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13:01
In that connection, this is a good resource
starting from about minute 15 or so, as I recall
(and that whole playlist is a must-watch anyway)
@Emilio wow!!!
Or possibly it's the third lecture?
I had no idea there were lectures online
can't remember it's been online
I thought he only had the transcript online
13:03
@ShaVuklia Those aren't the Feynman Lectures from the book
those are seven public lectures
ohh okay
much better than recordings of his course, to be honest, it's much more compact
[Free feynman lectures on physics](http://www.feynmanlectures.caltech.edu/)
yay thx @Yashas
[test](test)
the chat malfunctioned: doesn't show me links :D
(test)[test]
13:06
I'm reading Goldstein now as a recap for classical mechanics. I think it's pretty neat.
the only unfortunate thing is that we haven't had any vector analysis yet
so I have to study that on my own
for me too @Accidental
whaaaaattt
did i seriously just got rick rolled in a physics chat? :P
5
SE chat bugs are as weird as quantum mechanics
13:07
LOL yea I already found out yesterday
particularly mid-page 49
I am using $\mathfrak O$ unironically
(as marked on the page)
thanks @Emilio
wait
maybe I am using it ironically
can I be ironic about doing something unironically?
13:09
anything written by Feynman is a must read
user228700
Has anybody here experienced intense pain at joints/bones due to indigestion?
what did you eat!?
Nitrogen
user228700
@AccidentalFourierTransform Everyday food cooked at home.
can Indians get an indigestion?
you people have a natural resistance to that, right?
13:13
@Kaumudi.H lol
@Kaumudi In the ribcage, yeah.
user228700
I've been trying to figure out what's happened but to no avail.
@Kaumudi.H That sounds like a case for a doctor.
Acid reflux does that.
user228700
@0celouvskyopoulo7 Thank you for ur sympathy.
13:14
@BalarkaSen did you not see my compact surface thing?
23 hours ago, by 0celouvskyopoulo7
@BalarkaSen Interesting result of Minakshisundaram-Pleijel: Let $M$ be a compact surface, and $\lambda_j$ be the eigenvalues of the Laplacian. Then $$\sum_{j\ge 0}e^{-\lambda_jt}\sim \frac{\mathrm{vol}(M)}{4\pi t}+\frac{\chi(M)}{6}$$ as $t\downarrow 0$.
user228700
@ACuriousMind I phoned the doctor but she said that she can't see what the problem is, given that I don't have fever.
@BalarkaSen The spectrum of a compact surface completely determines what it is.
user228700
13:15
Just an inability to like, move or do anything. Typing also hurts like hell :'-(
How come Reed and whatnot pretend that $\pi \approx \delta /\delta \Phi + \Phi$, but both Rovelli and Haag say it's just $\pi \approx \delta /\delta \Phi $
maybe tag ACM
@0celouvskyopoulo7 why do i care
@ACuriousMind plz respond
user228700
So nobody, huh? Gah, I have no idea what to do now!
13:16
@BalarkaSen Because it's interesting?
@Slereah I don't know anything about the wavefunctional representation, really
why is it interesting
user228700
@BalarkaSen Man, you really couldn't care less, could you? Didn't even bother to capitalize the "i" :-P
quite unfortunate
I guess it's time to ask PSE
@BalarkaSen Because the eigenvalues of the Laplacian determine the topology, regardless of the metric
13:17
what canonical algebra do they use?
@Kaumudi i'm just being honest :P gimme a reason to care and i'll
it's about as interesting as Gauss-Bonnet
$[\delta+\phi,\phi]\neq 1$
no wait
hmm
$[\phi, \phi] = 0$
as u well know
@0celouvskyopoulo7 How does it "determine the topology"? It gives a topological constraint on the manifold to admit a Laplacian with a given spectrum. But why do I want to have a Laplacian with a given spectrum?
13:19
@Slereah it makes for a nice question, I think
You might even be lucky, someone like Valter Moretti might know
@BalarkaSen If I give you the eigenvalues of the Laplacian on a compact surface, you could in theory tell me which surface. If you don't think that's neat, ok.
I'm fairly sure those two representations aren't unitarily equivalent
@0celo I might, it might be neat, I just don't know the Laplacian story well enough.
to appreciate it
It's not a fundamental result
But there's a long standing question in analysis: Can you hear the shape of a drum?
For compact surfaces, the answer is yes.
Oh.
It relates to that?
13:22
That's the one
@BalarkaSen Yes, the harmonics of a drum are the eigenvalues of the Laplacian on it.
