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11:00 AM
is that your bank balance?
 
user228700
My bank balance? Oh, that's less than £2.
 
then what's 57?
it's very specific
 
@Kenshin Same price for those here, but is that really what you call a good laptop? Gaming computers are known to be really expensive, especially in the laptop format. I never needed a robust GPU
 
user228700
Yes, £57 = Rs. 5000
 
oh
@G.Bergeron yeah they're probably overpriced
 
11:02 AM
I don't like british pounds, they make me ruin myself when there. Same for swiss franc
 
@G.Bergeron I perosnally prefer a desktop because I find all laptops are too slow or have heating issues
 
@Kenshin ? Slow?
 
user228700
My parents are paying for this. I'm totally broke. I have enough to treat myself to some pastries, perhaps.
 
YEah a good desktop outperforms the best laptops
 
@Kenshin What are you doing with your computer?
 
11:03 AM
In the past I've run very large simulations in R
 
@Kaumudi.H Isn't this normal at that point in life?
 
user228700
@G.Bergeron I sure hope so :-P
 
@Kenshin I don't know I've always used apple computers and I know I'm never doing heavy simulations but never had problem besides RAM with 200+ tabs open in different browsers...
 
yeah my simluation needed more RAM
I've never used apple though
 
I'm looking into buying GPUs to do computing now, for personal use
@Kenshin We had them when I was a child and they where gray and I guess it sticked with me
@Kenshin For desktops with apple, you pay a bit too much for the brand, but I think the air line is still competitive
 
11:06 AM
I agree, I think apple desktop would be overpriced
But most dekstops are alot cheaper than laptops for the RAM and performance
You pay more for the portability of the laptop
 
And you get a nice wrapper for unix (os x) but were I to get a desktop, I would just buy components.
 
to fit all of that stuff in a smaller space
 
@Kenshin And the battery
 
exactly
 
But I like laptops!
 
11:07 AM
so cos I do all of my computing at home, I prefer to use all my money for performance rather than portability
 
@Kenshin I can understand, I just never really need the performance
 
yeah laptops are cooler
 
Can I ask my physics doubt ?
 
@koolman why don't you post it to physics.qandaexchange.com
 
yes
@Kenshin Isn't that for homeworks?
 
11:09 AM
yes
 
@Kenshin I have already posted , now I have a conceptual problem in that
 
alright @koolman what do you doubt?
 
In any case, going back to work... Good luck with the delivery @Kaumudi.H
 
Does kinetic friction does not apply when object rolls without slipping
 
no that's static friction
@koolman when you walk, it is static friction that pushes you forward do you agree?
because each foot is static with the ground
 
11:12 AM
It will reduce the linear acceleration
@Kenshin yes
 
Similarly with a rolling object, the point in contact with the ground is statically pushing back on the ground
just like in walking
it isn't "scraping" along the ground
 
So it will not affect linear acceleration @Kenshin
 
Basically rolling is just another form of walking, but if you had infinite legs and stepped very quickly
 
@Kenshin what about linear acceleration
 
@koolman it won't affect linear acceleration
 
11:19 AM
Why
 
@koolman this has a good explanation:
 
Ok let me see
 
wait
@koolman it may not be the best
anyway
basically
why would it slow down?
the friction is static
does the ground slow you down when you run? No
the friction actually helps the ball roll
 
@Kenshin it increases its angular acceleration
 
what?
 
user228700
@G.Bergeron Thanks :-)
 
I know what angular acceleration is
 
user228700
x'D Poor @Kenshin
 
@Kenshin then due to friction will it increase
Due to torque
 
what do you think
 
11:26 AM
Increase
 
and what do you think happens if angular accelartion increases?
 
More fast rolling
 
is this what you observe in real life?
that a ball continues to get faster forever?
 
Ah no
But there will be torque
 
will there be torque?
let's Imagine we release a ball with translational velocity of $v$
but let's suppose the ball has no rotational velocity
this means the object will slide correct?
in this scenario, there will be kinetic friction
that causes the ball to rotate
this will continue to apply to the ball
 
11:31 AM
Yes
 
until the ball is rotating such that the tangential velocity is equal to the translational velocity
 
Yes
 
but note the translational velocity is in the opposite direction to the tangential velocity
this means that the point of the object in contact with the ground actually has a velocity of 0
 
Yeah
Pure rolling
 
so what torque do you think will be generated when an object with velocity 0 (the ball) touches another object with velocity 0 (the ground)?
 
