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14:00
@yuggib oh shut up
@0celo7 Yes. Everyone who uses that argument is flat out wrong.
So how do you get the uncertainty principle?
It's wrong I guess
doing the Fourier transform as it has to be done for $L^2$ functions
Ok, how do you show that $-\mathrm{i}\nabla$ is Hermitian on $L^2$?
14:01
i.e. doing a suitable $\mathrm{l.i.m.}$
Because I'm pretty sure you need the wave functions to vanish at infinity for that
@HariPrasad : nearly. The proton has a definite tripartite nature, but the partons idea leaves it at that, whilst the quark idea employs quark confinement to try to explain why you've never seen the "fundamental particles". Only it doesn't really work for pion production or low-energy proton-antiproton annihilation to gamma photons.
@0celo7 it is not Hermitian, it is self-adjoint
@0celo7 Well, you can do that argument for compactly supported smooth functions, and they are dense in $L^2$, so you can get it by an approximation argument, I guess
14:02
@yuggib literally the same thing
@0celo7 no
@yuggib yes
@0celo7 No
@ACuriousMind yup
a matrix is Hermitian, an operator is either symmetric or self-adjoint
14:03
I'm reading a physics book
I don't care for your whacky terminology
that's your fault
@ACuriousMind do I want to know the proof of that
@0celo7 no
@0celo7 For their density? No.
@ACuriousMind why not
14:05
That's the part of functional analysis you do exactly once and want to never repeat
I think it's in my analysis book
Why is there far more matter than antimatter in the observable universe?
@HariPrasad Tell Stockholm if you find out.
Why does the zero-point energy of the vacuum not cause a large cosmological constant? What cancels it out?
@HariPrasad Why should the zero-point energy of the vacuum be large?
All these "naturalness" arguments babbling about the Planck scale never convinced me
14:11
@HariPrasad : see things like this in your link: "Thus one expects a collision between hadrons at very high energy to be dominated by interactions among essentially free quarks or gluons". Gluons in ordinary hadrons are virtual. They only exist in the mathematics of the model. A quark-gluon "soup" is more like pea soup. And there are no actual peas in pea soup.
and I'm pretty sure that's @ChrisWhite's star :)
@HariPrasad : there isn't. Because positronium is an "exotic" atom, composed of both matter and antimatter. And it's like light hydrogen. Have a read of this.
The proton is more like the positron than the electron. It ought to be classed as antimatter. But it isn't because it's ore common than the antiproton.
@JohnDuffield lol that's a lot of downvotes :P
user54412
@ACuriousMind now it is
14:20
@ChrisWhite Heh, okay
user54412
If we lived in a $\Lambda = 0$ universe, I'm pretty sure no one would even think to ask why vacuum energy isn't driving the universe apart.
@HariPrasad : the strong force cancels it out. But not quite.
@HariPrasad : it sure is a lot of downvotes. But science is not a democracy. Evidence is what separates fact from fiction, not votes. It isn't a religion either. Or so I'm told.
@JohnDuffield lol
@HariPrasad : here's an answer comparing the bag model of quark confinement to the balloon analogy for the expanding universe. The important point is that for a balloon in vacuum, the energy-pressure within is balanced by the tensile strength of the skin. For the balloon to expand the energy-pressure has to increase, which is in breach of conservation of energy. But another way for the balloon to expand is if the tensile strength reduces.
pea soup seems like a bad idea
@ACuriousMind where does the Yukawa PDE $\Delta\phi=m^2\phi$ actually show up
the PDE, not the integral for the solution
14:35
@HariPrasad : IMHO the $64,000 dollar question is where does the strong force go in proton-antiproton annihilation to gamma photons? And also IMHO, the answer has to be it doesn't go anywhere. Because it's the "elastic tension" present in space which means waves in space propagate at c.
OK, I gotta go. Bye for now.
@0celo7 that does not look like the Yukawa potential
looks more like the eigenvalue equation of the Laplacian
Looks like Euclidean Klein-Gordon to me
the Green's function for that equation is the Yukawa potential
That's the equation of motion for a (Euclidean/non-relativistic) scalar field.
Yes, I know that
14:39
Then why do you ask me where it shows up!?
You keep doing that
What would possess you to write it down
Asking a question, and then saying you knew the answer
@ACuriousMind apart from the fact that it lacks time ;-P
@yuggib Mmmh, I've known people who write the $\partial_t^2$ into the $\Delta$ for the Euclidean theory
@ACuriousMind that's just horrendous
14:40
uh, $\Delta$ is the 3-dim Laplacian
I don't really disagree :D
so where does it show up?
@0celo7 Well, then it's the vacuum Poisson equation for a massive instead of a massless mediating boson.
You're gonna be mad
You knew that.
14:41
:D
how about this
how does one get that equation from first principles?
I know the QFT calculation that gives the interaction energy
but that just gives an integral, not that PDE
Write down the Lagrangian for the massive scalar field. The time-independent solutions to the equation of motion obey that equation.
I.e. this is the field equation for the static case
Physics Physics chat session in 1 hour?
hmm, does the KGE come only from the SE?
or is there a "classical" way of getting it
@HariPrasad allegedly
@0celo7 What? Klein-Gordon is the full equation of motion. The Yukawa/Poisson equation is the special case of it for static fields
I know that
14:45
1
Q: Is there an established theory on statistical physics in curved spacetime?

