It's not like the algorithms change from language to language, just how to implement them. And that's all basically knowing the syntax and how to find functions and libraries you need
Am I missing something here?
Well, you (among others) seem to be missing that to measure "momentum" is defined through the application of the gradient of the translation operator $\nabla \hat T_{\mathbf r}[~] := \frac{d}{d \mathbf r_{\mathcal S} }[~]$
to what's given through observational da...
Specifically his recent comment,
@0celo7: "This is a deterministic classical system, not a probabilistic quantum one." -- As far as I understand the OP question it is concerned with attributing and measuring momentum values, e.g. of objects (such as $A$) wrt. to suitable systems (such as $\mathcal S$). There doesn't seem to be any requirement or exclusion being made concerning some categorizazion as "classical or quantum"; whatever you might mean by that. "doesn't $\hbar =0$ [...]?" -- Perhaps you mean cases or limits in which $$\frac{m_A~c^2~\Delta \tau_A}{\hbar} \gg 1 $$ ? ... — user122623 hours ago
This is most telling:
> There doesn't seem to be any requirement or exclusion being made concerning some categorizazion as "classical or quantum"; whatever you might mean by that
@0celo7 Well, I think 12262's point is that there is nothing, when looking at a physical system, telling you whether to use a classical or a quantum description of it.
Fundamentally, all systems are quantum. It's just that you get away with treating some classically ;)
@KyleKanos Maybe, but I ended up having to try to prove it to dilaton, dimension10, davidz, ben crowell, and a couple other and they ended with "plausible deniability"
Slowed down by a bunch of things: personal issues, changing major, doing 2 year MS program in Theor. Cond. Mat. Physics, then doing the PhD with an advisor who did a 10 year PhD and felt that was "normal"
@KyleKanos at first I thought it was. My recent post on the main site has a few comments all talking about hamsters, so I carried that over to what you said
rather than discrete evaluations, think of it like a continuous spectrum of evaluations. Your status can be found by integrating the evaluations over time
@0celo7 I'm no doctor, but I think you missed the kicker of what I said, and then kinda sorta killed it by carrying it further. But again, I'm no doctor
Yeah, I used cubic as it relates to square shape-wise. Linear doesn't match because a line segment is any shape in 1D. But my line was essentially taking the "hip to be square" and translating it into more "nerdy" or technical sounding lingo. Hip->Pelvis. Square->Cubic.
Am I missing something here?
Well, you (among others) seem to be missing that to measure "momentum" is defined through the application of the gradient of the translation operator $\nabla \hat T_{\mathbf r}[~] := \frac{d}{d \mathbf r_{\mathcal S} }[~]$
to what's given through observational da...