11:33 AM
But if a body rolls on an incline plane
 
this is new, you never stated we were on an incline plane before
but go on
 
I forget that
@Kenshin then there will be torque
 
indeed
and as the answer states, presumably the balls wont' slip,
 
@Kenshin torque cannot be from gravity
Force due to gravity is at its centre of mass
4
Q: Ball Rolling Down An Inclined Plane - Where does the torque come from?

user3904840There is a ball rolling down an incline, with no slipping. If we consider the point of contact between the ball and the inclined plane to be the pivot point (for our torque calculations), then I have noticed that friction is no longer in play, and gravity (and normal force) is the reason for the ...

 
yeah that answer explains it well
 
11:40 AM
So angular acceleration is increasing
 
when rolling down the hill, of course
 
Yeah
Thanks @Kenshin
 
np
 
@Kenshin on inclined plane also there will be no kinetic friction
 
correct, there will only be kinetic friction if there is "slipping"
which you would ordinarily assume there isn't, becuase if there was it would quickly accelerate the system back to equillibrium again
kind of like the example I gave with teh ball of velocity $v$ and no rotation, given enough time the torque due to slipping will force the ball back to the rolling state
 
11:43 AM
Yeah :-)
 
@koolman good question btw on the site with ur attempt shown
 
Thanks
 
11:56 AM
@Kenshin what should I do to this question physics.qandaexchange.com/?qa=618/angle-turned-by-disk
Sammy has explained me in comments
 
just leave it
the comments may help someone else in the future
and maybe someone will come and answer it one day which would help others even more
 
Ohk
@Kenshin Actually I have edited with answer
 
no don't do that
that's confusing
but you can answer your own question in the "answer" section
 
Then
 
I think you should leave the question as it was, and then just add your answer in the answer section
 
11:59 AM
@Kenshin but in that answer sammy helped me so he should add the answer
Should I message him
 
up to you dood
 
Ohk
 
hi
I earned a secret hat
 
12:13 PM
wow
that's awesome
my fasvourite is the klingon Newt
the rainbow serpant has shrunk alot since the time of the aborigines
 
What was the "where are you hat" for? Did it tell you when you got it?
Something to do with your location in the world I guess ...
 
@JohnRennie it says it's a secret hat
 
So it didn't say why it was awarded to you?
 
hello
 
nope
 
12:18 PM
@JohnRennie I got a secret hat too, no idea why
 
But I got it shortly after closing a few questions
I tried to close a few questions to get the abominable hat
and I got this one with it
Maybe it's for getting 2 hats after 10PM or something
 
I posted an answer to a question which already had several answers
 
after 10PM?
 
and then upvoted several answers in the same question (different question than before)
 
I didn't do any of that
@AccidentalFourierTransform what country areyou in?
 
12:21 PM
My hat is different than yours though
 
oh
 
its past 13.00 here, in Spain
 
it's irrelevant i thought you had the same hat lol
 
People get addicted for hats.
 
yeah, it is fun for some reason
 
12:22 PM
yeah cos they're awesome
 
Agreed.
@AccidentalFourierTransform You are a physics Graduate?
 
@SwapnilDas kind of, yes
I graduated recently, I dont have the official certificate yet
 
doesn't count then
 
12:24 PM
totally counts
@AccidentalFourierTransform, congratulations!
 
na the certificate is everything
I bought my certificate online
 
@heather thanks :D
 
0
Q: Perturbation Theory for a ring in an Electric Field

נעמי נבוparticle pf mass m move on a circular ring of radius a.The only variable of the system is the azimuthal angle, which we will call .The state of the system is described by a wave function ψ(φ) that must be periodic. ψ(φ + 2π) = ψ(φ) and normolaized. Now assume that the particle has a charge q an...

 
@Kenshin Ok bro calm down :P
 
^thoughts on this question?
 
12:25 PM
@heather i'd close it but I already have my abominable hat
 
@AccidentalFourierTransform Would you mind telling your specialization?
 
anyone else seen rogue one?
 
@SwapnilDas I'm studying theoretical physics.
 
@AccidentalFourierTransform Great. Even more specially (Like, string theory, Stat Mech. or GR)?
 
let me guess
condensed matter/statmech
 
12:28 PM
My guess is GR/mathematical physics.
 
@SwapnilDas I'm not much into GR. I like quantum field theory.
@Kenshin oh no, not at all :P
 
I just guessed the most popular branch of theoretical physics
 
I won (mathematical physics) !
 
no QFT <> mathematical physics
 
Most popular, seriously?
 