Wein EldI tried to check this in google scholar but didn't find a paper explicitly focused on this topic. Do anyone know of some references on this issue? I do not mean the thermodynamics in curved spacetime which is well covered by Tolman's book ``Relativity, Thermodynamics and Cosmology''.

but how do you actually get the KGE?
@0celo7 Uh, write down the Lagrangian, compute the E-L equations?
@ACuriousMind how do you get the Lagrangian
You guess it! You always guess it! (But in the case of the free scalar field, you can also get it as a continuum limit of a lattice of nearest-neighbour coupled harmonic oscillators. That is, in 1+1 D, it's the continuum Lagrangian for a vibrating string)
lol
you should hate me
I...knew that
14:47
That what the heck was your question?
but why should the field be a bunch of harmonic oscillators
Because everything's a harmonic oscillator! ;)
how does this question have 200+ views but only +4 on the top answer and why is it not accepted
@ACuriousMind I hope you're not serious
@0celo7 views dosen't matter
i see your answer
I'm half-serious. The other answer is because it has been wildly effective as a (mostly toy) model.
user54412
14:50
@0celo7 You wrote a pure math answer to a much simpler physics question
@ChrisWhite pure math beats physics any day
what the fuck is with physicists, anyway
just define stuff properly
@0celo7 JohnDuffield Did you even read my post? I explain everything very clearly.
I get more confused by a line of physics babble than a block of math
@HariPrasad What?
@ChrisWhite how can you answer that question without math
@0celo7 You know, unless one already knows the math, it's not clear to a casual reader how you even answer the question.
> Theorem. [...] $R_\Sigma=\text{const.}$
That's exactly what OP wanted.
14:53
It's always good to begin the answer with a short passage that answers the question in words, and then pull forth the heavy artillery
Also, the OP on the Stokes theorem did not accept my answer -.-
@0celo7 Yes, it is. I didn't say it wasn't. I said to a casual reader it's not clear
Where casual might even include people who have taken a GR course :P
He's lucky I didn't invoke some theorem on foliations!!
user54412
Neither in physics nor in pure math is complexity ever good in and of itself. Quite the opposite in fact.
@ChrisWhite That answer is not complex, it's precise.
And my Stokes answer is, AFAIK, the only proof of that fact in existence.
@ACuriousMind He's really lucky I didn't invoke the Schur Lemma, I think there's another proof via that method.
14:58
@0celo7 No, you're lucky because that would have yielded even less upvotes :P
@ACuriousMind Do people not know that lemma
I wonder if it's in do Carmo
It's in Jost
user54412
@0celo7 Maybe I'll write one later. The answer parallels the definition of $k$ -- it's not free to be just anything, since we scaled away any variation.
The only Schur lemma I know is the one about intertwiners of irreducible representations
@ACuriousMind There's that one too
Basically, if the sectional curvature depends only on $p\in M$, then it's constant on $M$.
And $M$ is a space form
this might only work in dimensions 3 and up
(does sectional curvature even exist for a 2-dim space?)
@ChrisWhite what $k$?
a priori, we don't know that we can put the metric in that form
all we have is homogeneity and isotropy
user54412
@0celo7 the whole point is putting the metric into that form
15:05
@ChrisWhite mb you calculate the Ricci curvature of a leaf, show it's $k$ and argue scalars constructed from a homogeneous metric are constant
is that what you want to do?
@ACuriousMind oooo, FLRW is a twisted product and there are theorems about the curvature of such spaces
there might be another proof lurking there...
user54412
You proved some thing was constant. Great. The question is why is this particular form of the metric fully general enough, where this particular k is not dependent on time.
@ChrisWhite Hmm, interesting, I guess $k$ could still be a function of the foliation parameter.
@ChrisWhite hmm, I actually don't see a reason for it to be constant in time
@ACuriousMind who confirms the edits that i make to questions?
@HariPrasad Users with more than 2000 reputation who participate in the suggested edit review queue or the author sof the posts.
@ACuriousMind alright
0
Q: Feasiblity of a long spinning top using an electromagnet to pull on Earth's magnetic field

AlexWould it be feasible to build a infinitely spinning top (ref. Inception) by including a battery powered electromagnet who's polarity flipped in sync with the top's rotation such that the pull against the Earth's magnetic field countered energy losses to air resistance, friction, etc. For scale,...

