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00:00 - 16:0016:00 - 00:00

12:01 AM
Yep
Built a collaborative filtering algorithm the other day
 
I think what he means is
\begin{align}
L_{\mu}(\partial x, \partial^2 x) &= \dfrac{\partial}{\partial \tau} (\dfrac{\partial \mathcal{L}}{\partial \dot{x}^{\mu}}) + \dfrac{\partial}{\partial \sigma} (\dfrac{\partial \mathcal{L}}{\partial x'^{\mu}}) \\
0 &= L_{\mu}(\partial x, \partial^2 x) \dot{x}^{\mu} \\
&= [\dfrac{\partial}{\partial \tau} (\dfrac{\partial \mathcal{L}}{\partial \dot{x}^{\mu}}) + \dfrac{\partial}{\partial \sigma} (\dfrac{\partial \mathcal{L}}{\partial x'^{\mu}})]\dot{x}^{\mu} \\
&= [\dfrac{\partial}{\partial \tau} (\dfrac{\partial \mathcal{L}(\dot{x},x')}{\partial \dot{x}^{\mu}}) + \dfrac{\parti
Which is a really weird, though apparently completely general, way of proving the Hessian is zero for two eigenvectors that completely avoids Qmech's proof
 
12:53 AM
0
A: How to find the rank of the matrix $\frac{\partial ^2\mathcal{L}}{\partial \dot{X^\mu} \partial \dot{X^\nu} }$ for the Nambu-Goto string Lagrangian?

bolbteppaA general proof applying to reparametrization-invariant actions $$S = \int d^2 u \mathcal{L}(x^{\mu},x_{,i}^{\mu}), \ \ \ \ i = 0,1, \ \ \ \mu = 0,1,\dots, D- 1,$$ is to note that part of the derivation of Noether's theorem (the derivation where you assume the volume element varies also), schema...

Work of art
 
 
1 hour later…
2:20 AM
The absolute legend Jon Skeet hit 6 orders of magnitude of reputation on StackOverflow... When's our own Jon Skeet (John Rennie) going to do the same ??
Lol jk
Although I'm not a very active user, I just wanted to say thanks, @JohnRennie. Your questions, answers, comments, attitude and contributions in general have helped (and continue to help) me in my studies and in my life.
 
2:33 AM
interesting choice of last name
 
skrt
 
 
1 hour later…
vzn
4:01 AM
@enumaris cool, would like to hear more & think others would too with speaker session in all your copious spare time :P ... ps would be interested to hear what you think of this (or other resident coders/ hackers/ intellectuals/ academics/ scientists etc)
 
4:26 AM
what happens if I take a measurement and get a 1% uncertainty i.e. the value is 500 Hz with uncertainty of 5 Hz. What happens to the uncertainty if I do this: y = 1 / 500 Hz. What is the uncertainty of y?
 
in Mathematics, 2 mins ago, by Secret
Therefore, one immediate consequence of being in a universe with a different value of $\pi$ is that you need to use more/less material to build some circle with a desired circumference
in Mathematics, 1 min ago, by Secret
and this can affect the length of rope you need to use for your pulley system, or the number of charges you can place in a storage ring as well meany other things...
 
4:50 AM
Last night dream, JohnRennie and I discussed about classical machines. A user then asked him certain questions, which he then posted a picture of some aircraftin a warehouse where its wings are attached with gears and mentioned how this is a counterexample because if the chain of gears are rotated clockwise, then the tri-ponged shaped gear become disengaged and thus not rotating. Only if the chain of gears are rotated clockwise will the full set of gears rotate.
He then mentioned that this is an example of a noncommutative gear system.
A bit earlier in the transcript, he posted a picture showing nonassociative gear systems, where the order of rotating the gears matter in that some gears will become disengaged when rotated in the wrong order
Finally, I asked him about whether there are other examples of simple (classical) machines that has this noncoummatative property as machines like levers, wheels don't have that. Johnrennie then mentioned that he only knew that the ancient civillisation had only ever made one such craft, implying that gears are unique in doing so.
 