12:30 PM
as in, the one where most people work
not necessarily the one most people like
 
i just earned a secret hat!
 
Oh. Then fine.
 
Good Job Heather
which one, same one asme?
 
@heather Yohoo!
 
same as accidental fourier transform's
should be showing up in a minute
 
12:31 PM
oh yeah, that's the opposite one of mine
I think it's to do with the December solstice
 
i did a couple of close vote reviews, then a low quality review, and got the hat =)
 
Do hats show up to the user himself?
 
and what hemisphere you dwell int
if you're in the North hemisphere you get heather's hat
if you're in the South hemisphere you get my hat
 
right...
the hat is called "where in the world"
so
 
I wonder what drives so many guys towards condensed matter
 
12:32 PM
mine is also called "where in the world"
@SwapnilDas because it's easier to find new stuff to work on
there are more unanswered questions in condensed matter than other branches
 
Umm.
 
umm
no. just no.
 
Not in GR, strings, QFT and so?
 
no, it's much harder to make a contribution there
GR is pretty well defined
The standard model is also pretty good
String theory is questionable science
We are waiting on a breakthrough
 
uh...standard model is not complete!
 
12:35 PM
but breakthrough's are hard, so people prefer condensed matter
 
quantum gravity! TOE!
but....
there are so many things that bother me here.
 
in the "publish or perish" culture, most perish when doing quantum gravity
 
Hmm.
 
@heather there's definitely questions to answer, but they are harder to answer
 
how 'bout quantum computing!
 
12:36 PM
condensed matter is easier because it is more applied
 
oh, yay, new hat showed up
 
YEs quantum computing is going tob e more popular in the future
 
But yeah, great minds do physics for revolutions, not papers :)
 
::winces::
 
but yes definitely lots of room for physicists to work in quantum computing which definitely overlaps statistical mechanics
@SwapnilDas yes but most physicists after age 30 just want a stable job
 
12:37 PM
i think what makes me extra interested in quantum computing is it is at the intersection of physics, math, computer science, and engineering, aka, all my interests. =)
though of course it's just interesting.
 
Yeah I think your the perfect age to contribute to it
 
@heather wait. Are you actually 13?
 
@AccidentalFourierTransform, year older, but yeah.
8th grade.
 
You'll be in uni when QM Computing will be expanding rapidly which is great
 
oh, okay
 
12:38 PM
well it's very early days right now
 
sure.
 
but there will be more investment into it soon I believ
 
@heather that is impressive, congratulations :-)
you'll be a very successful scientist some day
 
@heather yes congratulations for being in 8th grade
 
Heather is obviously talented.
 
12:41 PM
you don't know how old she is though?
maybe she was kept back several years
 
@Kenshin, i assure you i was not.
 
oh
 
@AccidentalFourierTransform thanks, but really, i've had lots of help.
 
1:22 PM
Can any one have some easier way as said by sammy for this
 
yes
 
What
 
i just want to check my simple solution gives the right answer then i'll tell u
 
Ohk
 
Ooh, I've got Where in the world now. I wonder if it has to do with updating your profile info ...
 
1:31 PM
@koolman ok I know it
@JohnRennie no I think it is doing any action today
I think it is to do with today's date, and your location in the world
congrats on the new hat :)
@koolman r u ready?
 
Ahhh. I wonder if you got the Moon because it's night time in Aus while AFT and I got the Sun because it's day time here ...
 
yeah that makes sense
what is AFT
 
ass field theory
 
oh
 
@Kenshin sammy has edited his answer with more easier way is it same you mean
 
1:34 PM
what @Slereah said.
 
@Kenshin Accidental Fourier Transform
 
@koolman my way is just (1) calculate the angular acceleration = 3
 
How
 
oh because angular acceleration*r = tangential acceleration
this is a known formula
 
Yea
 
1:36 PM
and we're given tangential acceleration = 3
and r= 1
so therefore angular acceleration = 3
 
ass field theory - I thought asses were already quantised. Why do we need a second quantisation approach? And precisely what are asses excitations of? If I get very excited might I end up with two or more asses?
 
then step (2) calculate tangnetial acceleration at point P
 
Ohk @Kenshin
 
at point P, r = 1/3, angar accleration is the same = 3, so 1/3*3 = 1
so tangential acccleration at P is 1
relative to the disk
but the disk is also moving at 3
so total tangential relative to ground is 1 + 3 = 4
this is the tangential component
the other component is the centrepital component
 
