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12:00 AM
Sure
 
Payment?
 
He wants the M.
 
Huh?
 
Or rather the $g$, I guess.
 
No payment
 
12:00 AM
What?
@Slereah wtf
 
It's all pro bono
 
@Slereah post a question on PSE then!
 
He wants to get paid in points
The rapscallion
Tomorrow tho
It's 1 AM
I need my beauty sleep
 
@Slereah Correct.
@ACuriousMind please explain
 
@0celo7 No.
 
12:03 AM
@ACuriousMind Oh come on
 
Please don't annoy me about it, I hate explaining failed jokes.
 
All the GR books: HE, Wald, BEE, CB, Zee, Weinberg, Carroll, Schutz, Hartle, MTW, Straumann, Penrose, Visser, Sachs-Wu, Kriele, Ringstrom, O'Neil, Chandrasekhar, Poisson, Stewart, Ludyk, Padmanbadan (can't spell that one), Joshi, Stephani, Einstein
 
You forgot Stephaniiii
 
there's another GR solutions book
 
yeah
I also have a book on like
 
12:06 AM
in the same Cambridge series
 
Scalar fields in GR
 
Does Gourgoulhon count?
I'd say it's at least "related"
 
kinda
 
::sigh::...new day, 19 things in the queue...
 
Tho really Stephani isn't only solutions
Like the first 13 chapters are GR shit
 
12:10 AM
I think that's a good starting list
I'll work on the post.
 
I have plenty of GR children books from when I was a kid
 
Like Schutz?
 
Pop science stuff
I also have this book
It's funny because he has a light cone of shame
 
Ha!
We should make a rating of math difficulty
 
Which one will be on top
 
12:15 AM
1-4, from Hartle to BEE
 
Kobayashi?
 
Is that a GR book?
 
diff geo
 
Oh, would we make that a "related" book?
 
That's gonna be a lot of 'em
 
12:16 AM
Yeah, do we have to list ALL of the geometry books?
Because that would be insane.
 
What about the math books on Lorentzian manifolds
I guess we should include like 2 or 3 diff geo books
Just the most referenced ones
 
I put those that I know of in the list above.
BEE and O'Neil.
Are there any more?
That surface book but that's not really GR.
 
I often see that one referenced
I like Poplawski for GR + torsion, although currently it's not a book
Just a book draft
 
I'm probably going to buy that one day
The Asian version is cheap.
The Asian version is cheap.
@Slereah 4 levels of difficulty:
1: Hartle, Schutz
2: Zee, Weinberg
3: Wald
4: HE, BEE
 
sounds aight
 
12:24 AM
Now where to put stuff like Poisson...
 
12:44 AM
@0celo7 Well I guess Danu's research interests are closer to mine than anyone else's here
@0celo7 UCSB is closer to LA
@ACuriousMind I have tried that haha but I end up picking a school for non-academic reasons (more personal reasons) which may not be the best mode of thought
 
@FenderLesPaul Well, given that academically both are quite good for you, what else could you possibly go on?
And academic reasons are not everything
 
It's more like, UCSB is definitely better than Berkeley for my research interests but I'd rather be at Berkeley so I can be close to someone
 
...close to someone?
is there someone else
 
sorry you had to find out this way
 
the joke's on you
I've cheated on you every day for the past two months
 
12:52 AM
I have seen too many of such relationships break apart to recommend that to anybody. But I'm a jaded cynic in that respect :P
 
@Slereah I'm going to restrict my attention to books I've actually had experience with
"On the Topology and Future Stability of the Universe" seems interesting but I have no clue what it's about
 
...the "clean sticky stuff of their covers" type of experience?
 
also it's in some strange font that burns my eyes, so I'll never read it
@ACuriousMind I'm on my second copy of HE, baby
wtf is with that font
 
@ACuriousMind oh it's not a relationship
 
awk
 
12:55 AM
my best friend is going there
 
@FenderLesPaul I've not been cheating on you
 
@0celo7 it's too late
to apologize
its too laaaaate
brb
 
@FenderLesPaul Ahhhhh, now that's different.
Although I still wouldn't base a decision on that, I guess
 
@ACuriousMind what's the heirarchy of classical GR books
 
How could you possibly expect me to have an answer to that?
 
