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5:01 PM
You m-foliate the pseudomanifold by the level sets of a simplicial map to some codimension m pseudomanifold.
 
5:28 PM
Hi, everybody.
 
Hi, Doctor Nick!
 
That's "Doctor Sank".
Quick, someone ask a good noise question.
::waits::
 
What kind of noise goes "beep beep"
 
A clown's nose.
 
What's the typical noise background of a commercial laser?
 
5:32 PM
@Semiclassical I doubt there's a "typical" for that.
 
It's NYOOOOOM
 
it's the best i could come up with off the top of my head
 
Oooooh, we should figure out what phase noise is.
Suppose I have a signal like this $$x(t) = \cos (\omega t + \phi(t))$$ where $\phi$ is a stochastic process.
Suppose we know the spectral density of $\phi$, i.e. $S_\phi(\omega)$.
What does that do to the spectral density of $x$?
I've never understood this as much as I wish I did.
 
What is a spectral density?
 
5:35 PM
I wish I knew anything about stochastic processes
 
Ghosts per $m^2$
5
 
@0celo7 Suppose I have a random process $\phi(t)$. This thing has some autocorrelation function $C(\tau) \equiv \langle \phi(0) \phi(\tau) \rangle$.
The spectral density is $$S(\omega) \equiv \int_{\infty}^\infty C(\tau) e^{i \omega \tau} \, d\tau \, .$$
 
What are the brackets here, average?
 
@Slereah Yes, ensemble average.
 
How is that defined?
 
5:37 PM
something like $\int \mathcal{D}\phi...$
 
...and it's assumed that $\langle \phi(t) \phi(t+\tau) \rangle = \langle \phi(0) \phi(\tau) \rangle$.
 
@Semiclassical nooo
 
If that's not true, $S$ isn't defined.
 
i'm pretty sure it's something like that
 
Oh also it's probably $\langle \phi(0) \phi(\tau)^* \rangle$.
 
5:38 PM
@DanielSank For all $\tau$?
 
i.e. some path integral over all possible trajectories $\phi(t)$
 
@Slereah For all $t$.
@Semiclassical No.
 
Oh so there is a specific frequency?
 
@Slereah Eh?
 
5:39 PM
What does $\tau$ represent
 
i have in mind the stuff in these notes: lumiere.ens.fr/~dmarti01/publications/notes_janelia.pdf
 
@Slereah The time between the two values of $\phi$ that we're correlating.
 
k
 
@Semiclassical Ah, yes one can do that. Let's not do that now.
 
e.g. equation (19) on the top of page 7
lol
"It can be done that way...but let's not."
(not a complaint, mind)
 
5:41 PM
@Semiclassical Yes, I'd rather not require path integration for the sake of understanding spectral density.
 
That's like when people around here immediately jump to relativistic QFT when someone asks what it means to move poles off the real axis.
It's unnecessarily complicated.
 
@DanielSank I'm sure by now you've complained more often about that than it has actually happened ;)
 
How else are you gonna find a ball falls if you don't do condensed matter field theory in a curved background
 
5:43 PM
@ACuriousMind Yep.
I'll keep complaining, too.
 
I think that doing it in the path integral context is a good deal more natural than the example you cite.
 
In my field, there are folks who have been hoodwinked into thinking that avoided level crossings are a quantum phenomenon. ~sigh~
@Semiclassical Uh, why?
 
well, for instance, I would strongly suspect that the spectral density in stochastic processes has some rather clear cut analogue in QFT.
 
Isn't it like the momentum space propagator
or something
 
@Semiclassical So what?
Spectral density has a totally simple meaning in my mind completely independently of quantum mechanics.
Why the hell would I make myself think about QFT?
 
5:46 PM
so you're in the physics chat room and you're objecting to it being given a QFT interpretation.
 
wtf!?
 
i just find it a goofy objection
 
How about this, if I pick a range of frequency $\omega \in [\omega_1, \omega_2]$, the mean square value of $\phi$ is $$\langle \phi^2 \rangle = \int_{\omega_1}^{\omega_2} S(\omega) \, \frac{d\omega}{2\pi} \, .$$
 
@DanielSank I was working on this all of 3 hours ago O.o
 
That's the simple meaning of spectral density.
(up to a factor of 2)
 
5:48 PM
(avoided level crossings in Hamiltonians)
 
@Mithrandir24601 Good on you.
Important stuff. Note that it's not quantum.
btw someone emailed me about that video you recorded of our seminar.
I guess the audio wasn't that bad.
 
