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3:01 PM
What movie
 
@Slereah the big gabagool
the godfather
 
Ah yes
did you see Goodfellas btw
if you want more gangsters
 
it's on my list
 
The three big ones
 
I haven't finished bada bing gabagool yet
 
3:04 PM
Goodfellas, Scarface and Godfather
 
man, people really didn't know how to fight back in the 70s
 
Speaking of 1970s.
What would it take for the Black Arrow to make a comeback in 2018?
Or at least make a similar rocket?
 
@0celo7 ever saw the Star Trek fighting style?
 
@Slereah never watched star trek
 
this passed for a fight scene
 
3:08 PM
pretty god damn boring
here's a good fight scene
 
So Maurer-Cartan is just the derivative of a Lie group element living in a Lie algebra, i.e. if $g = e^{\psi(x)^a T_a} e^{u^i(\psi(x)) H_i}$ then $\partial_{\mu} g = g (\partial_{\mu} \psi^a) T_a + g (\partial_{\mu} u^i) H_i$ implies $g^{-1} \partial_{\mu} g = (\partial_{\mu} \psi^a) T_a + (\partial_{\mu} u^i) H_i$ lives in the Lie algebra?
 
@0celo7 Here's an actual fight scene
 
lol
 
Classic movie
 
I need movies to have a timeline somewhere
I can't tell how much time is passing
 
3:13 PM
It's even worse in modern shows
 
did this dude meet the girl and get married a week later?
what's going on here
 
Where they just put in flashbacks without warning
I don't want every show to be fucking Memento
 
fuck time up maximally
that's when the best movie happens
Memento is not even that fucked up
 
GoT is bad
time just flies sometimes and other times it takes them a season to get across Westeros
 
Maybe I should watch Hardcore Henry
Where everything happens in real time
This is a proper fight
 
3:16 PM
Riki-Oh is an awesome movie
 
it is
 
jesus
some serious wife beating
holy shit this was allowed?
 
well it was in Hong Kong
Not in Red China
 
I mean in the gabagool
 
lol
 
3:18 PM
Anything went in the 70's
 
looks like Sonny died
welp
 
O_O
Turkey is mad.......................
VERY mad.
 
3:47 PM
Hi there! I am not an english native speaker and have a question. Is it okay to speak of an intensity when you mean a rate? E.g. the rate of a Poisson Process becomes the intensity of a Poisson process. Does that make sense in english?
 
It makes sense but it's not a natural clear way to say it, and it could potentially be misinterpreted
 
Hi. I've heard that Research in Condensed matter Theory is 'probably' the safest career in Theoretical Physics. Is that true?
 
it will give you the money yes
 
okay, thanks!
 
Not Strings or Gr?@Slereah
 
3:54 PM
no money in strings
 
You could always compete against the smartest people in the world for the fewest number of places to do the most pedantic work that could end up being wrong though
 
GR?
 
I did my masters in GR/Cosmo/Quantum Gravity and had to switch fields for my PhD because there were no positions left. Now i am doing stochastics and biophysics and have a relatively well paid PhD position
 
if you want to do GR you have to become a mathematician
aka forget all physics
 
Lots of competition perhaps?
@0celo7 Hopefully all was an exaggeration.
 
3:56 PM
yeah, the people who specialized on pure GR at my former institute were all mathematicians, thats true. physicists did strings/QLG/Cosmo and gravitational waves
 
@SwapnilDas GR is pretty much done from a physics perspective
the open problems are too difficult for physicists to tackle
 
But why is that payment thing so? Possible applications of Condensed matter?
@0celo7 And by the way, what are you doing? Mathematical Physics?
 
geometric analysis
 
You plan to become a mathematician?
 
yes
 
4:00 PM
Great. Best of luck.
 
thanks
 
Tell me how any guy specializing in this shall be paid : en.wikipedia.org/wiki/AdS/CMT_correspondence :P
 
no idea
 
I asked as it was the intersection of No money and all money.
@0celo7 By the way what your views on payment in mathematics?
 