12:57 AM
Osmosis.
I think MTW is the "king" but it's not a good book
 
My knowledge osmosis skills are great, but they do not extend to books, at all.
 
What non-GR books are useful for GR? Lee, Lee, Steenrod, Kobayashi-Nomizu, Milnor, do Carmo
Lee, Lee
Throw in all the Lee books
Cahill probably.
Seriously? It's category shit.
 
what is this chat room about? Because I have a question regarding rotations on Bloch sphere, can I ask it here?
 
Yep
But be warned: this chat is mostly GR
 
@AnuroopKuppam It's about whatever the people here want to talk about. If you have a question, just ask it, if someone wants to answer it, they will.
@0celo7 It's only "mostly GR" because that's what you yap about all day :P
 
1:08 AM
@ACuriousMind no
it's that French hooligan!
@ACuriousMind have some good music to raise your spirits
I have literally no clue what that song is about
But it's amazing.
If you get in trouble that just mean you fuckin' up.
Wise words.
 
I did however ask the question in physics.stackexchange.com/questions/244586/… , it did not garner much attention, owing to my incompetence in asking a question on stackexchange.
 
@ACuriousMind Americanized German last names are the worst.
 
@0celo7 Trump is better than Drumph, dont you think?
 
What?
 
Donald Trump's ancestors went by the name Drumph, before they arrived in America, so I am told
 
1:19 AM
Ok, so?
 
@0celo7 Drumpf is a German last name, and Trump is the Americanized version of it. I was just suggesting that Trump sounds better than Drumpf.
 
@AnuroopKuppam You can explicitly compute that $\exp(\theta \vec n \cdot \vec \sigma) = I\cos(\theta) + \mathrm{i}(\vec n \cdot \vec \sigma)\sin(\theta)$, showing that since the l.h.s. is the rotation generated by $\vec n \cdot \vec \sigma$, the r.h.s. is so, too.
 
I have never heard of a German called that.
 
One explicitly computes that by expanding in a power series, and using that $\sigma_i^2 = I$.
 
@ACuriousMind which idiot thought of naming a unit of a ring something that's not 1
 
1:25 AM
@0celo7 I don't understand that question.
 
@ACuriousMind let me give it a try.
 
@ACuriousMind $a\in R$ is a unit if there exists $b\in R$ s.t. $ab=1$
 
@0celo7 I know. Are you bugged by a "unit" not being the same as the multiplicative identity?
 
@ACuriousMind Yes
Because we call it a unital ring
 
@0celo7 Well, it's a unital ring because it has units (you can't define units in the absense of the mult. identity)
 
1:29 AM
@ACuriousMind the problem is that I simply cannot apply the LHS to a vector, because the operator matrices are still in the exponent. I have to expand it using the power series and I will arrive at RHS anyway.
 
And when looking at prime factors and such, "units" are a more natural class of "do nothing" objects than the identity.
@AnuroopKuppam You can arrive at the r.h.s. without applying it to any specific vector, see Wikipedia.
And why would that be a "problem", anyway?
 
@ACuriousMind now I have to prove that the LHS is infact a rotation about the axis $\hat{n}$, how do I do that.? I convinced myself that $R_x(\theta)$ is infact a rotation about X by applying it on a vector and checking that it infact is rotated by theta about X, and the same for Y and Z.
 
@ACuriousMind is it nontrivial to prove that if $ua=1$, then $au=1$? (u is a unit)
 
@AnuroopKuppam How do you define a "rotation about $n$"?
@0celo7 It's pretty trivial for someone who's used to algebra, but it is good to work it out yourself.
 
1:48 AM
@ACuriousMind I am not sure but I think one needs to show how the components of a vector change.
 
@AnuroopKuppam Here's a straightofrward way: If you're convinced that $\exp(\theta\sigma_i)$ are rotations about the $i$-th axis, just rotate your coordinate system such that $n$ is aligned with one of the corrdinate axes, so that the case reduces to the one you've already proven.
 
@ACuriousMind Ok, here's my attempt (not homework): Note, I proved for homework that $u$ is never a zero div. Some algebra: $ua=1,aua=a,(au-1)a=0$. Now I wanted to show that $au-1$ is not a zero div, but got stuck. A proof by contradiction failed.
Actually I showed that $u(au-1)=uau-u=u-u=0$, but since $u$ is not a zero div...
Is that correct?
 
