I drank orange juice too soon after brushing my teeth and my mouth feels awful!
What causes that foul taste with this combination of toothpaste and orange juice? Is it a reaction between the oil of wintergreen in the toothpaste and the citric acid in the OJ? Is it something else? What's the expl...
When calculating the number of moles of calcium hydroxide formed from each mole of sodium hydroxide in the balanced reaction CaCl2 + 2 NaOH ® Ca(OH)2 + 2 NaCl, the best conversion factor to use is
I understand that ate complexes can result from the addition of carbanions to neutral aluminum alkyls.
I was wondering what the balanced equation for this reaction is/what the structure would be in solid state - like does it dimerize
$$\ce{2 LiCH2CH3 + Al2(CH2CH3)6 ->\ \ \ ?}$$
Yeah but even if his English is bad, which is fine, tons of people on here don't speak English natively, but it really wasn't what I would call an extensive answer on the topic.
But yeah, some people feel so bad and it's like, don't worry, you're fine.
Are there any chemical reactions where in order to induce the reaction, you have to heat up a substance but after the reactions happens, the substance is much colder than even before you started heating it up?
This question (Is there a chemical that when added to water makes the water flash evaporate?) was posted 2 days ago, closed yesterday as being too broad and reopened today (14th Sep 2016 at 17:45Z, timeline). The question has never been edited so its contents are the same throughout.
I wonder wh...
I don't really understand why Jan wants to bounty me. I have no use for rep..
I mean, thanks, but others could do with it. I think that most of the rep I accrue from now on will probably be put towards bountying "interesting" questions.
I think what you are fundamentally saying is you are trying to relate classical thermodynamics to the molecular properties. It is best to have some firm familiarity with classical thermodynamics before attempting this. Classical thermodynamics does not require a molecular interpretation at all! (...
I must admit, I looked into the possibility it was a sock, but no evidence... also the modus operandi is not entirely the same
However, this alphonse guy has picked up the most irritating thing from Li Zhi, which is the refusal to listen to any comments asking him to paragraph his answers.
This past Sunday's data says there were actually 910 questions with reaction applied, though that includes 21 questions tagged only with reaction that were cleaned up beforehand.
Assuming the question set held roughly steady until tonight, that's 889 - 758 = 131 questions. With three people actively out editing questions, that's 3.44 minutes per question (or, 3:26 per question)
The pace was hindered by edit and review queue speed limits, but those will apply per-person and thus scale as the team size increases
The reaction of $\ce{(C5H5)Fe(CO)2Cl}$ with an equimolar amount of $\ce{Li+[C6H5]-}$ gives a product. Draw its structure and apply the 18 electron rule.
In a question I was given the molecular weight and percentages of each element in the compound. I worked out that there is $\ce{1 Fe}$, $\c...
@orthocresol Yeah, this guidance will be going into the faq thingy (when I hopefully can solidly get to it) (@heather)
@orthocresol yeah, that answer's annoying. Two links included without clear indication why, two sentences answering the actual structural question, and one final confusing sentence muddling things.
The two good sentences are probably a good answer. The rest is low-quality. Should probably be edited? Not sure why it got four upvotes.
Lets say we prepare a solution of HCl whit concentration of HCl to be 10^-8. Even on full dissociation (which it will, because it is a strong acid), the H+ ion concentration due to HCl is 10^-8.
So shouldn't the pH be 8? Is there any factor I am missing? Does the properties of acids change at lo...
Consider an acidic solution with Hydrogen ion concentration, $\ce{[H+]}$ of $10^{-5}\:\mathrm{M}$. Since $\:\mathrm{pH} = -\log \ce{[H+]}$ the $\:\mathrm{pH}$ of solution is $5$. Suppose we dilute solution 10 times with water. Now, $\ce{[H+]}$ is $10^{-6}\:\mathrm{M}$ and $\:\mathrm{pH}$ is $6$. ...
@heather @M.A.R. Yeah, homework is going to be a MUCH bigger and more involved task than dealing with reaction.
Much more specific stuff to deal with, and likely much lower quality of questions overall -- more decisions on closure, deletion, etc.; harder to edit.