5:25 AM
hmm
 
The two pictures posted by Dream Johnrennie, reproduced as close as I can with my drawing ability (In the dream, they are actually photorealistic)
(NB Yes, I get the gear size wrong in the aircraft picture, there are actually 8-9 on each wing)
 
 
1 hour later…
6:49 AM
@SirCumference It depends on the initial conditions. If you start with a Big Bang then only a universe with positive curvature can recollapse - NB recollapse.
If you start with a universe that started in the infinite past with a negative value of $\dot a$ then it will collapse.
Both of the above assume no matter with weird equations of state is present.
you might argue that a universe starting in the infinite past with a zero or negative value of $\dot a$ is a silly initial condition, and I'd probably agree with you. But then a universe starting at a finite time in the past with an infinite density isn't an especially sane initial condition either :-)
 
7:11 AM
It is still an open question whether bounded infinite sets and finite time blowups can exist physically in some form in reality
 
7:33 AM
How is $\overrightarrow{v} = \frac{\overrightarrow{p}c^2}{{E}_k}$?
My ${E}_k = \sqrt{(mc^2)^2 + (|\overrightarrow{p}|c)^2}$
 
@Rick It's $p^2c^2$ not $pc^2$
 
8:07 AM
yeah..I wrote it as $(pc)^2$
 
1
Q: statistics on question types

niels nielsenI have been here long enough to recognize that most of the questions posted here fall into a short list of different classes. examples: obvious homework or exam questions, high-level mathematical physics enquiries, crank/goofball stuff, everyday physics, off-topic (engineering, electronics, etc.)...

 
@Rick not in your first equation you haven't ...
Presumably you meant $$ \overrightarrow{v} = \frac{\overrightarrow{p}c}{{E}_k} $$
Oh hang on ...
 
mornin
 
@Rick OK, ignore me, your first equation was correct
 
@Slereah ni hao!
 
8:12 AM
@rick but what are you asking? How that equation is derived?
 
@JohnRennie Yes, that first equation
 
@Rick The quick way is to note that $p = \gamma mv$ and $E = \gamma mc^2$
With a bit of sweat you can show that the two equations for $E$ are the same
 
Well not for massless particles
 
Oh go away :-)
 
:p
 
8:22 AM
Today i found out why people fear apologising. Presumably it can be used as an admission of guilt in court. So people have to say things like "I'm sorry you feel that way" or some other forms of non apology.Incidentally this is why someone may force you to issue an apology to establish guilt. Hmm this sucks because people end up not getting closure. If anyone wants to apologize to me for anything i swear i will not take you to court and we will both feel better. I only pretend to be litigious.:P
The law is pretty powerful
Wow may be i should spend the comming weeks reading law and rhetoric
 
can any of you tell me ideals of the ring of countinuous functions?
I know what the maximal ideals are
 
what do you want to know
 
well what are they? Are they just subsets of of [0,1]
 
That doesn't make any sense. Ideals of C^0[0, 1] are subset of C^0[0, 1], not [0, 1].
 
Sorry I meant are all the ideals just functions that will be $0$ on a subset of [0,1]
 
8:28 AM
I don't think there's any general classification of all ideals of C^0[0, 1]. Maximal ideals consists of functions vanishing at a closed subset of [0, 1]...
 
I thought the maximum were vanishing on 1 point
 
Reading about preponderance of evidence. It is not what i thought it was. Hmm fascinating
 
Not on any closed subset
 
Ah, you're right. Yes.
I am describing intersections of the maximal ideals
 
So why wouldn't the ideals be made from vanishing on a subset?
 
8:30 AM
But no, not all ideals of C^0[0, 1] are the ideal of functions vanishing at a closed subset of [0, 1]. Consider the ideal (x^2), generated by the function f(x) = x^2.
 
I am definitely going to study some law. I think it's time. I need to know some basics as a geown mature american :P
 
It's a subideal of the ideal of functions vanishing at 0, but doesn't contain many many functions which vanishes at 0.
Namely, any element of (x^2) is of the form x^2g(x) for some continuous function g.
So that's like the functions which vanishes at least upto second order at 0
 
When you say generated by x^2 you mean functions that can be written as g(x)*x^2
 
Correct
 
right
 
8:33 AM
So yeah there are many many ideals of C^0[0, 1]. It's not a Noetherian ring.
 
how would you generate a uncountable subset
 
Wow i have to read law. Tomorrow i'm heading to Starbucks with a law book
 
from a countable intersection of max ideals
So like the ideal vanishing on [0.3,0.5]
*of functions vanishing on
 
You can't write that as a countable intersection of maximal ideals, indeed.
 
So the intersection can be uncountable?
 
8:36 AM
Yep.
 