Wait, actually Reed also mentions $\pi \approx \delta / \delta \Phi$
what's the difference between the two
@0celouvskyopoulo7 Interesting.
@0celouvskyopoulo7 what about a spherical drum
there is a factor of $i$ that looks suspicious there
13:25
Apparently the difference might be that in the other rep, the vacuum state is just $1$?
something about hermiticity
@Phase That's a compact surface
While in the "standard" one, it's a complicated thing
Wait so
Ah, I see
13:26
You could have a spherical drum?
It's two different Hilbert spaces
@Phase Probably not, the question is more philosophical in nature than practical
$\pi \approx \delta / \delta \Phi$ is for the classic $L^2(\Bbb R^n)$
maybe refrain from calling QM classic
While the more complicated one is for $L^2(\Bbb R^n, d\mu_k)$
for some measure
13:27
@0celouvskyopoulo7 well, drums just make sound by the surface vibrating up and down, wouldn't a spherical surface still somehow have states where the surface can oscillate?
I think the measure is just the Gaussian measure
It would be hard to produce though
Now the question is
@yuggib why were you bothering me about this
what did yuggib do?
He was the one telling me that $\pi \approx \delta / \delta \Phi$ was not Proper
13:32
@Phase I don't think there would be a way to make it vibrate evenly
I'm not sure
@0celouvskyopoulo7 I imagine different parts would vibrate differently, if you want the entire surface to vibrate in some way
@ACuriousMind Jeez, what happened there?
@0celouvskyopoulo7 You know that we generally don't discuss specific suspensions in public.
What is girl physics
I don't know, but there seems to be a deleted comment thread that's the origin of all of this
"I went to undergrad at MIT and grad school at Caltech. I get the feeling nobody here even has a degree in physics. :)"
I'm too stupid to post memes
Chrome wont even let me view the page
:37134404 put ! Before URL to send that linked images
"Your connection is not private" joy
"Particle physics has failed since the 70s. Sorry to hear you were one."
sick burn
13:41
Can someone send me a transcript?
Or images or smthn
@AccidentalFourierTransform Is it letting you expand the comment thread?
quickly
it will be deleted
thx bby
@Phase lol, why do you even use virgin
they are the devil
13:43
Well I'm at a Premier inn for a few weeks
If I had a choice I'd be on any other provider
Can someone go to Grad school and somehow not learn about Four vectors?
Grad school?
Idk but I assume its like a masters program in Europe
Undergrad surely would still force you to Learn four vectors
for SR
You don't know what grad school is?
It's a PhD program
13:48
I WAS ASKING WHAT IS A FOUR VECTOR
@AccidentalFourierTransform a 4-dimensional vector, clearly
do you not know relativity theory?
It's only relativity theory because it doesn't agree with reality
@AccidentalFourierTransform Is that...really necessary?
@ACuriousMind This is obscene.
13:51
Tesla is the future
@Kaumudi.H Thanks , but we already had a talk
Haag has a heuristic argument for the non-unitary equivalence of QFT but I'm not sure I get it
People, please don't misuse flags
@ACuriousMind hi
@LeakyNun Testicles are hardly appropriate for chat.
@0celouvskyopoulo7 alright, sorry
13:53
@0celouvskyopoulo7 testicles is a contentious topic it seems
Don't what
He says that for some Fock space representaiton $n = (n_0, n_1, ...)$, $(n^{(1)})$ and $(n^{(2)})$ are equivalent if they only differ by a finite number of particles, and then... I dunno
Can't remember who but someone went on a bit of a rant about how it's only ok for some users to talk about them or something
@Kenshin hello , how was your trip :-)
@Phase Daniel Sank; John Rennie.
13:55
@0celouvskyopoulo7 ok maybe "cant remember" was just a censor
rip
the argument
@Slereah are you talking to yourself?
@NateStemen You have an unfortunate surname.
I've had a realisation:
@0celouvskyopoulo7 I am only if you people don't answer
Rude
For like, 50% of the time, "The h bar" is just another maths.SE chat, but a topology specific one
13:56
I will help you with GR, not this
@Slereah What does "differing by a finite number of particles" mean?
@0celouvskyopoulo7 really, never heard that...
@NateStemen remove the t
@0c
nah not seeing it
sorry man
do you not know what that is?
13:57
@ACuriousMind I'm guessing if $n^{(1)} - n^{(2)}$ is $\neq 0$ only in a finite number of places
nah never heard to it
strange, ok
you will one day
then you will think of me
omfg...
@0celouvskyopoulo7 Ew. Please don't deter newcomers to this chat like that :P
@Slereah Yeah, I'm reading the screenshot you posted
What's wrong with what I said?
