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23:30
@ACuriousMind How do I measure the proper length of a spacelike geodesic
in a lab with human tools
@0celo7 wat
Have you got a spacelike geodesic in your lab?
@ACuriousMind there's probably one around
there is always one
Then just hold a ruler to it.
but how do I find it
I'm not responsible for where you left your rulers!
23:32
sorry if this sounds silly, but there's a construction in GR called "Fermi coordinates"
and you need the length of a spacelike goedesic
but I have no clue how one would go about finding it
@0celo7 Uh, isn't a straight spatial line a spacelike geodesic (at least for Minkowski)?
"The condition of stationarity yields new topological obstructions[22]; for example, if
(M, g) is compact, stationary and n = 3 then M is a Seifert manifold. "
wot
@ACuriousMind curved space brah
straight spatial line
@0celo7 Well, first measure how space is curved, then compute what shape the spacelike geodesic have, then measure them
how is straight defined
23:35
@0celo7 In my human lab with human tools, a normal human-made ruler is straight.
Spacetime curvature in the lab is usually measured by interferometry
Just check if the light's path is the same in all direction at all points
@ACuriousMind what about over large distances
suppose the spatial slices are curved
I seem to recall that measuring over "large" distances is a terrible mess in GR in any case
But I'm not a GR person, dunno why you ask me this
@ACuriousMind It is
I'm the one who told you that :)
@ACuriousMind because I have a different question
Over large distances you just integrate some spacelike curve :p
23:38
forget spacetime
@Slereah that does not even begin to make sense physically
@ACuriousMind forget spacetime, take some general curved Riemannian manifold
suppose I'm "in" this space
and a geodesic shoots by me
what do I see
@0celo7 That doesn't make any sense
A curve is not a physical object
will it appear perfectly straight to me?
@0celo7 If you stand on a sphere, do the meridians appear perfectly straight to you?
@ACuriousMind suppose we fix something to the geodesic and it moves along it
@0celo7 : You are on a manifold right now
23:41
@ACuriousMind I have no cluie.
@0celo7 You are on earth. Earth is a sphere. How does a meridian look to you?
Even better
Take two meridians
crossing the poles
Parallel lines do not cross each other in flat space
@ACuriousMind never seen one
and I'm not really "on Earth" ayy lmao
2
I'm in 3-space
@0celo7 confirmed for space alien
what if I was 2-dimensional
23:42
Yes, but just think about what @Slereah says. They cross at the poles. You'll see them intersect.
Also there's the whole thing about triangles having odd angle sums
You can have a triangle with 3 90° angles on a sphere
the sphere is a bad example
let's talk about 3-space
which one
hmm
that is a good question
I have honestly no idea how to imagine curved 3-space.
23:44
then how do I measure the length of a spacelike geodesic
I mean really the same arguments we said apply to $S^3$ I think
@0celo7 Find one, roll a tape along it
I don't see the issue.
You measure the length of timelike geodesics by sending clocks along them, you measure spacelike geodesics by rolling measuring tape along them.
@ACuriousMind you sob
this is a serious q
but how do I even find a spacelike geodesic
Well unless you are some sort of time lord, anything you measure with a ruler will be spacelike
@0celo7 Take a tachyon and look where it moves :P
23:46
@ACuriousMind seriously
@Slereah I think the "geodesic" part is the thing he has trouble finding, not the "spacelike".
I'm trying to make sense of Fermi normal coordinates
they're made out to be this natural coordinate system
Iteratively, I guess?
but the fact that you have to measure a spacelike geodesic on each axis
that doesn't even make sense
Well
Ask yourself
23:50
@0celo7 Well, again, if you know the shape of your space, you can just compute the shape of the geodesics, can't you?
How do we know what a geodesic is in flatspace
@ACuriousMind why would I know the shape
Because you measured it?
it is $\sqrt{\sum x^2}$
But this was obtained after a while
@ACuriousMind huh?
23:51
@0celo7 Dunno, if it isn't strongly enough curved so that you know how it's curved, it's kinda pointless to even do this whole stuff, isn't it?
Obtained via the Pythagorean theorem, among other thing
@ACuriousMind how do I know if it is curved
in curved space, you'd have to find that too, except that will depend on your location
this is a good question
what is the best way to figure out if spacetime is curved
geodesic deviation?
@0celo7 Just look at light?
23:52
Triangle test I'd say
Check if the angles of a triangle add up to $180°$
@ACuriousMind how does one look at light
@Slereah ok
how does one do that in spacetime
@0celo7 With a telescope.
Spacetime is locally euclidian
@ACuriousMind are you trolling me
So you can always measure an angle like in flat space
since that's a local property
23:53
so what you're telling me is that I will never measure spacetime curvature
@0celo7 No, recall how we tested GR in the first place!
@ACuriousMind ah
we're on completely different pages
no need to remind me of GR
I want something completely geometric
"light rays follow null geodesics" is physics
Then do what @Slereah says and parallel transport some vector around a large triangle.
how the heck do you do that??
Just measure the angles jeez
23:55
how do you parallel transport
Some variation of that Chinese device?
Or measure the angles, yes.
@ACuriousMind lol, what?
@Slereah OF WHAT
The corners
Of the triangle
The south-pointing chariot (or carriage) was an ancient Chinese two-wheeled vehicle that carried a movable pointer to indicate the south, no matter how the chariot turned. Usually, the pointer took the form of a doll or figure with an outstretched arm. The chariot was supposedly used as a compass for navigation, and may also have had other purposes. There are legends of earlier south-pointing chariots, but the first reliably documented one was created by Ma Jun (c. 200–265 CE) of Cao Wei during the Three Kingdoms, about eight hundred years before the first navigational use of a magnetic compass...
I think you physicists are too physicsy
23:56
What is too physical about measuring an angle
Take your protractor
Put it on the triangle
@ACuriousMind how did you remember that thing
I learned about it ages ago
> "The chariot can be used to detect straight lines or geodesics. A path on a surface the chariot travels along is a geodesic if and only if the pointer does not rotate with respect to the base of the chariot."
There you go.
@ACuriousMind indeed, will investigate
Now you just need to figure out the 3D version of it :P
now how does one do that for spacelike geodesics
@ACuriousMind 4D, really. and I have to figure out how to make it spacelike
@Slereah WHAT TRIANGLE
23:58
Any triangle.
@0celo7 Hm? It already detects "spacelike" only
Do you remember
THE MYTH
It detects geodesics on the Riemannian 2-sphere.
Of Karl Friedrich Gauss
Some people said he tried to prove the geometry of the universe
@ACuriousMind I need to lift it to 4D
23:59
By measuring the angles between three mountain points
and somehow make it distinguish spacelike and timelike
what if it goes on its merry way along a timelike geodesic
You take some geodesic survey equipment
You go to a mountain peak
You look at the two other peaks
You measure the angle between the two

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