Yes
 
1:38 PM
which is angularvelicty^2*r
 
kiss my ass to all orders in perturbation theory
 
= 9^2 * (1/3) = 3
then you just get the resultant force as root of 3^2 + 4^2
@koolman so there is no need to differentiate the position of P as sammy has done if you already know your formulas
 
I think it is angularvelicty^2/r
 
na that's not correct
 
1:42 PM
@koolman v there is tangential velocity
if you want angular velocity it becomes angularvelocity^2*r
 
@Kenshin oh sorry
 
since angular velocity*r = tangential velocity
 
Got it
This one is better , thanks @Kenshin
 
np
 
@Kenshin could you also explain me the edited answer of sammy
How he has get the linear acceleration at point P
 
1:48 PM
i dunno sorry
 
Np
@Kenshin you have the secret hat
Cool
 
ty
 
Hi again!
 
2:14 PM
The shortcomings for some type of all powerful entity is their domain specific rein. If you can fool them into a realm where they are powerless, they will be controlled very easily
To lure the all powerful into a simulation within a simulation...
 
2:49 PM
1
Q: What kind of waves can be/are produced by accelerating strong /weak forces

Suhrid MulayAccelerating masses are now confirmed to produce gravitational waves. Also it is known that accelerating charges (electrical) produce EM waves. But what kind of waves are produced when particles interacting via strong or weak force accelerate. Are waves even produced at all.

Bu they are different, and they are insanely short ranged
 
3:09 PM
Yipee got a secret hat just now
 
"Where in the world" seems easy to get
 
user228700
@JohnRennie: Are u around?
 
I'm here ...
Did you just get my mail?
 
user228700
Yes.
 
user228700
U sent it urself..?
 
3:15 PM
After I mailed you I thought why not just sent the receipt directly to that chap at TNT, so that's what I've done.
 
user228700
Ah, I see, okay. I'm sorry I read the mail a bit late...just now, actually.
 
If you've sent a copy as well that's all to the good.
 
user116211
0
Q: Quantum Field Theory in position space instead of momentum space?

LCFWhat are the reasons why we usually treat Quantum Field Theory in momentum space instead of position space? Are the computations (e.g. of Feynman diagrams) generally easier and are there other advantages of this formulation?

 
user116211
1
Q: Position space Feynman rules to momentum space

FWNitzFor example consider $2\to2$ scattering in scalar $\phi^4$ theory. When the in/out coming positions are fixed, it is easy to calculate in terms of contractions. When we fix the incoming / outgoing momenta instead, how can we use the Feynman rules in that case? In principle one can expand all th...

 
user228700
No, I read both e-mails just now.
 
3:17 PM
@Kaumudi.H We aren't dealing with the most efficient company ever to grace Hindustan :-)
 
user116211
Are the two posts above in anyway related?
 
user228700
:-) No, we're not.
 
Anyway, hopefully the message will get through.
@Kaumudi.H at least all this hoo haa adds a certain interest to developments. When you finally get the laptop it will feel as though you've triumphed ina great quest! :-)
Incidentally it wouldn't hurt to ring tomorrow and check the e-mails have been received.
 
with my new hat, my avatar looks like nyan cat :D
 
@AccidentalFourierTransform lol
 
3:25 PM
@ACuriousMind your hat is too mainstream, sorry
 
I haven't got any of the fancy ones yet :/
 
user228700
@JohnRennie Indeed, it certainly will :-)
 
user228700
@JohnRennie Oh, alright, I'll do it.
 
Hi :) Quick question: is it possible to see questions on SE from multiple tags at the same time?
 
3:35 PM
@Lalylulelo Yes, just type [tag-1] [tag-2] [tag-3] into the search box to find all questions tagged with tag-1, tag-2 and tag-3
 
thanks!
 
Sigh...if the algorithm for the snaphat is pedantic and doesn't count 30 minutes and 2 seconds as 30 minutes, I can't get the hat for this answer :/
2 seconds!
 
it seems to give the questions that are tagged with tag-1 and tag-2 and tag-3. But is it possible to have questions tagged with tag-1 or tag-2 or tag-3?
 
@Lalylulelo Type OR in between the tags ;)
 
ok, I tried by myself :p thanks !
 
3:41 PM
Thanks whoever voted that up, it appears the algorithm is pedantic
I need to type faster or give answers with less formulae :P
 
@ACuriousMind You should wait about 10 min for the updated hats.
@ACuriousMind You have got it.
 
@Loong I see, not so pedantic, then!
Now I wonder what the maximum tolerance for "30 minutes" is...
 
±0.5 min or file a bug report ;-)
 

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