13:59
@ACuriousMind right?
@Slereah How does one pronounce your last name, anyway?
@0celouvskyopoulo7 I can't find anything right with it.
@Slereah What are the $\Psi_{(n)}$?
@ACuriousMind $(0,0,...,0,\psi(x_1,x_2,...,x_n), 0, ...)$
@ACuriousMind do you have interesting integrations?
@LeakyNun Sorry, but I don't understand the question - what's an interesting integration, and why might I have one?
@Slereah Uhhhhh...could you elaborate?
14:01
Wait no
Let me check
I mean, $\Psi_{(n)}$ is a vector for a sequence $(n)$. I'd bet it's the one created from the vacuum by applying each $a_k$ $n_k$-times
"Let $\Psi_n$ denote the normalized state vector corresponding to the occupation distribution number $(n)$. These vectors form a complete orthonormal basis"
@ACuriousMind oh sorry, wrong ping
@ACuriousMind I don't aim to be right.
$$a_k \Psi_{(n)} = n_k^{1/2} \Psi_{(n - \delta_k)}$$
14:03
@Slereah ...proof?
@Slereah Ah, yes. Then I understand the argument
Ah, I think $\Psi_{(n)}$ doesn't denote a specific state
Just "the state with distribution $(n)$"
Where $(n) = (n_1, n_2, ...)$
That is a specific state :P
sure, but it could be any state
for a choice of $(n)$
Basically, what he's saying is that an irreducible representation of the $a_k$ is already given by choosing any $\Psi_{(n)}$ and taking the space spanned by all the other vectors created from it by applying $a_k$ or $a_k^\dagger$ to it.
14:06
Oooh
And the usual QFT state we pick is the vacuum, isn't it?
And I do know that for the study of topological defects, we pick the defect as the "background" state
So that's why that doesn't really work here
(Or you could pick any other state with $(n)$ in the same equivalence class. The point is that applying the $a_k$ only creates $\Psi_{(n')}$ states where $(n')$ is in the same equivalence class as the original $(n)$)
But what about "infinite" operators made from them, such as field operators
Or exponentials of it or such
We're just talking about representations of the CCR, not about fields at this point.
14:09
Alright
The second part of your screenshot is really neat. I never realised that one might encode a fermion state as a single real number between 0 and 1
Representing quantum states as vectors in $\mathfrak l^2$ fell out of favor
I'm not sure why
I wonder how long I can keep a book without the library getting mad
oh nice, you can renew book loans online
user228700
@Koolman Ah, OK :-)
Haag's argument for interacting theories is that for different values of the coupling constant $g$ of a field, the vacuum has to depend on $g$ (since its energy will vary with it), and if we had the same Fock representation, then $\Omega_g = \Omega_0$
14:23
Question: how do we even know that we can generate the conditions for fusion in such a way that there's an energy efficient way to do it?
@Phase look at the sky
But that's an immense gravitational field, my question is how do we know that we can create suitable conditions without needing more energy than we'd get out the fusion itself
I dont believe in the sun
Well then we do not know!
Although with recent progress I think it's doable
we're getting pretty close to sustainable fusion
14:25
@AccidentalFourierTransform why not?
@Slereah Uh, I don't believe I've ever seen the sun in the night sky.
@Slereah reassuring
@0celouvskyopoulo7 God are you dumb? it gets colder and turns into the moon.
have you ever seen the sun?
I dont think so
And you haven't either.
"This conclusion is usually referred to as Haag's theorem"
Don't play coy, Haag
You can just say it's yours
14:26
@Phase If I flag this you will get suspended.
Really?
I am talking to you as per @ACuriousMind 's instructions
@Phase Yes
But I am not supposed to flag without asking you to stop
I guess I should start using those upside down question marks
I have severe PTSD
I'm sorry for shaming you for your lack of Astrophysics knowledge, and the sun-moon duality of quantum mechanics
I've checked my flat-earth privilege
14:28
good
؟I respect your feelings؟
"This means that the fields in an interacting theory are more singular objects than in the free theory and we do not have the canonical commutation relations."
nooo
@0celouvskyopoulo7 Why would you flag it? Don't just tell people "you'll get suspended", tell them why you would flag it in the first place.
He called me dumb
That's Not Nice
Yeah, I'm gonna flag you for not saying why you'd flag me
Get banned
14:29
go for it.
Yeah but no tattletales
can I get suspended for writing ω?
