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2:00 PM
In reality there are some absolutely terrible people out there who commit horrible acts of human indecency, but are emotionally and intellectually very mature. The problem is human understanding and visions are not consistent.
 
These are dangerous realms of philosophy and psychology you should not just perceive as black and white or oversimplify. You'll find your ideas in a wild knot if you go deep enough.
 
Anonymous
@BalarkaSen Yes, a lot depends on the situtation one is under. In difficult situations even emotionally mature people (in normal life) can commit terrible crimes.
 
@BalarkaSen I mean, we really haven't nailed down what "intelligence" even is properly, afaik, so I'd think that's sort of a precursor to any conversation about such?
 
Anonymous
I was just pointing out that empathy is a part of intelligence.
 
2:02 PM
Like, almost everything is a gross oversimplification of human intelligence
(AFAIK of course)
 
Anonymous
Actually it is very difficult to talk about intelligence in quantitative terms.
 
So... I see its philosophy session hour atm
 
Anonymous
Everything is an oversimplification.
 
Yes, it is difficult and yes, I can't define it. It might not even be a consistent notion.
 
@blue Exactly.
 
2:05 PM
@BalarkaSen when doing complex analysis, did you see the claim "$\Delta u=0\implies \Delta|\nabla u|\ge 0$"?
 
nope
 
One might argue that physical theories are usually an exercise in simplification while precisely avoiding oversimplification. Therefore, "everything is an oversimplification" is an oversimplification.
 
I like that.
 
welp
it's the mystery claim
 
I mean, the brain is 1000x more complex than a desktop processor, and as any good overclocker will tell you, we haven't even been able to consistently quantify their performance.
(sorry)
 
2:07 PM
So $\Delta |\nabla f|^2=|\nabla\nabla f|^2$ by Bochner's theorem
And $\Delta |\nabla f|^2=2|\nabla f|\Delta |\nabla f|+2|\nabla |\nabla f||^2$.
So $$\Delta |\nabla f|=\frac{|\nabla\nabla f|^2-2|\nabla|\nabla f||^2}{2|\nabla f|}$$
 
Anonymous
This is an interesting field actually. When intelligence has to be coded into program(s). That's why Artificial Intelligence one of the hot topics. :)
 
That doesn't necessarily look positive to me...
 
@blue You say it depends on the situation. I am uneasy about this too; does situation mean material situation? I can easily imagine persons who lived in the perfect material world, but their own contradictions of thoughts lead them down paths of insanity and paranoid downward spiral. That's something you can't explain with "situation".
There has been numerous examples of this through human history, psychology, literature. An experiment was done with rats a few years ago.
 
Anonymous
@BalarkaSen Maybe it was too much perfectness that drove them insane!
 
Indeed.
 
Anonymous
2:10 PM
There is a term for it(this exact situation) in psychology, which I forget
 
Human mind is a strange, strange thing. It's almost a curse.
 
@ACuriousMind Couldn't Newton have invented a buggy door?
that was later adopted to a car
 
@0celo now you're a french, russian and greek at the same time
 
Missing a two above, it's $$\Delta|\nabla f|=\frac{|\nabla \nabla f|^2-|\nabla|\nabla f||^2}{|\nabla f|}$$
So what is $|\nabla\nabla f|^2-|\nabla|\nabla f||^2$...
 
Hello all
Could someone help me out? I need to calculate $\vec{E_{rad}}=\frac{\mu_0q}{4\pi r} \left [ (\hat r \cdot \vec{a})\hat r - \vec{a}\right ]$ for a point charge situated at the origin and hit by a plane wave $E_I=E_0\cos(kz-wt)\hat y$. I also need to calculate the radiation field $\vec{B}$ produced by this charge.
 
2:20 PM
no
 
But I'm not sure what to use for $\vec{a}$ and $\hat r$
I know that the charge accelerates in the same direction as the oscillating electric field, so I think $\vec{a}=a\hat y$
And I thought that $\hat r = (\hat x + \hat y + \hat z)$
 
o.o
I can't into calculus
 
Anonymous
@loltospoon What does the plane wave represent?
 