Do all physics professors read law? I will feel better if they did lolz. Or at least if some of their emails were informed by legal precedent. Hehe. . . The world is changing and presumably people have to look out for themselves too
 
THe example with x^2
nevermind
So ideals of C[0,1] aren't isomorphic to open/closed subsets of [0,1]?
 
Off to bed now. I am going to try to read law and rhetoric every night as self defence. This will be pretty cool stuff to know, for life in general and to keep out of trouble
 
I don't parse that question. Do you mean to say the ideal of functions vanishing at a subset of [0, 1]?
Well first it can only be a closed set - zero set of a continuous function is a closed set.
 
8:40 AM
Oh, right
 
Studying ideals upto isomorphism is also not a very natural thing to do.
You can think about them as non-unital rings and work with isomorphism of non-unital rings but...
I'm curious. Why are you asking ring theory around in the physics chat? ;)
 
0
A: What was the 'quantum mechanics' before quantum mechanics?

John Forkosh The aim of asking this is, mainly, to gain insight on how one may approach a subject as unintuitive as quantum mechanics. Everything's unintuitive until it isn't. Your profile says you're undergrad math and physics, so you'd probably agree that Newtonian gravitation is pretty reasonably intu...

I want to downvote this just because the syntax annoys me
 
@Slereah You >>>downvoted<<< it?
Just for >>> the syntax <<<??
 
NOT YET
 
Because the math chat isn't active I dont think
 
8:46 AM
@mtheorylord Not at this time of the day. But it's generally very active
 
So there is no bijection from ideals of C[0,1] to open/closed subsets of [0,1]
Weird
 
Right. There is however a correspondence between points of [0, 1] and maximal ideals of C[0, 1].
This can be upgraded to a homeomorphism between [0, 1] and maxSpecC[0, 1]
Where maxSpec(R) is the maximal spectrum of a commutative ring
In general if X is compact Hausdorff, maxSpec C(X) is homeomorphic to X
This has a name, maybe Gelfand's observation or something.
It's one of the motivating examples in algebraic geometry, where you look at the spectrum of a ring instead of the maximal spectrum
(So all the prime ideals)
 
Caffeine headache is coming on
brb dying
I need me some vacation
alas I started my job too recently to get any and no holidays 'til april
 
9:10 AM
you must be allowed sick time
take a couple spaced out sick days off around your weekend
 
u need a doctor's note
"The concepts of algebraic quantum field theory were first introduced in a contribution
of Haag to the Lille conference 1957 "
Right in my hometown!
"The crucial mathematical fact is that infinitely dimensional C*-algebras in general have a huge number of disjoint folia."
@ACuriousMind what is the folium
 
 
2 hours later…
11:22 AM
Laws of physics on a nutshell: A bunch of correlated phenomenon such that whenever A happens, B happens, and C happens, and you always get D as a result
 
0
Q: ???? F=ma With inverse square law gives me a particular solution of Y=(const.) (T to the 2/3 power)?

WoodyPaulF=ma , for stuff in free fall, like a tiny particle of little mass m falling into a big mass M , using the 1/ysquare force means you solve dsq y/dt sq = -const/ysqo, which is a well known differential equation and studied in “MASSIVE” detail for over 300 years. Somehow, just diddling around co...

ooooof
that could use some attention
particularly on tags
CC @Qmechanic
 
11:37 AM
@EmilioPisanty Hi, just a short question. Do you maybe know how it can be shown that the von Neumann entropy of a joint state of the form
$$\rho^{(AB)} = \sum_k q_i |a_{i}^{(A)} \rangle \langle a_{i}^{(A)} | \otimes \rho_{i}^{(B)}$$ is given by $$S(\rho^{(AB)}) = H(\vec{q}) + \sum_i q_i S(\rho_{i}^{(B)})?$$
 
You found a solution to an equation of motion with acceleration dependent on position. You're trying to compare to an equation of motion when acceleration is constant. — StephenG 44 secs ago
definitely not mathematical physics, is it considered homework like?
 
12:11 PM
@JohnRennie how can I explain that an accelerating electron radiates energy...In detail please...
 
what do you mean by "explain"
 
I mean I want to know it conceptually...
 
A dangerous trap
 
-6
Q: plzzz i need answer

Tayyab KhalidUsing superposition find a) the current through the 4- resistor due to the voltage source b) the current through the 4- resistor due to the current source Draw and label the circuit diagram, otherwise you will lose your marks. Write each step of calculation and also mention ...