Wait a moment...
In a non-commutative ring, you can have that $ab=1$, but $ba\neq 1$.
The thing you're trying to prove is either trivial or false.
and "unit" is usually only use in the commutative context
 
Hmm
Actually what I did is false
I used $au=1$ in my proof that a unit is not a zero div
 
Your ring must be assumed commutative, what is there even to prove? $au=ua$ by definition.
 
1:58 AM
:P
Lemme ask the prof
He said something about it being nontrivial and he didn't want to get into it
 
Just to be clear, what is your exact setting?
I.e. what are $u$ and $a$ elements of?
 
From my notes:
Def. $a\in R$, $R$ a ring, is a unit if $\exists b\in R$ s.t. $ab=ba=1$.
Upon a closer inspection, the textbook requires $R$ to be commutative.
At this point, the prof usually specifics "ring" vs. "commutative ring".
 
@ACuriousMind rotating the entire co-ordinate system, will actually change the angles $\theta$ and $\phi$ of a vector and figuring them is not so easy.
 
2:18 AM
@AnuroopKuppam Well, indeed, any explicit calculation here is not going to be "easy", it's going to get a bit ugly at some point either way. This is one of the computations one does once and then never does again.
 
@ACuriousMind Will give it a try and let you know.
 
2:38 AM
S.W. Hawking and G.F.R. Ellis (1973), *The Large Scale Structure of Space-Time*.

R.M. Wald (1984), *General Relativity*.

J.K. Beem, P.E. Ehrlich, and K.L. Easily (1996), *Global Lorentzian Geometry*.

Y. Choquet-Bruhat (2009), *General Relativity and the Einstein Equations*.

A. Zee (2013), *Einstein Gravity in a Nutshell*.

S. Weinberg (1972), *Gravitation and Cosmology*.

S. Carroll (2004), *Spacetime and Geometry*.

C.W. Misner, K.S. Thorne, and J.A. Wheeler (1973), *Gravitation*.

N. Straumann (2013), *General Relativity*.
@Slereah
That's a little ridiculous :P
It's also crazy how many of those I knew off the top of my head
 
 
2 hours later…
user54412
4:21 AM
@JohnRennie If it's any consolation that's no more wrong than the other 10 answers on the page. Really I think everyone just missed the simple explanation that the original statement makes sense in some form of non-relativistic QM, so one cannot introduce the speed of light and expect anything good to happen. For some reason this one statement of Cox's gets a lot of flak by people who want to claim he's stupid. It brings out misdirected pedantry more than anything else.
 
user54412
@FenderLesPaul You know, everyone always says to ignore non-academic issues (short-term significant others, friends, weather, entertainment, etc.), but I think that's just foolish. You're going to spend more time in grad school than any stage of your life so far, and you have every right to aim for something enjoyable.
3
 
user54412
Sure, there's a danger of overvaluing non-academic stuff. I know Californians who never even considered moving out of state because they don't believe the sun shines anywhere else in the world.
 
user54412
But appropriate weighting of all factors is necessary to making a fully rational decision.
 
4:58 AM
Well said^
 
5:58 AM
hey is anybody active?
My professor just told me one of the weirdest things and i can make no sense of it
@ACuriousMind
@ChrisWhite
its about gravitation
@0celo7
He said something about "gravitational waves in a "digital background" "
does that mean anything?
 
6:13 AM
Is he a philosophy professor?
 
nono......a person who studies GR
a good one as well/....
so....any thoughts?
 
 
2 hours later…
7:50 AM
@FenderLesPaul So, can you make a case for both choices?
 
8:04 AM
@Sidarth You'll need to expand on that.
 
8:39 AM
@0celo7 looks okay
 
9:22 AM
 
user116211
11:07 AM
14
Q: Uncertainty in Uncertainty?

