@JohnRennie You'll be proud to know I stayed up until 6 in the morning doing electromagnetism while listening to Trout Mask Replica from beginning to end on my headphones
@vzn @JohnRennie @slereah @0celo7. But I don't understand. Even if $\Lambda$ is sufficiently strong such that the strong cosmic censorship violating spacetime extend beyond the cauchy horizon, it does not seemed it can affect the rest of the universe as the penrose diagram basically showed that region is within the event horizon of the black hole?
So in a sense, even if indeterminism does occured, it cannot be experimentally verified without jumping into the black hole
@Secret my feeling is the applied wave experiments are the closest to "realistically" modelling what happens in black holes (have you seen em? now several labs! check em out!). everything else is very provisional.
@BalarkaSen I've listened to Trout Mask Replica many times, trying to convince myself that it really is a work of genius.
@0celo7 When you're writing a Windows app lots of API calls can return a generic error "not enough memory" but that doesn't mean there isn't enough RAM. It just means there wasn't enough of something. Apps frequently don't bother to chck exactly what happened and just display an out of memory error.
No, it's not the PC - not the amount of memory you're have.
Some internal memory buffer in Windows has been exhausted
Adding more memory to the PC won't fix that because the buffers have a preset size that isn't dependent on the amount of RAM. Some app or driver has leaked system objects somewhere and that has caused the problem.
It can be tough to figure out what is responsible. Generally you have to try and see what is running when the problem happens. But if it only happens occasionally it's hard to see any pattern in the occurences.
@BalarkaSen I admire it. It's a hell of an achievement. But it's not my first choice of albums when I want some music to listen to. I have to be in a very special mood to want to play TMR!
@BalarkaSen "A category $\mathcal C$ over manifolds is called locally flat if $\mathcal C$ admits a local pointed skeleton $(C_\alpha, 0_\alpha)$ where each $\mathcal C$-object $C_\alpha$ is over some $\Bbb R^{m(\alpha)}$ and if all translations $t_x$ on $\Bbb R^{m(\alpha)}$ are $\mathcal C$-morphisms."
Since youhave been reading about monsters recently, you might knew something about that strong cosmic censorship result. I suspect we cannot experimentally test it as any indeterminisim beyond the cauchy horizon is within the event horizon according to that penrose diagram?
I don't know how well we can reason about black holes with our existing theory in an experimental perspective as any external observer will never see the event horizon forming, the best they can see is an apparent horizon...
@vzn are you talking about the dumb hole experiments or something else? I don't recall there are other black hole analogues or mimics other than dumb holes
Slereah: yeah, ordinal stuff. Thus it sounds surprising that the proof need 20000 lines cause we already have peano axioms to start with. I suspect, it might have something to do with 4 not being an immediate successor of 2, but I need to check...
@0celo7 There is perhaps an interesting point to be made. Gromov once asked what an intrinsic definition of a Riemannian manifold is; admitting a certain section of the tensor square of it's tangent bundle is not really intrinsic so to speak. Connes gave an answer: en.wikipedia.org/wiki/…
I don't understand his answer but perhaps you definitely would
"One of the reasons that the proof of 2 + 2 = 4 is so long is that 2 and 4 are complex numbers—i.e. we are really proving (2+0i) + (2+0i) = (4+0i)—and these have a complicated construction (see the Axioms for Complex Numbers) "
He says a Riemannian manifold carries exactly the same information as a representation of C(M) inside a certain Hilbert space carrying a certain operator
A totally functional analytic description
This is probably the key to answer what the "right" category of Riemannian manifolds is... IDK
@Slereah you can assign to certain differential operators a mass that appears in their asymptotic expansions that turns out to be the ADM mass of a certain asymptotically flat manifold
Guys a little help here: My book asks a question where it states that photoelectric effect is "virtually" temperature-independent. Isn't that wrong? If I remember correctly, the work-function is temperature-dependent..
@Sid In semiconductors the level of an electron will depend on the temperature
At higher temperatures electrons fill up higher energy levels
hence the photoelectric effect will not have the same effect, I think?
For single atoms it does not really depend on temperature, certainly, but in solids I'm not sure
Although even for a monoatomic gas I think the electrons have a very slight chance to be in a higher electron orbital if the temperature is high enough