I don't think pure mathematics should exist as a discipline so my opinion isn't worth much
 
4:05 PM
You doing applied?
 
no
 
Then why..?
 
it's worthless
 
Ohk.
 
I'm a hypocrite
 
4:07 PM
@Slereah I'm just curious, did you ever do Physics professionally?
@0celo7 It's fine :P
 
@SwapnilDas not really
I did some internships
But alas the money train ran out
 
@BalarkaSen
 
YES
HELL YEAH MANE
 
have you even played the game?
 
if you want to do physics at an institute or university, the payment isnt really that great and is fixed by the local governments most of the time (for a PhD student in germany it is pretty much fixed what your salary is going to be). if you want to get rich, you have to go to a private company after you graduate or get your PhD. but then youll mostly just do applied physics in order to improve a given product or such things
 
4:12 PM
@0celo7 I grew up playing GTA
 
mob wives are certainly interesting
 
@Nicouh well, it's theoretically fixed but it's even worse - often you'll only get a half-time position but are nevertheless expected to work full time
 
He was a gooda boyyy
 
michael didn't marry a paisan
poor english girl
 
Why is $v \otimes v + q(V) 1$ an ideal of the tensor algebra
 
4:16 PM
ahaha he lied to her
 
@ACuriousMind Yep, i know. for PhD students its mostly 50%, sometimes 66% and in rare cases 75% of a normally paid position. But even 100% payment wont make you rich compared to industry jobs
 
@Slereah what's q?
 
inner product
 
..gotta go, get a bus
 
Still trying to understand Clifford algebras, but JUST
 
4:17 PM
@ACuriousMind the quadratic form that defines the Clifford algebra
 
ok that was actually a pretty damn good movie
 
The Godfather?
Yes, it is said to be so
 
I could see myself being a mobster in an alternate life
 
Well that's the Holliwood version
In real life they were mostly just petty thugs
 
4:18 PM
have there even been any recent mob movies?
the genre is pretty much dead, no?
 
probably tons, but nothing famous springs to mind
 
[Math stuff: Making $\epsilon-\delta$ proofs less backward]
 
@Slereah that's not an ideal, you probably mean the ideal generated by elements that fulfill that.
 
It was kind of a genre for the time were the mob was active in the 20's-40's, then in the 60's-80's when it became nostalgic
 
@Slereah Note that you take the ideal generated by $v\otimes v+q(v)$
 
4:20 PM
@ACuriousMind I probably do
(I am bad at algebra)
 
@Slereah maybe learn some commutative algebra
this will all make sense then
 
"The ideal generated by a, denoted (a), is defined to be the smallest ideal containingthe element a."
How unhelpful
 
@Nicouh it sure won't but you can make a decent living
 
@ACuriousMind ...don't you have to work?
what time is it in germany
 
@0celo7 5 pm, just got off work
 
4:22 PM
I see
 
Where "work" was welcoming sessions and eating cake :D
 
Ah, so the set of ideals will be $$I = \{ \sum_i A_i (v \otimes v + q(v) 1) B_i \}$$
For all $A, B \in TV$
So the Clifford algebra is the set obtained by identifying all elements in that ideal in the tensor algebra?
 
@Slereah for a single generator, you simply multiply the entire ring by the element an the result is the ideal, e.g. The ideal generated by 2 in the integers are the even numbers
 
What if I have infinitely many generators
well, possibly
I'm not sure
I guess I should try to figure out the Clifford algebra of $\Bbb R$
Which is $\Bbb C$ IIRC
So the generator is $x \otimes x + |x|^2$
 
@Slereah yes, but the better way to think about it is to simply think of it as the tensor algebra with the rule $v \otimes v = q (v) $ applied to all expressions.
 
4:27 PM
what is TV
@ACuriousMind I already told him that
 
Tensor algebra of $V$
 
and to be fair that expression makes no sense
 
Why wouldn't it make sense?
 