 
You're trying to think about modern physics in a way that makes sense in classical physics
Or at least with cute diagrams
Not a great idea in general
But if you really wish to, there's a somewhat intuitive concept for that topic
Involving the breaking of field lines by accelerating charges
 
12:21 PM
@Slereah use homeomorphism to escape
 
@BalarkaSen what if it's not connected
 
work on a connected component presumably
 
that's about as intuitive as this topic gets
 
> Notice that the transverse field is weakest to the right and left, and strongest in the perpendicular directions. As time passes, the shell expands at the speed of light. The transverse field also gets stronger because the gap, between the particle's actual location and the point where it would be, expands
Mind = blown
So... radiation is basically the change in the field lines travelling at the speed of light...
 
@JohnDoe not off the top of my head, no
where'd that come from?
 
12:35 PM
I had some thoughts on this one, but I need to revise electromagnetism
This "expanding sphere at the speed of light" is convenient in thinking about SR, since the invariance of the speed of light will means I don't need to worry about reference frames
NB. Still find SR and GR less intuitive than quantum mechanics
 
@Secret you're weird! :-)
 
IMO, GR throw a lot of intuitive notions of "distance" out of the window, and my thinking style often relies on being able to map how far concepts are in some parameter space
For example, as the black hole examples showed, I cannot even tell easily how far is point A from the event horizon because that notion depends on which reference frame I am in (and in some coordinate systems, it may not even make sense)
and then you have the bag of gold spacetime, which because it expands so quickly, is practically infinite even through its metric basically said it is some kind of compact region of spacetime
I can of course just go back to the tensor equations to solve them, but computing christoffel symbols take so much time that I have to leave many of my questions on hold because I cannot easily guess what happen via some back of the envelop calculation
hopefully when I finally get back to it, I will be able to develop a better intuition on it
Meanwhile, in quantum mechanics, if anything gone wrong, I can always fall back onto the wavefunction to search for answers, which abstract notions of "distance" will not depends on which frame I am in. In addition, the hilbert space structure makes it a bit easier to figure out where things are thus easier to do some back on the envelop calculations
Or in short: Too many things are changing at the same time in GR, while in quantum mechanics, not many things are changing at the same time thus easier to figure out how to conceptualise the problem
 
12:57 PM
" Curiously, there exist gravitational configurations that possess even larger entropy than a black hole of the same mass, in fact, arbitrarily high entropy. These are the so-called monsters"
Oh no
Monsters and ghosts
I want off this ride
 
Do these gravitational monsters behave like black holes? From your description above they basically look like someone took some material from the heat death back to the universe in the present day?
 
If I ever discover a physics thing it will be all ghouls and witches
 
(NB I know nothing about the gravitational monster you just mentioned before your post)
Suppose I can take your description literally, these monsters might make very good cooling system as they are basically infinite heat sinks
 
This paper seems to reference a book that doesn't exist
"Relativity, groups and fields"
I think they mean "Relativity, groups and topology"
Apparently Valter Moretti will go to this : qft-horizons.sciencesconf.org
In mine own land
Maybe I should go
I wonder if anyone can attend
"The thin sandwich variation problem"
I wonder if it's related to the Hamburger problem
 
1:11 PM
If I had a tube (one end open, one end closed) that had 1st harmonic at 5cm, is it possible to predict the length of the 3rd and 5th harmonic?
 
"Participants are asked to pay a registration fee of 340 EUR upon arrival at the conference center."
Mama mia
 
> Venue is possible as soon as on Monday 21st May after 15:00
whut
 
It means you can arrive on monday
Les Houches seems to be where all the cool GR conferences are
 
@Slereah it’s related to the constraint equations
 
I wonder how many huge GR books that are just compilations of papers available nowhere else exist
 
1:26 PM
@JohnDoe post it on main, I'd say
 
A lot of mysterious papers seem to be in those
 
@EmilioPisanty Okay I have done so, thanks.
 
@JohnDoe yeah, just saw it
two comments
\mathrm{Tr}, not Tr
\ln, not ln
 
@EmilioPisanty Okay will edit.
 