@blue not sure what you mean. It is a planar monochromatic EM wave. It is the thing that accelerates the charge.
 
Anonymous
@loltospoon So it is the electric field, right?
 
2:28 PM
@blue yep.
 
Anonymous
So you want to calculate the net electric field at a position $\vec{r}$ ?
 
Anonymous
Just superpose the two fields
 
the sad reality is that most of physics doesn't matter.
unless what you're doing influences GDP or war it's not very good
 
Anonymous
Chemistry matters more than physics :P
 
2:34 PM
yeah but chemistry is feh
 
I agree
chemistry and biology > math and physics
no doubt
 
i don't think math is really a candidate for comparison
it's not even science in the strictest sense
 
Anonymous
But the thing is one field cannot survive without the others. They are all interconnected. Like development in QM helped to discover a lot in chemistry.
 
Anonymous
And for development of QM you needed math
 
Not really
 
Anonymous
2:36 PM
And so on....
 
we can survive without you for sure
 
@BalarkaSen Well, it isn't a natural science if that's what you mean :/
 
QM is actually completely disjoint from mathematical reality
 
You can do electronics with physics
Very GDP
And uo
And you need qm for it
 
QM doesn't even make sense
 
2:37 PM
@paracetamol I guess? I generally think of "observation, experiment, explanation" whenever I hear the word "science"
 
True
 
Math does not fit in that context.
 
@blue not sure what you mean by superpose the two fields. Am I not supposed to be using the equation I've written above?
 
...what is $\nabla [g(\nabla f,\nabla f)]$?
index notation to the rescue
 
Anonymous
@loltospoon What is $\vec{a}$ in that I can't understand.
 
Anonymous
2:39 PM
The question is vague
 
@blue the resultign acceleration of the charge after getting hit by the wave
 
Speaking of science, I heard this a while back: If it moves, it's Biology. If it stinks, it's Chemistry. If it doesn't work, it's Physics
 
drink some HF
it doesn't stink
 
@blue the charge gets hit by the wave and there is some radiation fields that get created. I need to find these fields.
 
you'll be fine
 
2:40 PM
@0celouvskyopoulos It's...toxic
 
Plus the resulting mess'll "stink" ;)
 
you'll melt
 
Anonymous
The equation is not dimensionally correct. $(r.a) \vec{r}$ doesn't have the same dimension as a
 
I don't trust index notation...
 
2:41 PM
@0celouvskyopoulos Sure, it isn't an ideal body-dissolving chemical, but...meh
8 secs ago, by paracetamol
Sure, it isn't an ideal body-dissolving chemical, but...meh
 
no need to say the same thing twice
 
you'll be fine
I promise on @ACuriousMind 's honor
 
^ Ah well...if you put it that way...
 
1 min ago, by 0celouvskyopoulos
you'll be fine
 
fugg
you get a curvature term
I hate geometry
 
2:42 PM
You changed name again @0celouvskyopoulos
 
@Fawad what?
please don't slander my good name
 
^ It was good?!
Whoa...
 
@blue that's the equation in my book. I just double checked it
 
@0celouvskyopoulos you changed name at some 12 am I guess chat.stackexchange.com/search?q=0celouvskyopoulos&room=71
 
Anonymous
@loltospoon That's just not dimensionally correct...
 
Anonymous
2:44 PM
Ask on the main site maybe
 
@Fawad This is scary...
 
@Fawad idk man
 
@0celouvskyopoulos I admit that would be both possible and hilarious.
 
@ACuriousMind I mean, Euler gets credit for a cohomology class so I think Newton can get a car door ;)
 
How does entanglement even work in QFT
What's a simple example of entanglement in QFT
 
2:46 PM
stop asking these questions
there is no hope
 
why not
 
So I have $2g_{ab}(\nabla_i\nabla^af)(\nabla^bf)$
 
@Slereah $\lvert p_1,p_2\rangle + \lvert p_3,p_4\rangle$ for any set of four distinct momenta.
 