I guess the generic element of the multivector space is like... $a + b dx$
 
a 2-tensor equaling a number?
if that makes sense in your world I need some of your drugs
 
4:30 PM
@0celo7 the algebra structure doesn't know about tensors - It's just equating one element of a ring to another
Also, no, you don't get any of my drugs
Find your own dealer
 
lmao
 
So $x_1 x_2 = (x_1 \otimes x_2) = (a_1 \otimes a_2 + a_1 \otimes b_2 dx + a_2 \otimes b_1 dx + b_1 dx \otimes b_2 dx)$
And $dx \otimes dx = -q(dx) = -1$
 
@ACuriousMind I understand that
@ACuriousMind that
 
Which I guess makes sense if I pick $dx = i$
 
that's fine
 
4:33 PM
Am I all good so far
 
I tried to beat someone to death with a crowbar and it didn't work
sadface
 
$a_1 a_2 + (a_1 b_2 a_2 b_1) i - b_1 b_2$
 
r/nocontext
PUBG will get you banned 0celo7
 
@BalarkaSen #PUBGthings
 
@ACuriousMind is that Correct Application so far
 
4:34 PM
the RNG is a cruel mistress
 
I am learning symplectic topology @0celo7
 
Is the whole $v \otimes v = q(v)$ the reason behind the $Z_2$ grading
why there's the split between even and odd algebras
 
I think so, @Slereah
 
@Slereah on mobile, can't read the TeX and not willing to start the brain-parser :P
 
The natural grading comes from the tensor algebra grading
 
4:35 PM
Well I have to go home myself anyway
Time for me to scram
brb
 
But you identify a 2-tensor with a 1-tensor, so the Z-grading quotients to Z/2-grading
 
Actually, the CliffOrd algebra has a Z_d grading where d is the dimension, but it turns out that even and odd are the useful applications of that grading
Hm, should possibly even be d+1
 
what an awful game
::starts another round::
@BalarkaSen I managed to quit playing
only because I'm so bad at it
 
4:57 PM
Does US beef have a $Z_2$ grading
 
I'm guessing the algebra means we can only have elements of the form $e_1 \otimes e_2\otimes e_3 \otimes ...$
Hence the link with p forms
That aren't equivalent to elements of lower degrees, anyway
 
Does $e^x + \sin x = c$ have analytic solutions for any real $c$?
 
highly unlikely
 
$c=0$
Errr
1
 
5:12 PM
yes
 
ah sorry, I mean solve for $x$ in terms of $c$
 
Then x=0
Probably not then
 
I see
 
I've realised the good thing about music exams is you can say it was written 'early 19th century' and you're probably right...
 
My guess is maybe you expand $e^x$ and $\sin(x)$ as Taylor expansions then use Lagrange inversion to invert the series, whether that's do-able is another thing
In mathematical analysis, the Lagrange inversion theorem, also known as the Lagrange–Bürmann formula, gives the Taylor series expansion of the inverse function of an analytic function. == Theorem statement == Suppose z is defined as a function of w by an equation of the form f ( w ) = z {\displaystyle f(w)=z\,} where f is analytic at a point a and f '(a) ≠ 0. Then it is possible to invert or solve the equation for w in the form of a series, w = a + ...
 
5:14 PM
@BalarkaSen I've always found sympletic geometry to be very hard to get interested in, particularly because it doesn't show up anywhere of interest.
 
Except Hamiltonian mechanics which is one of the main motivations...
 
Balarka is not talking about wikipedia level things
 
If there's a function it's probably a bullshit function
Like hypergeometric or jacobi stuff
 
I was originally expecting something like the Lambert W since it kinda reminds of $e^x = x$ but I guess having a trig does make a huge difference
 
Fine the twistor theory of symplectic manifolds :p
 
5:18 PM
Wow, the close queue has reached triple digits, I see 101 items in the queue. All >3kers, please review!
 