Why not \operatorname{Tr}
$$\operatorname{Tr} \mathrm{Tr} \text{Tr} \mathfrak{Tr}$$
I guess it's mostly the same
 
1:29 PM
@Slereah also works
 
@EmilioPisanty I’m reading a paper by two people who’ve been in the game for 40 years and they still don’t know you do \ln in TeX
 
@0celo7 yeah, well
 
Or \log, whatever
 
other people being sloppy doesn't mean it's not sloppy
 
the annoying thing is that not all functions are there by default
There's not all the inverse functions and hyperbolic functions
 
1:32 PM
@Slereah yeah, Tr and tr being pretty annoying examples
 
yeah
 
imma start using \mathsf{Tr} just to miff people off
 
I mean, \det is in it
Why not the trace
 
$$\mathsf{Tr}(\rho)$$
so wrong
 
yet so right
 
1:33 PM
O_O suspending me for something that trivial?
 
yeah, that too
 
Nice
I love flaggers. Keeping my chat Christian
 
@Secret hmmmm. I should 'fess up to starring that, probably didn't help.
 
always a fun read
“[That professor]’s math class is hard. You’ll have to come to class for it.”
 
1:36 PM
Emilo: ok nvm
In other news, I just did some search on those monster things. Since they are not black holes, if they do exist, they would make really good infinite heat sinks
 
@Slereah “The Civil War was inevitable, but it didn’t have to be that way.”
heh
 
Sigh, idiot phone
 
@EmilioPisanty $\mathcal T\mathfrak r\{\rho\}$
 
@0celo7 that just made me reload the page to kill the mathjax it was so ugly
still is even just on the plain tex
 
$\mathscr{T}\Re$
 
1:42 PM
0
Q: Can anyone explain Quantum Electrodynamics

HarkCan anyone explain qed(quantum electrodynamics) to me? I really want to understand it. But i couldn't find a simple explanation.

yeah, good luck with that
 
toooooo broad
 
I wonder if I'm allergic to celery
is there some gene that prevents you from liking celery?
 
and something at that level cannot be simplified without introducing inaccuracies
 
the smart gene
 
it always tastes awful
 
1:44 PM
The hell is $\wp$
 
weierstrass
 
Oh
 
Celery literally taste like plastic bags
 
I feel sick
I had it with hummus but it was still bad
 
I thought you were a comical American stereotype
why didn't you eat burgers
 
1:48 PM
@Slereah why would anyone think that?
 
the words from your mouth
I just imagine you in a cowboy suit shooting guns in the air
 
I hate cowboys
 
Oh no @0celo7 hates America
 
slander
I should update my laptop's OS
it's a few years old
 
Don't you fool
are you gonna get windows 10
 
1:52 PM
I have Win 10 on my desktop
it's better than Win 8.1
I want to update my OSX to whatever the newest is
High Sierra
 
Transmission: ""Decrypted""
Slereah's response probability is still erratic
More observation needed to devise next action
 
2:11 PM
" I’ve seen it far more times than I can count: a kid walks onto campus, picks a tough STEM major like Engineering, then, after seeing he can’t cut it there, switches over to something less challenging (but still hard) like Chemistry or Pre-Med. Then after flunking those classes, changes major again and again, until finally getting a degree in Theatre or African Studies or Gender Studies or well, something not exactly associated with high difficulty…or pay."
>engineering
>hard
"students who major in African Studies on day 1 of college generally don’t switch over to Engineering nearly as often as the other way around."
 
The hell is the first track?
Does not sound metal, but there is a lot of screaming
 
"In several ways, mathematics is actually an easy discipline: you don’t have to write papers, reading assignments are a few pages at most, and you usually don’t even have homework. All you need to do in mathematics is understand…"
 
@EmilioPisanty : Indeed. Misuse of the math phys tag, for starters.
 
2:38 PM
@Secret Igorrr is kinda experimental.
It's not really metal, but there are influences here and there
 
It has a very brutal vibe to all the songs in the album (along with some kind of sadness). I don't think I will like to listen to them in a normal mood.
(My current mood is a bit frustrated because I am trying to piece together some code I wrote in the past in order to update and clean it up)
The sad sounding piano is good though with some classical victorian impression
IMO, Music only sound good when one is in the correct mood
 
3:01 PM
all my classes got canceled
what a joke
 
Snow?
Or is there a missile alert
 
like a half inch of snow
 
Over just a half inch?
 
it's the south
people lose their minds
 
3:06 PM
sevilla has lost her mind
 
who's that?
 