A lot of the measurement business revolves around the notion of being able to have tensor products of two states, but is that even possible in an interating QFT
 
stop it acm
oh god I have to take the square of this
 
2:48 PM
Can you decompose the Hilbert space into sub-Hilbert spaces like that
 
@Slereah Show me the state space of an interacting QFT and I'll show you the answer :P
 
@ACuriousMind First difficulty!
 
$$\nabla_i |\nabla f|=\frac{g_{ab}\nabla_i\nabla^a f\nabla^bf}{|\nabla f|}$$
I'm willing to trust that result
 
[Random GR question]

Suppose I have the following metric $\eta_{\alpha\beta}+h_{\alpha\beta}$ where $h_{\alpha\beta}=diag(a,0,0,0)$. Therefore the full metric will be $diag(a-1,1,1,1)$. Are there solutions which can make $1>a-1>0$, or is it impossible to bent spacetime so much so that the signature of the metric becomes 1,1,1,1?
 
that's just a scaling of Minkowski space
there's an isometry to diag(-1,1,1,1).
 
2:50 PM
Also generally, if you have some particles becoming entangled, can you always describe this as one system observing the other
 
oh wait, $a-1>0$
 
@Secret If the signature is like that, it's not GR
 
@Secret that's just Euclidean space.
 
Yeah I know, I am just wondering whether GR allows the introduction of a very large distortion so that it causes minkowski space to become euclidien (given we already have a similar(?) case where in black holes the time and space directions get flipped)
 
It doesn't.
Otherwise you're dealing with another theory entirely
 
2:52 PM
$$g^{ij}g_{ab}g_{cd}\nabla_i\nabla^a f\nabla^bf\nabla_j\nabla^cf\nabla^df$$
 
hmm I see
 
hmmm 🤔
 
hmmmmm
 
what even is that
 
2:55 PM
why so many gradients (or is that the covariant derivative)
 
covariant derivatives
@Secret I think that if $\mathrm{Ric}\ge 0$, then $\Delta f=0\implies \Delta |\nabla f|\ge 0$.
The computation is lengthy
I know that $\Delta|\nabla f|^2\ge 0$.
And I have $\Delta|\nabla f|^2=2|\nabla \nabla f|^2+\mathrm{Ric}(\nabla f,\nabla f)$.
 
11
Q: Is quantum entanglement functionally equivalent to a measurement?

DavidI saw the following talk the other day: http://www.youtube.com/watch?v=dEaecUuEqfc&feature=share In it, Dr. Ron Garret posits that entanglement isn't really that "special" of a property. He argues (and shows) that the mathematics behind it is analogous to the math behind measurement. Is this tr...

Hm
I guess it's possible that measurement and entanglement are mostly the same thing
Then doing measurement of a "single particle" would be doable
in the abstract, that is
 
If $\Delta(PV^{\gamma})=0$ then $P\gamma V^{\gamma -1} \Delta V + V^{\gamma}\Delta P=0$...Why is it similar to product rule? It is differentiating with respect to?
 
Prove $\angle BDE=\angle BAC$.
 
3:04 PM
for entanglement in indistinguishable particles, refer to this for details
arxiv version: https://arxiv.org/abs/1511.03445
If I recall, going to QFT does means making particles indistinguishable
 
Anonymous
@Aryabhatta Are you the user Maxwell?
 
No.. he had asked me this ques. On FB
 
Anonymous
Sorry, too hard to believe.
 
Anonymous
One asks the question and other asks the other part of the question :P
 
Anonymous
At the same time
 
3:06 PM
@blue, that's on you.
I.said him to post it here.
 
Anonymous
Fine fine. I am not interested in the question anyway. And I don't think anyone will answer it for you until you show your effort in solving it.
 
@Fawad Hi
 
@JohnRennie hello,teach me
 
@blue, that's not my part
 
3:09 PM
@Fawad OK?
 
The amusing thing is that the quantum measurement problem is barely related to QM itself
 
@JohnRennie yes?
 
I can do QM and QFT for months without ever worrying about measurement
 
@Fawad What do you want me to help with?
 
@Fawad @JohnRennie I don't understand why expansion of Delta is like that. Why is it similar to product rule?
 