Anonymous
@bolbteppa That wouldn't be an analytic solution, would it?
 
If you can apply Lagrange inversion then your inversion will be analytic
 
Anonymous
@bolbteppa I thought analytic solution means that you can write the solution closed form (a summation of infinite terms isn't an analytic solution afaik). But the inversion theorem seems to give a solution with infinite terms (?)
 
@Blue Analytic means having a Taylor series
 
Analytic can mean whatever you want it to mean :P
2
 
5:24 PM
Wherever the Lagrange-Burman series is defined, it is analytic
It is not everywhere defined, however, is the point
Locally any analytic function can be inverted. That's the analytic inverse function theorem
 
Anonymous
@BalarkaSen Where did you find that definition?
 
@Blue Probably Wikipedia ;)
 
Any textbook on analysis.
Also wikipedia :)
 
you're talking about completely different things
Balarka is clearly in the wrong here
 
That's the funny thing, yes :P
 
5:27 PM
I'm confused?
 
@BalarkaSen People who talk about "analytic solutions" of equations usually don't mean the "has a convergent series expansion" sense of the word.
 
Oh, you're using analytic to mean a closed form expression
 
Anonymous
@ACuriousMind Oh, I know what analytic functions are. But analytic solutions are ones which can be written in a closed form, which I knew till now. For example: mathworld.wolfram.com/Analytic.html
 
As Lang would have said, your terminology sucks ass
 
Anonymous
@BalarkaSen I sort of like your response to all the terminologies which you don't like :P
 
5:29 PM
I don't dislike it, it's just garbage
"Closed form expressions" are a pretty vague thing anyway
It's hard to define rigorously what a closed form is. Only physicists and engineers use that notion
 
Anonymous
@BalarkaSen Yep, I got that part
 
Yeah, it basically means "solutions composed of functions I like"
 
That ^
 
Anonymous
Lol
 
$d\omega=0$ is perfectly rigorous...
 
5:30 PM
That use of the word analytic is children's level use, nobody uses it that way
 
There is, however, a good paper by Timothy Chow somewhere on the internet which puts the finger on the issue
 
@ACuriousMind composed of functions found in Abramowitz and Stegun...
 
Good paper. I had a lot of fun reading it once.
 
@0celo7 That's one possible definition of "liking", mostly for masochists ;P
 
Worse than closed form function is "closed form numbers"
 
5:35 PM
shot in the head by a Kar 98 from a mile awa
 
Those are impossibly abused by people
 
damn
 
@0celo7 getrekt
 
There's a set of elementary functions IIRC
 
Anonymous
@bolbteppa Given that Secret was talking about fitting it in Lambert W function, I can agree
 
5:36 PM
I had a really good kit too
 
It's like polynomials, roots, exp
And inverse
 
@Slereah That's how Chow defines them.
Adjoin it to the function field of rational functions, more or less
But then asking which functions are elementary and which aren't becomes a very hard question in transcendence theory
I like the following take towards a study of "closed form numbers":maths.ed.ac.uk/~aar/papers/kontzagi.pdf
 
Is there like
A canonical form
For members of a clifford algebra
Do you just pick the representative of lowest rank
 
I have to write my dynamics notes
Jesus hell
 
Anonymous
5:51 PM
@BalarkaSen For the ODE sessions?
 
Anonymous
How are those classes going?
 
Yeah. Actually we moved on from ODEs to the deep end of dynamics a long time ago
It's going pretty good, I really like them
 
if I just stop playing PUBG I'll be happy
 
Anonymous
Heh, yeah, I had expected that :) I'm still doing the qualitative analysis of ODE. I don't get much time. Just a couple of hours a week for ODE. So...going pretty slow
 
Anonymous
Hirsch Smale is good
 
Anonymous
5:53 PM
Also the NPTEL lectures which I'm using
 
Anonymous
You were using some strange Russian book, no?
 