15:17
@ACuriousMind why does $k$ have to be constant
@ACuriousMind is $\mathbb{R}^3$ homeomorphic to the 3-hyperboloid
@ACuriousMind I think there should be a live widget in a member's profile page that shows which question, the member is currently writing answer to.
I don't think so.
(Also, why does everyone @ me with general questions here?!
You're the smart one
@ACuriousMind Is that a response to me or Hari?
@0celo7 yes
@0celo7 Hari
15:21
why do I have so many damn GR books
cuz you're a nerd
nooooooo
say it ain't so
I think this is missing a few steps
@JohnRennie so why is $k$ constant in time
@0celo7 which $k$?
huh, the leaf of a Lorentzian warped product is totally geodesic
@JohnRennie the one in FLRW
constant in time, space is easy
@0celo7 You have to stop asking random people questions as if they should know what you're talking about :P
15:26
@0celo7 erm, because ACM said so?
@ACuriousMind mb he read the transcript
@JohnRennie that's what I usually go with
but he didn't say anything about it this time
@DanielSank You know what's an asynchronous communication protocol? Snapchat.
I send stuff and get a response three hours later and have fuck all of a clue of what I originally sent.
@0celo7 I'd have to go away and think about it
@JohnRennie It's not explained in Wald, Zee, Hawking-Ellis, Straumann or Weinberg.
Reading Beem et al. now.
I would guess it's related to a symmetry - mysterious constants usually are.
And it's probably so obvious none of the authors thought it worth explaining.
Well now Beem et al. assume that the spatial topology doesn't change
Hmm, I wonder if you can adjust $a(t)$ by a time-varying factor to cancel the one in $k(t)$
15:39
Are there any metrics in GR that change topology? I didn't think there were.
@JohnRennie No, but even then
The metric does not know about the topology, at least nontrivially
And it's certainly not "obvious"
and I'm not sure that $\mathbb{R}^3$ and $H^3$ aren't homeomorphic
they're not isometric with the standard metrics
What is $H^3$?
hyperbolic space
A model for hyperbolic space is the open disk, and the open disk is homeomorphic to real space.
@ACuriousMind If you have a foliation, do all leaves have the same topology?
15:42
Depends on how you defined your foliation :P
@JohnRennie Ok, so it would seem that topologically the $k=0$ space could morph into the $k=-1$ space.
So it has to be (1) geometric (2) physical
(2) would be very unsatisfying
...said the person chatting in a Physics chat.
@ACuriousMind my disdain for physics is known
@0celo7 you love mathematics.
Oh I just realized you Fourier transform something in that one thing with neutrons
@ACuriousMind help, what is it
there's like a delta function potential
15:45
18 mins ago, by ACuriousMind
@0celo7 You have to stop asking random people questions as if they should know what you're talking about :P
That also holds for non-random people.
@ACuriousMind neutron scattering
that thing, you know what I'm talking about, right?
I...know that neutrons can scatter. That's about it
ah, the Born approximation
@ACuriousMind That is the one where the scattering amplitude is the Fourier transform of the potential, right?
what happens after 9 minutes?
we feast
15:51
@0celo7 I don't know. Have you googled "Born approximation"?
@ACuriousMind I think you know the answer
I fear I indeed do.
I did, but the Wiki article was not what I was looking for.
@0celo7 Which doesn't mean that he has an obligation to give it to you. And especially not that he has an obligation to drop anything and give it to you now.
@HariPrasad we have a scheduled physics chat hour once a fortnight, and it's about to start
15:52
@JohnRennie good
@dmckee I know, but maybe you can help me?
@0celo7 Wait, did you mean that I know the answer to "Have you googled..." or were you saying I'm lying when I said I don't know?
> The scattering amplitude is proportional to the Fourier transform of the potential energy.
Thanks Google
@ACuriousMind Depends on how paranoid you are.
@0celo7 No, it depends on what you meant and nothing else.
I understood one thing, dmckee apparently the other. Which one did you mean?
Huh?
I actually did Google it
Before I asked you
15:55
That's not what I'm asking about
And I didn't call you a liar
I misunderstood @dmckee misunderstanding
So...you were saying you thought I knew you had googled it before asking me?
@ACuriousMind No, I was joking that you probably thought I didn't Google it
Okay, that's what I got. Except that I didn't think you were joking :P
vzn
vzn
feel old! remember when 'google' was only a noun
15:57
@JohnRennie how is the scheduled physics chat any different from what happens the other 335 hours a fortnight?
vzn
vzn
@Mike it has special/ secret sauce added.
this is possibly the only SE chat room I'm ever in that's almost always on topic.
vzn
vzn
@Mike lol guess you are a newb then :P
@Mike in the old days the chat was very quiet, so a scheduled chat time was organised to drum up interest.
@Mike There are usually more and different people around during a chat session, but you're right, it's not particularly different these days
15:58
@Mike hahahahahahahahah
These days the chat is a lot busier so the chat session does tend to merge with the general chatter
We talk about physics maybe 15% of the time
@vzn ... well, I'm originally from Mos Eisley so perhaps my gauge of on topic is skewed.
Mostly we talk about math
@0celo7 yes. Look a butterfly!
vzn
vzn
15:59
@Mike how is that room these days? tried it a bit in the past, saw rumors (in here) of a big/ epic conflagration, dont know details....

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