in The Factory Floor, Jan 8 at 14:53, by Green
@Secret I found an article last week that discusses the idea that we are about to enter a dark age. https://www.ribbonfarm.com/2017/11/30/prolegomena-to-any-dark-age-psychohistory/‌​#more-6143
Trump will lead us into the 2nd Dark Age
 
Servilia of the Junii is a character from the HBO/BBC/RAI original television series, Rome, played by Lindsay Duncan from 2005 to 2007. The mother of Marcus Junius Brutus, lover of the married Julius Caesar and enemy of Atia of the Julii, Servilia is depicted as a sophisticated and regal Roman matron who follows her heart to her detriment. Betrayed by love, and hungering for revenge, she slowly becomes as cruel as those she would destroy. Servilia is loosely based on the historical personage of Servilia, mother of Marcus Junius Brutus, and lover of Julius Caesar. == Personality == The HBO website...
 
thanks
 
is there a name for the dumbest GR star
Hydrostatic pressure fluid star
 
3:12 PM
really dumb notation question but
 
I have a bruise on my toe
wonder how I got that
 
there are people who don't even have toes
you big baby
 
it's been there for like a week
 
when you have an IVP, should I avoid writing $y(x) = f(x) + k$ and instead write that $y(x) \in (g(x):g(x) = f(x) + k)$ for $k\in R$
im sure my notation for the set thing is atrocious but
 
IVP?
 
3:14 PM
hopefully my question makes sense
initial value problem
 
I have no idea what you're talking aboot
 
first one is fine
 
It seems shitty to say that the function i'm looking for is "equal" to a family of solutions
oh ok
 
yeah you dont have to be that rigorous
 
Also if you want to write a family of solutions don't include the argument
 
3:15 PM
whaddaya mean?
 
wtf are you people talking about
 
$$y \in \{ g | g = f + k \}$$
 
Oh
 
Typo
$y$ is the function, $y(x)$ is a real number
 
Fair, im still new to a lot of these notations and rigor aha
Which brings a second question
 
3:16 PM
...
wtf is going on
 
is it a sin to stipulate that like, $k\in R$ in the brackets?
Or should I put it outside
 
can someone tell me what's happening
 
@BalarkaSen is it worth losing a single mark for a meme
 
oh dear god the romans were crazy
 
3:21 PM
I cant resist
 
sigh
 
that makes it all worth it
 
The recent instability in h bar is caused by that one source of weirdness decline
 
@Secret what on earth are you talking about
 
As things become less weird, so do its existence
 
3:24 PM
@0celo7 can you translate for me
I left my secret $\to$ english dictionary at home
 
@0celo7 To 1st order, rambles due to frustation in coding
To 2nd order: Slereah
To 3rd order: ???
 
yeah, @Slereah
what did you do
 
I'm innocent of whatever he's rambling about
 
Secret is writing an anime script
I want to watch this fantastic anime
 
I want vzn and secret to write an anime
 
3:33 PM
same
 
Secret can handle the Metal Gear solid tier exposition with the mind bending plot
and VZN can add the <- subtle implications that give it deeper context
 
nanomachines
 
"I have a dream"
That was the best part of Metal Gear Rising tbh
 
la li lu le lo
 
I stopped watching a MGR playthrough after 30 minutes
it's too much for my brain
 
3:35 PM
Nah man it's glorious
Just switch your brain off
enjoy the gameplay and the memes
@Secret when Im done with exams I kinda wanna draw a comic for fun, so if you have any crazy ideas lmk
 
Well, I have so much things I want to do, but before this stupid script bundle is dealt with, I will be too guilty to procrastinate
 
Is this the metal gear
 
there was an invincible vampire
quite a strange thing
 
Vamp is quite strange
even stranger is how he was just so over-the-top gay for Raiden
turns out he's romanian
"According to Solid Snake, his name is not a reference to his vampire-like behavior, but to the fact that he was bisexual." from the WIKI @0celo7 what is this
 
lmao
 
3:52 PM
What's a $C^\infty$ vector bundle
Are there vector bundles that aren't $C^\infty$ modules
Well, I suppose $C^k$ is a vector space
 
@Slereah that statement makes no sense
 
Which part
Oh no, partition of unity proof
It never ends
 
@Slereah haven't you seen those a dozen times
should be able to do it in your sleep
 
it is fine
$C^\infty$ vector bundle is just a vector bundle such that the product of a smooth section by a smooth function is still a smooth section, right?
 
00:00 - 16:0016:00 - 00:00

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