I was using Arnol'd. Where are you in Hirsch-Smale?
 
Anonymous
@BalarkaSen I'm not doing the book linearly. Following the NPTEL lectures and reading the related portions from Hirsch Smale. I completed those population models, equilibrium points, stability (although at an elementary level)
 
Anonymous
Oh and the arzela ascoli theorem stuff
 
mmkay. Be careful to read the classification theorems
 
Anonymous
5:58 PM
Okay, I'll keep that in mind
 
The baby model for classification of linear systems is the (forced) pendulum :)
 
Anonymous
I learnt the analysis of the sine gordon equation for the pendulum
 
Anonymous
Not anything more though
 
When I say pendulum I mean the linearized equation
 
Anonymous
Ah, I see
 
Anonymous
6:00 PM
Haven't reached that yet I think
 
@Slereah seminar is tomorrow
I need to think of a clever opening line
"Welcome to the abuse of terminology and notation seminar"
 
Welcome to MASS
(Because the Churc)
(And ADM mass)
 
@0celo7 "Leeetsss gettt riiight into the newssss"
 
@BalarkaSen there's only one person in our generation there and he's a complete normie
it would not work
 
maybe you could look at those GR Cauchy videos I gave you
 
6:08 PM
ah sucks
 
and find a good zinger
 
@Slereah oh shit I forgot about those
wonder where I saved them
I think I'm going to talk about physicists for a bit
and why trusting their lies leads to the dark side
 
Do you mean slander physicists
 
@Slereah that's like slandering Trump
 
A very confusing statement, because you love slandering physicists but hate slandering Trump
 
6:12 PM
I aim to confuse.
 
0
Q: Can chaos theory apply to human interactions?

A.DarwishFor example say you miss a train and therfore meet the love of your life, would this be considered an example of chaos theory?

That's ... a surprising question ...
 
a fine question but more for the sociology SE
 
@Slereah ugh what's the transformation formula for metrics?
 
Anonymous
@JohnRennie So...ummm...someone even upvoted it XD
 
@Blue I did
 
Anonymous
6:19 PM
Probably 0celo
 
Do you mean $$g_{\mu'\nu'} = \frac{\partial x^\mu}{\partial x^{\mu'}} \frac{\partial x^\nu}{\partial x^{\nu'}} g_{\mu\nu}$$
 
Anonymous
aaah!
 
Anonymous
I guessed it
 
@Slereah thx I can never remember the index order
 
I just use $$\frac{\partial}{\partial x^{\mu}} = \partial_\mu$$
 
6:20 PM
@Slereah gonna try to compute an ADM mass
 
Schwarzschild?
Minkowski would be easier, but perhaps less illuminating
 
Euclidean but with strange coordinates
"Boundary conditions at spatial infinity from a Hamiltonian point of view,"
so many papers
 
There's too many papers on almost every topic
You have to go into really weird and minor theories to get a manageable amount of papers
usually when the theory is just one guy
or one guy and another guy saying he's wrong
and they're just doing a back and forth of papers
Like that guy who tries to do a formalism for QM using fiber bundle
literally the only guy
I should try to reread it
Now that I know marginally more about fiber bundles
 
this is basically impossible to compute
jesus
 
I'm curious to know if the parallel transport is equivalent to the propagator
 
6:29 PM
"The energy determined in general relativity on
the basis of the traditional Hamiltonian approach does not have physical meaning"
nice title
 
Is it the whole zero hamiltonian thing
 
if the metric does not decay fast enough the ADM energy depends on the coordinates you use
 
It's based on the Einstein pseudotensor, no?
Not too surprising
 
yeah there's no way I'm doing this calculation
 
I hate to say this to you, but did you consider
APPROXIMATING IT
 
6:34 PM
I just want to understand how something can be $O(r^{-3/2})$, get integrated over spheres of radius $R$, and then be finite as $R\to\infty$
seems like it should be $O(R^{1/2})$
 

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