Udit DeyI was reading about how the Planck's Constant can be measured with LEDs, which made me think about this question. The Heisenberg Uncertainty Principle states that: $$\Delta x \Delta p \ge {\hbar\over2}$$ a.k.a, there is always some uncertainty while measuring things. This is a fundamental law. N...

 
user116211
::Facepalm::
 
user116211
From now, anyone who wants to build up rep.....
 
user116211
Just ask such old wine in new bottle sort of uncertainty questions even though without searching a bit of the otherwise gazillions of questions lying in PSE.
 
user116211
You'd be rep-rich.
 
Answering them is also fun business ;)
 
user116211
11:14 AM
@Danu ;P
 
user116211
ACM is always at the rescue.
 
While checking out what badges I could next obtain, I got so annoyed that this answer is still stuck at 19 :P
 
user116211
@Danu 20 is okay?
 
@user36790 people may be completely amazed to know that there are states for which the uncertainty principle do not hold :-D
 
user116211
@Mehrdad: Indeed, thanks! 19 upvotes and you're the first to notice that... — ACuriousMind 23 mins ago
 
user116211
11:16 AM
That's epic absence of mind ;P
 
think how many upvotes for that
 
user116211
@yuggib oh.
 
user116211
@Danu: WTF!
 
@yuggib Domain issues (that's what you're referring to, right?) don't usually tend to amaze people, in my experience...
 
user116211
-8 ;(
 
11:19 AM
@ACuriousMind no, I mean this
it has also experimentally realized...let me search it
 
@yuggib Oh, but that's about measurements.
 
> Reformulation of the Heisenberg uncertainty principle
And you're saying the uncertainty principle doesn't hold?
 
@ACuriousMind the Heisenberg principle is all about measurements
@Danu I am saying it doesn't hold as stated
not that QM is wrong, or anything
 
@yuggib No, when I write down $\sigma(A,\psi)\sigma(B,\psi)\geq 0.5\langle [A,B]\rangle_\psi$, I do not refer to any measurement at all.
 
@ACuriousMind $0.5$ ewwwww
 
11:22 AM
@Danu I hate the inline spacing for fractions :P
 
$1/2$?
 
@Danu Then there's always the ambiguity if what follows is still under the fraction or multiplied to it, so I have to use more brackets...
 
No, without brackets there is no ambiguity
 
@ACuriousMind well, you are assuming that these operations are yielded by a measuring process
if else everything is moot
 
@yuggib Well, $A$ and $B$ correspond to observables I could in principle measure, but to me, the uncertainty principle is not about what happens if I actually do measure them. It's about the "widths" of wavefunctions, how "smeared out" the state is with respect to these observables, not about what experimental noise I get when using a particular apparatus to actually measure them.
 
11:27 AM
ok, I see your point
and probably this is also what people mostly refer to when arguing over uncertainty principle
 
Nevertheless, that paper is interesting because it shows you cannot transport this abstract uncertainty relation over to measurements straightforwardly. Nice reference to have
 
yeah, I think so
that damn Ozawa does a lot of interesting stuff
(he's the one that have proved existence of a measuring apparatus for any observable)
(and also the one who has done the quantum set theory, where the self-adjoint operators are real numbers of this new ZFC-type set theory)
 
@Slereah dammit I can't answer that right now
Someone else will steal MY POINTS
@Slereah Why hasn't some math person written a tome on black holes
There's plenty of interesting geometry there
 
Have you ever seen a black hole in the sky
 
No, and I don't give a shit.
Einstein was wrong, deal with it.
Did you know that Eimstime failed the driving test a whole bunch of times
 
11:39 AM
@yuggib He's the one who wrote that paper on measurements that you had a bit of difficulty to obtain, right?
 
And constantly shit all over the place
 
@ACuriousMind yeah exactly
because many universities do not pay for the old issues of J. Math. Phys.
only for the ones of the last 5 or 10 years
(I have no idea why)
 
Hint : It's money
 
yeah, but then I suppose they would not have a subscription at all...
why just a subscription for recent papers (that are 97% of the time available on arXiv)?
 
For the 3% I guess
And I suppose the old papers come up less often
 
12:11 PM
@Slereah anything back from Ellis?
 
As I said
He basically said WOOPS I'M A BIT BUSY
Where are the famous Kerr CTCs in the Penrose diagram, anyway
 
Huh?
 