@DanielSank Yeah, I know - I nearly did a PhD on stuff like that and spent an hour (with the professor) getting told that it's classical as well :)
 
@DanielSank Let's build a motorcycle
 
@DanielSank Oh, nice :) I'm impressed they listened to it - might have been one of the new cohort
 
pleasepleasepleasepleaseplease
 
5:52 PM
@BernardoMeurer I may or may not be going to VA tomorrow. Never trust the government.
 
@BernardoMeurer dude
 
@0celo7 What does the government have to do with you going home?
 
@BernardoMeurer not home. I have to prove to the VA government that I'm alive
 
@0celo7 Wait, what?
 
@BernardoMeurer my driver's license expired and that's as good as dying
So I have to prove I didn't
 
5:54 PM
goodness
Good luck at the DMV
 
They play screeching noises during the hold music to get you to hang up
It's evil
 
Hahahahaha
The Portuguese embassy in brazil played this horrible depressive fado for hold music
You'd consider cutting your wrists while waiting for someone to pick up
That's why I can't hear fado anymore
 
MLG airhorn music should be put on as hold music
or some vaporwave
 
@0celo7 What about people who don't get a driver's licence?
Are they legally dead by US standards?
 
depends on the state
 
5:59 PM
@Semiclassical That's...not a reassuring answer :D
 
and while you'd hardly be considered legally dead, I can well believe it has some real pain-in-the-ass consequences
 
@Slereah I think that unit is called the 'Fadeev'
 
@DanielSank What is the PSD of the Fourier transform of a white Gaussian noise?
 
Anonymous
I actually need some book recommendations for Fourier transform of noise and pressure signals (and the procedure to implement it using programming- C/Matlab would be suitable). Any suggestions anyone?
 
@DanielSank why exactly are they not quantum?
@DanielSank I have a question but it's not about noise
 
6:08 PM
@ACuriousMind that was a bit of an exaggeration. It's more like I don't legally exist
I have to prove I legally exist
 
@DanielSank This problem occurs when I measure the spectrum (Fourier transform) of a signal, and want to know the time domain signal. The measured data necessarily have AWGN. I'm not sure of the answer to this (need a proof).
 
I existed legally yesterday. But today I don't. Quite sad.
 
compute faster mathematica
 
gotta go faster
 
faster faster faster
(alternatively: harder better faster stronger)
 
6:16 PM
sanic wolfram
 
alpha sanic
I am having to face the fact that I don't know how to (numerically) obtain the time evolution of an initial wave function in a 1D potential.
I can sorta do it using Mathematica's NDSolve but it's slow and i don't really trust it
 
@Semiclassical just compute e^-iHt
 
That was a joke
Although there are methods for computing integral kernels. You can do a greens function method
Fourier transform
 
right.
 
6:21 PM
@0celo7 Thiw is the best way
 
I mean, if V(x)=0, then the time evolution in momentum space is just $\phi(k,t)=\phi(k,0)e^{-i k^2 t/2}$ (up to units)
and then one just has to compute the inverse transform
which amounts to getting an integral representation of $\psi(x,t)$ at all times.
(and I mostly am interested in the V(x)=0 case at the moment)
 
@Semiclassical are the problems you want to solve 1D?
 
@Semiclassical so, just do split-step propagation then
29
Q: Are there simple ways to numerically solve the time-dependent Schödinger equation?

Emilio PisantyI would like to run some simple simulations of scattering of wavepackets off of simple potentials in one dimension. Are there simple ways to numerically solve the one-dimensional TDSE for a single particle? I know that, in general, trying to use naïve approaches to integrate partial differential...

Potentially relevant
 
@lılostafa That'a a really weird question. You want the PSD of a Fourier transform?
@Blue Yes I know a lot about this. What exactly are you trying to do?
 
huh, daang
 
6:32 PM
@EmilioPisanty Because they show up if you study two coupled classical oscillators...
@lılostafa Ah, ok yes I can help with this.
 
Gah
Pictures here on Lagrange multipliers are great, why did I always think in the plane medium.com/@andrew.chamberlain/…
 
But @lılostafa let us be very clear. You measure a time domain signal, yes? Then you compute the Fourier transform of it, yes? and you wish to know something about the statistics of the Fourier coefficients that you have computed?
@bolbteppa Wikipedia's page on Lagrange multipliers has a good diagram too.
@EmilioPisanty Golden rule: ask the damned question.
 
@EmilioPisanty thanks. this one is also nice, because of the gifs: mathematica.stackexchange.com/questions/80996/…
 
One of the wiki pics is the projection of that links pics on the plane, more confusing to me for some reason
 
@DanielSank It's basically the same, but I measure the Fourier transform :)
 
Anonymous
6:38 PM
@DanielSank I'm not completely sure about what I intend to achieve. I saw some recent papers on application of application of machine learning and Fourier transform in signal processing (electrocardiographs, arterial pressure, etc). I'm trying to replicate those results at uni lab and thinking of potential research topics related to that). Basically my experimental physics adviser told me to learn the basics and visit him within 1-2 weeks.
 