3:12 PM
@Slereah That's why I choose to not worry about it, mostly :)
 
I decided that -+++ is not that bad and I might change into that convention from now on
MWI is the correct interpretation
thats pretty obvious
 
@Fawad I have only just joined the chat and I have no idea what you are talking about. What expansion of Delta and what do you mean by Delta?
@AccidentalFourierTransform :: John faints in shock ::
 
If $\Delta(PV^{\gamma})=0$ then $P\gamma V^{\gamma -1} \Delta V + V^{\gamma}\Delta P=0$...Why is it similar to product rule? It is differentiating with respect to?
 
@Fawad What is your definition of $\Delta$? What does it mean?
 
@ACuriousMind change
 
3:14 PM
definition as in formulas, not words
 
$\Delta = \text{final}-\text{initial}$
 
$\Delta f(x)=f'(x)\Delta x+\text{small}$ typically
 
@Fawad You sure it shouldn't infinitesimal change?
Because then that is basically using a derivative without explicitly saying so
 
@ACuriousMind but then there is the point where I must!
 
I'll never understand why people insist on doing thermodynamics without properly introducing differentials.
 
3:17 PM
"properly introducing differentials" and "infinitesimal change" are not really related
:-P
 
@ACuriousMind it isn't mentioned ,it is in waves ,while correcting Newton's formula for wave as adiabatic not isothermal.
@AccidentalFourierTransform correct. If + small typically is not taken then it is ≈
 
@AccidentalFourierTransform Oh, they are, because if we would just say "Take the differential" we wouldn't need to wave your hands around talking about change :P
 
Wait, quick question
 
I never really understood what all the $\delta W$ or $\delta Q$ and such are about in thermodynamics before I learned about differential forms.
 
Chandrasekhar is pronounced "Shondo-she-kor", right?
 
3:20 PM
"Chondo-she-kor"
 
Wait, you sure?
 
yesterday, by blue
Chondro-Shekhor
 
Chan-drah-see-car
 
@ACuriousMind they don't even introduce the contact manifold of thermogeometrodynamics
 
Grah, I'm confused
 
3:21 PM
@Slereah I know, right?! ;P
Joking aside, you really don't need to be that fancy to be a little better in explaining thermo.
 
Anonymous
@SirCumference Not "S"...whew...where did you get that!
 
I don't know what forms have to do with thermodynamics
 
but for what?
after all, its thermo
nobody really gives a f
 
@blue Wikipedia's pronunciation sounded like that :P
 
@AccidentalFourierTransform is a really infuriating troll
He's not an idiot, clearly
 
3:23 PM
OK, so is "Chandra" pronounced "Chondro"?
 
Anonymous
@SirCumference Probably not written by a native :P
 
Anonymous
@SirCumference Yes :)
 
Anonymous
@AccidentalFourierTransform That sounds weird
 
Anonymous
kher at the end
 
3:24 PM
Your face sounds weird.
 
@blue of course it does, it's Hindi
 
@blue Like "kur"?
 
Anonymous
@AccidentalFourierTransform Man, Hindi is my native language.
 
@JohnRennie halp
 
@blue why tho
 
3:25 PM
@blue I know.
 
De Broglie sounds weird and it's my native language
 
@BernardoMeurer what have you broken now?:-)
3
 
@JohnRennie I have a question on pointers :P
 
Anonymous
@0celouvskyopoulos That "kher" sound at the end isn't what it sounds like. It is more widely used like "khor"
 
@BernardoMeurer OK?
 
3:26 PM
@JohnRennie Remember how we allocated a matrix like this:
matrix = calloc((size_t) m_size, sizeof(int *));
if (matrix == NULL) catchError("Matrix allocation failed.");
for (int i = 0; i < m_size; ++i) {
    matrix[i] = calloc((size_t) m_size, sizeof(int));
    if(matrix[i] == NULL) catchError("Matrix allocation failed");
}
 
Anonymous
Chundra-Shekhor or Chondro-Shekhor sounds better and is more widely used
 
@BernardoMeurer Yes, OK, an array of pointers ...
 
Can anyone else from India confirm?
No offense to @blue, just seeing if it's unanimously pronounced that way
 
Yeah, matrix is int **matrix
 
So what happened to 2017?
@ACuriousMind did he delete his account?
 
