴜʟʟᴘᴇᴛʀᴏʟ sketch what '-.-
@DanielSank Ooooh
@ACuriousMind ?
should I try to make a 3D plot of $f_1+f_2$?
23:37
Start with 2D
@DanielSank I just realized that if you plot the amplitude over the $x$-$t$ plane, the nodes are zero lines parallel to the coordinate axes.
I don't know what to plot in 2D
@ACuriousMind Yep.
Yeah, now I see why you say "two standing waves" isn't the correct statement.
@ACuriousMind Yeah.
23:38
@ACuriousMind ah
The problem is that when we say "standing wave" our brain puts up a gif plotting the wave as a function of position and varying it in time.
There is literally nothing interesting here. We have just come around to realize that our brains are used to plotting a certain slice of a 2D plot.
Actually, I still don't understand why those two solutions to the sine equation gave the space and time nodes...
I guess that is interesting.
why would you star that
@DanielSank huh?
you solved a trig equation
@DanielSank Hmmm? The equation is searching for the zeros - and the zeros always lie on one of the zero lines, which become nodes when you project on either x or t
@ACuriousMind But why did the $y = x + 2n\pi$ and $y = (2n+1)\pi - x$ solutions separate the lines like that?
I salute you, oh King of removed posts!
4
@DanielSank wait, are those supposed to solve $\sin x=\sin y$?
23:45
@DanielSank I think because the x-t coordinate system is set up like that (parallel to the zero lines). If you rotate the coordinate system, it doesn't do that anymore.
@DanielSank I would salute back you but you have no accomplishments of that magnitude
@DanielSank Also, Black Sheep.
Parvitude might be more appropriate :P
I don't know that word.
Wow.
magnus - big; parvus - small
@ACuriousMind Lol you think I remember Latin.
23:48
@0celo7 Actually, no, I fully expected you to not understand that :P
@ACuriousMind Don't know whether I think you're an ass or happy you finally understand how bad my memory is.
Do you want to be put on ignore again for a "week?"
@Sᴋᴜʟʟᴘᴇᴛʀᴏʟ No.
Huh?
23:52
Strike out "ass."
If posting Latin adjectives while knowing that the other person will not know the words is not being an ass...don't know where that thought was going
@Sᴋᴜʟʟᴘᴇᴛʀᴏʟ I don't care about that.
@Sᴋᴜʟʟᴘᴇᴛʀᴏʟ It's also too late.
@0celo7 Parvitude is not an adjective ;)
(and while parvus is, I even wrote there what it means)
@ACuriousMind Hmm, are "magnus" and "parvus" not adjectives?
23:55
magnus and parvus are, but I really wrote that to explain how I came up with parvitude, not to shame you for not knowing them
@ACuriousMind There are better things to shame me about.
Like your refusal to draw sketchs :P
refusal?
For this kind of stuff
No, I just had no clue what to draw
23:58
You gotta start drawing right away pal
I'm stuck proving Schur's Lemma, what do I draw there
arrows
I recently met a student of Latin and Ancient Greek at a party. That almost made me wish I could do that without cutting back on physics and math.
inb4 ACM tells me to use rank-nullity or some crap
@ACuriousMind That might be even more useless than theoretical physics in the market.
:P

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