@AccidentalFourierTransform As you noticed, that depends on the context (as with most things). :P
14:30
@AccidentalFourierTransform congrats :P
$$\mathbf{O\omega O}$$
$|ω\rangle$
it was a shitty question anyway
it does look like a butt
@Slereah $|)\rangle$ nah
fuck
The standard way to write a Hilbert ray that isn't $\omega$ is $\psi$
14:32
@Slereah Honestly, what did you expect?
@ACuriousMind who knows
Can't the QFT people just switch to distribution algebras
Like sensible individuals
Then they can write all that without any problem
What is the equivalent of that problem in the non-relativistic statistical QM, by the way?
Since it's also infinitely many degrees of freedom
NRQM typically has finitely many d.o.f.
$2N$, where $N$ (fixed) is the number of particles
Not if you have infinitely many particles
well in that case you have Haag as well
Also you mean $2Nn$ with $n$ the dimension :p
14:37
I just reabsorbed the $n$ in the number $2$
that's not a lot of dimensions
Or it's a very large $2$
$$\Huge 2$$
> We derive new representations of the Einstein-Hilbert action in which graviton perturbation theory is immensely simplified. To accomplish this, we recast the Einstein-Hilbert action as a theory of purely cubic interactions among gravitons and a single auxiliary field.

> The corresponding equations of motion are the Einstein field equations rewritten as two coupled first-order differential equations. Since all Feynman diagrams are cubic, we are able to derive new off-shell recursion relations for tree-level graviton scattering amplitudes. With a judicious choice of gauge fixing, we then c
neat
Neat indeed
it's always hard to find good stuff for the full Pauli Fierz action
since it's infinite and nasty
no, its massless I think
the gauge-fixed massive graviton propagator is awful
its half a page long
lol
Enough Haag for now, I should tidy up the flat
14:43
You know that user
who did the whole "physical entity" "fourth dimension" and "straight A's at MIT"
I think this might not be their first account
Look at this
Such accusations carry a serious penalty.
I said I think, and the link seems to be unnaturally similar to the other user
The other user also posted essentially this question twice on their "girlsciencemajor" or whatever account
It's just fishy is all I'm'a sayin
and you suggesting that girlsciencemajor is JD?
Wait who's JD again?
Is this the guy who's voldemort?
14:46
Voldemort
@Phase We do prefer that you raise such speculations (if you think you have evidence) as a custom mod flag and not in public. It's not really constructive to accuse other users of sockpuppetry in public.
nice
oh, sorry I didn't really know there's a system for it.
How do I submit this flag?
There's no "system" in any specific sense, but in general, many concerns you have about the site that you feel you might want to bring up here actually either belong into a meta post or a custom mod flag.
Oh ok, nevermind then
@AccidentalFourierTransform: well I thought it was funny :-)
14:48
It's not that serious it just seemed too uncanny to not point out at least, given how it's also suspended
but I'll zip now
@Phase You'd just flag any post of either of the users with a custom flag explaining what the issue is.
@JohnRennie what's it?
the question is, if I pick an arbitrary Fock state and use the usual CCR of the ladder operators, can I work out QFT in general?
a bit vague but I'm not quite sure how to express it
go review the rules of differentiation. — ILoveMath 11 hours ago
@AccidentalFourierTransform your, erm, emoticon
14:51
of course you did
Did you get suspended for it, or was the post just deleted?
ah, the ω!
YES I WAS SUSPENDED BUT I WOULD DO IT AGAIN
Sorry, what happened?
Is this post still around?
Jeez, why is everyone so keen on drama today? Chill out, people.
@AccidentalFourierTransform I had never seen that emoticon before and I have to confess I laughed out loud, which is not my usual response to the physics chat.
14:54
sick
@ACuriousMind I think you know why.
It's not for the sake of drama, I just want to know what the emoticon is. Also, @ACuriousMind what's the deal with this should I try and edit it or just flag it
no, my figurine is legless
@Phase It was a man with large testicles.
What is this... figurine... doing in my... house???
@0celouvskyopoulo7 Well there we go
14:55
user image
2
look what you did
I don't know why people think such things are funny
@Phase Uh...you should edit it if you think the end result will be on-topic, otherwise you should flag it.
@0celouvskyopoulo7 I have genuinely no idea
it was a / followed by a lower case omega (presumably the unicode character ω) then a \
It looked uncannily like a logogram of a spectacularly large pair of testicles. Try typing it and you'll see.
$\Upsilon$
What's the protocol for actually changing questions by editing
This is all I could think of that would even partially make it valid
Changed wave to field and stuff
Also missed typos, corrected them now
14:59
@ACuriousMind

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