3:28 PM
@JohnRennie So, how do I move this into a function of it's own, that receives **matrix and m_size. I tried this:
 
@SirCumference, are you referring to the video's pronunciation ?
 
void allocMatrix(int **matrix, int m_size){
    matrix = calloc((size_t) m_size, sizeof(int *));
    if (matrix == NULL) catchError("Matrix allocation failed.");
    for (int i = 0; i < m_size; ++i) {
        matrix[i] = calloc((size_t) m_size, sizeof(int));
        if(matrix[i] == NULL) catchError("Matrix allocation failed");
    }
}
 
Anonymous
@SirCumference If you ask Kaumudi you'll get a slightly different answer...because she is from South India
 
@HsMjstyMstdn Just the pronunciation in general
 
which india is best india
 
3:28 PM
Ok :)
 
But that explodes
 
@Kaumudi.H, how do you pronounce "Chandrasekhar"?
 
I agree with @blue that the ending is weird
 
@0celouvskyopoulos have you tried using the user search? :P
 
@Slereah the one in north america
 
Ahah
 
That's on the Wikipedia page
 
Anonymous
@SirCumference Why do you need it anyway ? :P
 
@Sir
oops
 
The PSE post I pasted about entanglement and measurement
One of the answer?
 
3:29 PM
@blue So I can accurately pronounce "Chandrasekhar limit"
 
@SirCumference, that one's even weirder
 
This topic is discussed a bit in somewhat lay terms in chapter 1 of my thesis. – DanielSank Jun 24 '15 at 5:37
 
void allocMatrix(int ***matrix, int m_size){
    *matrix = calloc((size_t) m_size, sizeof(int *));
    if (*matrix == NULL) catchError("Matrix allocation failed.");
    for (int i = 0; i < m_size; ++i) {
        (*matrix)[i] = calloc((size_t) m_size, sizeof(int));
        if((*matrix)[i] == NULL) catchError("Matrix allocation failed");
    }
}
 
I guess I'll read Sank's thesis
 
@JohnRennie Do I really need three levels of indirection :(
I was hoping to get away without that :P
 
3:30 PM
@ACuriousMind how do I do that?
@BernardoMeurer I'm signing for my apartment
 
Anonymous
@SirCumference Pronounce it anyway you like...doesn't even matter :P Foreigners sound cute when they pronounce Indian names in their own way. :D
 
You can tell Michelle to...something. I don't know why she couldn't be bothered to help me.
 
@JohnRennie Could I return the address instead? so then I do int **matrix = allocMatrix(m_size) ?
 
But fuck it
Whatever
 
@0celouvskyopoulos Sigh
 
3:31 PM
@blue But...but...I want to sound educated :P
 
@BernardoMeurer yes, that's a neater way to do it.
 
@BernardoMeurer it's not my fault
She didn't respond to me
 
@SirCumference look here, the lady does a fine job
https://www.youtube.com/watch?v=n-lJjR7pM7k
 
I'm already doing things last minute
 
@JohnRennie Sweet, so then I return &matrix ?
 
3:32 PM
@0celouvskyopoulos There's a big "Type to search user" box on the users page
 
Anonymous
@HsMjstyMstdn Yes, that's better
 
Anonymous
She doesn't use the "kher" sound at the end
 
@blue (Y)
 
Just return matrix not the address of matrix. matrix has type **int and your function returns **int. So just return matrix.
Balls, how do I render an asterisk in the chat?
 
Please do not mention the make generalizations.
 
3:33 PM
` * `
 
*male genitalia
 
I'll make generalizations all I want
 
@JohnRennie Got it
@JohnRennie It works!
 
@HsMjstyMstdn "Chandra-sekar"
 
@BernardoMeurer Naturally :-)
 
3:34 PM
@JohnRennie Do I have to free that memory? Only in main right?
Or wherever I called that function from
 
@SirCumference I'm no expert but in general, Indian words are best pronounced when not overthought
 
Anonymous
@SirCumference That lady's pronunciation is fine. You can use that :)
 
@BernardoMeurer If you're only ever going to allocate the memory once there's an argument for not bothring to free it as it will be freed anyway when your process terminates.
 