None of them seem to show any bit where a timelike curve would loop back
Aren't Penrose diagrams supposed to preserve the causal structure
 
Are there CTCs?
Proof?
Or the HE page and I'll take a look at it later
 
12:19 PM
What book is that
 
Some rando paper
 
Ok I'm eating right now and doin homework, I'll look at it later
Dammit phone why won't you autocorrect doin
It's doinG
@Slereah Uh, I think the Sanchez metric is the one I have.
So you're fucked.
 
Unless someone else finds it!
 
I ordered a MyCopy of the book it's in.
I'll write the thing when I have it.
 
What book
 
12:30 PM
Not telling you.
How many GR books are on Spriner though
 
Hundreds, probably
You never solved that metric at all, you fraud
it was all someone else!
 
> postulate 2 is required by postulate 1: if the speed of light were not the same in all inertial frames, measurements of different speeds would make it possible to distinguish between inertial frames.As a result,a preferred,absolute frame could be identified.
I don't quite get it, I know that the constancy of speed of light is the reason why we have a (-+++) metric, and hence things like time dilation. But I am not sure how to understand how if we measuring the speed of light being different will aloow everything to be modelled in just one type of inertial frame?
 
The speed of light stems from the laws of physics
The Maxwell equation gives you a propagation speed for EM waves
If it varied between frames, the Maxwell equations would vary between frames
 
Ah I see, then postulate will be invalid
postulate 1*
 
Hence you could pick a frame where the Maxwell equation is in a particular form
 
12:39 PM
@Slereah There are not hundreds of dedicated GR books.
 
Are there not
 
No
 
14580 results on Springer for english books physics with "general relativity"
 
Those are not dedicated
Actually there's 138
 
Not bad
 
12:53 PM
But even then
A lot are bullshit.
Like the matrix one, or the other without calculus.
And there's some SR books in there too
Is Callahan any good?
 
Without calculus?
Callahan is a good intro
I wouldn't recommend it to a seasoned GR man tho
Callahan is basically
SR, SR in accelerating frames, SR in rotating frames, curved imbedded manifolds
Then curved manifolds
Then GR
 
Penrose coming today
 
and then some Schwartzschild with the remaining time
It doesn't do a lot of GR proper but it was one of my first GR book and I think it was a good thing
 
Holy fuck is Visser coming from like China by boat
It's still "in transit"
 
in a rickshaw
 
1:00 PM
Amazon wants me to buy HE again
 
Can't have too many HE
Was there ever a reedition of HE
Seems weird that such a classic was only published in the 70's
 
The paperback I have is a 90s reprint
The Original was hardback
Random capitalization GG iPad
 
I had to buy the old hardback Feynmann Gibbs
Then the next year, it was reedited
 
2:00 PM
Don't you mean Hibbs
 
Pibbs
It was written by Mister Pibbs
 
Ah, Dibbs
 
http://www.nature.com/nphys/journal/vaop/ncurrent/full/nphys3700.html

Multiparticle systems
 
@Slereah Penrose is on the truck and out for delivery!!!
Oh wait I misread your post in my haste this morning.
Shit, I don't have my laptop with me, won't be able to answer it until tonight!
 
2:53 PM
guys on SO chat are really weird
 
@DeNiSkA what do you mean?
I mean, it's probably true, we're all kind of weird, but chat demands stories
 
@DavidZ guys there are quite undisciplned compared to this chat room
in Lounge<C++> on Stack Overflow Chat, 14 mins ago, by Rerito
@DeNiSkA Hang yourself
@DavidZ you are also SO user with high rep. woah O.O
 
@DeNiSkA Hmm... yeah. Seems so.
The C++ chat room does have somewhat of a bad reputation
 
@DavidZ even python!
whatever i post, they delete it
 
Well, that doesn't necessarily make them undisciplined! It depends on what you're posting, and what the culture of the room is.
It does raise some eyebrows though.
 
3:05 PM
@DavidZ yeah ;)
 
@Slereah you around
 
mb
Maybe I went with the metric all wrong
Maybe I should just take the metric in the $X_1 X_2$ basis
And do a good ol diffeomorphism
 
3:46 PM
@ACuriousMind ?
 
What would be $x,t$ in this basis, tho
Hm
 
This account is temporarily suspended to cool down
what does this mean
 
Well WA doesn't know
 

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