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05:00 - 18:0018:00 - 00:00

Sid
Sid
18:03
@Abcd Did you understand why so?
@Sid not really
Sid
Sid
Also, you are planning for JEE-19? Which coaching, if any?
@Abcd Understand this simply, Li+ has only 2 electrons. So, one shell. EA=Energy released on adding electron. As its size is small, you can easily add electron
@Sid Yes. FIITJEE
@Sid Okay
18:25
Is it possible to compare the electron affinities of Na$^+$ vs Cl$^-$ with similar heuristics?
Na$^+$ has 2 shells while Cl$^-$ has 3 shells
Sid
Sid
Possibly. I am not sure..
Anonymous
18:43
@Secret Cl(2-) doesn't exist while Na ion exists. So that might be a hint...
19:13
Hi, everybody.
Sid
Sid
Hey @DanielSank !
19:45
Anybody around who knows their group theory?
@EmilioPisanty ::raises hand::
@ACuriousMind Say I have some vector space $V$ and an action of $\rm SO(3)$ on $V$
and I know that this gives rise to a reducible representation
how do I separate it out into its component irreps?
I was doing this before with $\rm SO(2)$ and it was easy but it was a hack, I was just taking some random vector $v\in V$, finding $f(R(\theta))v$ explicitly and taking its Fourier series w.r.t. $\theta$
which works fine, but it's a hack
and I'm not sure how to generalize to the 3D case
@EmilioPisanty Look at the values of $L^2$.
@ACuriousMind hmmmm, yes
You can diagonalize it, and its eigenspaces of different eigenvalues are precisely the irreducible subrepresentations
19:56
i.e. find $L^2$ on that space and diagonalize it?
Yup, seems the easiest way to me
how do I find $L^2$?
as an operator
I imagine $L_z$ is something like $$L_z=i\frac{\mathrm d f(R_z(\theta))}{\mathrm d\theta}$$ or something?
Yep (if you evaluate at $\theta = 0$)
so, find the matrix representation w.r.t. some basis of $V$ and then square that?
Yeah, then add all the $L_i^2$.
20:00
yeah, that sounds like a plan
thanks =)
Random question: Why having a system with charge separation will in general have lower entropy than that of a neutral system?
is it because the coloumb interaction reduces significantly the number of possible microstates the system can take
For example, let the system be a dipole formed by plastic spheres separated at distance d , and one where both plastic spheres are uncharged. How to calculate the entropy of these two different systems?
@Secret It's just combinatorics, here's a toy model: Think about a box with two halves and $n$ positive and $n$ negative particles in it. We say it's neutral when there are equally many positive and negative particles in both halves.. If it's charged, there's $n/2 + m$ positive particles in one half and $n/2 - m$ in the other.
A state is an assignment of each particle to one of the halves. Now you can just compute that there are more states where $n/2$ particles of each kind are in each half than when there's a charge imbalance.
Ah I see, that makes sense
@ACuriousMind hmmm, something's not quite right here
$$\begin{pmatrix}
0 & -1 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \\
3 & 0 & 0 & -2 & 0 & 0 & 0 & 0 & 0 & 0 \\
0 & 0 & 0 & 0 & -1 & 0 & 0 & 0 & 0 & 0 \\
0 & 2 & 0 & 0 & 0 & 0 & -3 & 0 & 0 & 0 \\
0 & 0 & 2 & 0 & 0 & 0 & 0 & -2 & 0 & 0 \\
0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & -1 & 0 \\
0 & 0 & 0 & 1 & 0 & 0 & 0 & 0 & 0 & 0 \\
0 & 0 & 0 & 0 & 1 & 0 & 0 & 0 & 0 & 0 \\
0 & 0 & 0 & 0 & 0 & 1 & 0 & 0 & 0 & 0 \\
0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \\
\end{pmatrix}$$
not the most hermitian matrix I ever saw
20:14
Yeah, that's...not $L^2$ ;P
It looks sorta "close" though
@ACuriousMind that's meant to be $L_z$
@EmilioPisanty Huh.
@ACuriousMind wait
I think my basis is not orthonormal
yeah, that's probably it
@EmilioPisanty So, you have a map $\theta \mapsto R_z(\theta)$, and you computed $\partial_\theta R_z(\theta)\rvert_{\theta = 0}$ and that's what came out?
@ACuriousMind yeah
but my basis wasn't normalized
ah
$$
\begin{pmatrix}
0 & -\sqrt{3} & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \\
\sqrt{3} & 0 & 0 & -2 & 0 & 0 & 0 & 0 & 0 & 0 \\
0 & 0 & 0 & 0 & -\sqrt{2} & 0 & 0 & 0 & 0 & 0 \\
0 & 2 & 0 & 0 & 0 & 0 & -\sqrt{3} & 0 & 0 & 0 \\
0 & 0 & \sqrt{2} & 0 & 0 & 0 & 0 & -\sqrt{2} & 0 & 0 \\
0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & -1 & 0 \\
0 & 0 & 0 & \sqrt{3} & 0 & 0 & 0 & 0 & 0 & 0 \\
0 & 0 & 0 & 0 & \sqrt{2} & 0 & 0 & 0 & 0 & 0 \\
0 & 0 & 0 & 0 & 0 & 1 & 0 & 0 & 0 & 0 \\
0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \\
\end{pmatrix}$$
much better
so, now
how do I do simultaneous diagonalization in mathematica?
20:38
Why do you need to do simultaneous diagonalization? The only matrix you need to diagonalize is $L^2$, isn't it?
 
2 hours later…
22:09
@ACuriousMind never hurts to diagonalize $L_z$ too
or, more precisely, I also want to know where my old $\rm SO(2)$ irreps ended up in this mess ;-)
 
1 hour later…
23:21
@EmilioPisanty When the eigenvalues are integers, one trick is to consider diagonalizing $A+b B$ where $b$ is some irrational number. With $b$ suitably chosen you can remove possible repetitons of eigenvalues of $A$ or $B$ so each eigenspace is 1-dimensional and you get a simultaneous eigenvectors of $A$ anf $B$ directly.
@ZeroTheHero yeah, it's done already ;-)
much through that route
I'm pretty amazed that Mathematica managed to diagonalize things exactly with square roots and everything
if the eigenvalues are non-degenerate Mma can do wonders but it may take time and lots and lots of memory.
I do not know how they do it...
but I've done this trick with more than 2 operators and it gets to a point where the calculations are just too long...
anyways...
23:39
@EmilioPisanty do you use TeXStudio?
@0celo7 nope, TeXMaker
as I recall I tried them both simultaneously for a while, over ubuntu, and texmaker was better
I like my editor on mac much better
but it was a while ago
I'm trying to use my fancy new PC for my projects and it's a pain to learn a new thing
it's indenting things randomly
I have the same problem with vim
23:44
when it works, that is
I don't want to turn off the indenting because I like it
Indenting manually is a PITA sometimes, but I tend to prefer it over correcting automatic indentations. It helps keeping the indentation consistent.
why doest thou curse me, gods?
@0celo7 What book is that?
@JaimeGallego A thing I am writing
the exact contents are a secret as of right now
it is safe to say there will be some calculus
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