Sigh, I guess I'll just use "Chrondro-shekor"
 
@JohnRennie That doesn't sound like good practice :P
 
3:36 PM
But it's probably better practice to free it. Pointer values are global so you can free the memory anywhere you want.
 
@SirCumference Monstrosity
 
@BernardoMeurer C or C++?
 
The reason for manually freeing just before (normal) termination is to prevent a surprise if you ever re-use the code in another context.
 
@JohnRennie C :P
 
@HsMjstyMstdn ;-;
 
3:37 PM
And to be in the habit and caring about that every single time.
 
@BernardoMeurer OK, no helpful class destructors to do the freeing then.
 
@JohnRennie Hell yeah, greatest language of all
 
@BernardoMeurer The lisp guys would disagree. But it would be a parenthetical comment.
 
David has a good point. By far the majority of obscure bugs in large C apps are due to mishandling pointers. It's good to develop an obsessive regard for memory management.
 
@dmckee Lol
 
3:38 PM
@BernardoMeurer what the hell are you doing
 
@JohnRennie I am very obsessive
@0celouvskyopoulos Programming lab
 
@BernardoMeurer: I am currently about halfway through writing about 20,000 lines of VBScript to do data replication.
It is actually quite good fun, especially since it successfully replicated some data for the first time this morning. But my goodness it makes the brain hurt.
 
Can this chat please talk about something other than programming for once?
 
When did we last talk about programming?
It was ages ago.
 
Yesterday
 
3:41 PM
Well gee I tried talking about QM but I didn't see you jump on board for that!
 
@0celouvskyopoulos That's ages ago in the IT world :-)
 
So what you say @JohnRennie on that product rule?
 
@JohnRennie I have all the VB stuff :P
 
@Fawad what you posted isn't well defined. Presumably you lifted it out of some book or article and that will give the context for what exactly $\Delta(PV^\gamma)$ means.
 
Anonymous
@0celouvskyopoulos Like the thing that starts with a J and ends with an E ? :P
 
3:43 PM
The first language I put a lot of time into was VB.NET
Sadly
 
I'd guess it is a differential in disguise ie it is really $\frac{d}{dx}(PV^\gamma)$ where $x$ is some parameter being varied.
@Fawad in which case it looks like the product rule because it is the product rule.
 
@JohnRennie I too guess same. Then since LHS is 0 ,dx vanishes.
 
@Fawad differentials aren't fractions so you can't just multiply both sides by $dx$, though to be fair physicists frequently do treat differentials like fractions and it usually works fine.
 
@JohnRennie there is a hot question on math.se
707
Q: Is $\frac{\textrm{d}y}{\textrm{d}x}$ not a ratio?

BB_MLIn the book Thomas's Calculus (11th edition) it is mentioned (Section 3.8 pg 225) that the derivative $\frac{\textrm{d}y}{\textrm{d}x}$ is not a ratio. Couldn't it be interpreted as a ratio, because according to the formula $\textrm{d}y = f'(x)\textrm{d}x$ we are able to plug in values for $\text...

 
I'm looking at a 3 years old post that has unlatexed math in it
Should I edit it
 
3:53 PM
@Slereah yes,if it also don't have good answers
 
it has an accepted answer
I leave it to Jesus to say if it is good
 
@Slereah good luck then.
 
is it possible to edit a post without bumping it back to the front page, perhaps
 
@Slereah no, but texifying a post is a valid reason to edit, imo
 
@ACuriousMind you not searching on meta.stackexchange? I saw one question like that
 
3:58 PM
Sorry, I don't know what you are trying to say - why would I search meta.SE?
 
@JohnRennie If i have a txt file which is a list of words, one in each line. How can I read that into an array in C?
 
-1
Q: Editing without upping?

xavierm02Is there some way to edit an answer without pushing the question to the top of the list? My use case would be this answer that I just edited because the English was bad enough for two people to add comments about it. But an edit that minor shouldn't have pushed it to the top of the question list.

Btw funny English^
 

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