The question ultimately boils down to what is the Fourier transform of an additive white Gaussian noise?
 
@lılostafa Yes that I can answer very surely.
Note that the Fourier transform is statistical. Think about it: each time you measure a real time trace of a white noise, it is different, so the Fourier transform is not a deterministic quantity.
If you measure white noise, then each Fourier coefficient is a random complex number which has a Gaussian distributed real and imaginary part.
(Not that this is true even if the white noise is not Gaussian)
The widths of the distributions of the real and imaginary parts is related to the variance of the time domain signal.
I have written a very detailed document on this issue. I will send you a link momentarily...
Download and build this TeX file.
Uh... hm... I guess you have to clone the whole repo for that to work. If you want a pdf just give me an email address and I'll send it to you.
I have to go.
 
6:55 PM
@DanielSank Nice, thanks. I built it.
@Daniel Does the same reasoning apply for continuous Fourier transform of the noise too?
 
0
Q: Is it possible to expand the list of migration sites for off-topic posts?

GeoffreyRecently, it seems that we've been getting several questions that would be more appropriate for Cross Validated. This question is only the most recent example. Right now, the only choices for off-topic migrations are to Physics Meta or Mathematics. I think we need more choices - like Cross Valid...

 
(although practically we just need the DFT)
 
@DanielSank =P
 
Could someone please explain what I'm doing wrong here, because it's annoying me that I can't see my basic mistake.

It's for a uniformly charged rod of length a from 0 to a, and it's electric field at a point m from the origin.

I took $\eta = Q/a$ and then $\eta = dQ/da$, rearranged for $\eta da = dQ$, multiplied both sides by k and divided by r^2 on both sides to get $\int \eta k / r^2 da = \int k / r^2 dQ = E$ , with my reasoning for all of this being looking at the right hand side and doing operations on both sides to make the right hand side eventually just be a summation of point cha
 
7:10 PM
What are the equivalents to the Bessel-function sidebands of a particle in a harmonic oscillator that's emitting light along the direction of motion, if you quantize that harmonic oscillator and get a Lamb-dicke hamiltonian?
 
oh and I substitued in (m-a) into r.
 
I.e. If I'm working in the quantized version, how can I recover the classical Bessel sidebands?
Probably too complicated for chat, though =P, I'll ask it on main soon
 
7:27 PM
oh
$\int k/r^2 dQ$ doesn't represent the sum of point charges along a rod does it
 
7:54 PM
@DanielSank In the paper you have derived the distribution of the transformed noise, which is half the answer; it doesn't say anything about the power spectral density. I need that too if I want to generate the noise numerically.
 
8:16 PM
@lılostafa I'm pretty sure, yes. You have to learn a little about the Weiner process to understand why. I'm not quite as good at that yet.
@lılostafa Are you essentially asking for the correlation between the Fourier coefficients?
 
hey guys. what is the topology of H^n? (hyperbolic surface)
is it something familiar?
 
@EmilioPisanty Don't you "=P" me. Ask you question, young man!
 
for example the topology of ads_n is R^{n-1}\times S^1
@DanielSank "=P" is equivalent to "ER=EPR" lol
 
@mathvc_ I don't get it.
 
ER=EPR is a conjecture just kidding lol
 
8:35 PM
@mathvc_ It's the hyperbolic n-space, not surface. The underlying topology is the same as that of R^n
 
8:50 PM
@BalarkaSen On hooooooold with the DMV
 
that was supposed to be @BernardoMeurer
one of you needs to change your name
 
@BalarkaSen really? the topology is the same as R^n?
 
@mathvc_ yes
hyperbolic space is a ball with a weird metric
 
Or the upper (positive) half space.
 
8:55 PM
oh! yes I got it
but why the topology of ads_n is R^{n-1}\times s^1?
 
because it's a fucked up hyperbolic space
and you can lift the metric to $\Bbb R^n$ anyway, I think
 
so what's that s^1 for?
 
@mathvc_ I think the time coordinate in the standard representation is cyclic.
"It is known – the proof is elementary – that"
Ayy Gromov
 
so why the topology of ds_n is S^{n-1}\times R? lol
 
Algum Brasileiro ?
 
9:10 PM
@0celo7 What up
 
9:24 PM
@BernardoMeurer going to Va tomorrow. Not good.
 

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